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How to Extract text from given string?

I want to extract a perticular image path string from a given string .
The String is http:\localhost:9090\SpringMVC\images\integration-icon.png
Now i want to get only the path after images like
\images\integration-icon.png
i tried this
Pattern pattern = Pattern.compile("SpringMVC");
Matcher matcher = pattern.matcher(str);
System.out.println("Checking");
if (matcher.find()) {
System.out.println(matcher.group(1));
}
how can i get ?

String filename = filepath.substring(filepath.lastIndexOf("\\") + 1);
or (haven't tried and looks somewhat odd)
String filename = filepath.substring(filepath.lastIndexOf("\\", "images\\".length()) + 1);

String string = "http:\localhost:9090\ZenoBusinessStore\images\integration-icon.png";
int index = string.indexOf("images\\");
String output = string.substring(index);

String text = "http:\localhost:9090\SpringMVC\images\integration-icon.png"
String subText = text.subString(text.indexOf("\images"), text.length());
System.out.println(subText);

String in = "http:\\localhost:9090\\ZenoBusinessStore\\images\\integration-icon.png";
String op = in.replace("http:\\localhost:9090\\ZenoBusinessStore", "");
System.out.println(op);

ZenoBusinessStore must be the name of your project which is constant.
Now split the string
String s = "http:\localhost:9090\ZenoBusinessStore\images\integration-icon.png";
String ary = s.split("ZenoBusinessStore");
Now the 2nd element of the array is your image path.
System.out.println(ary[1]);

Use '\\'. It's because backslash is used in escape sequence like '\n'. With a single \ the compiler have no way to know.

How to replace or convert the first occurrence of a dot from a string in java

Example:
Input
Str = P.O.Box
Output
Str= PO BOX
I can able to convert the string to uppercase and replace all dot(.) with a space.
public static void main(String args[]){
String s = "P.O.Box 1836";
String uppercase = s.toUpperCase();
System.out.println("uppercase "+uppercase);
String replace = uppercase.replace("."," ");
System.out.println("replace "+replace);
}

System.out.print(s.toUpperCase().replaceFirst("[.]", "").replaceAll("[.]"," "));

If you look the String API carefully, you would notice that there's a methods that goes by:-
replaceFirst(String regex, String replacement)
Hope it helps.

You have to use the replaceFirst method twice. First for replacing the . with <nothing>. Second for replacing the second . with a <space>.
String str = "P.O.Box";
str = str.replaceFirst("[.]", "");
System.out.println(str.replaceFirst("[.]", " "));

This one liner should do the job:
String s = "P.O.Box";
String replace = s.toUpperCase().replaceAll("\\.(?=[^.]*\\.)", "").replace('.', ' ');
//=> PO BOX

String resultValue = "";
String[] result = uppercase.split("[.]");
for (String value : result)
{
if (value.toCharArray().length > 1)
{
resultValue = resultValue + " " + value;
}
else
{
resultValue = resultValue + value;
}
}

Try this
System.out.println("P.O.Box".toUpperCase().replaceFirst("\\.","").replaceAll("\\."," "));
Out put
PO BOX
NOTE: \\ is needed here if you just use . only your out put will blank.
Live demo.

You should use replaceFirst method twice.
String replace = uppercase.replace("\\.", "").replaceFirst("\\.", "");

As you want to remove the first dot and replace the second one with a space, you need replace the whole P.O. section
Use
replace("P\\.O\\.", "PO ");

Usage of the java function 'split()

I would like to split the word in java based on the delimeter'-'when it appeared last.
I am expecting the result as "sweet_memory_in" and "everbodylife#gmail.com". Do we have any inbuilt function in java.
Complete word is sweet_memory_in_everbodylife#gmail.com

String s = "sweet_memory_in_everbodylife#gmail.com";
String first = s.substring(0,s.lastIndexOf("_"));
String second = s.substring(s.lastIndexOf("_")+1 );

try this
String s = "sweet_memory_in_everbodylife#gmail.com";
String s1 = s.substring(0,s.lastIndexOf("_"));
String s2 = s.substring(s.lastIndexOf("_")+1,s.length());

Regex may help. Other way is to get the last index of _ and use substring to split it.

Try out this code :
String data = "sweet_memory_in_everbodylife#gmail.com";
int lastIndex = data.lastIndexOf("_");
String firstSplit = data.substring(0, lastIndex);
String secondSplit = data.substring(lastIndex + 1, data.length());
System.out.println(firstSplit);
System.out.println(secondSplit);

Try this my friend (Javascript Codes):
var str = 'sweet_memory_in_everbodylife#gmail.com';
var arr1 = str.substring(str.lastIndexOf("_")).split("_");
var arr2 = str.split("_"+arr1[1]);
alert(arr2[0] +" --> "+arr1[1]);

Parse string starting from the end

I want to split string around only the last _ character , example:some_string_foo_bar into two substrings some_string_foo bar.
I tried to use Pattern and StringTokenizer, but they always start from the beginning of stirng. Any idea how to do this?

Use lastIndexOf; there's no reason to do a full split.

Sure, this might be of some use. Here's an example.
String source = "hello_world_foo";
int pos = source.lastIndexOf('_');
String before = source.substring(0, pos);
String after = source.substring(pos + 1);

You can use:
String strX = "some_string_foo";
String str1 = strX.substring(0,strX.lastIndexOf("_"));
String str2 = strX.subscting(strX.lastIndexOf("_"),strX.length());

String[] arr = str.split("_");
String lastOne = arr[arr.length-1];

Making a song name out of a URL

I have a URL and I want it to look like this:
Action Manatee - Action
http://xxxxxx.com/songs2/Music%20Promotion/Stream/Action%20Manatee%20-%20Action.mp3
What is the syntax for trimming up to where it after this "Stream/" and make spaces where the %20 is. I also want to trim the .mp3

Hmm, for that particular example, I would split the string according to the '/' character then trim the text that follows the final '.' character. Finally, do a replace of "%20" into " ". That should leave you with the string you want
Tested
String initial = "http://xxxxxx.com/songs2/Music%20Promotion/Stream/Action%20Manatee%20-%20Action.mp3";
String[] split = initial.split("/");
String output = split[split.length-1];
int length = output.lastIndexOf('.');
output = output.substring(0, length);
output = output.replace("%20", " ");

String urlParts[] = URL.split("\/");
String urlLast = urlParts[length-1];
String nameDotMp = urlLast.replaceAll("%20");
String name = nameDotMp.substring(0,nameDotMp.length-5);

You could use the split() and replace() methods to accomplish this, here are two ways:
Split your string apart by using the forward slashes:
string yourUrl = [URL Listed];
//Breaks your URL into sections on slashes
string[] sections = yourUrl.split("\/");
//Grabs the last section after the slashes, and replaces the %20 with spaces
string newString = sections[sectiongs.length-1].replace("%20"," ");
Split your string at the Stream/ section: (Only use this if you can guarantee it will be in that form)
string yourUrl = [URL Listed];
//This will get everything after Stream (your song name)
string newString = yourUrl.split("Stream\/")[1];
//Replaces your %20s with spaces
newString = newString.replace("%20"," ");

URL songURL = new URL("yourpath/filename");
String filename = songURL.getFile();