WAS Liberty 8.5.5.4, JPA 2.0 - discovered implementations: NONE - java

I was able to get JPA working with eclipse Luna and installing eclipseLink (and created a User Lib with the 3 jars).
However, I have now moved to Rational Application Developer (RAD) and attempting to use the JPA that is delivered with WAS Liberty. I initially used RAD JPA facet to configure JPA and then edited persistence.xml.
I am getting this error:
Caused by: javax.persistence.PersistenceException: No persistence providers available for "test2" after trying the following discovered implementations: NONE
I assume (always dangerous) the NONE is a configuration error and I cannot do anything until that is resolved...
I have copied the wlp\dev\api\spec\com.ibm.ws.javaee.persistence.2.0_1.0.1.jar into WEB-INF/lib and included that in my java build path.
As you can see below, I was guessing my provider was not correct, and tried several values...
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="test2" transaction-type="RESOURCE_LOCAL">
<!-- provider>org.eclipse.persistence.jpa.PersistenceProvider</provider-->
<!-- provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider-->
<provider>com.ibm.websphere.persistence.PersistenceProviderImpl</provider>
<non-jta-data-source>java:comp/env/New Generic JDBC</non-jta-data-source>
<class>com.ibm.analytics.jpa.Dimtask</class>
<properties>
<property name="openjpa.jdbc.Schema" value="RM"/>
<property name="javax.persistence.jdbc.url" value="jdbc:netezza://netezza-1.site.ibm.com:5480/DATABASENAME"/>
<property name="javax.persistence.jdbc.user" value="jspoon"/>
<property name="javax.persistence.jdbc.password" value="xxxxxxx"/>
<property name="javax.persistence.jdbc.driver" value="org.netezza.Driver"/>
</properties>
</persistence-unit>
</persistence>
What else can I do to get past the NONE?
Here is the updated version of persistence.xml, I just commented out the provider.
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="test2" transaction-type="RESOURCE_LOCAL">
<!-- provider>org.eclipse.persistence.jpa.PersistenceProvider</provider-->
<!-- provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider-->
<!-- provider>com.ibm.websphere.persistence.PersistenceProviderImpl</provider-->
<non-jta-data-source>java:comp/env/New Generic JDBC</non-jta-data-source>
<class>com.ibm.analytics.jpa.Dimtask</class>
<properties>
<property name="openjpa.jdbc.Schema" value="RM"/>
<property name="javax.persistence.jdbc.url" value="jdbc:netezza://netezza-1.boulder.ibm.com:5480/BACC_TST_ISHANGO_DW"/>
<property name="javax.persistence.jdbc.user" value="jspoon"/>
<property name="javax.persistence.jdbc.password" value="C0ke4y0u"/>
<property name="javax.persistence.jdbc.driver" value="org.netezza.Driver"/>
</properties>
</persistence-unit>
</persistence>
I created my Entity class using JPA Tooling, and using a simple junit test to call a named query. The first step is to create the EMF and it is a static in my class (so none of the test is actually running, it is failing at instantiation creating the static variable):
static EntityManagerFactory emf = Persistence.createEntityManagerFactory( "test2" );
This is the exact same code as used before with eclipse and eclipseLink.

Related

Eclipselink going to wrong database platform

While trying to run a JPA application, I get:
[EL Fine]: 2014-07-09 16:55:52.532--Thread(Thread[http-bio-8080-exec-6,5,main])--Detected database platform: org.eclipse.persistence.platform.database.HSQLPlatform
Which is NOT the correct platform. (should be an Oracle thin client). The
same project when checked out on a different machine works fine. Only
difference that we can detect is the jdk version (13 versus 60 on mine).
My Persistance.xml looks like:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="JPA_DatabasePU" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<non-jta-data-source>wellsDB</non-jta-data-source>
<class>my.domain.jpaDatabase.entities.Fred.Feature</class>
<properties>
<property name="javax.persistence.jdbc.driver" value="oracle.jdbc.OracleDriver"/>
<property name="javax.persistence.jdbc.url" value="jdbc:oracle:thin:user#//db.domain.my:1521/inst"/>
<property name="javax.persistence.jdbc.user" value="username"/>
<property name="javax.persistence.jdbc.password" value="password"/>
<property name="eclipselink.logging.level" value="FINEST"/>
</properties>
</persistence-unit>
</persistence>
What am I missing??
You could try to set the target database?
<property name="eclipselink.target-database" value="Oracle"/>
Well the answer was to replace the Tomee 1.5 install with a fresh install of Tomee 1.6. I cant see difference in the conf files but there you are. From my point of view, the important thing is that this fixed the issue. The created war deploys without a problem on the production Tomee as well.

How to create database tables from Java code using JPA and JavaDB embedded?

My application uses JPA and JavaDB in embedded mode. In the persistence.xml file I use this property:
<property name="javax.persistence.jdbc.url" value="jdbc:derby:meuspiladb;create=true" />
so an empty database will be created if it does not exist yet.
Currently I have a create_tables.sql file where I put the SQL code to create the tables, and then I run it manually after the database is created. I would like to make this be automatic but I don't know how.
If the database is new I have to create the tables. What is the best way to create them from Java code?
My persistence.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="MeusPila3_PU" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>br.meuspila.corretora.Corretora</class>
<class>br.meuspila.ativo.Ativo</class>
<class>br.meuspila.bolsa.Bolsa</class>
<class>br.meuspila.movimento.Movimento</class>
<class>br.meuspila.provento.Provento</class>
<class>br.meuspila.operacao.Operacao</class>
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:derby:meuspiladb;create=true" />
<property name="javax.persistence.jdbc.user" value="APP"/>
<property name="javax.persistence.jdbc.driver" value="org.apache.derby.jdbc.EmbeddedDriver"/>
</properties>
</persistence-unit>
</persistence>
You can use Hibernate with JPA, then use configuration option hibernate.hbm2ddl.auto=create.

com.impetus.kundera.metadata.KunderaMetadataManager - No Entity metadata found for the class

I'm trying to uses queries in my Cassandra DB with Kundera (Cassandra ORM), this queries work in an others project but when I try to do it in webapp (using tomcat 6.0), I got this error :
com.impetus.kundera.metadata.KunderaMetadataManager - No Entity metadata found for the class
=> JavaNullPointerException.
But when I leave the persistence.xml from my project I got an other error. (NoPersistence.xml found or something ... )
So, my project found Persistence.xml, but not my Entity class : fileCassandra.
You can see my persistence.xml :
<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<!-- 192.168.3.107 -->
<persistence-unit name="cassandra_pu">
<provider>com.impetus.kundera.KunderaPersistence</provider>
<class>net.***.common.db.***.FileCassandra</class>
<properties>
<property name="kundera.nodes" value="localhost"/>
<property name="kundera.port" value="9160"/>
<property name="kundera.keyspace" value="KunderaExamples"/>
<property name="kundera.dialect" value="cassandra"/>
<property name="kundera.client.lookup.class" value="com.impetus.client.cassandra.pelops.PelopsClientFactory" />
<property name="kundera.cache.provider.class" value="com.impetus.kundera.cache.ehcache.EhCacheProvider"/>
<!-- <property name="kundera.cache.config.resource" value="/ehcache-test.xml"/> -->
</properties>
</persistence-unit>
</persistence>
net..common.db..FileCassandra I must replace by * because it's name from my companie ;)

apache derby + jpa

I have embedded derby database and i work with jpa. This is my persistence.xml:
<?xml version="1.0" encoding="UTF-8"?>
<persistence
version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="pers">
<class>entities.Leverancier</class>
<class>entities.Prijsproduct</class>
<class>entities.Product</class>
</persistence-unit>
</persistence>
What should i change or add to get this working. When I run my code now I get the following:
Exception in thread "main" javax.persistence.PersistenceException: No Persistence provider for EntityManager named pers
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:55)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:33)
at test.Test.main(Test.java:19)
Your persistence.xml is not correct. Look at a sample below:
<persistence-unit name="MyAppPU" transaction-type="RESOURCE_LOCAL">
<!-- This is where you mention your JPA runtime provider e.g. it's EclipseLink here -->
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>mypkg.MyEntity</class>
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:derby://localhost:1527/my_schema"/>
<property name="javax.persistence.jdbc.password" value="pass"/>
<property name="javax.persistence.jdbc.driver" value="org.apache.derby.jdbc.ClientDriver"/>
<property name="javax.persistence.jdbc.user" value="user"/>
</properties>
</persistence-unit>
You also have to make sure that you put your JPA provider jar files (along with the derby-client jar) in the classpath.

how inject a EntityManager between ear

I'm using JBoss 4.2.3 and I deployed two ears called triad-1.0.ear and reportservices-1.0.ear, the thing is that I want to use the entity manager of the project triad in the project reportservices. This is the architecture JBoss follows:
triad-1.0.ear:
triad-core-1.0.jar:
META-INF:
MANIFEST.MF
components.xml
ejb-jar.xml
jboss.xml
persistence.xml
reportservices-1.0.ear:
reportservices-core-1.0.jar:
META-INF:
MANIFEST.MF
components.xml
ejb-jar.xml
jboss.xml
persistence.xml
this is my attempt to make the entitymanager global between ear in the persistence.xml:
<?xml version="1.0" encoding="UTF-8"?>
<!--
Attention: Generated code! Do not modify by hand!
Generated by: persistence.xml.vsl in andromda-ejb3-cartridge.
-->
<persistence
xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"
version="1.0">
<persistence-unit name="triad">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<jta-data-source>java:/jdbc/triad</jta-data-source>
<properties>
<property name="hibernate.hbm2ddl.auto" value="update"/>
<property name="hibernate.dialect" value="org.hibernate.dialect.Oracle9Dialect"/>
<property name="jboss.entity.manager.jndi.name" value="java:/triadFactory"/>
<property name="jboss.entity.manager.factory.jndi.name" value="java:/triadFactory"/>
</properties>
</persistence-unit>
</persistence>
I'm sorry but the question doesn't make much sense in my opinion (I don't even get what you mean by "make public the persistence.xml"). Just in case, it is possible:
to use the same datasource in several persistence units.
to (re)use a persistence unit in several applications (provided the packaging make it possible).
My suggestion would be to explain what you would like to do in plain english (forget the technical details for now).
i finally solved mi problem with the injection, you need to set this properties in the persistence.xml and check in jboss jmx console, in the option of jdni view if the injection was correct the properties here's an example of the persistence.xml
<persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0">
<persistence-unit name="example">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<jta-data-source>java:/jdbc/example</jta-data-source>
<properties>
<property name="hibernate.hbm2ddl.auto" value="update"/>
<property name="hibernate.dialect" value="org.hibernate.dialect.Oracle9Dialect"/>
<property name="jboss.entity.manager.jndi.name" value="java:/example"/>
<property name="jboss.entity.manager.factory.jndi.name" value="java:/example"/>
</properties>
</persistence-unit>
</persistence>`
the properties that allowing the injection are "jboss.entity.manager.jndi.name" and "jboss.entity.manager.factory.jndi.name"
notes the data have the same name that the data source but called by his jdni name sets in the xml of the datasource project.

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