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ParseException when parsing 3 character abbreviated month using SimpleDateFormat

Here is my code,
SimpleDateFormat format = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
Date dft = (Date) format.parse("16-MAY-2018 09:30:22:000");
I am getting below exception
java.text.ParseException: Unparseable date: "16-MAY-2018 09:30:22"
What's to be used to parse milliseconds?

The pattern should be MMM because there are three characters in the month.
You should also prefer java.time classes to the ones you're currently using if you're on Java 8 or above:
DateTimeFormatter formatter = new DateTimeFormatterBuilder()
.appendPattern("dd-MMM-yyyy")
.appendLiteral(' ')
.append(ISO_LOCAL_TIME)
.toFormatter();
LocalDateTime timestamp = LocalDateTime.parse("16-May-2018 09:30:22", formatter);

Use this pattern: dd-MMM-yyyy HH:mm:ss

Date dft = (Date) format.parse("16-05-2018 09:30:22");
OR change it to
SimpleDateFormat format = new SimpleDateFormat("dd-MMM-yyyy HH:mm:ss");

you are using dd-MM-yyyy HH:mm:ss, so parsable is
16-05-2018 09:30:22
and if you want 16-MAY-2018 09:30:22 then use
dd-MMM-yyyy HH:mm:ss

"16-MAY-2018 09:30:22" is not parsable with that time format. If you want to parse that you have to change date format to "dd-MMM-yyyy HH:mm:ss". The double M is only for numbered months (so should be 05 for May).
Check the SimpleDateFormat javadoc for more details: here

Unable to parse this date

I am getting dates in this format 14-MAY-13 01.17.16.250000 PM and
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd-MMM-yy hh:mm:ss aaa");
simpleDateFormat.parse("14-MAY-13 01.17.16.250000 PM")
Gives me this exception
java.text.ParseException: Unparseable date: "14-MAY-13 01.17.16.250000 PM" ..What should be format of simpledateformat?

Try
new SimpleDateFormat("dd-MMM-yy hh.mm.ss.SSSSSS aaa");

The format must be corrected (see the javadoc for more information). You should also set the Locale to the SimpleDateFormat to be sure the month will be parsed with the correct language.
new SimpleDateFormat("dd-MMM-yy hh.mm.ss.SSSSSS aaa", Locale.US);
If you don't give the Locale, SimpleDateFormat will use the default locale of your system which can be not the locale of the given string input.

You need to use the SSSSSS for milliseconds and replace : with . to match this part 01.17.16.250000.
SimpleDateFormat simpleDateFormat =
new SimpleDateFormat("dd-MMM-yy hh.mm.ss.SSSSSS aaa");

In your Formatstring you expect hh:mm:ss but in your input string your have hh.mm.ss and you also didn't include the miliseconds.
So the format string should be dd-MMM-yy hh.mm.ss.SSSSSS aaa

Simple date format and date formate should be same, try this
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd-MMM-yy hh:mm:ss:SSSSSS aaa");
Date d = simpleDateFormat.parse("14-MAY-13 01:17:16:250000 PM");

the exception with parsing a date YYYY-MM-DD HH:mm:ss

I try to parse a date in the format YYYY-MM-DD HH:mm:ss
String now = "2012-11-02 12:02:00";
DateFormat formatter;
formatter = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy");
Date date_temp = (Date) formatter.parse(now.toString());
System.out.println("output: " + date_temp);
It gives me following exception
java.text.ParseException: Unparseable date: "2012-11-02 12:02:00"

Well yes, you've created a formatted with one format ("EEE MMM dd HH:mm:ss z yyyy") and then given it a string in a completely different format to parse. Why did you think that would work? Try this:
// Locale specified to avoid any cultural differences. You may also
// want to specify the time zone.
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss",
Locale.US);
Date date = formatter.parse(now);
Note that the parsed Date does not know anything about formatting - the result of calling toString() (as you're doing implicitly here) is always just the default format, in the JRE default time zone. If you want to print it out with a particular format, use SimpleDateFormat again.
Also note that I've combined declaration and initialization for the variable. Prefer that over declaring a variable in one line and giving it an initial value later.

Of course your date string is not in the format you are using in SimpleDateFormat. So it won't be able to parse it into a date object.
Try using this: -
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

Issue i am facing with dateFormat.parse(string)?

I have below code snippet
SimpleDateFormat dateFormat = new SimpleDateFormat(
"yyyy-MM-dd hh:mm:ss.SSS");
String processedContentDate="2012-04-10 12:53:28.033";
java.util.Date parsedDate = dateFormat.parse(processedContentDate);
java.sql.Timestamp timestamp = new java.sql.Timestamp(
parsedDate.getTime());
I get parsed date as Tue Apr 10 00:53:28 IST 2012 and timestamp as 2012-04-10 00:53:28.033 . i want to get the time exactly as 12:53:28.033(as in my original string)
not 00:53:28.033. Not getting why 12:53:28 is getting converted to 00:53:28. what should I do to get 12:53:28?
EDIT: After getting the response, I tried this small programme where current time is 14:34:38.899
but at both lines i.e at line 1 and line 2, I got below parsed date
2012-04-10 14:34:38.899
As per reply I should have got 02:34:38.899 at line 1 as date format is yyyy-MM-dd hh:mm:ss.SSS")
java.util.Date date= new java.util.Date();
String strDate=date.toString();
java.util.Date parsedDate;
java.util.Date parsedDate2;
SimpleDateFormat dateFormat = new SimpleDateFormat(
"yyyy-MM-dd hh:mm:ss.SSS");// line 1
SimpleDateFormat dateFormat2 = new SimpleDateFormat(
"yyyy-MM-dd HH:mm:ss.SSS");//line 2
try {
java.sql.Timestamp timestamp = new java.sql.Timestamp(date.getTime());
strDate=timestamp.toString();
parsedDate = dateFormat.parse(strDate);//line1
parsedDate2 = dateFormat2.parse(strDate);//line2

Define your dateFormat like that
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
HH instead of hh. See SimpleDateFormat

Your date format must be yyyy-MM-dd HH:mm:ss.SSS.
hh is hours in am/pm, while HH is hours in a day (that's where you mistake is). See SimpleDateFormat.

As per definition of Date.toString() and Timestamp.toString, the .toString() output is always using a 24-hour clock. If you want to show the time using AM/PM, you should use the dateformatter to print the date. As you are using the same date/time as a source for both (strDate will use 14:34), when you parse the date, the SimpleDateFormat using the 12-hour clock is "lenient" and allows parsing of 14 as an hour.
If you set
dateFormat.setLenient(false);
you'll probably find that the dateFormat.parse(strDate) will fail.
To print dates, I would never rely on toString, but always use a formatter.
System.out.println(dateFormat.format(parsedDate)); // should show ...02:36...
System.out.println(dateFormat2.format(parsedDate)); // should show ...14:36...
System.out.println(dateFormat.format(parsedDate2)); // should show ...02:36...
System.out.println(dateFormat2.format(parsedDate2)); // should show ...14:36...

Try below code:
SimpleDateFormat fmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date date = fmt.parse("yourdate");
SimpleDateFormat fmtOut = new SimpleDateFormat("dd-MM-yyyy hh:mm a");String myDate = fmtOut.format(date);
If yourdate is 2016-06-10 12:06:43, then output will be 10-06-2016 12:06 pm.

Java - Date constructor accepts a Date String, But deprecated. Tried alternatives, but no luck

String temp_date="07/28/2011 11:06:37 AM";
Date date = new Date(temp_date); //Depricated
SimpleDateFormat sdf = new SimpleDateFormat("MMM-dd-yyyy hh:mm:ss");
String comp_date= sdf.format(date);
System.out.println(comp_date);
This works, But If I use something like this
String temp_date="07/28/2011 11:06:37 AM";
try{
SimpleDateFormat sdf = new SimpleDateFormat("MMM-dd-yyyy hh:mm:ss");
Date comp_date= sdf.parse(temp_date);
System.out.println(comp_date);
}catch(Exception e){
System.out.println(e);
}
This exception is thrown:
java.text.ParseException: Unparseable date: "07/28/2011 11:06:37 AM"

Your parsing pattern is wrong. It does not match the date string representation. The MMM denotes a 3-letter localized month abbreviation, while you have 2-digit month number in your actual date, you need MM. You've also slashes / as date/month/year separator and not -. For the AM/PM marker you also need an a afterwards so that the right hh can be parsed.
This should work:
SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy hh:mm:ss a");
For an explanation of those patterns, read the SimpleDateFormat javadoc.
I believe that your concrete functional requirement is to convert the given date string as specified by the pattern MM/dd/yyyy hh:mm:ss a into another date string format, as specified by the pattern MMM-dd-yyyy hh:mm:ss. In that case, you should then have two SimpleDateFormat instances, one which parses the string in the given pattern to a Date and another which formats the parsed Date to the given pattern. This should do what you want:
String inputDate = "07/28/2011 11:06:37 AM";
Date date = new SimpleDateFormat("MM/dd/yyyy hh:mm:ss a").parse(inputDate);
String outputDate = new SimpleDateFormat("MMM-dd-yyyy HH:mm:ss").format(date);
System.out.println(outputDate); // Jul-28-2011 11:06:37
Note that I changed hh in output to be HH because it would otherwise end up in 1-12 hour representation without an AM/PM marker. The HH represents it as 0-23 hour.

The format you gave the SimpleDateFormat uses - between the month, date, and year. Your string uses slashes.

At first look, it looks as if your format string is wrong.
MMM -- You specified this for the month, but you aren't passing a 3 char month.
Try MM and see if that helps.
Take a look at this for some additional date format information:
http://www.java2s.com/Tutorial/Java/0040__Data-Type/SimpleDateFormat.htm