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Finding exact match with equal sign with append function in SQL

sqlQueryString.append(" and upper(username) like upper(:searchString) ");
This code returns data like exampleusername, exampleusername1, exampleusername12...
I want it to return data with an exact match to the username that is being searched.
For example when I put in bobJacobs (an example username), I want it to return only bobJacobs records, not other records that may contain bobJacobs in them, for example samandbobJacobs24, bobJacobs23, etc.
I've tried:
sqlQueryString.append(" and upper(username) = upper(:searchString) ");
But it doesn't work. Any solutions?

JPA Select query not returning results with one letter word

I have a query that when given a word that starts with a one-letter word followed by space character and then another word (ex: "T Distribution"), does not return results. While given "Distribution" alone returns results including the results for "T Distribution". It is the same behavior with all search terms beginning with a one-letter word followed by space character and then another word.
The problem appears when the search term is of this pattern:
"[one-letter][space][letter/word]". example: "o ring".
What would be the problem that the LIKE operator not working correctly in this case?
Here is my query:
#Cacheable(value = "filteredConcept")
#Query("SELECT NEW sina.backend.data.model.ConceptSummaryVer04(s.id, s.arabicGloss, s.englishGloss, s.example, s.dataSourceId,
s.synsetFrequnecy, s.arabicWordsCache, s.englishWordsCache, s.superId, s.categoryId, s.dataSourceCacheAr, s.dataSourceCacheEn,
s.superTypeCasheAr, s.superTypeCasheEn, s.area, s.era, s.rank, s.undiacritizedArabicWordsCache, s.normalizedEnglishWordsCache,
s.isTranslation, s.isGloss, s.arabicSynonymsCount, s.englishSynonymsCount) FROM Concept s
where s.undiacritizedArabicWordsCache LIKE %:searchTerm% AND data_source_id != 200 AND data_source_id != 31")
List<ConceptSummaryVer04> findByArabicWordsCacheAndNotConcept(#Param("searchTerm") String searchTerm, Sort sort);
the result of the query on the database itself:
link to screenshot
results on the database are returned no matter the letters case:
link to screenshot

I solved this problem.
It was due to the default configuration of the Full-text index on mysql database which is by default set to 2 (ft_min_word_len = 2).
I changed that and rebuilt the index. Then, one-letter words were returned by the query.
12.9.6 Fine-Tuning MySQL Full-Text Search

Use some quotes:
LIKE '%:searchTerm%';

Set searchTerm="%your_word%" and use it on query like this :
... s.undiacritizedArabicWordsCache LIKE :searchTerm ...

Using trim() to remove spaces,but still didn't get expected output

Ok,i am developing spring MVC based web application, application shows data is list, and i also facilitate filter options to enhanced search functionality, I also remove extra space by using trim(), but what happening now, when user input data in text field and enter the corresponding result will be displayed into the list, but if space added after input, the result will be "NOT FOUND" even i handle the space in javascript too
Java Code which fetches data from database
if (searchParamDTO.getRegNO().trim() != null && !searchParamDTO.getRegNO().trim().equals("") && !searchParamDTO.getRegNO().trim().equals("null")) {
query += " AND UR.REG_UNIQUE_ID = :REG_UNIQUE_ID ";
param.addValue("REG_UNIQUE_ID", searchParamDTO.getRegNO());
}
JavaScript Code: fetches the value in behalf of id
function setSearchParameters() {
regNo = $('#regNo').val().trim();}
i also attached two screenshot with spaces and without spaces
Without space
With space

I would suggest to trim on server side as well.
It is always better to validate on server side as we can use same serve code for different UI applications And request could be with wrong or tampered data.
String regNo = searchParamDTO.getRegNO().trim();
if (regNo != null && !"".equals(regNo) && !"null".equals(regNo)) {
query += " AND UR.REG_UNIQUE_ID = :REG_UNIQUE_ID ";
param.addValue("REG_UNIQUE_ID", regNo);
}

How to handle special characters like single/double quotes/space inside XPATH JAVA

I'm trying to click on element using below code and its working fine if variable does not have special characters.
Values that passed in variable are:
Product Passed
Test Message -> Failed
Double Units 13/2" -> failed
I cannot go with partial text, because sometimes only difference between two element is special character.
String Answertoselect = ElementName.replaceAll("'", "\\\\'");
String selectanswer = Answertoselect.replaceAll(" ", "${nbsp}");

Java XMLInputFactory - truncates text when reading data with .getData()

I'm using XMLInputFactory to read data (sql queries) from xml file.
In some cases, the data is truncated. For example:
select CASE WHEN count(*) > 0 THEN 'LX1VQMSSRV069 OK' ELSE 'LX1VQMSSRV069 NOK' END from [PIWSLog].[dbo].[log]
is read as (text is truncated after the last '.'):
select CASE WHEN count(*) > 0 THEN 'LX1VQMSSRV069 OK' ELSE 'LX1VQMSSRV069 NOK' END from [PIWSLog].[dbo]
I've tested with several string and it seems that the problem is with the char's in [].[].[]..
I'm readind data using:
mySQLquery = event.asCharacters().getData();
Another situation is if the string has '\n'. Like, if it has two '\n', the event.asCharacters().getData(); reads correctly, but if it has three '\n' it truncates the string after the second '\n'. This is very odd!
Any idea what's the problem and how can I solve it?

The XMLInputFactory API is not obliged to give you all of the characters of a String in one go. It's permitted to pass you a sequence of events, each containing a fragment of the string.
You'll probably find that if you read another event after the one containing the truncated string, you'll find the remainder of your string (possibly after several events).