I can't seem to open up the Tomcat console despite having just been able to successfully do so. When I click on the "startup" Windows Batch File, the console opens then closes itself immediately afterwards. I've read that it has something to do with setting up the environment variables / paths correctly but I've looked at it and it seems fine; you can check the picture out.
NOTE: Over the course of step 6, the javac command did not work for me. To fix I added a second "C:\Program Files..jdk1.8.0_131\bin" into the Path variable (as you can see in the picture. This enabled me to use the javac command but I have no idea why it didn't detect the JAVA_HOME.
Trying to run startup via cmd console outputs the message: D:\myProject\tomcat\bin>startup
The JRE_HOME environment variable is not defined correctly
This environment variable is needed to run this program
I'm still a beginner with server management so I've been following this tutorial: https://www.ntu.edu.sg/home/ehchua/programming/howto/Tomcat_HowTo.html. I'm at the end of step 6c) where it tells me I should restart the server after compiling an servlet and creating an xml. But lo and behold, it won't open again after quitting...
You must not point JAVA_HOME to bin directory. Just point it to jdk directory, and add a %JAVA_HOME%\bin to your path variable.
Related
I am trying to install Java in Windows 10 Home (64 bit). Like many tutorials point out, I downloaded the Java jdk setup file, executed it and once installed changed the Path in the Environment Variables. But for some reason, when I execute the command 'javac' it returns the not internal/external command error in Command Prompt but runs absolutely fine in Powershell. I tried to rectify this by uninstalling Java and reinstalling it very carefully, following all the steps but still this keeps on happening.
Also, during installation of Java, I lost the original value to my Path variable. Could this be causing the problem?
Edit : I was able to get the java command running in the command prompt but javac still won't work. I've already tried the methods suggested on other forums and this one but no luck so far.
See there is no problem with Java installation if you can find JDK(Java development kit) and JRE(Server Java runtime environment) in programme files in windows in a JAVA folder.
The main problem is with the environment variable declaration.
Go to environment variables and make a new path for that.
JAVA_HOME = "YOUR JDK & JRE INSTALLATION PATH"
And another one is
JAVA = "YOUR JDK & JRE INSTALLATION PATH"
Hope that help to you. After doing that if still there problem persisist just restart your PC and check again.
Just add your variable location up to /bin/
Refer to this :
https://www.windows-commandline.com/javac-not-recognized-internal-external-command/
Open file explorer
Right click computer then click properties
click advanced system settings
click environmental variables
click path (for me there was one in user variables for admin and another in system variables)
find the directory for javac (for me it was here C:\Program Files (x86)\Java\jdk1.8.0_191\bin)
so go back to file explorer and open program files x86
then open the java folder
then open the jdk folder
then open the bin folder
highlight the path in the search bar and copy it
click edit on path and paste into the path in the environmental variable for both(if you have more than one path)
If no path exists then create one in user variables
If there is any existing text place a semicolon ; between the text you pasted in there and the preexisting text.
close command prompt and reopen it.
type javac -version
the version info should be listed
This problem comes up with the directory of your command prompt.
check your PowerShell and command prompt default directory.
We can run command prompt as WinKey+R then type cmd, Hit the enter button then check our java version cmd javac -version.
I'm trying to get the java command to work on my computer. Whenever I try to use it, I get the error "'java' is not recognized as an internal or..."
What I've done
So far I've traced the issue through my system environment variables, which has a variable PATH that links to "C:\ProgramData\Oracle\Java\javapath" or javapath for short.
There are 3 files in the javapath folder, and if you click on them a popup says:
But when I examine the properties of the shortcut and click "open folder location" it sends me to the right place (?? what is this).
Just in case, I tried to recreate the shortcut; I called it java2 and it now works (opens a command box for a split second and closes) when I click on it. However, testing it in command prompt with the line "java2 -version" returns "'java2' is not recognized as an internal or external..."
Details
I just installed java 8, and I've verified that it was installed correctly
I'm running a 64 bit windows 7 OS
Have you checked your environment variables for Windows? When you installed the JDK/JRE the directory should have been added to the PATH variable. The directory added needs to contain the java.exe executable. It should be located in C:\Program Files\Java or something like that if you installed it using the default settings. Once you find that directory find the bin directory inside it.
In order to check that:
Right click My Computer and hit Properties
On the left side hit Advanced System Settings
Hit the Advanced tab and then Environment Variables down at the bottom
Find the PATH variable and then hit edit. Confirm that the location of the JDK /bin directory is there, if it is not then add it.
Also, if the JAVA_HOME variable isn't already set, this may be a good idea.
I did the following steps but java does not seem to be working for me, do I need to restart my system if yes then why?
1. Right click My Computer->Advence Option->Environment Varibles->System Variables
2. variable : Path->Edit
3. Copy your jdk bin directory i.e.C:\Program Files\Java\jdk1.7.0_51\bin
4. Paste it after putting a semi-colon(;) in value section
i am getting below error while running java in cmd
C:\Users\User>java -version
Error: opening registry key 'Software\JavaSoft\Java Runtime Environment'
Error: could not find java.dll
Error: Could not find Java SE Runtime Environment.
No, but you will need to close and recreate any cmd windows, running java programs, or the like.
To check it's correct, open a new cmd window and type set -> review the information for PATH and JAVA_HOME.
You should set two things:
JAVA_HOME
PATH
The first lies under the "User variables for [your user name]" section. Add the JAVA_HOME variable and set it to where your jdk is installed. i.e. C:\Program Files\Java\jdk1.7.0_51\
The second lies under the "System variables" section. You should find the "path" variable, and edit it. Then, append ";%JAVA_HOME%\bin" (minus the quotes) to the end of the path variable.
After you have done this, save the variables and close that window clicking the "ok" button. Close down all instances of the command prompt (and any IDE you may be developing with such as Eclipse or NetBeans), and reopen one command prompt. Then, if you would like to test whether or not your changes worked and are in effect, try the following:
echo %JAVA_HOME%
This should output where you set your java home variable to.
echo %PATH%
At the end of what is output, you should see your java home\bin addition to the path variable
java -version
If you can run this command from the command line, it means that your environment was set up correctly and java is now in your path.
Not necessary. Quit and Open the command prompt again (if any) that runs the java process and type java -version to check if it installed successfully.
If you are using mac, source ~/.bashrc or source ~/.zshrc should refresh your environmental variable. No need to re-start the terminal even.
No, you don't need to restart your system.
However, you have to restart your command prompt application to update the changes done on Environment variables.
NO.
You don't need to restart the system, but just the application like cmd or any IDE you are using for java development (i.e Eclipse) need to restart.
And to confirm that the java path is set that you have mentioned in JAVA_HOME environment variable, you can open cmd and you can check with commands echo %JAVA_HOME% or echo %PATH%.
I reinstall the JDK and set the JAVA_HOME and PATH variable again. now it's working.
In my case under user variable section(for particularuser) JAVA_HOME set to jre not jdk path . I change it to JDK path , It worked for me
yes need to restart cmd prompt after env variable change
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I am installing Tomcat 7 in my PC it works in Eclipse but when I try to open in bin/ tomcat7.exe it just open and closes, (I am stopping the server in Eclipse). Also, in Eclipse I'am trying to open admin console like URL:(localhost:1234/admin) it shows 404 error. Can anyone who knows this problem explain a solution?
If you are using Windows, you can follow the following to run tomcat7.exe :
Open your Command prompt (cmd)
Set your JAVA_HOME or JRE_HOME. Eg. set JRE_HOME=C:\Program Files\Java\jre7
Go to the directory of your tomcat. Eg. cd C:\Program Files\apache-tomcat-7.0.35\bin
Run startup.bat file. Eg. startup.
This should start your tomcat server without using Eclipse.
First Set JAVA_HOME and CLASSPath path
For Windows Java Path Settings
Right click on Computer and open Properties.
In Windows Vista or Windows 7, go to Advanced System Settings.
Else go to next step. Go to Advanced Tab and click on Environment
Variables button.
Select CLASSPath under the list of System Variables, and press Edit and add If CLASSPath not available there click New button add
C:\Program Files\java\jre 1.x.x_xx\bin
after a semicolon.
Now click on New' button under system variables and enter
JAVA_HOME as variable name and path to jdk home directory (ex.
C:\Program Files\Java\jdk1.x.x_xx
After Completing Java Path Settings
Go to the directory of your Tomcat. Eg. cd C:\Program
Files\apache-tomcat-7.0.35\bin
Run startup.bat file
To start your application server in Windows :
Open command prompt .(Run as Administrator).
Go to the path (..\apache-tomcat-8.0.27\bin) and run startup.bat
A new command prompt opens up and should stay unclosed to tell your server is in running state.
If command prompt opens and closes automatically, then the reason can be as below.
tomcat is already in started state in Eclipse.
Check the connector port configured in server.xml file and check if that port is free in your local machine. [netstat command]
Change the connector port to some unused port, preferably in 80XX series.
Let me know if you are able to invoke localhost:(the http connector port) you have configured in server.xml through you web browser.
You don't start Tomcat by double clicking the exe, use the batch files instead.
startup.bat starts the server, shutdown.bat stops it again.
And ignore the advise to get the service installer. You don't need those unless you want the server to start on system boot and run in the background. Which you don't want unless you're going to configure a production server, which you aren't here.
The batch files are in the same directory on your computer as the exe.
you have to set JAVA_HOME and JRE_HOME in System environment.while setting the JAVA_HOME and JRE_HOME, you should assure that JRE path that you are setting is corresponding to the JDK whose path you have set in JAVA_HOME. some time what happens that there may be more than one JDK in the system so conflict occurs. better to have only one JDK and corresponding JRE.
This is probably due to a bad setup of an environment variable.
For example, if you setup incorrect JAVA_OPTS, tomcat startup will fail.
You can check your configuration by calling : catalina configtest
Here an example of the output for bad setup of JAVA_OPTS :
Error occurred during initialization of VM Could not reserve enough space for object heap
Error: Could not create the Java Virtual Machine.
Error: A fatal exception has occurred. Program will exit.
It works for me after updating the jdk path in JAVA_HOME compatible to your tomcat version in user Variables.
the JAVA_HOME and JRE_HOME environment variables set should not have semicolon or ; at the end...I was facing similar problem...removed semi-colon or ; from the end and tomcat server started from cmd screen after running startup command(of tomcat..bin folder).
I checked environment variables and compiler version everything was fine, deleting junk files from work folder worked for me.
Just download the tomcat 32-bit/64-bit Windows Service Installer (pgp, md5) as in this set up is given which will install tomcat on your PC and you can also start and stop tomcat using the tomcat service.
In my experience tomcat7 might not like it if JAVA_PATH or JDK_PATH contain bracket symbols like in "Program Files (x86)". Make sure you format path in your environmental variables correctly or move your JDK to another folder.
In my case, I had some reference to a jar file in catilana.bat, but the jar I had removed from my system. Tomcat started successfully once I removed that reference from catilana.bat
Check your JRE_HOME location in environment variables. if it didn't work then try
1). Open CMD in administration mode.
2). locate to your tomcat directory.
3). run startup.bat --->> It will show your problem.
Had the same problem with Apache Tomcat 9 version.
Solution is very simple.
Apache Tomcat 9 is supported by Java 8 and later versions. So, I had JRE_HOME with JRE7 path, I binded it to new JRE8 and everything works fine.
Different versions of Apache Tomcat are available for different versions of the Servlet and JSP specifications. The mapping between the specifications and the respective Apache Tomcat versions is:
why the error occurs when i am starting the jboss server 6.0 ?
'findstr' is not recognized as an internal or external command,
operable program or batch file.
It looks like your PATH environment variable hasn't been set up correctly. Does this link help?
http://community.jboss.org/wiki/FindstrCommandNotFound
EDIT: are you sure that the JBoss startup batch script (usually in %JBOSS_HOME%\bin\run.bat) is picking up the PATH correctly? It might be running as a different user with a different PATH. Edit this script and add the line echo %PATH% before the first line that contains findstr. What output does this give you?
The only other place findstr is used (in jboss-6.0.0.20100721-M4 anyway) is in the service.bat script in the same folder as run.bat . Again, you could try putting echo %PATH% before the line in this script that uses findstr if the previous step didn't help you.
EDIT 2: according to your comments, the echo %PATH% line I asked you to add gave the following output:
E:\jdk1.6\bin;E:\apache-ant-1.7.0\bin;E:\jboss-6.0\bin\run.bat
Clearly this doesn't contain C:\WINDOWS\system32, so JBoss definitely won't be able to find findstr. But I don't understand why the PATH is ending up like this. How are you starting JBoss - as a service or by running run.bat? Is JBoss being run under some user account which has been set up with a very restricted PATH? Do you have some other script which is manipulating the PATH before JBoss starts? Also, which version of Windows are you using?
Also, it's not immediately clear to me from your three comments
I'm already checked that the findstr application is already in that path C:\WINDOWS\system32\
E:\jboss-6.0\bin\run.bat
Am also set that in the system variables in Environmental Variables
whether C:\WINDOWS\system32 is in the PATH in Control Panel > System > Environment Variables. Is C:\WINDOWS\system32 in the PATH in the System Variables section within the Environment Variables dialog?
This doesn't seem to be an issue with JBoss. This seems to be more of an issue with the environment within which you are running it. I can quite imagine a lot of other programs would be unhappy with being run in a similar environment.