I have a bat file with the following contents:
set logfile= D:\log.txt
java com.stuff.MyClass %1 %2 %3 >> %logfile%
when I run the bat file though, I get the following:
C:\>set logfile= D:\log.txt
C:\>java com.stuff.MyClass <val of %1> <val of %2> <val of %3> 1>>D:\log.txt
The parameter is incorrect.
I'm almost positive the "The parameter is incorrect." is due to the extraneous 1 in there. I also think this might have something with the encoding of the .bat file, but I can't quite figure out what is causing it. Anyone ever run into this before or know what might be causing it and how to fix it?
Edit
And the lesson, as always, is check if its plugged in first before you go asking for help. The bat file, in version control, uses D:\log.txt because it is intended to be run from the server which contains a D drive. When testing my changes and running locally, on my computer which doesn't have a D drive, I failed to make the change to use C:\log.txt which is what caused the error. Sorry for wasting you time, thanks for the help, try to resist the urge to downvote me too much.
I doubt that that's the problem - I expect the command processor to deal with that part for you.
Here's evidence of it working for me:
Test.java:
public class Test
{
public static void main(String args[]) throws Exception
{
System.out.println(args.length);
for (String arg : args)
{
System.out.println(arg);
}
}
}
test.bat:
set logfile= c:\users\jon\test\test.log
java Test %1 %2 %3 >> %logfile%
On the command line:
c:\Users\Jon\Test> [User input] test.bat first second third
c:\Users\Jon\Test>set logfile= c:\users\jon\test\test.log
c:\Users\Jon\Test>java Test first second third 1>>c:\users\jon\test\test.log
c:\Users\Jon\Test> [User input] type test.log
3
first
second
third
the 1 is not extraneous: it is inserted by cmd.exe meaning stdout (instead of ">>", you can also write "1>>". contrast this to redirecting stderr: "2>>"). so the problem must be with your parameters.
This may seem like a stupid question, but is there an existing D: drive in the context that the bat file runs in?
Once I had a case where a bat file was used as the command line of a task within the Task Manager, but the Run As user was set to a local user on the box, giving no access to network drives.
Interpolated for your case, if the D: drive were a network drive, running the bat file as, say, the local administrator account on that machine instead of a domain user account would likely fail to have access to D:.
Related
I'm trying to use Apache Commons Exec to run a git command which uses a regex.
When I form my CommandLine and print it out it looks like this:
[git, --no-pager, grep, --line-number, --untracked, --extended-regexp, "^\s*public void\s+(testFindByAdAccount).*", --, *Test.java]
However when I execute this, git returns no results, resulting in an exit code 1.
When I run this command manually though, it returns plenty of results and succeeds. Changing the --extended-regexp argument to just a string like testFindByAdAccount does yield results when run via Exec, so I think Apache Commons is doing something to the regexp argument making it invalid. Any ideas what is going on?
EDIT: Adding a reproducible example
Clone https://github.com/ragurney/min-example
Run gradlew shadowJar to produce jar file for project
Run the app with java -jar app/build/libs/app-all.jar
Note the output which shows the command printed fails with an exit code 1 (because there are no results returned by the git command)
$ java -jar app/build/libs/app-all.jar
HELLOOOOOO
WD::: null
[git, --no-pager, grep, --line-number, --untracked, --extended-regexp, "^\s*public void\s+(testAppHasAGreeting)\(\).*", --, *Test.java]
WD::: /Users/rgurney/Src/personal/min-example
Exception in thread "main" java.lang.RuntimeException: org.apache.commons.exec.ExecuteException: Process exited with an error: 1 (Exit value: 1)
at min.example.App.lambda$runCommand$1(App.java:74)
at io.vavr.control.Try.getOrElseThrow(Try.java:748)
Running the command manually does produce expected results:
$ git --no-pager grep --line-number --untracked --extended-regexp "^\s*public void\s+(testAppHasAGreeting)\(\).*" -- "*Test.java"
app/src/test/java/min/example/AppTest.java:11: public void testAppHasAGreeting() {
I got a clue as to what's going on here when the sample you provided worked just fine on my Windows laptop but failed on my Linux desktop.
Once I made sure the git version wasn't the culprit (tested several versions between 2.17 and 2.39 on both machines), I figured the difference must be in the way different shells handle quoting. Specifically, the only argument here that has any potential quoting issues is the regex ("^\s*public void\s+(testFindByAdAccount).*"), which is added to the command line by commandLine.addArgument(regex);.
addArgument may look innocuous, but under the hood, it allows the CommandLine to handle the quoting itself (i.e., addArgument(String argument) calls addArgument(String argument, true). Since you've handled the quoting yourself, you should not allow the CommandLine to handle the quoting, and should explicitly call it with the second argument false. i.e.:
public static List<String> grep(String regex, String filePattern, String wd) {
CommandLine commandLine = CommandLine.parse("git");
commandLine.addArgument("--no-pager");
commandLine.addArgument("grep");
commandLine.addArgument("--line-number");
commandLine.addArgument("--untracked");
commandLine.addArgument("--extended-regexp");
commandLine.addArgument(regex, false);
// Here -----------------------^
commandLine.addArgument("--");
commandLine.addArgument(filePattern);
System.out.println(commandLine);
return List.of(runCommand(commandLine, wd).split("\n"));
}
This takes the quote-handling logic away and ensures the same code runs smoothly both on Windows and Linux (at least those I've tested).
I'm on latest Windows 10. I have JDK 15. Latest Visual Studio Code (System). In VS Code, I have half of the Java Extension Pack Installed, i.e Language Support for Java (Red Hat) | Debugger for Java (Microsoft) | Visual Studio IntelliCode (Microsoft). So I did that to just get that run button on the top right (the default installed VS Code didn't have that run button for JAVA programs), below the close button, to that I can run the JAVA programs inside the VS Code. I didn't wanna go out to the directory then open Power Shell or CMD and then write java filename.java and run the program...
Now the issue is that when I click the run button, I think, a Power Shell is opened inside the VS Code and then something other than "java FileName.java" is being written. Because of that I can't really see what the compilation error is. I can only see the line number where the problem is, not actually the solution for that. || If I run the same in the PowerShell outside the VS Code with this "java FileName.java", I can see that there is some issue at x line and also the solution for the same.
So I wanted to know if there is any way to get this type of output inside the Visual Studio Code.
Or if there is any way that Instead of writing a lot of thing like this, we can simple tell the Visual Studio Code to run "java fileName.java" inside VS Code when I click the Run Button at the top.
EDIT:
The Code that I'm running is this one.....
File Name - test.java
import java.io.*;
public class SOPFileTest{
public static void main(String arr[]){
try{
// Creating a File object that represents the disk file.
PrintStream o = new PrintStream(new File("A.txt"));
// Store current System.out before assigning a new value
PrintStream console = System.out;
// Assign o to output stream
System.setOut(o);
System.out.println("Test 1");
// Use stored value for output stream
System.setOut(console);
System.out.println("Test 2");
}
catch(Exception e){
System.out.println(e.getMessage());
}
}
Now I've noticed somethings, they are:
-When (FileName == Class Name)
---Then (VS Code)
-----Prints the Last System.out.println in the console
-----A.txt is not created / written inside
---Then (Powershell)
-----Prints the Last System.out.println in the console
-----A.txt is created and/or written inside
-When (FileName != Class Name)
---Then (VS Code)
-----shows the error same as the image that I included above.
---Then (Powershell)
-----Prints the Last System.out.println in the console
-----A.txt is created and/or written inside
So powershell works as I intend it would, the VS Code isn't...
If the filename is different from ClassName, java extension will detect it and throws probelms, which is build failed and you can choose if continue:
If you choose proceed, there should be:
[UPDATE -- Screenshot in Powershell:]
It's about the same as problems shown in VS Code.
Java extension requires class must be defined in its own file, so filename should be as the same as ClassName, then everything works well, no matter in integrated Terminal in VS Code, or in the PowerShell outside VS Code:
So I wanted to know if there is any way to get this type of output
inside the Visual Studio Code.
Keeping the filename and classname same makes sure it could be built and compiled successfully, which is the first step.
And the text file should be generated in current working directory, check it in your file explorer.
In an effort to make my app more OSX friendly, I am trying to set the dock name of my program to something like MyApp instead of a fully qualified class name (the default), such as myproject.mypackage.mysubpackage.myclass. Obviously, the first is much more appealing.
To do this, I use the OSX -Xdock:name command as a command line option when executing my .jar file. So to execute it, the command might look something like java -Xdock:name=MyApp -jar /mypath/myjar.jar. This works perfectly and sets the .jar's dock name to MyApp. But the issue is that this .jar will never be executed via command line and will be a double-clicked runnable .jar with a GUI display.
The only way I have thought of to set this command line option programmatically is to have a second class execute the class that actually starts the program. So something like this:
public class AppStarter {
public static void main(String[] args) {
String cmd = "java -Xdock:name=MyApp -cp myproject/mypackage/AppBuilder";
try {
Runtime runtime = Runtime.getRuntime();
runtime.exec(cmd);
} catch(IOException ex) {
//Display error message
}
}
}
public class AppBuilder {
public static void main(String[] args) {
//Start actual program and build GUI display
}
}
So here, AppStarter sets the command line options for AppBuilder, which when executed, has the dock name MyApp. The problem I see with this is that it is very tightly coupled. If for some reason the command line is inaccessible on the device or some IOException keeps getting thrown, literally nothing will happen with the program and it will be dead. There would be no way for the average computer user to recover from this.
So I'm wondering if it is possible to perhaps set these command line options after the .jar has already started executing. The old way to programmatically set the app's name has been ineffective for several OSX updates, so I'm stuck with only this command line option. Thanks for any advice.
Once the java command is executed, the command line arguments are parsed and set for the running JVM. You cannot change it any more.
This is usually handled by execution scripts (bash, etc.). If you cannot use them, you can use your approach, but the biggest disadvantage is that it will be running in a separate process.
I apologize for the simplicity of this problem.
I'm trying to use a program called ChromHMM to analyze some biological data. I try and run the program according to the instructions but can't seem to enter the arguments correctly.
Here is an example:
E:\ComputationalAnalysis\ChromHMM>java -mx1600M -jar ChromHMM.jar BinarizeBed
chromosomelengthfile=\CHROMSIZES\hg19.txt inputbeddir=\Donor1 cellmarkfileta
ble=\Donor1\cellmarkfile.txt outputbinarydir=\firstoutput
It returns just this:
usage BinarizeBed [-b binsize][-c controldir][-center][-colfields chromosome,sta
rt,end[,strand]][-e offsetend][-f foldthresh][-n shift][-o outputcontroldir][-p
poissonthresh][-peaks][-s offsetstart][-strictthresh][-t outputsignaldir][-u pse
udocountcontrol][-w flankwidthcontrol] chromosomelengthfile inputbeddir cellmark
filetable outputbinarydir
In the manual it says the 4 arguments at the end are the only ones required to run. Does anyone know what I'm doing wrong? I'm trying to do this from the windows command prompt
try removing the name of the argument and the equals;just pass the value. so in your example you would have the following.
E:\ComputationalAnalysis\ChromHMM>java -mx1600M -jar ChromHMM.jar BinarizeBed
\CHROMSIZES\hg19.txt \Donor1 cellmarkfileta \Donor1\cellmarkfile.txt \firstoutput
I have an error in my first step with Java, so when i try to run the code hello world:
class apples{
public static void main(String args[]){
System.out.println("Hello World!");
}
}
I go to: - Run as .. -> Then i choose Java aplicacion - > And i press Ok
But when i press Ok does not appear the window down to show me the correct message Hello World
Your code works fine for me:
class apples
{
public static void main(String args[])
{
System.out.println("Hello World!");
}
}
I downloaded it to c:\temp\apples.java.
Here's how I compiled and ran it:
C:\temp>javac -cp . apples.java
C:\temp>dir apples
Volume in drive C is HP_PAVILION
Volume Serial Number is 0200-EE0C
Directory of C:\temp
C:\temp>dir ap*
Volume in drive C is HP_PAVILION
Volume Serial Number is 0200-EE0C
Directory of C:\temp
08/15/2010 09:15 PM 418 apples.class
08/15/2010 09:15 PM 123 apples.java
2 File(s) 541 bytes
0 Dir(s) 107,868,696,576 bytes free
C:\temp>java -cp . apples
Hello World!
C:\temp>
Your lack of understanding and the IDE appear to be impeding your progress. Do simple things without the IDE for a while until you get the hang of it. A command shell and a text editor will be sufficient.
Sorry about missing javac; cut & paste error.
If you look at the screenshot, your class name is there, last in the list. Select it and press OK. To not see this message again, right-click on the class name on the left side and select there Run...->Java Application.
The only problem that causes your error here is that the classname and the filename do not match - and they have to.
Solution
Rename either the file thesame.java to apple.java or the class to thesame. Then if you select "Run as..." again, eclipse will present a menu item to start your Java application.
(other mentioned, that there's no requirement that a top-level class and the filename do match - unless the top level class is public. Of course this is true. But the problem was about "running" a class under eclipse as a Java application)
Try public class apples and make sure the file is apples.java. Also it should be public static void main(String[] args)
You have 2 classes by name of "thesame.java" under the source folder. Since one is directly under the src folder, and other under (default package), they use the same namespace, hence Interpreter is confused which java file to execute and is asking you to select the class you want to execute.
Class names must be capitalized... so change apples to Apples. Also, if you are a beginner (which it seems like), I would recommend the Netbeans IDE -- it's a bit more friendlier for new users than Eclipse.
You class must be named "thesame" if you store it in a file called "thesame.java", as you have. Either rename your class to "thesame" or change the file to be "apples.java".
You should move the "[]" to be before "args". So, String[] args.
Either select "apples" at the bottom of the menu you posted and run it, or right-click on the Java file and make it the default thing to run for this project. Or launch it by right-clicking on the file and selecting "run".