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Inserting String variable into JSON which is in a form of String

I have a JSON payload saved as a String
String jsonBody = “{\n”
+ ” \“example\“: {\n”
+ ” \“example\“: [\n”
+ ” {\n”
+ ” \“example\“: 100,\n”
+ ” \“this_is_example_json_key\“: \“this_is_example_json_value\“,\n”
I created that by copying body from i.e Postman into
String jsonBody = "here I pasted the body";
Unfortunately I cannot have everything hardcoded there, so I have to change some values to variables. The JSON in postman looks like:
"this_is_example_json_key":"x"
And so on. Let's assume that:
String x = “this_is_example_json_value“;
If I just replace it like
+ ” \“this_is_example_json_key\“: \“ + x + \“,\n”
or something like that, the value in the body will be just this_is_example_json_value, where I need "this_is_example_json_value" (the "" marks are part of the value).
So the question is, how to set up those + / " in the String, so in the end in the value of the JSON I will end up with the value inside " ".
I've tried to play with the " / + but nothing of those were working. Variable must be passed with those " " because otherwise, the API is sending back an error.

Since java 15, if you want only use the string, you can also do in this way:
int this_is_example_json_value= 100;
String json = """
{
"this_is_example_json_key": %d
}
""".formatted(this_is_example_json_value);
Here the official jep.

Don't try to build up JSON using strings. Use a proper JSON parser.
import org.json.JSONException;
import org.json.JSONObject;
public class Eg {
public static void main(String[] args) throws JSONException {
String x = "this_is_example_json_value";
JSONObject example = new JSONObject();
example.put("this_is_example_json_key", x);
System.out.println(example.toString());
}
}
Which outputs:
{"this_is_example_json_key":"this_is_example_json_value"}
With no messing around wondering what needs to be escaped.

you can use an extra " \ " "
String x = "this_is_example_json_value";
String jsonBody = "{\n"
+ "\"example\": {\n"
+ " \"example\": [\n"
+ " {\n"
+ " \"example\": 100,\n"
+ "\"this_is_example_json_key\":" + "\"" + x + "\"" + "\n }"
+"\n ]\n }\n }";
in this case you will get a json string
{
"example": {
"example": [
{
"example": 100,
"this_is_example_json_key": "this_is_example_json_value"
}
]
}
}

How to remove specific line from multi-line string

I have below java string as command output
String output = "NIC Value\n"
+ "------ -----\n"
+ "vmn0 on \n"
+ "vmn1 on \n"
+ "vmn2 on \n"
+ "vmn3 on \n"
+ "vmn4 on";
I want to remove second line with dash from above string. How can I do it?
I tried it using contains method but it is generating blank line after removing second line.
if(output!=null && output.contains("-"))
output = output.replace("-","");

This is complete answer you are looking for:
String output = "NIC Value\n"
+ "------ -----\n"
+ "vmn0 on \n"
+ "vmn1 on \n"
+ "vmn2 on \n"
+ "vmn3 on \n"
+ "vmn4 on";
String str = Stream.of(output.split("\n"))
.filter(s -> !s.contains("--"))
.collect(Collectors.joining("\n"));

You can use this to remove that line and use the result,
String result = output.replace("------ -----\n", "");
It will replace that line with an empty String

Splitting array in string does not give last element

Hi I am splitting and storing string with use of array but does not give result
String str = "123456";
String[] arrOfStr = str.split("");
String otpnum1 = arrOfStr[0];
String otpnum2 = arrOfStr[1];
String otpnum3 = arrOfStr[2];
String otpnum4 = arrOfStr[3];
String otpnum5 = arrOfStr[4];
String otpnum6 = arrOfStr[5];
System.out.println("otp"+otpnum1+otpnum2+otpnum3+otpnum4+otpnum5+otpnum6);
OUTPUT
System.out: otp12345

You are printing without any space or newline, which is the reason you are not able to interpret individual variables. Use this
System.out.println("otp " + otpnum1+ " " + otpnum2+" " + " "+ otpnum3+ " " + otpnum4+ " " + otpnum5+ " " + otpnum6);

I understand, the output is 12345, and expected 123456 for the result.
But, looking your code looks like correct.
I have try your code here, for test, and works fine.
The output was: otp123456

URL in JSON object as POST request Android

Please help me to send a JSON object in POST HTTP request through HttpClient, in Android.
The problem I am facing is that the JSON object having the URL is replaced by forward slash ,i.e
originally it should have the following value in JSON object
{"product":
{"featured_src":"https:\/\/example.com\/wp-content\/uploads\/2015\/06\/sidney-compressed.jpg,
"short_description":"this is a test","title":"Raiders from the North"}
}
i tried many options to keep it in the above format. But it always comes as {"featured_src":

We assume this is your input
private final static String JSON_DATA = "{"
+ " \"product\": ["
+ " {"
+ " \"featured_src\": \"https:\\/\\/example.com\\/wp-content"
+ "\\/uploads\\/2015\\/06\\/sidney-compressed.jpg\","
+ " \"short_description\": \"this is a test\","
+ " \"title\" : \"Raiders from the North\""
+ " }"
+ " ]"
+ "}";
You could use replace to do the trick.
YOUR_STRING.replace("\\", "");
Finally your method would look like this, by passing your string as parameter
private static String jsonUrlCorrector(String json_data) {
json_data = json_data.replace("\\", "");
return json_data;
}
Here is the input:
{"product":[{"featured_src":"https:\/\/example.com\/wp-content\/uploads\/2015\/06\/sidney-compressed.jpg","short_description": "this is a test","title":"Raiders from the North"}]}
Here is the output
{"product":[{"featured_src":"https://example.com/wp-content/uploads/2015/06/sidney-compressed.jpg","short_description":"this is a test","title":"Raiders from the North"}]}

How can I split the data over multiple lines in a JTextArea?

How can I put each line of the host in the message body? I work with a JTextArea.
String host = InetAddress.getLocalHost().getHostName().toString();
texto_recepcion.setText(host + texto_recepcion.getText() + dpRecepcion.getAddress() + " " + mensaje_recibido + "\n");
How it is now:

I resolve my question with append function.
String host = InetAddress.getLocalHost().getHostName().toString();
texto_recepcion.append(host); // ***Use the function append for solve the problem***
texto_recepcion.setText(texto_recepcion.getText() + dpRecepcion.getAddress() + " " + mensaje_recibido + "\n");
Thanks a lot

Why don't you add the newline character "\n" to the beginning of the string?
texto_recepcion.setText("\n" + host + texto_recepcion.getText() + dpRecepcion.getAddress() + " " + mensaje_recibido);