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WAS Liberty 8.5.5.4, JPA 2.0 - discovered implementations: NONE

I was able to get JPA working with eclipse Luna and installing eclipseLink (and created a User Lib with the 3 jars).
However, I have now moved to Rational Application Developer (RAD) and attempting to use the JPA that is delivered with WAS Liberty. I initially used RAD JPA facet to configure JPA and then edited persistence.xml.
I am getting this error:
Caused by: javax.persistence.PersistenceException: No persistence providers available for "test2" after trying the following discovered implementations: NONE
I assume (always dangerous) the NONE is a configuration error and I cannot do anything until that is resolved...
I have copied the wlp\dev\api\spec\com.ibm.ws.javaee.persistence.2.0_1.0.1.jar into WEB-INF/lib and included that in my java build path.
As you can see below, I was guessing my provider was not correct, and tried several values...
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="test2" transaction-type="RESOURCE_LOCAL">
<!-- provider>org.eclipse.persistence.jpa.PersistenceProvider</provider-->
<!-- provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider-->
<provider>com.ibm.websphere.persistence.PersistenceProviderImpl</provider>
<non-jta-data-source>java:comp/env/New Generic JDBC</non-jta-data-source>
<class>com.ibm.analytics.jpa.Dimtask</class>
<properties>
<property name="openjpa.jdbc.Schema" value="RM"/>
<property name="javax.persistence.jdbc.url" value="jdbc:netezza://netezza-1.site.ibm.com:5480/DATABASENAME"/>
<property name="javax.persistence.jdbc.user" value="jspoon"/>
<property name="javax.persistence.jdbc.password" value="xxxxxxx"/>
<property name="javax.persistence.jdbc.driver" value="org.netezza.Driver"/>
</properties>
</persistence-unit>
</persistence>
What else can I do to get past the NONE?
Here is the updated version of persistence.xml, I just commented out the provider.
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="test2" transaction-type="RESOURCE_LOCAL">
<!-- provider>org.eclipse.persistence.jpa.PersistenceProvider</provider-->
<!-- provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider-->
<!-- provider>com.ibm.websphere.persistence.PersistenceProviderImpl</provider-->
<non-jta-data-source>java:comp/env/New Generic JDBC</non-jta-data-source>
<class>com.ibm.analytics.jpa.Dimtask</class>
<properties>
<property name="openjpa.jdbc.Schema" value="RM"/>
<property name="javax.persistence.jdbc.url" value="jdbc:netezza://netezza-1.boulder.ibm.com:5480/BACC_TST_ISHANGO_DW"/>
<property name="javax.persistence.jdbc.user" value="jspoon"/>
<property name="javax.persistence.jdbc.password" value="C0ke4y0u"/>
<property name="javax.persistence.jdbc.driver" value="org.netezza.Driver"/>
</properties>
</persistence-unit>
</persistence>
I created my Entity class using JPA Tooling, and using a simple junit test to call a named query. The first step is to create the EMF and it is a static in my class (so none of the test is actually running, it is failing at instantiation creating the static variable):
static EntityManagerFactory emf = Persistence.createEntityManagerFactory( "test2" );
This is the exact same code as used before with eclipse and eclipseLink.

How to create database tables from Java code using JPA and JavaDB embedded?

My application uses JPA and JavaDB in embedded mode. In the persistence.xml file I use this property:
<property name="javax.persistence.jdbc.url" value="jdbc:derby:meuspiladb;create=true" />
so an empty database will be created if it does not exist yet.
Currently I have a create_tables.sql file where I put the SQL code to create the tables, and then I run it manually after the database is created. I would like to make this be automatic but I don't know how.
If the database is new I have to create the tables. What is the best way to create them from Java code?
My persistence.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="MeusPila3_PU" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>br.meuspila.corretora.Corretora</class>
<class>br.meuspila.ativo.Ativo</class>
<class>br.meuspila.bolsa.Bolsa</class>
<class>br.meuspila.movimento.Movimento</class>
<class>br.meuspila.provento.Provento</class>
<class>br.meuspila.operacao.Operacao</class>
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:derby:meuspiladb;create=true" />
<property name="javax.persistence.jdbc.user" value="APP"/>
<property name="javax.persistence.jdbc.driver" value="org.apache.derby.jdbc.EmbeddedDriver"/>
</properties>
</persistence-unit>
</persistence>

You can use Hibernate with JPA, then use configuration option hibernate.hbm2ddl.auto=create.

apache derby + jpa

I have embedded derby database and i work with jpa. This is my persistence.xml:
<?xml version="1.0" encoding="UTF-8"?>
<persistence
version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="pers">
<class>entities.Leverancier</class>
<class>entities.Prijsproduct</class>
<class>entities.Product</class>
</persistence-unit>
</persistence>
What should i change or add to get this working. When I run my code now I get the following:
Exception in thread "main" javax.persistence.PersistenceException: No Persistence provider for EntityManager named pers
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:55)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:33)
at test.Test.main(Test.java:19)

Your persistence.xml is not correct. Look at a sample below:
<persistence-unit name="MyAppPU" transaction-type="RESOURCE_LOCAL">
<!-- This is where you mention your JPA runtime provider e.g. it's EclipseLink here -->
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>mypkg.MyEntity</class>
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:derby://localhost:1527/my_schema"/>
<property name="javax.persistence.jdbc.password" value="pass"/>
<property name="javax.persistence.jdbc.driver" value="org.apache.derby.jdbc.ClientDriver"/>
<property name="javax.persistence.jdbc.user" value="user"/>
</properties>
</persistence-unit>
You also have to make sure that you put your JPA provider jar files (along with the derby-client jar) in the classpath.

#PersistenceUnit annotation not working

I want to use the #PersistenceUnit annotation in my app to create an application managed EntityManager
#PersistenceUnit(unitName="primary")
private static EntityManagerFactory entityManagerFactory;
EntityManager entityManager = entityManagerFactory.createEntityManager();
This doesn't seem to be working. I run my code through a debugger and discover that entityManagerFactory is null. My guess is that the injection of Persistence context with the #PersistenceUnit annotation is not working.
My app is a CDI app. It was not previously a CDI application - I converted it to CDI by creating a beans.xml file in WEB-INF, I needed to in order to do something like this.
Is there anything I need to configure within CDI to get the annotation to work? Thanks.

I have a JPA application running with only Java SE. I don't have a WEB-INF/beans.xml, but I do have a META-INF/persistence.xml configuration file:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="JPAPU" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>jpa.Container</class>
<class>jpa.Item</class>
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:derby:D:\NetBeansProjects\JPA\jpaTestDB;create=true"/>
<property name="javax.persistence.jdbc.password" value=""/>
<property name="javax.persistence.jdbc.driver" value="org.apache.derby.jdbc.EmbeddedDriver"/>
<property name="javax.persistence.jdbc.user" value=""/>
<property name="eclipselink.ddl-generation" value="create-tables"/>
</properties>
</persistence-unit>
</persistence>
Container and Item are the two persistence classes in my jpa package.
This was generated automatically by Netbeans. There is also some information about using JPA without Java EE in the official (Sun/Oracle) Java EE tutorial in the persistence chapter.

How do injection with JPA?

Is possible do injection in EntityManager with EclipseLink 2.3 ?
This is my persistence.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="SuaParte" transaction-type="RESOURCE_LOCAL">
// classes..
<properties>
<property name="eclipselink.jdbc.batch-writing" value="JDBC"/>
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/schema"/>
<property name="javax.persistence.jdbc.user" value="root"/>
<property name="javax.persistence.jdbc.password" value="root"/>
<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver"/>
</properties>
</persistence-unit>
</persistence>
I'm new with JPA so I created this persistence.xml file at first just to test to see if it works, but now I would like to use #PersistenceContext to don't have to worry about manage the EntityMangerFactory and EntityManager.
I'm using Eclipse Indigo Java EE Web Developers with GlassFish v3.
UPDATE:
I follow #Andrei Bodnarescu approach and this tutorial too and everything is fine to get a connection with my database through GF3:
And i change my persistence.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="SuaParte" transaction-type="JTA">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<jta-data-source>jdbc/mysql</jta-data-source>
//classes..
</persistence-unit>
</persistence>
So i try to persist something in my database:
#Stateless
#LocalBean
public class DaoUser {
#PersistenceContext(unitName="SuaParte")
private EntityManager em;
public void persist(User user){
try{
em.persist(user);
}catch(Exception e){
e.printStackTrace();
}
}
}
And it returns a java.lang.NullPointerException in em.persist(user);.
What am I doing wrong ?

You have to change the transaction-type to JTA as follows -
<persistence-unit name="SuaParte" transaction-type="JTA">
And then you can use #PersistenceContext as follows if you want Glassfish to inject the EntityManager into your EJB -
#Stateless
#LocalBean
public class MyEjb {
#PersistenceContext("SuaParte")
private EntityManager suaParteEM;
}
You can do in Servlet and ManagedBean too.
Also, on your Glassfish server you can create JDBC Connection Pool and JDBC Resource, give it a JNDI name and use it to declare your EntityManager in the persistence.xml as follows -
<persistence-unit name="SuaParte" transaction-type="JTA">
<jta-data-source>JNDI_Name_Of_JDBC_Resource</jta-data-source>
You can create the JDBC Resources on from the Glassfish Admin-Console.

BheshG's answer is very good, here's just some small addendums.
i think that in order to activate CDI and thus have dependency injection you need to create an empty beans.xml file that you must place in the WEB-INF folder of your project
To create a data source in GF3 and expose it via JNDI like BheshG sais, you must to basically this:
resources->JDBC->JDBC Connection pools and make a connection pool
Create a datasource that will use the pool.
(I wanted to post images with examples for conenction pool and datasource, but I can't since I don't have reputation points. In order to not seem spammy and trolly, I'm just gonna say: email me if you want more details or an example project, as I'm working on a tutorial on exactly that right now)
Now you can use that datasource in the persistence.xml file to attach it to a persistence unit:
<persistence-unit name="emJTA">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<jta-data-source>jdbc/postgre_ds_jta</jta-data-source>
<mapping-file>META-INF/emp-mappings.xml</mapping-file>
<class>model.Employee</class>
<class>model.ProjectManager</class>
<class>model.Department</class>
<class>model.Project</class>
<class>model.Phone</class>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQLDialect" />
<property name="hibernate.hbm2ddl.auto" value="update" />
</properties>
</persistence-unit>