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How to run JMeter through CMD from jdk/bin directory?

I want to run JMeter test plans from a UNIX server where env variables for java is not set. Its a test server and I dont have access to set that. We have different JDK versions and all are sitting in directories. I need to run my JMeter TestPlans on this server. I went to JDK /bin folder and tired to execute the below command
$ {jmeter-path}/bin/jmeter -nt testplan.jmx -l testresult.jtl
but this says
./bin/java: not found
But if I do simple java -version it shows the version result.Is that something that JMeter needs specifically the java env variable set or it wont run ? I dont have permission to set and I want to run the testplan using the JDK/JRE from its directories. A help would be appreciated. Thanks in advance!
UPDATE:
I think I could work around this by editing the jmeter script file as suggested in the one of the comments. Since my requirement was running the JMeter from a specific server, I could achieve this by editing the JAVA_HOME variable value in the script.

JMeter looks for java executable in system PATH so you have 2 options:
Add bin folder of your JDK or JRE to PATH, something like:
PATH=$PATH:/location/of/your/jbk/bin && export PATH && {jmeter-path}/bin/jmeter -nt testplan.jmx -l testresult.jtl
Or if you have java in PATH just run ApacheJMeter.jar like:
java -jar {jmeter-path}/bin/ApacheJMeter.jar
You might also want to use jmeter.sh wrapper script instead of jmeter, it has some logic regarding java binary location
More information: Get Started With JMeter: Installation & Tests

The official JMeter Getting Started documentation says this:
To install a release build, simply unzip the zip/tar file into the directory where you want JMeter to be installed. Provided that you have a JRE/JDK correctly installed and the JAVA_HOME environment variable set, there is nothing more for you to do.
Based on the symptoms that you reported, I think that you have not set JAVA_HOME correctly. It should be set to an absolute path to your Java installation's top directory.

Can't open Tomcat startup

I can't seem to open up the Tomcat console despite having just been able to successfully do so. When I click on the "startup" Windows Batch File, the console opens then closes itself immediately afterwards. I've read that it has something to do with setting up the environment variables / paths correctly but I've looked at it and it seems fine; you can check the picture out.
NOTE: Over the course of step 6, the javac command did not work for me. To fix I added a second "C:\Program Files..jdk1.8.0_131\bin" into the Path variable (as you can see in the picture. This enabled me to use the javac command but I have no idea why it didn't detect the JAVA_HOME.
Trying to run startup via cmd console outputs the message: D:\myProject\tomcat\bin>startup
The JRE_HOME environment variable is not defined correctly
This environment variable is needed to run this program
I'm still a beginner with server management so I've been following this tutorial: https://www.ntu.edu.sg/home/ehchua/programming/howto/Tomcat_HowTo.html. I'm at the end of step 6c) where it tells me I should restart the server after compiling an servlet and creating an xml. But lo and behold, it won't open again after quitting...

You must not point JAVA_HOME to bin directory. Just point it to jdk directory, and add a %JAVA_HOME%\bin to your path variable.

My Tomcat is not running it just open and close when I click on tomcat7.exe [closed]

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I am installing Tomcat 7 in my PC it works in Eclipse but when I try to open in bin/ tomcat7.exe it just open and closes, (I am stopping the server in Eclipse). Also, in Eclipse I'am trying to open admin console like URL:(localhost:1234/admin) it shows 404 error. Can anyone who knows this problem explain a solution?

If you are using Windows, you can follow the following to run tomcat7.exe :
Open your Command prompt (cmd)
Set your JAVA_HOME or JRE_HOME. Eg. set JRE_HOME=C:\Program Files\Java\jre7
Go to the directory of your tomcat. Eg. cd C:\Program Files\apache-tomcat-7.0.35\bin
Run startup.bat file. Eg. startup.
This should start your tomcat server without using Eclipse.

First Set JAVA_HOME and CLASSPath path
For Windows Java Path Settings
Right click on Computer and open Properties.
In Windows Vista or Windows 7, go to Advanced System Settings.
Else go to next step. Go to Advanced Tab and click on Environment
Variables button.
Select CLASSPath under the list of System Variables, and press Edit and add If CLASSPath not available there click New button add
C:\Program Files\java\jre 1.x.x_xx\bin
after a semicolon.
Now click on New' button under system variables and enter
JAVA_HOME as variable name and path to jdk home directory (ex.
C:\Program Files\Java\jdk1.x.x_xx
After Completing Java Path Settings
Go to the directory of your Tomcat. Eg. cd C:\Program
Files\apache-tomcat-7.0.35\bin
Run startup.bat file

To start your application server in Windows :
Open command prompt .(Run as Administrator).
Go to the path (..\apache-tomcat-8.0.27\bin) and run startup.bat
A new command prompt opens up and should stay unclosed to tell your server is in running state.
If command prompt opens and closes automatically, then the reason can be as below.
tomcat is already in started state in Eclipse.
Check the connector port configured in server.xml file and check if that port is free in your local machine. [netstat command]
Change the connector port to some unused port, preferably in 80XX series.
Let me know if you are able to invoke localhost:(the http connector port) you have configured in server.xml through you web browser.

You don't start Tomcat by double clicking the exe, use the batch files instead.
startup.bat starts the server, shutdown.bat stops it again.
And ignore the advise to get the service installer. You don't need those unless you want the server to start on system boot and run in the background. Which you don't want unless you're going to configure a production server, which you aren't here.
The batch files are in the same directory on your computer as the exe.

you have to set JAVA_HOME and JRE_HOME in System environment.while setting the JAVA_HOME and JRE_HOME, you should assure that JRE path that you are setting is corresponding to the JDK whose path you have set in JAVA_HOME. some time what happens that there may be more than one JDK in the system so conflict occurs. better to have only one JDK and corresponding JRE.

This is probably due to a bad setup of an environment variable.
For example, if you setup incorrect JAVA_OPTS, tomcat startup will fail.
You can check your configuration by calling : catalina configtest
Here an example of the output for bad setup of JAVA_OPTS :
Error occurred during initialization of VM Could not reserve enough space for object heap
Error: Could not create the Java Virtual Machine.
Error: A fatal exception has occurred. Program will exit.

It works for me after updating the jdk path in JAVA_HOME compatible to your tomcat version in user Variables.

the JAVA_HOME and JRE_HOME environment variables set should not have semicolon or ; at the end...I was facing similar problem...removed semi-colon or ; from the end and tomcat server started from cmd screen after running startup command(of tomcat..bin folder).

I checked environment variables and compiler version everything was fine, deleting junk files from work folder worked for me.

Just download the tomcat 32-bit/64-bit Windows Service Installer (pgp, md5) as in this set up is given which will install tomcat on your PC and you can also start and stop tomcat using the tomcat service.

In my experience tomcat7 might not like it if JAVA_PATH or JDK_PATH contain bracket symbols like in "Program Files (x86)". Make sure you format path in your environmental variables correctly or move your JDK to another folder.

In my case, I had some reference to a jar file in catilana.bat, but the jar I had removed from my system. Tomcat started successfully once I removed that reference from catilana.bat

Check your JRE_HOME location in environment variables. if it didn't work then try
1). Open CMD in administration mode.
2). locate to your tomcat directory.
3). run startup.bat --->> It will show your problem.

Had the same problem with Apache Tomcat 9 version.
Solution is very simple.
Apache Tomcat 9 is supported by Java 8 and later versions. So, I had JRE_HOME with JRE7 path, I binded it to new JRE8 and everything works fine.
Different versions of Apache Tomcat are available for different versions of the Servlet and JSP specifications. The mapping between the specifications and the respective Apache Tomcat versions is:

Trouble in Setting Java Environment Path on Ubuntu (libjvm.so: cannot open shared object file: No such file or directory)

Found the solution!
Ubuntu by default ignore the command "RD_LIBRARY_PATH" therefore I need to add those codes in ".bashrc" instead of "/etc/environment" or .profile.
it now work perfectly fine!
I am trying to run a program that reads Java method from C/C++ code. (I made it on Windows successfully, now, I am working on Linux)
I made it successfully compiled and run on Ubuntu, however, the problem is..
Whenever I try to run the program, I have to type following commands on terminal..
source /etc/environment
./invoke #program name is invoke
If I do not type "source /etc/environment" every time I boot my PC, the error message I get is...
error while loading shared libraries: libjvm.so: cannot open shared object file: No such file or directory
Ok. Here is what I added in /etc/environment
export PATH="$PATH:/usr/lib/jvm/jdk1.7.0_25_x64/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games"
export JAVA_HOME=/usr/lib/jvm/jdk1.7.0_25_x64
export LD_LIBRARY_PATH=$JAVA_HOME/jre/lib/amd64:$JAVA_HOME/jre/lib/amd64/server
What I want is that, as you know, I want to run the program without typing "source /etc/environment".
I also tried typing those PATHs on /etc/profile, but result was same... I should type "source /etc/profile" every time I reboot my PC..
How to make it permanently applied to whole range of System without typing "source /etc/environment" stuffs everytime I boot?
if you need to see source code of the program, here is downloadable address:
http://cfile237.uf.daum.net/attach/247819495212DF1C07B9EB

This worked for me:
For x86:
export LD_LIBRARY_PATH=/usr/lib/jvm/default-java/jre/lib/i386:/usr/lib/jvm/default-java/jre/lib/i386/server
For x86_64
export LD_LIBRARY_PATH=/usr/lib/jvm/default-java/jre/lib/amd64:/usr/lib/jvm/default-java/jre/lib/amd64/server

I had the same problem of setting the path(permanently) however I was using Red Hat, If you look change PATH permanently on Ubuntu it might help you. There was a file on Red Hat .profile that once you add your exports statements, they will get loaded when the computer starts. :) There should be the kind of file for ubuntu
export PATH="$PATH:/usr/lib/jvm/jdk1.7.0_25_x64/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games"
export JAVA_HOME=/usr/lib/jvm/jdk1.7.0_25_x64

Put "-Djava.library.path=FULL_PATH_HERE/jre/lib/amd64" as a JVM option in your C code.
Edit the full_path_here part.
The path is allowed to be relative, but I don't think you can use $JAVA_HOME as a placeholder for the environment variable.

Found the solution!
Ubuntu by default ignore the command "RD_LIBRARY_PATH" therefore I need to add those codes in ".bashrc" instead of "/etc/environment" or .profile.
it now work perfectly fine!

add the path of the missing libraries in the file /etc/ld.so.conf
execute the following command: ldconfig
this way, you'll add the new libraries to the default ones.
To check whether the new libraries have been linked,
execute the following command: ldconfig -p
to have the list of libraries currently linked by default.

Tomcat -- Running a web application

I'm trying to run a sample app in Tomcat. I've installed tomcat, set up the environment variable by creating a new system variable called JAVA_HOME which is set to C:\Program Files\Java\jdk1.6.0_20. And I've created a new dir for the web app in the tomcat program directory. In the cmd prompt I navigate to the tomcat program directory and type in bin/startup.sh and I get the following error: 'bin' is not recognized as an internal or external command, operable program, or batch file.
I'm using tomcat 6.0 and I'm on a windows machine. What could the problem?

On Windows you must run the startup.bat file instead of the startup.sh file (note the extension is different).
Also, enter the bin directory before executing the bat script.
cd bin
startup.bat

Your on windows try:
bin\startup.bat

If you try typing in bin\startup.bat on a Windows machine and still get the same error, there's a possibility that Windows is not seeing the batch script where it should be. As a-horse-with-no-name already said, try installing Tomcat to a location where there are no spaces in the path. In your case, anywhere other than Program Files.
EDIT: To resolve this space issue, you can do two things: 1) Install JDK/JRE to a common location without spaces (say, C:\Java) and set it to be JAVA_HOME environment variable. 2) Install Tomcat to another location (say, C:\Tomcat) and proceed from there. Since these are all in common location, I believe you can do this as a limited account user without needing admin privileges.

Try to install Tomcat (and possibly the JDK) into a directory without spaces.

The script you ran is intended for *nix systems. Try bin\startup.bat

I'm a little confused by some of the answers. First, the error you are receiving is from Windows. Nothing to do with Tomcat. The Windows OS thinks you have entered a command, and doesn't recognize it. Files with the .bat extension are always recognized by Windows as Batch file commands....... soooo..... Navigate to the bin directory, again, under your tomcat installation. Then....
Don't append the bin in front of the command. You should do a quick look to make sure that the "startup.bat" file is here (dir *.bat). Then just type "startup.bat".
Seems like I just type "catalina.bat start" (for my tomcat catalina installation)