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Replace anything within two brackets

I have this string:
String string = "The status is %status(" + randomString + ")%";
How can I replace the part between percent signs with anything, but without knowing randomString?

You can use String.replaceAll. An example:
String randomString = "asdf";
String string = "The status is %status(" + randomString + ")%";
String replacement = "myStatus";
String fString = string.replaceAll("%status(.*)%", replacement);
System.out.println(fString);
Which outputs:
The status is myStatus

The regex you want to use is %(.+)%, which matches %status(foo)% and %status(asidh37887123-48hsZXas;;fgfg)%.
To replace it, you can do string.replaceAll("%(.+)%", "anything").
This will turn The status is %status(foo)% to The status is anything.

Two ways to do it :
String string = "The status is %status(aaaaaaaaaaaaaaa)%";
int x = string.indexOf("%");
int y = string.lastIndexOf("%");
System.out.println(x);
System.out.println(y);
string = string.substring(0,x)+string.substring(y+1,string.length());
System.out.println(string);
string = "The status is %status(aaaaaaaaaaaaaaa)%";
string = string.replaceAll("%.+%", "");
System.out.println(string);
Result :

Get the specific value from the last part of a String in Android

I wanted to get the value from the last part of a String, here's my example String
String str="www.mywebsite.com?id=0001&user=myname"
I like to get the word myname from that String, All examples that I'm seeing is like this
String getUser = str.substring(str.length() - 6);
but user value length changes every transaction so I can't fix that to any value. Can anyone please help me in how I will be able to get the user value from that String. Thanks.

String getUser=str.subString(str.lastIndexOf("=")+1,Str.length());
Will return myname.

If your string is going to be a uri, you can use Uri's getQueryParameter:
String str="www.mywebsite.com?id=0001&user=myname";
Uri uri = Uri.parse(str);
return uri.getQueryParameter("user");

Try this
String getUser = str.substring(str.lastIndexOf("=") + 1);

Try this
String foo = "www.mywebsite.com?id=0001&user=myname";
String[] split = foo.split("=");
String name = split[split.length-1];
with String.split(), you can split strings with a delimiter and put the values in an array. It is similar to PHPs' explode method.

String str="www.mywebsite.com?id=0001&user=myname";
String user = getQueryParamValue(str);
public static final String getQueryParam(String url) {
List<NameValuePair> params = URLEncodedUtils.parse(new URI(url), "UTF-8");
for (NameValuePair param : params){
if("user".equalsIgnoreCase(param.getName())) {
return param.getValue();
}
}
return null;
}

regex to match and replace two characters between string

I have a string String a = "(3e4+2e2)sin(30)"; and i want to show it as a = "(3e4+2e2)*sin(30)";
I am not able to write a regular expression for this.

Try this replaceAll:
a = a.replaceAll("\) *(\\w+)", ")*$1");

You can go with this
String func = "sin";// or any function you want like cos.
String a = "(3e4+2e2)sin(30)";
a = a.replaceAll("[)]" + func, ")*siz");
System.out.println(a);

this should work
a = a.replaceAll("\\)(\\s)*([^*+/-])", ") * $2");

String input = "(3e4+2e2)sin(30)".replaceAll("(\\(.+?\\))(.+)", "$1*$2"); //(3e4+2e2)*sin(30)

Assuming the characters within the first parenthesis will always be in similar pattern, you can split this string into two at the position where you would like to insert the character and then form the final string by appending the first half of the string, new character and second half of the string.
string a = "(3e4+2e2)sin(30)";
string[] splitArray1 = Regex.Split(a, #"^\(\w+[+]\w+\)");
string[] splitArray2 = Regex.Split(a, #"\w+\([0-9]+\)$");
string updatedInput = splitArray2[0] + "*" + splitArray1[1];
Console.WriteLine("Input = {0} Output = {1}", a, updatedInput);

I did not try but the following should work
String a = "(3e4+2e2)sin(30)";
a = a.replaceAll("[)](\\w+)", ")*$1");
System.out.println(a);

Usage of the java function 'split()

I would like to split the word in java based on the delimeter'-'when it appeared last.
I am expecting the result as "sweet_memory_in" and "everbodylife#gmail.com". Do we have any inbuilt function in java.
Complete word is sweet_memory_in_everbodylife#gmail.com

String s = "sweet_memory_in_everbodylife#gmail.com";
String first = s.substring(0,s.lastIndexOf("_"));
String second = s.substring(s.lastIndexOf("_")+1 );

try this
String s = "sweet_memory_in_everbodylife#gmail.com";
String s1 = s.substring(0,s.lastIndexOf("_"));
String s2 = s.substring(s.lastIndexOf("_")+1,s.length());

Regex may help. Other way is to get the last index of _ and use substring to split it.

Try out this code :
String data = "sweet_memory_in_everbodylife#gmail.com";
int lastIndex = data.lastIndexOf("_");
String firstSplit = data.substring(0, lastIndex);
String secondSplit = data.substring(lastIndex + 1, data.length());
System.out.println(firstSplit);
System.out.println(secondSplit);

Try this my friend (Javascript Codes):
var str = 'sweet_memory_in_everbodylife#gmail.com';
var arr1 = str.substring(str.lastIndexOf("_")).split("_");
var arr2 = str.split("_"+arr1[1]);
alert(arr2[0] +" --> "+arr1[1]);

Parse string starting from the end

I want to split string around only the last _ character , example:some_string_foo_bar into two substrings some_string_foo bar.
I tried to use Pattern and StringTokenizer, but they always start from the beginning of stirng. Any idea how to do this?

Use lastIndexOf; there's no reason to do a full split.

Sure, this might be of some use. Here's an example.
String source = "hello_world_foo";
int pos = source.lastIndexOf('_');
String before = source.substring(0, pos);
String after = source.substring(pos + 1);

You can use:
String strX = "some_string_foo";
String str1 = strX.substring(0,strX.lastIndexOf("_"));
String str2 = strX.subscting(strX.lastIndexOf("_"),strX.length());

String[] arr = str.split("_");
String lastOne = arr[arr.length-1];