I try to parse a date in the format YYYY-MM-DD HH:mm:ss
String now = "2012-11-02 12:02:00";
DateFormat formatter;
formatter = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy");
Date date_temp = (Date) formatter.parse(now.toString());
System.out.println("output: " + date_temp);
It gives me following exception
java.text.ParseException: Unparseable date: "2012-11-02 12:02:00"
Well yes, you've created a formatted with one format ("EEE MMM dd HH:mm:ss z yyyy") and then given it a string in a completely different format to parse. Why did you think that would work? Try this:
// Locale specified to avoid any cultural differences. You may also
// want to specify the time zone.
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss",
Locale.US);
Date date = formatter.parse(now);
Note that the parsed Date does not know anything about formatting - the result of calling toString() (as you're doing implicitly here) is always just the default format, in the JRE default time zone. If you want to print it out with a particular format, use SimpleDateFormat again.
Also note that I've combined declaration and initialization for the variable. Prefer that over declaring a variable in one line and giving it an initial value later.
Of course your date string is not in the format you are using in SimpleDateFormat. So it won't be able to parse it into a date object.
Try using this: -
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Related
Here is my code,
SimpleDateFormat format = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
Date dft = (Date) format.parse("16-MAY-2018 09:30:22:000");
I am getting below exception
java.text.ParseException: Unparseable date: "16-MAY-2018 09:30:22"
What's to be used to parse milliseconds?
The pattern should be MMM because there are three characters in the month.
You should also prefer java.time classes to the ones you're currently using if you're on Java 8 or above:
DateTimeFormatter formatter = new DateTimeFormatterBuilder()
.appendPattern("dd-MMM-yyyy")
.appendLiteral(' ')
.append(ISO_LOCAL_TIME)
.toFormatter();
LocalDateTime timestamp = LocalDateTime.parse("16-May-2018 09:30:22", formatter);
Use this pattern: dd-MMM-yyyy HH:mm:ss
Date dft = (Date) format.parse("16-05-2018 09:30:22");
OR change it to
SimpleDateFormat format = new SimpleDateFormat("dd-MMM-yyyy HH:mm:ss");
you are using dd-MM-yyyy HH:mm:ss, so parsable is
16-05-2018 09:30:22
and if you want 16-MAY-2018 09:30:22 then use
dd-MMM-yyyy HH:mm:ss
"16-MAY-2018 09:30:22" is not parsable with that time format. If you want to parse that you have to change date format to "dd-MMM-yyyy HH:mm:ss". The double M is only for numbered months (so should be 05 for May).
Check the SimpleDateFormat javadoc for more details: here
I am developing a Web application into GWT and I am using the Object DatePicker. This object retrieves the date in a defined format which I am translating into a String such as:
Wed May 14 2014 00:00
For me it is useful to use this date as String for some operations. However, for one of them I need the Timestamp object. For that reason, I am making use of the SimpleDateFormat object in the following way:
SimpleDateFormat sdf = new SimpleDateFormat("E MMM dd yyyy HH:mm");
Timestamp tDateIni = new Timestamp(sdf.parse(sDateIni).getTime());
Yet, when I run the remote debug I get a ParseException. Do you know what could the mistake be? I think I am using in a bad format the SimpleDateFormat object in the part "E MMM", but I am not sure. Thanks a lot in advance!
If you want to parse the date at client side in GWT then try with DateTimeFormat
DateTimeFormat dateTimeFormat=DateTimeFormat.getFormat("E MMM dd yyyy HH:mm");
Date date=dateTimeFormat.parse("Wed May 14 2014 00:00");
If you want to parse the date at server side then pass the time in milliseconds as long value instead of date string from client side and form the date back at server side using new Date(timeInMills)
Your date format uses the day of the week format that requires "EEE" instead of "E". This is causing the exception when the program is trying to read in your date string. It is expecting one letter for the day of the week.
http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html
Change this from
SimpleDateFormat sdf = new SimpleDateFormat("E MMM dd yyyy HH:mm");
to
SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd yyyy HH:mm");
It should be EEE instead of E to represent Weekdays like Wed
Below code, perfectly works (TESTED)
public static void main(String[] args) {
String s = "Wed May 14 2014 00:00";
SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd yyyy HH:mm");
try {
Timestamp tDateIni = new Timestamp(sdf.parse(s).getTime());
System.out.println(tDateIni.getTime());
} catch (ParseException ex) {
System.out.println("Parse Error");
}
}
I have added the Locale object in the SimpleDateFormat object and now it works. Thank you for all your help and your comments!!!
can anyone help me with converting DATETIME funtction in Java.
I retrieve the date time format from SMS headers in this format "Fri May 18 09:22:39 FJT 2012" .I want to convert it to this format "2012-05-18 09:51:42.39".Can anyone help.
Use a SimpleDateFormat for that purpose. Although I am not sure that the timezone "FJT" is known in Java. So you will maybe have to do some tricks for that.
As #Guillaume suggested, use SimpleDateFormat. Here's an example:
public String convert() throws ParseException {
SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy");
Date output = format.parse("Fri May 18 09:22:39 FJT 2012");
Calendar outputCal = Calendar.getInstance(format.getTimeZone());
outputCal.setTime(output);
return String.format("%04d-%02d-%02d %02d:%02d:%02d",outputCal.get(Calendar.YEAR), outputCal.get(Calendar.MONTH)+1, outputCal.get(Calendar.DAY_OF_MONTH), outputCal.get(Calendar.HOUR_OF_DAY), outputCal.get(Calendar.MINUTE), outputCal.get(Calendar.SECOND));
}
Everything is hardcoded - you have to add parameters as necessary
import java.text.SimpleDateFormat;
...
String d = "Fri May 18 09:22:39 FJT 2012";
SimpleDateFormat inputFormat = new SimpleDateFormat("EEE MMM d HH:mm:ss ZZZ yyyy");
SimpleDateFormat outputFormat = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss.SS");
outputFormat.setTimeZone(TimeZone.getTimeZone("GMT")); // set yr time zone for output
Date date = inputFormat.parse(d);
System.out.println(outputFormat.format(date));
My first attempt was:
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z");
Date date = formatter.parse(string);
It throws ParseException, so I found this hack:
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z");
TimeZone timeZone = TimeZone.getTimeZone("Etc/GMT");
formatter.setTimeZone(timeZone);
Date date = formatter.parse(string);
It did not work either, and now I'm stuck. It parses without problems if I just change the timezone to "GMT".
edit: An example string to parse would be "2011-11-29 10:40:24 Etc/GMT"
edit2: I would prefer not to remove timezone information completely. I am coding a server that receives the date from an external user, so perhaps other dates will have other timezones.
To be more precise: This specific date I receive is from the receipt from the apple server after making an in app purchase on an iphone app, but I could also receive dates from other sources.
Don't know if this question is still relevant to you, but if you use Joda time, this'll work:
DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss ZZZ").parseDateTime(s)
Without Joda time the following will work (bit more work though):
String s = "2011-11-29 10:40:24 Etc/GMT";
// split the input in a date and a timezone part
int lastSpaceIndex = s.lastIndexOf(' ');
String dateString = s.substring(0, lastSpaceIndex);
String timeZoneString = s.substring(lastSpaceIndex + 1);
// convert the timezone to an actual TimeZone object
// and feed that to the formatter
TimeZone zone = TimeZone.getTimeZone(timeZoneString);
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
formatter.setTimeZone(zone);
// parse the timezoneless part
Date date = formatter.parse(dateString);
It didn't work for me either the thing is I tried setting TimeZone of SimpleDateFormatter to "Etc/GMT" and then formatted a new date here is the output:
2011-11-30 10:46:32 GMT+00:00
So Etc/GMT is being translated as GMT+00:00
If you really want to stick to parse "2011-09-02 10:26:35 Etc/GMT" then following will help too without even considering explicit Timezone change:
java.text.SimpleDateFormat isoFormat = new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss 'Etc/GMT'");
isoFormat.parse("2010-05-23 09:01:02 Etc/GMT");
Works fine.
Following code is working for me
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
sdf.setTimeZone(TimeZone.getTimeZone("Etc/GMT"));
try { System.out.println( sdf.parse("2011-09-02 10:26:35 Etc/GMT") );
} catch (ParseException e){
e.printStackTrace();
}
Few questions:
How can I print now (The current Date/Time) in the format below.
How can I convert a string date, into a date object if I know the format, same format as below.
Example:
2011-05-04 19:12:46 -0500
Format:
YYYY-MM-DD HH:MM:SS [+|-]hh[mm]
Try:
Date yourDate = new Date(...);
SimpleDateFormat myDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss Z");
System.out.print(myDateFormat.format(yourDate);
The link to SimpleDateFormat Javadoc is here.
Check out SimpleDateFormat: http://download.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html
SimpleDateFormat.format() and SimpleDateFormat.parse()