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How to fetch a string out of "08-1_2-4_1517614" ie "1517614"

If i have string like 08-1_2-4_1517614 and if i need to fetch the value "1517614" out of this for string manipulation in java
Any help will be much appreciated

String test = " 08-1_2-4_1517614";
String [] tokens = test.split("_");
System.out.println(tokens[tokens.length - 1]);
Or with regex:
String test = " 08-1_2-4_1517614";
System.out.println(test.replaceFirst(".+_", ""));
Or:
System.out.println(test.substring(test.lastIndexOf("_") + 1));

Here is a regex replace option:
String input = "08-1_2-4_1517614";
String output = input.replaceAll("^.*_", "");
A more general regex replace option using a capture group:
String output = input.replaceAll(".*(?<!\\d)(\\d+)$", "$1");
Or we could take a substring:
String output = input.substring(input.lastIndexOf("_") + 1);

Is the pattern always the same?
https://docs.oracle.com/javase/8/docs/api/java/lang/String.html#substring-int-int- could be your friend.
"08-1_2-4_1517614".substring(9, "08-1_2-4_1517614".length()) e.g.

Best way to do it, in case you want to resuse other parts of the original String.
String num = "08-1_2-4_1517614";
String[] parts = num.split("_");
String value = parts[parts.length - 1];
System.out.println(value);

The most simple is to use regex to find all the numbers after the final underscore.
Pattern patt = Pattern.compile("[^_]+$");
Matcher matcher = patt.matcher("08-1_2-4_1517614");
if(matcher.find()) {
System.out.println(matcher.group());
}else{
System.out.println("No Match Found");
}

Or use
str.substring(str.lastIndexOf("_") + 1, str.length())

I'd go for the one-liner:
System.out.println(myString.substring(9, 16));

How to parse WebElement

In debug mode I can see that locator of one of the element on the page is: By.name: NameOfMyElement_123.
The question is, how can I parse the following string (By.name: NameOfMyElement_123) in Java in order to have the type of my locator (name) and value (NameOfMyElement_123) ?

String[] split = "By.name: NameOfMyElement_123".split(" ");
or
Pattern p = Pattern.compile("([\\w.]*): ([\\w]*_[\\d]*)");
Matcher m = p.matcher("By.name: NameOfMyElement_123");
while (m.find()){
System.out.println(m.group(1));
System.out.println(m.group(2));
}

You could use split(). In this case, it's best to split with :
String[] splittedText = element.split(':');
String type = splittedText[0].trim();
String value = splittedText[1].trim();

Nothing fancy is necessary, two split() methods are enough:
String[] firstSplit = element.split(':');
String[] secondSplit = firstSplit[0].split('.');
String type = secondSplit[1].trim(); // will result in "name"
String value = firstSplit[1].trim(); // will result in "NameOfMyElement_123"

regex to match and replace two characters between string

I have a string String a = "(3e4+2e2)sin(30)"; and i want to show it as a = "(3e4+2e2)*sin(30)";
I am not able to write a regular expression for this.

Try this replaceAll:
a = a.replaceAll("\) *(\\w+)", ")*$1");

You can go with this
String func = "sin";// or any function you want like cos.
String a = "(3e4+2e2)sin(30)";
a = a.replaceAll("[)]" + func, ")*siz");
System.out.println(a);

this should work
a = a.replaceAll("\\)(\\s)*([^*+/-])", ") * $2");

String input = "(3e4+2e2)sin(30)".replaceAll("(\\(.+?\\))(.+)", "$1*$2"); //(3e4+2e2)*sin(30)

Assuming the characters within the first parenthesis will always be in similar pattern, you can split this string into two at the position where you would like to insert the character and then form the final string by appending the first half of the string, new character and second half of the string.
string a = "(3e4+2e2)sin(30)";
string[] splitArray1 = Regex.Split(a, #"^\(\w+[+]\w+\)");
string[] splitArray2 = Regex.Split(a, #"\w+\([0-9]+\)$");
string updatedInput = splitArray2[0] + "*" + splitArray1[1];
Console.WriteLine("Input = {0} Output = {1}", a, updatedInput);

I did not try but the following should work
String a = "(3e4+2e2)sin(30)";
a = a.replaceAll("[)](\\w+)", ")*$1");
System.out.println(a);

How to Extract text from given string?

I want to extract a perticular image path string from a given string .
The String is http:\localhost:9090\SpringMVC\images\integration-icon.png
Now i want to get only the path after images like
\images\integration-icon.png
i tried this
Pattern pattern = Pattern.compile("SpringMVC");
Matcher matcher = pattern.matcher(str);
System.out.println("Checking");
if (matcher.find()) {
System.out.println(matcher.group(1));
}
how can i get ?

String filename = filepath.substring(filepath.lastIndexOf("\\") + 1);
or (haven't tried and looks somewhat odd)
String filename = filepath.substring(filepath.lastIndexOf("\\", "images\\".length()) + 1);

String string = "http:\localhost:9090\ZenoBusinessStore\images\integration-icon.png";
int index = string.indexOf("images\\");
String output = string.substring(index);

String text = "http:\localhost:9090\SpringMVC\images\integration-icon.png"
String subText = text.subString(text.indexOf("\images"), text.length());
System.out.println(subText);

String in = "http:\\localhost:9090\\ZenoBusinessStore\\images\\integration-icon.png";
String op = in.replace("http:\\localhost:9090\\ZenoBusinessStore", "");
System.out.println(op);

ZenoBusinessStore must be the name of your project which is constant.
Now split the string
String s = "http:\localhost:9090\ZenoBusinessStore\images\integration-icon.png";
String ary = s.split("ZenoBusinessStore");
Now the 2nd element of the array is your image path.
System.out.println(ary[1]);

Use '\\'. It's because backslash is used in escape sequence like '\n'. With a single \ the compiler have no way to know.

Removing link from Text in Java?

I need to change somethign like this -> Hello, go here http://www.google.com for your ...
grab the link, and change it in a method i made, and replace it back into the string like this
-> Hello, go here http://www.yahoo.com for your...
Here is what i have so far:
if(Text.toLowerCase().contains("http://"))
{
// Do stuff
}
else if(Text.toLowerCase().contains("https://"))
{
// Do stuff
}
All i need to do is change the URL in the String to something different. The Url in the String will not always be http://www.google.com, so i can not just say replace("http://www.google.com","")

Use regex:
String oldUrl = text.replaceAll(".*(https?://)www((\\.\\w+)+).*", "www$2");
text = text.replaceAll("(https?://)www(\\.\\w+)+", "$1" + traslateUrl(oldUrl));
Note: code changed to meet extra requirements in comments below.

you can grab the link from the string using below code. I assumed the string will contain only .com domain
String input = "Hello, go here http://www.google.com";
Pattern pattern = Pattern.compile("http[s]{0,1}://www.[a-z-]*.com");
Matcher m = pattern.matcher(input);
while (m.find()) {
String str = m.group();
}

Have you tried something like:
s= s.replaceFirst("http:.+[ ]", new link);
This will find any word beginning with http up till the first white space and replace it with whatever you want
if you want to keep the link then you can do:
String oldURL;
if (s.contains("http")) {
String[] words = s.split(" ");
for (String word: words) {
if (word.contains("http")) {
oldURL = word;
break;
}
}
//then replace the url or whatever
}

You can try this
private String removeUrl(String commentstr)
{
String urlPattern = "((https?|ftp|gopher|telnet|file|Unsure|http):((//)|(\\\\))+[\\w\\d:##%/;$()~_?\\+-=\\\\\\.&]*)";
Pattern p = Pattern.compile(urlPattern,Pattern.CASE_INSENSITIVE);
Matcher m = p.matcher(commentstr);
int i = 0;
while (m.find()) {
commentstr = commentstr.replaceAll(m.group(i),"").trim();
i++;
}
return commentstr;
}