this is in main method I just Want to sum the numbers available in the text file located in E:\Java_Examples\data.txt.
int sum = 0;
try {
FileReader f1 = new FileReader("E:\\Java_Examples\\data.txt");
BufferedReader s1=new BufferedReader(f1);
String line="";
while(s1.readLine()!=null)
{
line=s1.readLine();
sum+=Integer.parseInt(line);
}
s1.close();
} catch(IOException e)
{
System.out.println("File not found");
}
Can anyone help with this?
It is throwing exception java.lang.NumberFormatException: Cannot parse
null string?Why?
Because you are calling readLine after the stream is empty.
Instead of this...
while(s1.readLine()!=null)
{
line=s1.readLine();
sum+=Integer.parseInt(line);
}
You could do something like this...
while((line = s1.readLine())!=null)
{
sum+=Integer.parseInt(line);
}
This sort of bug, and the large amount of code required for the simple task, happens when you write low-level code instead of using simpler approaches offered by the JDK.
Use Scanner:
int sum = 0;
Scanner scanner = new Scanner(new FileInputStream("E:/Java_Examples/data.txt"));
while (scanner.hasNextLine()) {
String line = scanner.nextLine();
sum += Integer.parseInt(line);
}
Or use Files for a one liner:
int sum = Files.lines(Paths.get("E:/Java_Examples/data.txt"))
.mapToInt(Integer::parseInt)
.sum();
I'm using the following code to read from a file
int lineNumber = 0;
try{
BufferedReader in = new BufferedReader (new FileReader("electric.txt"));
String line = null;
while((line = in.readLine()) != null){
lineNumber++;
system.out.println("Line "+ lineNumber + " : "+ line);
}
} catch(IOException e){
e.printStackTrace();
}
My file have specific values on each line, for exemple first line is int, second string, third boolean etc...
My question is how do I get each data type in a variable?
Basically, in a naive approach, you just do as many reads as you need:
String firstLine = in.readLine();
String secondLine = in.readLine();
...
Then you could do something like:
Whatever dataObject = new Whatever(firstLine, secondLine, ...);
for example (maybe within a loop, as you probably want to read the data for many data objects, not just a single one).
In other words: you read the required attributes in some helper variables, to then push those into the object you want to fill with data. Advantage: this works for very large data, as you only read a few lines at a time. Downside: you have to worry about invalid files, missing lines, and such things (so you need quite a bit of error handling).
Alternatively: simply read the whole file into memory first, for example using List<String> allLines = java.util.Files.readAllLines(somePathToYourFile); Then, you iterate these allLines an further process your content, now without worrying about IOExceptions for example.
If you want to check whether the line is boolean, integer, or String, this is a possible solution. If you need to check that the line is long or short, double or float, etc. You still have to handle those cases.
System.out.println("Line " + lineNumber + " : " + line + ", Datatype: " + typeChecker(line));
public static String typeChecker(String line){
if (line.equals("true")||line.equals("false"))
return "boolean";
else{ if (isInteger(line))
return "int";
}
return "String";
}
public static boolean isInteger(String s) {
try {
Integer.parseInt(s);
} catch(NumberFormatException e) {
return false;
} catch(NullPointerException e) {
return false;
}
return true;
}
In Java, is there any method to read a particular line from a file? For example, read line 32 or any other line number.
For small files:
String line32 = Files.readAllLines(Paths.get("file.txt")).get(32)
For large files:
try (Stream<String> lines = Files.lines(Paths.get("file.txt"))) {
line32 = lines.skip(31).findFirst().get();
}
Unless you have previous knowledge about the lines in the file, there's no way to directly access the 32nd line without reading the 31 previous lines.
That's true for all languages and all modern file systems.
So effectively you'll simply read lines until you've found the 32nd one.
Not that I know of, but what you could do is loop through the first 31 lines doing nothing using the readline() function of BufferedReader
FileInputStream fs= new FileInputStream("someFile.txt");
BufferedReader br = new BufferedReader(new InputStreamReader(fs));
for(int i = 0; i < 31; ++i)
br.readLine();
String lineIWant = br.readLine();
Joachim is right on, of course, and an alternate implementation to Chris' (for small files only because it loads the entire file) might be to use commons-io from Apache (though arguably you might not want to introduce a new dependency just for this, if you find it useful for other stuff too though, it could make sense).
For example:
String line32 = (String) FileUtils.readLines(file).get(31);
http://commons.apache.org/io/api-release/org/apache/commons/io/FileUtils.html#readLines(java.io.File, java.lang.String)
You may try indexed-file-reader (Apache License 2.0). The class IndexedFileReader has a method called readLines(int from, int to) which returns a SortedMap whose key is the line number and the value is the line that was read.
Example:
File file = new File("src/test/resources/file.txt");
reader = new IndexedFileReader(file);
lines = reader.readLines(6, 10);
assertNotNull("Null result.", lines);
assertEquals("Incorrect length.", 5, lines.size());
assertTrue("Incorrect value.", lines.get(6).startsWith("[6]"));
assertTrue("Incorrect value.", lines.get(7).startsWith("[7]"));
assertTrue("Incorrect value.", lines.get(8).startsWith("[8]"));
assertTrue("Incorrect value.", lines.get(9).startsWith("[9]"));
assertTrue("Incorrect value.", lines.get(10).startsWith("[10]"));
The above example reads a text file composed of 50 lines in the following format:
[1] The quick brown fox jumped over the lazy dog ODD
[2] The quick brown fox jumped over the lazy dog EVEN
Disclamer: I wrote this library
Although as said in other answers, it is not possible to get to the exact line without knowing the offset (pointer) before. So, I've achieved this by creating an temporary index file which would store the offset values of every line. If the file is small enough, you could just store the indexes (offset) in memory without needing a separate file for it.
The offsets can be calculated by using the RandomAccessFile
RandomAccessFile raf = new RandomAccessFile("myFile.txt","r");
//above 'r' means open in read only mode
ArrayList<Integer> arrayList = new ArrayList<Integer>();
String cur_line = "";
while((cur_line=raf.readLine())!=null)
{
arrayList.add(raf.getFilePointer());
}
//Print the 32 line
//Seeks the file to the particular location from where our '32' line starts
raf.seek(raf.seek(arrayList.get(31));
System.out.println(raf.readLine());
raf.close();
Also visit the Java docs on RandomAccessFile for more information:
Complexity: This is O(n) as it reads the entire file once. Please be aware for the memory requirements. If it's too big to be in memory, then make a temporary file that stores the offsets instead of ArrayList as shown above.
Note: If all you want in '32' line, you just have to call the readLine() also available through other classes '32' times. The above approach is useful if you want to get the a specific line (based on line number of course) multiple times.
Another way.
try (BufferedReader reader = Files.newBufferedReader(
Paths.get("file.txt"), StandardCharsets.UTF_8)) {
List<String> line = reader.lines()
.skip(31)
.limit(1)
.collect(Collectors.toList());
line.stream().forEach(System.out::println);
}
No, unless in that file format the line lengths are pre-determined (e.g. all lines with a fixed length), you'll have to iterate line by line to count them.
In Java 8,
For small files:
String line = Files.readAllLines(Paths.get("file.txt")).get(n);
For large files:
String line;
try (Stream<String> lines = Files.lines(Paths.get("file.txt"))) {
line = lines.skip(n).findFirst().get();
}
In Java 7
String line;
try (BufferedReader br = new BufferedReader(new FileReader("file.txt"))) {
for (int i = 0; i < n; i++)
br.readLine();
line = br.readLine();
}
Source: Reading nth line from file
If you are talking about a text file, then there is really no way to do this without reading all the lines that precede it - After all, lines are determined by the presence of a newline, so it has to be read.
Use a stream that supports readline, and just read the first X-1 lines and dump the results, then process the next one.
It works for me:
I have combined the answer of
Reading a simple text file
But instead of return a String I am returning a LinkedList of Strings. Then I can select the line that I want.
public static LinkedList<String> readFromAssets(Context context, String filename) throws IOException {
BufferedReader reader = new BufferedReader(new InputStreamReader(context.getAssets().open(filename)));
LinkedList<String>linkedList = new LinkedList<>();
// do reading, usually loop until end of file reading
StringBuilder sb = new StringBuilder();
String mLine = reader.readLine();
while (mLine != null) {
linkedList.add(mLine);
sb.append(mLine); // process line
mLine = reader.readLine();
}
reader.close();
return linkedList;
}
Use this code:
import java.nio.file.Files;
import java.nio.file.Paths;
public class FileWork
{
public static void main(String[] args) throws IOException {
String line = Files.readAllLines(Paths.get("D:/abc.txt")).get(1);
System.out.println(line);
}
}
You can use LineNumberReader instead of BufferedReader. Go through the api. You can find setLineNumber and getLineNumber methods.
You can also take a look at LineNumberReader, subclass of BufferedReader. Along with the readline method, it also has setter/getter methods to access line number. Very useful to keep track of the number of lines read, while reading data from file.
public String readLine(int line){
FileReader tempFileReader = null;
BufferedReader tempBufferedReader = null;
try { tempFileReader = new FileReader(textFile);
tempBufferedReader = new BufferedReader(tempFileReader);
} catch (Exception e) { }
String returnStr = "ERROR";
for(int i = 0; i < line - 1; i++){
try { tempBufferedReader.readLine(); } catch (Exception e) { }
}
try { returnStr = tempBufferedReader.readLine(); } catch (Exception e) { }
return returnStr;
}
you can use the skip() function to skip the lines from begining.
public static void readFile(String filePath, long lineNum) {
List<String> list = new ArrayList<>();
long totalLines, startLine = 0;
try (Stream<String> lines = Files.lines(Paths.get(filePath))) {
totalLines = Files.lines(Paths.get(filePath)).count();
startLine = totalLines - lineNum;
// Stream<String> line32 = lines.skip(((startLine)+1));
list = lines.skip(startLine).collect(Collectors.toList());
// lines.forEach(list::add);
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
list.forEach(System.out::println);
}
EASY WAY - Reading a line using line number.
Let's say Line number starts from 1 till null .
public class TextFileAssignmentOct {
private void readData(int rowNum, BufferedReader br) throws IOException {
int n=1; //Line number starts from 1
String row;
while((row=br.readLine()) != null) { // Reads every line
if (n == rowNum) { // When Line number matches with which you want to read
System.out.println(row);
}
n++; //This increments Line number
}
}
public static void main(String[] args) throws IOException {
File f = new File("../JavaPractice/FileRead.txt");
FileReader fr = new FileReader(f);
BufferedReader br = new BufferedReader(fr);
TextFileAssignmentOct txf = new TextFileAssignmentOct();
txf.readData(4, br); //Read a Specific Line using Line number and Passing buffered reader
}
}
for a text file you can use an integer with a loop to help you get the number of the line, don't forget to import the classes we are using in this example
File myObj = new File("C:\\Users\\LENOVO\\Desktop\\test.txt");//path of the file
FileReader fr = new FileReader(myObj);
fr.read();
BufferedReader bf = new BufferedReader(fr); //BufferedReader of the FileReader fr
String line = bf.readLine();
int lineNumber = 0;
while (line != null) {
lineNumber = lineNumber + 1;
if(lineNumber == 7)
{
//show line
System.out.println("line: " + lineNumber + " has :" + line);
break;
}
//lecture de la prochaine ligne, reading next
line = bf.readLine();
}
They are all wrong I just wrote this in about 10 seconds.
With this I managed to just call the object.getQuestion("linenumber") in the main method to return whatever line I want.
public class Questions {
File file = new File("Question2Files/triviagame1.txt");
public Questions() {
}
public String getQuestion(int numLine) throws IOException {
BufferedReader br = new BufferedReader(new FileReader(file));
String line = "";
for(int i = 0; i < numLine; i++) {
line = br.readLine();
}
return line; }}
So I am trying to change the format of a text file that has line numbers every couple of lines just to make it cleaner and easier to read. I made a simple program that goes in and replaces all of the first three characters of a line with spaces, these three character spaces are where the numbers can be. The actual text doesn't start until a few more spaces in. When i do this and have the end result printed out it comes out with a diamond with a question mark in it and I'm assuming that this is the result of missing characters. It seems like most of the missing characters are the apostrophe symbol. If anyone could let me know how to fix it i would really appreciate it :)
public class Conversion {
public static void main(String args[]) throws IOException {
BufferedReader scan = null;
try {
scan = new BufferedReader(new FileReader(new File("C:\\Users\\Nasir\\Desktop\\Beowulftesting.txt")));
} catch (FileNotFoundException e) {
System.out.println("failed to read file");
}
String finalVersion = "";
String currLine;
while( (currLine = scan.readLine()) !=null){
if(currLine.length()>3)
currLine = " "+ currLine.substring(3);
finalVersion+=currLine+"\n";
}
scan.close();
System.out.println(finalVersion);
}
}
Instead of using FileReader, use an InputStreamReader with the correct text encoding. I think the strange characters are appearing because you're reading the file with the wrong encoding.
By the way, don't use += with strings in a loop, like you have. Instead, use a StringBuilder:
StringBuilder finalVersion = new StringBuilder();
String currLine;
while ((currLine = scan.readLine()) != null) {
if (currLine.length() > 3) {
finalVersion.append(" ").append(currLine.substring(3));
} else {
finalVersion.append(currLine);
}
finalVersion.append('\n');
}
My java code takes almost 10-15minutes to run (Input file is 7200+ lines long list of query). How do I make it run in short time to get same results?
How do I make my code to search only for aA to zZ and 0 to 9??
If I don't do #2, some characters in my output are shown as "?". How do I solve this issue?
// no parameters are used in the main method
public static void main(String[] args) {
// assumes a text file named test.txt in a folder under the C:\file\test.txt
Scanner s = null;
BufferedWriter out = null;
try {
// create a scanner to read from the text file test.txt
FileInputStream fstream = new FileInputStream("C:\\user\\query.txt");
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
// Write to the file
out = new BufferedWriter(new FileWriter("C:\\user\\outputquery.txt"));
// keep getting the next String from the text, separated by white space
// and print each token in a line in the output file
//while (s.hasNext()) {
// String token = s.next();
// System.out.println(token);
// out.write(token + "\r\n");
//}
String strLine="";
String str="";
while ((strLine = br.readLine()) != null) {
str+=strLine;
}
String st=str.replaceAll(" ", "");
char[]third =st.toCharArray();
System.out.println("Character Total");
for(int counter =0;counter<third.length;counter++){
//String ch= "a";
char ch= third[counter];
int count=0;
for ( int i=0; i<third.length; i++){
// if (ch=="a")
if (ch==third[i])
count++;
}
boolean flag=false;
for(int j=counter-1;j>=0;j--){
//if(ch=="b")
if(ch==third[j])
flag=true;
}
if(!flag){
System.out.println(ch+" "+count);
out.write(ch+" "+count);
}
}
// close the output file
out.close();
} catch (IOException e) {
// print any error messages
System.out.println(e.getMessage());
}
// optional to close the scanner here, the close can occur at the end of the code
finally {
if (s != null) {
// close the input file
s.close();
}
}
}
For something like this I would NOT recommend java though it entirely possible it is much easier with GAWK or something similar. GAWK also has java like syntax so its easy to pick up. You should check it out.
SO isn't really the place to ask such a broad how-do-I-do-this-question but I will refer you to the following page on regular expression and text match in Java. Also, check out the Javadocs for regexes.
If you follow that link you should get what you want, else you could post a more specific question back on SO.