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Unable to capture next line character in Java

I have a requirement of parsing through an python file which contains multiple sql queries and get the start and end positions of the query to get only the query part using JAVA
I am using .contains function to check for sql(''' as my opening character for the query and now for the closing character I have ''') but there are some cases where ''') comes in between the query when there is a variable involved which should not be detected as an end of the query.
Something like this :
spark.sql(''' SELECT .......
FROM.....
WHERE xxx IN ('''+ Variable +''')
''')
here the last but one line also gets detected as end of line if I use line.contains(" ''') ") which is wrong.
All I can think of is to check for next line character as the end of the query as each query is separated by two empty lines. So tried these if (line.contains(" ''')\n") & if (line.contains(" ''')\r\n") but none of them work for me.
Kindly let me know of any other way to do this.
Note that I do not have the privilege to change the query file.
Thanks

I believe simple contains won't solve this problem.
You will have to use Pattern if you are looking to match \n.
String query = "spark.sql(''' SELECT .......\n" +
"FROM..... \n" +
"WHERE xxx IN ('''+ Variable +''')\n" +
"''')";
Pattern pattern = Pattern.compile("^spark.sql\\('''(.*)'''\\)$", Pattern.DOTALL);
System.out.println(pattern.matcher(query).find());
Output:
true
Pattern.DOTALL tells Java to allow the dot to match newline characters, too.

Using trim() but still didn't get expected output

Ok,i am developing spring MVC based web application, application shows data is list, and i also facilitate filter options to enhanced search functionality, I also remove extra space by using trim(), but what happening now, when user input data in text field and enter the corresponding result will be displayed into the list, but if space added after input, the result will be "NOT FOUND" even i handle the space in javascript too
Java Code which fetches data from database
if (searchParamDTO.getRegNO().trim() != null && !searchParamDTO.getRegNO().trim().equals("") && !searchParamDTO.getRegNO().trim().equals("null")) {
query += " AND UR.REG_UNIQUE_ID = :REG_UNIQUE_ID ";
param.addValue("REG_UNIQUE_ID", searchParamDTO.getRegNO());
}
JavaScript Code: fetches the value in behalf of id
function setSearchParameters() {
regNo = $('#regNo').val().trim();}
i also attached two screenshot with spaces and without spaces
Without space
With space

As #Greg H said you're trimming the string when checking if it's blank, but then adding the raw string to the query which will include any trailing spaces.
Then, this line param.addValue("REG_UNIQUE_ID", searchParamDTO.getRegNO()); should be replaced by param.addValue("REG_UNIQUE_ID", searchParamDTO.getRegNO().trim());

Java Special character encoding issue

I tried to insert some special character via java into oracle table and then retrieve it again--assuming my encoding will work.
Below is the code which i tried.
String s=new String("yesterday"+"\u2019"+"s");
...
statement.executeUpdate("INSERT into test1 values ('"+s+"')");
ResultSet rs=statement.executeQuery("select * from test1");
while (rs.next()) {
System.out.println(new String(rs.getString(1).getBytes("UTF-8"),"UTF-8"));
}
...
Now, when I try to see output via commandline execution it displays special character always: yesterday’s
My question is: why even after using encoding, it is not showing expected result. i.e. yesterday’s. Is above mentioned code is not correct or some modification is required?
P.S.: In eclipse, the code might result yesterday’s, but if executed via command line , it shows yesterday’s
I am using :
-- JDK1.6
-- Oracle : 11.1.0.6.0
-- NLS_Database_Parameters: NLS_CHARACTERSET WE8MSWIN1252
--Windows
Edit:
\u2019 : this is RIGHT SINGLE QUOTATION MARK & I am looking for this character only.

Check the java property "file.encoding" when you run on the commandline, it may be set to something other than "UTF-8" causing the text to display incorrectly when you output on the commandline.

Here is an illustration of what I suggested in a comment (change the character set of your client). Straight from my SQL*Plus:
SQL> select unistr('\2019') from dual;
U
-
Æ
SQL> $chcp 1252
Active code page: 1252
SQL> select unistr('\2019') from dual;
U
-
’
If this works for you, you may want to add $chcp 1252 to your [g]login.sql.

The problem is that the character encoding for the apostrophe is \u0027
I ran this in the command line:
public class Yesterday{
public static void main(String[] args) {
String s = new String("yesterday" + "\u0027" +"s");
System.out.println(s);
}
}
it resulted in:
yesterday's

Croatian character in Java standard output

I have a database with some cratian characters in it like Đ , in the database the character is stored correctly, when using a datatable in primefaces it also shows the character in the webpage just fine.
The problem is that when I send it to the out.println() the character Đ in the name is missing.
for (People p : people) {
System.out.println("p.getName());
}
I tried using String name2 = p.getName().getBytes("ISO-8859-2"); but it still not working

I assume you are using UTF-8 as default encoding on the Database and for Primefaces
Have also a look to this:
Display special characters using System.out.println

How to distinguish in quotes delimiter vs out of quotes delimiter

I have a txt file that contains the following
SELECT TOP 20 personid AS "testQu;otes"
FROM myTable
WHERE lname LIKE '%pi%' OR lname LIKE '%m;i%';
SELECT TOP 10 personid AS "testQu;otes"
FROM myTable2
WHERE lname LIKE '%ti%' OR lname LIKE '%h;i%';
............
The above query can be any legit SQl statement (on one or multiple lines , i.e. any way user wishes to type in )
I need to split this txt and put into an array
File file ... blah blah blah
..........................
String myArray [] = text.split(";");
But this does not work properly because it take into account ALL ; . I need to ignore those ; that are within ";" AND ';'. For example ; in here '%h;i%' does not count because it is inside ''. How can I split correctly ?

Assuming that each ; you want to split on is at the end of line you can try to split on each ; + line separator after it like
text.split(";"+System.lineSeparator())
If your file has other line separators then default ones you can try with
text.split(";\n")
text.split(";\r\n")
text.split(";\r")
BTW if you want to include ; in split result (if you don't want to get rid of it) you can use look-behind mechanism like
text.split("(?<=;)"+System.lineSeparator())
In case you are dynamically reading file line-by-line just check if line.endsWith(";").

I see a 'new line' after your ';' - It is generalizable to the whole text file ?
If you must/want use regular expression you could split with a regex of the form
;$
The $ means "end of line", depending of the regex implementation of Java (don't remember).
I will not use regex for this kind of task. Parsing the text and counting the number of ' or " to be able to recognize the reals ";" delimiters is sufficient.