so I have an array list of Objects and in it are string numbers. I want to add decimal places to these numbers (8).
String value = String.valueOf(accountEntry.get(4));
double amount = Double.valueOf(value);
String formatted = String.format(Locale.GERMANY,"%.8f",amount);
accountEntry.add(formatted);
For example 101700000000 should output 1017 but instead it is 101700000000,00000000
Does anyone know where the problem is?
Hello try something like this using Regex , this way you can remove all zeros at the end.
String value = String.valueOf("101700000000");
double amount = Double.valueOf(value);
String formatted = String.format(Locale.GERMANY,"%d",(long)amount);
formatted = formatted.replaceAll("0+$", "");
System.out.println(formatted);
Input :101700000000 ===> Output: 1017
Does anyone know where the problem is?
Your Input is : 101700000000 and you are formatting String.format(Locale.GERMANY,"%.8f",amount); In here your output will be 101700000000,00000000 So for understand this String Format will not transform your input magicaly to 1017. You need to use another algorithm for this problem
I am trying to convert a String number to two decimal places in Java. I saw lot of posts on satckoverflow but somehow I am getting an exception.
String number = "1.9040409535344458";
String result = String.format("%.2f", number);
System.out.println(result);
This is the exception I am getting -
java.util.IllegalFormatConversionException: f != java.lang.String
I would like to have 1.904 as the output. Does anyone know what wrong I am doing here?
You can try using a NumberFormat. For example:
String number = "1.9040409535344458";
NumberFormat formatter = new DecimalFormat("#0.000");
String result = formatter.format(Double.valueOf(number));
System.out.println(result);
Just declare number to be double :
Double number = 1.9040409535344458;
instead of
String number = "1.9040409535344458";
OUTPUT :
1.90
you should first convert the string into double and then change the decimal value
String number = "1.9040409535344458";
double result = Double.parseDouble(number);//converts the string into double
result = result *100;//adjust the decimal value
System.out.println(result);
You are using a format not meant for a String. I would recommend either converting your String to a double or storing it as a double in the first place. Convert the String to a double, and pass that double to String.format.
I need to right align an input string of digits with a mask using plus symbols.
For example:
String input = "893";
String mask = "&&&&&&";
should return
String output = "+++893";
I'm very confused on how to implement this with NumberFormat and or DecimalFormat as I haven't used them before. Any help would be appreciated.
If you need to use DeciamlFormat you could use:
int input = 893;
DecimalFormat decFormat = new DecimalFormat("000000"); //as many palces as you need
String output = decFormat.format(input);
And then replace all leading zeros with + sign.
String.format("%06d", input); //also gives you leading zeros
You still have to check if the output is too long, if you always want 6 places.
You could try this: If the length of the mask is greater than the length of the input, take the difference and add that many plus signs to the front of the input.
What is the best way to format the following number that is given to me as a String?
String number = "1000500000.574" //assume my value will always be a String
I want this to be a String with the value: 1,000,500,000.57
How can I format it as such?
You might want to look at the DecimalFormat class; it supports different locales (eg: in some countries that would get formatted as 1.000.500.000,57 instead).
You also need to convert that string into a number, this can be done with:
double amount = Double.parseDouble(number);
Code sample:
String number = "1000500000.574";
double amount = Double.parseDouble(number);
DecimalFormat formatter = new DecimalFormat("#,###.00");
System.out.println(formatter.format(amount));
This can also be accomplished using String.format(), which may be easier and/or more flexible if you are formatting multiple numbers in one string.
String number = "1000500000.574";
Double numParsed = Double.parseDouble(number);
System.out.println(String.format("The input number is: %,.2f", numParsed));
// Or
String numString = String.format("%,.2f", numParsed);
For the format string "%,.2f" - "," means separate digit groups with commas, and ".2" means round to two places after the decimal.
For reference on other formatting options, see https://docs.oracle.com/javase/tutorial/java/data/numberformat.html
Given this is the number one Google result for format number commas java, here's an answer that works for people who are working with whole numbers and don't care about decimals.
String.format("%,d", 2000000)
outputs:
2,000,000
Once you've converted your String to a number, you can use
// format the number for the default locale
NumberFormat.getInstance().format(num)
or
// format the number for a particular locale
NumberFormat.getInstance(locale).format(num)
I've created my own formatting utility. Which is extremely fast at processing the formatting along with giving you many features :)
It supports:
Comma Formatting E.g. 1234567 becomes 1,234,567.
Prefixing with "Thousand(K),Million(M),Billion(B),Trillion(T)".
Precision of 0 through 15.
Precision re-sizing (Means if you want 6 digit precision, but only have 3 available digits it forces it to 3).
Prefix lowering (Means if the prefix you choose is too large it lowers it to a more suitable prefix).
The code can be found here. You call it like this:
public static void main(String[])
{
int settings = ValueFormat.COMMAS | ValueFormat.PRECISION(2) | ValueFormat.MILLIONS;
String formatted = ValueFormat.format(1234567, settings);
}
I should also point out this doesn't handle decimal support, but is very useful for integer values. The above example would show "1.23M" as the output. I could probably add decimal support maybe, but didn't see too much use for it since then I might as well merge this into a BigInteger type of class that handles compressed char[] arrays for math computations.
you can also use the below solution
public static String getRoundOffValue(double value){
DecimalFormat df = new DecimalFormat("##,##,##,##,##,##,##0.00");
return df.format(value);
}
public void convert(int s)
{
System.out.println(NumberFormat.getNumberInstance(Locale.US).format(s));
}
public static void main(String args[])
{
LocalEx n=new LocalEx();
n.convert(10000);
}
You can do the entire conversion in one line, using the following code:
String number = "1000500000.574";
String convertedString = new DecimalFormat("#,###.##").format(Double.parseDouble(number));
The last two # signs in the DecimalFormat constructor can also be 0s. Either way works.
Here is the simplest way to get there:
String number = "10987655.876";
double result = Double.parseDouble(number);
System.out.println(String.format("%,.2f",result));
output:
10,987,655.88
The first answer works very well, but for ZERO / 0 it will format as .00
Hence the format #,##0.00 is working well for me.
Always test different numbers such as 0 / 100 / 2334.30 and negative numbers before deploying to production system.
According to chartGPT
Using DecimalFormat:
DecimalFormat df = new DecimalFormat("#,###.00");
String formattedNumber = df.format(yourNumber);
Using NumberFormat:
NumberFormat nf = NumberFormat.getNumberInstance();
nf.setGroupingUsed(true);
String formattedNumber = nf.format(yourNumber);
Using String.format():
String formattedNumber = String.format("%,.2f", yourNumber);
Note: In all the above examples, "yourNumber" is the double value that you want to format with a comma. The ".2f" in the format string indicates that the decimal places should be rounded to 2 decimal places. You can adjust this value as needed.
How do I convert scientific notation to regular int
For example: 1.23E2
I would like to convert it to 123
Thanks.
If you have your value as a String, you could use
int val = new BigDecimal(stringValue).intValue();
You can just cast it to int as:
double d = 1.23E2; // or float d = 1.23E2f;
int i = (int)d; // i is now 123
I am assuming you have it as a string.
Take a look at the DecimalFormat class. Most people use it for formatting numbers as strings, but it actually has a parse method to go the other way around! You initialize it with your pattern (see the tutorial), and then invoke parse() on the input string.
Check out DecimalFormat.parse().
Sample code:
DecimalFormat df = new DecimalFormat();
Number num = df.parse("1.23E2", new ParsePosition(0));
int ans = num.intValue();
System.out.println(ans); // This prints 123
You can also use something like this.
(int) Double.parseDouble("1.23E2")
You can implement your own solution:
String string = notation.replace(".", "").split("E")[0]