There are two times such as "startTime" = 23:57 and "endTime" = 00:50. How can I define that startTime belongs to the day that is before "endTime"?
Date min = date("23:57");
Date max = date("00:50");
private static Date date(final String time) {
final Calendar calendar = Calendar.getInstance();
String[] hm = time.split(":");
int hour = Integer.parseInt(hm[0]);
int minute = Integer.parseInt(hm[1]);
calendar.set(Calendar.HOUR,hour);
calendar.set(Calendar.MINUTE,minute);
final Date result = calendar.getTime();
return result;
}
you could append a token of some kind, like + to the end your time:
Date max = date("00:50+");
and when parsing the time:
if time.endsWith("+") {
calendar.add(Calendar.HOUR, 24);
}
if you needed to handle periods of longer than 24 hours you could use +1, +2 etc.
Related
I have a timepicker for a start time and an end time. It's in Sweden so here is 24 hour clock. If I set the start time at 23:00 and the end time at 02:00 it should be 3 hours difference. But in this case its 22 hours.
I calculate the difference lite this:
String a =""+Math.abs(diff/(60*60*1000)%24);
String b =""+Math.abs(diff/(60*1000)%60);
How can this be fixed?
UPDATE
Here is some more code:
DateFormat formatter = new SimpleDateFormat("HH:mm");
Date date1 = formatter.parse(str_time1);
Date date2 = formatter.parse(str_time2);
long diff = date2.getTime() - date1.getTime();
String a =""+Math.abs(diff/(60*60*1000)%24);
String b =""+Math.abs(diff/(60*1000)%60);
UPDATE 2
Here is my timepickerdialog and maybe the error start even here:
final Calendar c = Calendar.getInstance();
mHour = c.get(Calendar.HOUR_OF_DAY);
mMinute = c.get(Calendar.MINUTE);
// Launch Time Picker Dialog
final TimePickerDialog timePickerDialog = new TimePickerDialog(this,
new TimePickerDialog.OnTimeSetListener() {
#Override
public void onTimeSet(TimePicker view, int hourOfDay,
int minute) {
startworkFrom.setText(hourOfDay + ":" + minute);
}
}, mHour, mMinute, true);
timePickerDialog.show();
Here is a solution to the problem I had:
public int theTimeMachineHours(EditText a, EditText b) throws Exception{
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("HH:mm");
Date startDate = simpleDateFormat.parse(a.getText().toString());
Date endDate = simpleDateFormat.parse(b.getText().toString());
long difference = endDate.getTime() - startDate.getTime();
if(difference<0)
{
Date dateMax = simpleDateFormat.parse("24:00");
Date dateMin = simpleDateFormat.parse("00:00");
difference=(dateMax.getTime() -startDate.getTime() )+(endDate.getTime()-dateMin.getTime());
}
int days = (int) (difference / (1000*60*60*24));
int hours = (int) ((difference - (1000*60*60*24*days)) / (1000*60*60));
int min = (int) (difference - (1000*60*60*24*days) - (1000*60*60*hours)) / (1000*60);
return hours;
}
this might help:
result_time = (end_time - start_time +24) % 24;
// +24 to avoid the result from going to negative
where end_time is your ending time i.e 02:00
start_time is starting time i.e 23:00
and % is modulo operator
Try using kk:mm instead HH:mm
So change the code to:
DateFormat formatter = new SimpleDateFormat("kk:mm");
I want to add string time with format HH:mm:ss and special hour field. Example :
"20:15:30" (string) add "13:50:35" (string) -> result i want : "34:06:05" (string).
I have search similar code :
String time1="20:15:30";
String time2="13:50:35";
SimpleDateFormat timeFormat = new SimpleDateFormat("HH:mm:ss");
timeFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
Date date1 = timeFormat.parse(time1);
Date date2 = timeFormat.parse(time2);
long sum = date1.getTime() + date2.getTime();
String date3 = timeFormat.format(new Date(sum));
System.out.println("The sum is "+ date3);
And result of above code : The sum is 10:06:05 not i want. How is easy way to do this ?
You could simply take advantage of either Java 8's or Joda Time's duration capabilities.
For example, this simply creates a duration which is the sum of the number of seconds of the two times
LocalTime lt1 = LocalTime.parse("20:15:30", DateTimeFormatter.ofPattern("HH:mm:ss"));
LocalTime lt2 = LocalTime.parse("13:50:35", DateTimeFormatter.ofPattern("HH:mm:ss"));
//long t = lt1.toSecondOfDay() + lt2.toSecondOfDay();
//Duration duration = Duration.ofSeconds(t);
Duration duration = Duration.between(lt2, lt1);
System.out.println(formatDuration(duration));
Which prints out 34:06:05
formatDuration method
public static String formatDuration(Duration duration) {
long hours = duration.toHours();
duration = duration.minusHours(hours);
long minutes = duration.toMinutes();
duration = duration.minusMinutes(minutes);
long seconds = duration.getSeconds();
return String.format("%02d:%02d:%02d", hours, minutes, seconds);
}
SimpleDateFormat can't do that, but you can do it yourself, by parsing the input with a regular expression, and formatting the output with the format method.
private static String addTime(String ... times) {
if (times.length < 2)
throw new IllegalArgumentException("At least 2 times are required");
Pattern timePattern = Pattern.compile("([0-9]+):([0-5][0-9]):([0-5][0-9])");
// Parse times and sum hours, minutes, and seconds
int hour = 0, minute = 0, second = 0;
for (String time : times) {
Matcher m = timePattern.matcher(time);
if (! m.matches())
throw new IllegalArgumentException("Invalid time: " + time);
hour += Integer.parseInt(m.group(1));
minute += Integer.parseInt(m.group(2));
second += Integer.parseInt(m.group(3));
}
// Handle overflow
minute += second / 60; second %= 60;
hour += minute / 60; minute %= 60;
// Format and return result
return String.format("%02d:%02d:%02d", hour, minute, second);
}
Test
System.out.println(addTime("20:15:30", "13:50:35"));
System.out.println(addTime("20:15:30", "13:50:35", "20:15:30", "13:50:35"));
System.out.println(addTime("98765:43:21", "12:34:56"));
Output
34:06:05
68:12:10
98778:18:17
So i'm trying to get a random time between two set times. But the resulting date is not what I'm expecting.
I'm expecting a result that is within the two dates I give as the earliest and the latest, but I get a date thats on the next day, and it appears as though if I take the time i'm supposed to get and subtract 12 I get this answer.
This is the log get: http://prntscr.com/6205yh
private long nextLong(Random rng, long n) {
long bits, val;
do
{
bits = (rng.nextLong() << 1) >>> 1;
val = bits % n;
} while (bits - val + (n - 1) < 0L);
return val;
}
#SuppressWarnings("deprecation")
public Calendar getNextDate() {
try
{
Calendar now = Calendar.getInstance(Locale.getDefault());
String earliest = getConfig().getString("Date.Spawn Earliest");
String latest = getConfig().getString("Date.Spawn Latest");
// Format the hours and minutes into dates
SimpleDateFormat format = new SimpleDateFormat("HH:mm");
Date earliestDate = format.parse(earliest);
Date latestDate = format.parse(latest);
// Figure out the random time between the two
long e = earliestDate.getTime();
long l = latestDate.getTime();
long d = nextLong(new Random(), l - e) + e;
Date date = new Date(d);
// Update the hours and minutes into a new Calander with todays day,month and year.
Calendar then = Calendar.getInstance(Locale.getDefault());
System.out.println(date.getHours()+":"+date.getMinutes());
then.set(Calendar.HOUR, date.getHours());
then.set(Calendar.MINUTE, date.getMinutes());
// If it is later then the random time and nows hours are still higher then the latest time; add 7 days to get next week
if (now.after(then) && now.getTime().getHours() > latestDate.getHours())
then.add(Calendar.DAY_OF_MONTH, 7);
System.out.println("At the moment it is: " + now.getTime().toString());
System.out.println("Dragon will spawn at: " + then.getTime().toString());
return then;
}
catch (ParseException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
return null;
}
}`
If someone could explain to me whats going on I would be very grateful.
This could be better :)
Date dateStart;
Date dateEnd;
int diff = (int) (dateEnd.getTime() - dateStart.getTime());
Date randomDate = new Date(dateStart.getTime()
+ new Random(System.currentTimeMillis()).nextInt(diff));
Calendar then = Calendar.getInstance();
then.setTime(randomDate);
I'm new to Java
How do I get the total number of months between two (2) jdatechooser? I've search already about this but the date was set to the code, In my case I want to put the dates via JDateChooser.
I can do this through this code but if the year change I was not able to compute the total number of months I want to do this without using JodaTime.
Here is my code
public void month(){
int TotalMonth;
Calendar toDate;
Calendar fromDate;
int increment;
Date dt1 = date1.getDate(); //datechooser 1
Date dt2 = date2.getDate(); //datechooser 2
fromDate = Calendar.getInstance();
toDate = Calendar.getInstance();
if(dt1.after(dt2))
{
fromDate.setTime(dt2);
toDate.setTime(dt1);
}
else
{
fromDate.setTime(dt1);
toDate.setTime(dt2);
}
increment = 0;
TotalMonth = toDate.get(Calendar.MONTH) - (fromDate.get(Calendar.MONTH + increment));
jLabel2.setText(Integer.toString(age));
}
JodaTime is simpler, however...
You need to loop from the start time to the end, incrementing the MONTH field on each loop while the date remains before the end time...
For example...
try {
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
Calendar cal1 = Calendar.getInstance();
cal1.setTime(sdf.parse("08/03/1972"));
Calendar cal2 = Calendar.getInstance();
cal2.setTime(sdf.parse("08/03/2014"));
// Yes, you can use cal1, but I you might want
// to preserve it for other reasons...
Calendar cal3 = Calendar.getInstance();
cal3.setTime(cal1.getTime());
int months = 0;
while (cal3.before(cal2)) {
cal3.add(Calendar.MONTH, 1);
months++;
}
System.out.println("Months = " + months);
} catch (ParseException exp) {
exp.printStackTrace();
}
Prints out Months = 505.
If you change cal2 to 08/04/1972, it will print Months = 1
What I need to do in my Android project is to find all the previous Tuesdays for the last three months and put them into a String Array. It appears that neither the Calendar Class nor SimpleDateFormat would work for this.
So for example, today is Tuesday, so it would start today and I'd need to return 2013_8_13, and next in the array would be 2013_8_6, then 2013_7_30, and so on. Am I wrong about the Calendar Class or SimpleDateFormat? If so, could you give me an idea as to how it could be done?
EDIT: Updated answer to go back to a certain day instead of back a certain number of days. Also changed String array to ArrayList
ArrayList<String> tuesdayArrayList = new ArrayList<String>();
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy_M_d");
Calendar calendar = Calendar.getInstance();
int day = calendar.get(Calendar.DAY_OF_WEEK);
Date date = new Date();
Date cutoffDate;
int cutoffYear = 2013;
int cutoffMonth = Calendar.JUNE;
int cutoffDayOfMonth = 25;
cutoffDate = new GregorianCalendar(cutoffYear, cutoffMonth, cutoffDayOfMonth).getTime();
while (day != Calendar.TUESDAY) {
calendar.add(Calendar.DATE, 1);
day = calendar.get(Calendar.DAY_OF_WEEK);
}
int i = 0;
while (date.after(cutoffDate)) {
calendar.add(Calendar.DATE, -7);
int year = calendar.get(Calendar.YEAR);
int month = calendar.get(Calendar.MONTH);
int dayOfMonth = calendar.get(Calendar.DAY_OF_MONTH);
date = new GregorianCalendar(year, month, dayOfMonth).getTime();
tuesdayArrayList.add(dateFormat.format(date));
Log.d("myTag: ", tuesdayArrayList.get(i));
i++;
}