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Java code snippet to trim the decimal places in a number based on a condition [duplicate]

I am invoking a method called "calculateStampDuty", which will return the
amount of stamp duty to be paid on a property. The percentage calculation works
fine, and returns the correct value of "15000.0". However, I want to display the value to
the front end user as just "15000", so just want to remove the decimal and any preceding values
thereafter. How can this be done? My code is below:
float HouseValue = 150000;
double percentageValue;
percentageValue = calculateStampDuty(10, HouseValue);
private double calculateStampDuty(int PercentageIn, double HouseValueIn){
double test = PercentageIn * HouseValueIn / 100;
return test;
}
I have tried the following:
Creating a new string which will convert the double value to a string, as per below:
String newValue = percentageValue.toString();
I have tried using the 'valueOf' method on the String object, as per below:
String total2 = String.valueOf(percentageValue);
However, I just cannot get a value with no decimal places. Does anyone know
in this example how you would get "15000" instead of "15000.0"?
Thanks

Nice and simple. Add this snippet in whatever you're outputting to:
String.format("%.0f", percentageValue)

You can convert the double value into a int value.
int x = (int) y where y is your double variable. Then, printing x does not give decimal places (15000 instead of 15000.0).

I did this to remove the decimal places from the double value
new DecimalFormat("#").format(100.0);
The output of the above is
100

You could use
String newValue = Integer.toString((int)percentageValue);
Or
String newValue = Double.toString(Math.floor(percentageValue));

You can convert double,float variables to integer in a single line of code using explicit type casting.
float x = 3.05
int y = (int) x;
System.out.println(y);
The output will be 3

I would try this:
String numWihoutDecimal = String.valueOf(percentageValue).split("\\.")[0];
I've tested this and it works so then it's just convert from this string to whatever type of number or whatever variable you want. You could do something like this.
int num = Integer.parseInt(String.valueOf(percentageValue).split("\\.")[0]);

Try this you will get a string from the format method.
DecimalFormat df = new DecimalFormat("##0");
df.format((Math.round(doubleValue * 100.0) / 100.0));

Double d = 1000d;
System.out.println("Normal value :"+d);
System.out.println("Without decimal points :"+d.longValue());

Use
Math.Round(double);
I have used it myself. It actually rounds off the decimal places.
d = 19.82;
ans = Math.round(d);
System.out.println(ans);
// Output : 20
d = 19.33;
ans = Math.round(d);
System.out.println(ans);
// Output : 19
Hope it Helps :-)

the simple way to remove
new java.text.DecimalFormat("#").format(value)

The solution is by using DecimalFormat class. This class provides a lot of functionality to format a number.
To get a double value as string with no decimals use the code below.
DecimalFormat decimalFormat = new DecimalFormat(".");
decimalFormat.setGroupingUsed(false);
decimalFormat.setDecimalSeparatorAlwaysShown(false);
String year = decimalFormat.format(32024.2345D);

With a cast. You're basically telling the compiler "I know that I'll lose information with this, but it's okay". And then you convert the casted integer into a string to display it.
String newValue = ((int) percentageValue).toString();

You can use DecimalFormat, but please also note that it is not a good idea to use double in these situations, rather use BigDecimal

String truncatedValue = String.format("%f", percentageValue).split("\\.")[0]; solves the purpose
The problem is two fold-
To retain the integral (mathematical integer) part of the double. Hence can't typecast (int) percentageValue
Truncate (and not round) the decimal part. Hence can't use String.format("%.0f", percentageValue) or new java.text.DecimalFormat("#").format(percentageValue) as both of these round the decimal part.

Type casting to integer may create problem but even long type can not hold every bit of double after narrowing down to decimal places. If you know your values will never exceed Long.MAX_VALUE value, this might be a clean solution.
So use the following with the above known risk.
double mValue = 1234567890.123456;
long mStrippedValue = new Double(mValue).longValue();

Alternatively, you can use the method int integerValue = (int)Math.round(double a);

Double i = Double.parseDouble("String with double value");
Log.i(tag, "display double " + i);
try {
NumberFormat nf = NumberFormat.getInstance();
nf.setMaximumFractionDigits(0); // set as you need
String myStringmax = nf.format(i);
String result = myStringmax.replaceAll("[-+.^:,]", "");
Double i = Double.parseDouble(result);
int max = Integer.parseInt(result);
} catch (Exception e) {
System.out.println("ex=" + e);
}

declare a double value and convert to long convert to string and formated to float the double value finally replace all the value like 123456789,0000 to 123456789
Double value = double value ;
Long longValue = value.longValue();
String strCellValue1 = new String(longValue.toString().format("%f",value).replaceAll("\\,?0*$", ""));

public class RemoveDecimalPoint{
public static void main(String []args){
System.out.println(""+ removePoint(250022005.60));
}
public static String removePoint(double number) {
long x = (long) number;
return x+"";
}
}

This should do the trick.
System.out.println(percentageValue.split("\\.")[0]);

Try:
String newValue = String.format("%d", (int)d);

How can I use parseInt for a double?

My program receives some input (a String). It is rather possible that the input is in the form of a double, like "1.5". But I would like to convert it to an integer, so I can end up with just a 1.
First, I tried this:
Integer.parseInt(someString);
But it doesn't work - I'm assuming it is because of the dot . that it can't parse it.
So I thought that maybe the Integer class can create an integer from a double. So I decided to create a double and then make it an int, like this:
Integer.parseInt(Double.parseDouble(someString));
But apparently there is
no suitable method found for parseInt(double)
So, what do you suggest? Are there one-liners for this? I thought about making a method that removes the dot and all characters after it... but that doesn't sound very cool.

It is safe to parse any numbers as double, then convert it to another type after. Like this:
// someString = "1.5";
double val = Double.parseDouble(someString); // -> val = 1.5;
int intVal = (int) Math.floor(val); // -> intVal = 1;
Note that with Java 7 (not tested with earlier JVM, but I think it should work too), this will also yield the same result as above :
int intVal = (int) Double.parseDouble(someString);
as converting from a floating value to an int will drop any decimal without rounding.

use casting.
double val = Double.parseDouble(someString);
int intVal = (int) Math.floor(val);

You've got the Double, I assume, with Double.parseDouble. So just use:
int i = (int) Double.parseDouble(someString);

Try,
int no= new Double(string).intValue();

Try this:
1) Parse the string as double
2) cast from double to int
public static void main(String[] args) {
String str = "123.32";
int i = (int) Math.floor(Double.parseDouble(str));
System.out.println(i);
}

How to use Java's DecimalFormat for "smart" currency formatting?

I'd like to use Java's DecimalFormat to format doubles like so:
#1 - 100 -> $100
#2 - 100.5 -> $100.50
#3 - 100.41 -> $100.41
The best I can come up with so far is:
new DecimalFormat("'$'0.##");
But this doesn't work for case #2, and instead outputs "$100.5"
Edit:
A lot of these answers are only considering cases #2 and #3 and not realizing that their solution will cause #1 to format 100 as "$100.00" instead of just "$100".

Does it have to use DecimalFormat?
If not, it looks like the following should work:
String currencyString = NumberFormat.getCurrencyInstance().format(currencyNumber);
//Handle the weird exception of formatting whole dollar amounts with no decimal
currencyString = currencyString.replaceAll("\\.00", "");

Use NumberFormat:
NumberFormat n = NumberFormat.getCurrencyInstance(Locale.US);
double doublePayment = 100.13;
String s = n.format(doublePayment);
System.out.println(s);
Also, don't use doubles to represent exact values. If you're using currency values in something like a Monte Carlo method (where the values aren't exact anyways), double is preferred.
See also: Write Java programs to calculate and format currency

Try
new DecimalFormat("'$'0.00");
Edit:
I Tried
DecimalFormat d = new DecimalFormat("'$'0.00");
System.out.println(d.format(100));
System.out.println(d.format(100.5));
System.out.println(d.format(100.41));
and got
$100.00
$100.50
$100.41

Try using
DecimalFormat.setMinimumFractionDigits(2);
DecimalFormat.setMaximumFractionDigits(2);

You can check "is number whole or not" and choose needed number format.
public class test {
public static void main(String[] args){
System.out.println(function(100d));
System.out.println(function(100.5d));
System.out.println(function(100.42d));
}
public static String function(Double doubleValue){
boolean isWholeNumber=(doubleValue == Math.round(doubleValue));
DecimalFormatSymbols formatSymbols = new DecimalFormatSymbols(Locale.GERMAN);
formatSymbols.setDecimalSeparator('.');
String pattern= isWholeNumber ? "#.##" : "#.00";
DecimalFormat df = new DecimalFormat(pattern, formatSymbols);
return df.format(doubleValue);
}
}
will give exactly what you want:
100
100.50
100.42

You can use the following format:
DecimalFormat dformat = new DecimalFormat("$#.##");

I know its too late. However following worked for me :
DecimalFormatSymbols otherSymbols = new DecimalFormatSymbols(Locale.UK);
new DecimalFormat("\u00A4#######0.00",otherSymbols).format(totalSale);
\u00A4 : acts as a placeholder for currency symbol
#######0.00 : acts as a placeholder pattern for actual number with 2 decimal
places precision.
Hope this helps whoever reads this in future :)

You can try by using two different DecimalFormat objects based on the condition as follows:
double d=100;
double d2=100.5;
double d3=100.41;
DecimalFormat df=new DecimalFormat("'$'0.00");
if(d%1==0){ // this is to check a whole number
DecimalFormat df2=new DecimalFormat("'$'");
System.out.println(df2.format(d));
}
System.out.println(df.format(d2));
System.out.println(df.format(d3));
Output:-
$100
$100.50
$100.41

You could use the Java Money API to achieve this. (although this is not using DecialFormat)
long amountInCents = ...;
double amountInEuro = amountInCents / 100.00;
String customPattern;
if (minimumOrderValueInCents % 100 == 0) {
customPattern = "# ¤";
} else {
customPattern = "#.## ¤";
}
Money minDeliveryAmount = Money.of(amountInEuro, "EUR");
MonetaryAmountFormat formatter = MonetaryFormats.getAmountFormat(AmountFormatQueryBuilder.of(Locale.GERMANY)
.set(CurrencyStyle.SYMBOL)
.set("pattern", customPattern)
.build());
System.out.println(minDeliveryAmount);

printf also works.
Example:
double anyNumber = 100;
printf("The value is %4.2f ", anyNumber);
Output:
The value is 100.00
4.2 means force the number to have two digits after the decimal. The 4 controls how many digits to the right of the decimal.

How to Java String.format with a variable precision?

I'd like to vary the precision of a double representation in a string I'm formatting based on user input. Right now I'm trying something like:
String foo = String.format("%.*f\n", precision, my_double);
however I receive a java.util.UnknownFormatConversionException. My inspiration for this approach was C printf and this resource (section 1.3.1).
Do I have a simple syntax error somewhere, does Java support this case, or is there a better approach?
Edit:
I suppose I could do something like:
String foo = String.format("%." + precision + "f\n", my_double);
but I'd still be interested in native support for such an operation.

You sort of answered your own question - build your format string dynamically... valid format strings follow the conventions outlined here: http://java.sun.com/j2se/1.5.0/docs/api/java/util/Formatter.html#syntax.
If you want a formatted decimal that occupies 8 total characters (including the decimal point) and you wanted 4 digits after the decimal point, your format string should look like "%8.4f"...
To my knowledge there is no "native support" in Java beyond format strings being flexible.

You can use the DecimalFormat class.
double d1 = 3.14159;
double d2 = 1.235;
DecimalFormat df = new DecimalFormat("#.##");
double roundedD1 = df.format(d); // 3.14
double roundedD2 = df.format(d); // 1.24
If you want to set the precision at run time call:
df.setMaximumFractionDigits(precision)

Why not :
String form = "%."+precision+"f\n";
String foo = String.format(form, my_double);
or :
public static String myFormat(String src, int precision, Object args...)
{
String form = "%."+precision+"f\n";
return String.format(form, args);
}

double pi = Math.PI; // 3.141592653589793
int n = 5;
DecimalFormat df = new DecimalFormat();
df.setMaximumFractionDigits(n);
System.out.printf(df.format(pi)); // 3.14159
You can set value of n at runtime. Here from the above code given n = 5 will print 3.14159

How to convert a string 3.0103E-7 to 0.00000030103 in Java?

How to convert a string 0E-11 to 0.00000000000 in Java? I want to display the number in non scientific notations. I've tried looking at the number formatter in Java, however I need to specific the exact number of decimals I want but I will not always know. I simply want the number of decimal places as specificed by my original number.

Apparently the correct answer is to user BigDecimal and retrieve the precision and scale numbers. Then use those numbers in the Formatter. Something similar like this:
BigDecimal bg = new BigDecimal(rs.getString(i));
Formatter fmt = new Formatter();
fmt.format("%." + bg.scale() + "f", bg);
buf.append( fmt);

Using BigDecimal:
public static String removeScientificNotation(String value)
{
return new BigDecimal(value).toPlainString();
}
public static void main(String[] arguments) throws Exception
{
System.out.println(removeScientificNotation("3.0103E-7"));
}
Prints:
0.00000030103

I would use BigDecimal.Pass your string into it as a parameter and then use String.format to represent your newly created BigDecimal without scientific notation.
Float or Double classes can be used too.

double d = Double.parseDouble("7.399999999999985E-5");
NumberFormat formatter = new DecimalFormat("###.#####");
String f = formatter.format(d);
System.out.println(f); // output --> 0.00007

I haven't tried it, but java.text.NumberFormat might do what you want.