I want to split string around only the last _ character , example:some_string_foo_bar into two substrings some_string_foo bar.
I tried to use Pattern and StringTokenizer, but they always start from the beginning of stirng. Any idea how to do this?
Use lastIndexOf; there's no reason to do a full split.
Sure, this might be of some use. Here's an example.
String source = "hello_world_foo";
int pos = source.lastIndexOf('_');
String before = source.substring(0, pos);
String after = source.substring(pos + 1);
You can use:
String strX = "some_string_foo";
String str1 = strX.substring(0,strX.lastIndexOf("_"));
String str2 = strX.subscting(strX.lastIndexOf("_"),strX.length());
String[] arr = str.split("_");
String lastOne = arr[arr.length-1];
Related
I have a string String a = "(3e4+2e2)sin(30)"; and i want to show it as a = "(3e4+2e2)*sin(30)";
I am not able to write a regular expression for this.
Try this replaceAll:
a = a.replaceAll("\) *(\\w+)", ")*$1");
You can go with this
String func = "sin";// or any function you want like cos.
String a = "(3e4+2e2)sin(30)";
a = a.replaceAll("[)]" + func, ")*siz");
System.out.println(a);
this should work
a = a.replaceAll("\\)(\\s)*([^*+/-])", ") * $2");
String input = "(3e4+2e2)sin(30)".replaceAll("(\\(.+?\\))(.+)", "$1*$2"); //(3e4+2e2)*sin(30)
Assuming the characters within the first parenthesis will always be in similar pattern, you can split this string into two at the position where you would like to insert the character and then form the final string by appending the first half of the string, new character and second half of the string.
string a = "(3e4+2e2)sin(30)";
string[] splitArray1 = Regex.Split(a, #"^\(\w+[+]\w+\)");
string[] splitArray2 = Regex.Split(a, #"\w+\([0-9]+\)$");
string updatedInput = splitArray2[0] + "*" + splitArray1[1];
Console.WriteLine("Input = {0} Output = {1}", a, updatedInput);
I did not try but the following should work
String a = "(3e4+2e2)sin(30)";
a = a.replaceAll("[)](\\w+)", ")*$1");
System.out.println(a);
I want to extract a perticular image path string from a given string .
The String is http:\localhost:9090\SpringMVC\images\integration-icon.png
Now i want to get only the path after images like
\images\integration-icon.png
i tried this
Pattern pattern = Pattern.compile("SpringMVC");
Matcher matcher = pattern.matcher(str);
System.out.println("Checking");
if (matcher.find()) {
System.out.println(matcher.group(1));
}
how can i get ?
String filename = filepath.substring(filepath.lastIndexOf("\\") + 1);
or (haven't tried and looks somewhat odd)
String filename = filepath.substring(filepath.lastIndexOf("\\", "images\\".length()) + 1);
String string = "http:\localhost:9090\ZenoBusinessStore\images\integration-icon.png";
int index = string.indexOf("images\\");
String output = string.substring(index);
String text = "http:\localhost:9090\SpringMVC\images\integration-icon.png"
String subText = text.subString(text.indexOf("\images"), text.length());
System.out.println(subText);
String in = "http:\\localhost:9090\\ZenoBusinessStore\\images\\integration-icon.png";
String op = in.replace("http:\\localhost:9090\\ZenoBusinessStore", "");
System.out.println(op);
ZenoBusinessStore must be the name of your project which is constant.
Now split the string
String s = "http:\localhost:9090\ZenoBusinessStore\images\integration-icon.png";
String ary = s.split("ZenoBusinessStore");
Now the 2nd element of the array is your image path.
System.out.println(ary[1]);
Use '\\'. It's because backslash is used in escape sequence like '\n'. With a single \ the compiler have no way to know.
What kind of method would I use to make this:
http://www.site.net/files/file1.zip
To
file1.zip?
String yourString = "http://www.site.net/files/file1.zip";
int index = yourString.lastIndexOf('/');
String targetString = yourString.substring(index + 1);
System.out.println(targetString);// file1.zip
String str = "http://www.site.net/files/file1.zip";
str = str.substring(str.lastIndexOf("/")+1);
You could use regex to extract the last part:
#Test
public void extractFileNameFromUrl() {
final Matcher matcher = Pattern.compile("[\\w+.]*$").matcher("http://www.site.net/files/file1.zip");
Assert.assertEquals("file1.zip", matcher.find() ? matcher.group(0) : null);
}
It'll return only "file1.zip". Included here as a test as I used it to validate the code.
Use split:
String[] arr = "http://www.site.net/files/file1.zip".split("/");
Then:
String lastPart = arr[arr.length-1];
Update: Another simpler way to get this:
File file = new File("http://www.site.net/files/file1.zip");
System.out.printf("Path: [%s]%n", file.getName()); // file1.zip
I would like to split the word in java based on the delimeter'-'when it appeared last.
I am expecting the result as "sweet_memory_in" and "everbodylife#gmail.com". Do we have any inbuilt function in java.
Complete word is sweet_memory_in_everbodylife#gmail.com
String s = "sweet_memory_in_everbodylife#gmail.com";
String first = s.substring(0,s.lastIndexOf("_"));
String second = s.substring(s.lastIndexOf("_")+1 );
try this
String s = "sweet_memory_in_everbodylife#gmail.com";
String s1 = s.substring(0,s.lastIndexOf("_"));
String s2 = s.substring(s.lastIndexOf("_")+1,s.length());
Regex may help. Other way is to get the last index of _ and use substring to split it.
Try out this code :
String data = "sweet_memory_in_everbodylife#gmail.com";
int lastIndex = data.lastIndexOf("_");
String firstSplit = data.substring(0, lastIndex);
String secondSplit = data.substring(lastIndex + 1, data.length());
System.out.println(firstSplit);
System.out.println(secondSplit);
Try this my friend (Javascript Codes):
var str = 'sweet_memory_in_everbodylife#gmail.com';
var arr1 = str.substring(str.lastIndexOf("_")).split("_");
var arr2 = str.split("_"+arr1[1]);
alert(arr2[0] +" --> "+arr1[1]);
I have a URL and I want it to look like this:
Action Manatee - Action
http://xxxxxx.com/songs2/Music%20Promotion/Stream/Action%20Manatee%20-%20Action.mp3
What is the syntax for trimming up to where it after this "Stream/" and make spaces where the %20 is. I also want to trim the .mp3
Hmm, for that particular example, I would split the string according to the '/' character then trim the text that follows the final '.' character. Finally, do a replace of "%20" into " ". That should leave you with the string you want
Tested
String initial = "http://xxxxxx.com/songs2/Music%20Promotion/Stream/Action%20Manatee%20-%20Action.mp3";
String[] split = initial.split("/");
String output = split[split.length-1];
int length = output.lastIndexOf('.');
output = output.substring(0, length);
output = output.replace("%20", " ");
String urlParts[] = URL.split("\/");
String urlLast = urlParts[length-1];
String nameDotMp = urlLast.replaceAll("%20");
String name = nameDotMp.substring(0,nameDotMp.length-5);
You could use the split() and replace() methods to accomplish this, here are two ways:
Split your string apart by using the forward slashes:
string yourUrl = [URL Listed];
//Breaks your URL into sections on slashes
string[] sections = yourUrl.split("\/");
//Grabs the last section after the slashes, and replaces the %20 with spaces
string newString = sections[sectiongs.length-1].replace("%20"," ");
Split your string at the Stream/ section: (Only use this if you can guarantee it will be in that form)
string yourUrl = [URL Listed];
//This will get everything after Stream (your song name)
string newString = yourUrl.split("Stream\/")[1];
//Replaces your %20s with spaces
newString = newString.replace("%20"," ");
URL songURL = new URL("yourpath/filename");
String filename = songURL.getFile();