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How can I read lines from a inputted file and then store the most recently read lines in an array?

I am trying to create a program that takes an inputted text file and reads the lines one by one. It then needs to store the most recently read lines (the number of lines depends on the parameter lines) in an array and then I need to print the lines using PrintWriter.
I started the first part but I'm not sure if I have the right idea. If anyone can help me on the second part as well that would be very appreciated!
public void RecentLines(Reader in, Writer out, int lines) throws IOException {
BufferedReader r3ader = new BufferedReader(in);
String str;
while((str = r3ader.readLine()) != null){
String[] arr = str.split(" ");
for( int i =0; i < lines; i++){
arr[i] = r3ader.readLine();
}
}
EDIT
the full question is this:
Create a program which reads lines from IN, one line at the time until the end. Your method must maintain an internal buffer that stores the most recently read lines (this might be best done using an array). Once the method reaches the end of the file, it should print the lines stored in the internal buffer into out, probably best done by creating a PrintWriter to decorate this Writer. (Except for your debugging purposes during the development stage, this method should not print anything to System.out.)

Try this one:
public void RecentLines(Reader in, Writer out, int lines) throws IOException {
BufferedReader r3ader = new BufferedReader(in);
String str;
int i=0;
String[] lineArray = new String[lines];
while((str = r3ader.readLine()) != null){
lines[i%lines] = str;
i++;
if(!r3ader.hasNextLine()){
break;
}
}

sounds like a task for data structures. Queue seems to be the best fit for a given task.
public void RecentLines(Reader in, Writer out, int lines) throws IOException {
BufferedReader r3ader = new BufferedReader(in);
BufferedWriter wout = new BufferedWriter(out);
String str;
Queue<String> content = new LinkedList<String>();
int i = 0;
while ((str = r3ader.readLine()) != null) {
if (i >= lines) {
content.remove();
}
content.add(str);
i++;
}
wout.write(String.valueOf(content));
}

Compare Strings from between 2 files using Java

public class comparee {
static int count=0;
public static void main(String[] args) throws IOException {
String a,b;
FileReader fi = new FileReader(new File("C:\\Users\\IBM_ADMIN\\Desktop\\SAM_PUBLIC_MONTHLY_20150802\\a.txt")); // new file
FileReader fii = new FileReader(new File("C:\\Users\\IBM_ADMIN\\Desktop\\SAM_PUBLIC_MONTHLY_20150802\\b.txt")); // new file
BufferedReader br =new BufferedReader(fi); //new
BufferedReader br1 =new BufferedReader(fii); //old
FileWriter fw = new FileWriter(new File("C:\\Users\\IBM_ADMIN\\Desktop\\SAM_PUBLIC_MONTHLY_20150802\\samnew.txt"));
int count = 0;
while((a=br.readLine()) != null)
{
while((b=br1.readLine()) != null)
{
if(!(a.equals(b)))
{
count++;
fw.write(a);
}
}
System.out.println(count);
}
}
}
Hi, I am trying to compare string from a.txt and b.txt by reading line by line.
I would like to write the line on samdata.txt which is not available in a.txt but available on b.txt. would appreciate any help :) thanks
P.S the above code logic is incorrect

Comparing files is a complex operation, because you normally would have to look ahead in both files in order to find the next matching lines.
Now, if you are absolutely(!) sure that b.txt contains all the lines from a.txt, in the same order as a.txt, but has extra lines inserted at various places, then the following might be ok.
BTW: Your variable names are confusing, so I'm renaming them and using try-with-resources to ensure the readers and the writer get closed.
File fileA = new File("C:\\Users\\IBM_ADMIN\\Desktop\\SAM_PUBLIC_MONTHLY_20150802\\a.txt");
File fileB = new File("C:\\Users\\IBM_ADMIN\\Desktop\\SAM_PUBLIC_MONTHLY_20150802\\b.txt");
File fileNew = new File("C:\\Users\\IBM_ADMIN\\Desktop\\SAM_PUBLIC_MONTHLY_20150802\\samnew.txt");
int count = 0;
try (Reader readerA = new BufferedReader(new FileReader(fileA));
Reader readerB = new BufferedReader(new FileReader(fileB));
PrintWriter writer = new PrintWriter(new FileWriter(fileNew))) {
// Read first line of each file
String lineA = readerA.readLine();
String lineB = readerB.readLine();
// Compare lines
while (lineA != null || lineB != null) {
if (lineB == null) {
// Oops! Found extra line in file A
lineA = readerA.readLine(); // Read next line from file A
} else if (lineA == null || ! lineA.equals(lineB)) {
// Found new line in file B
writer.println(lineB);
lineB = readerB.readLine(); // Read next line from file A
count++;
} else {
// Lines are equal, so read next line from both files
lineA = readerA.readLine();
lineB = readerB.readLine();
}
}
}
System.out.println(count);

Why don't you read b.txt into a list and then in your code check if each line you read in a.txt is available in the list (list.contains()).

InputStreamReader and reading random lines from .txt file

I have a method for my app to read a random line from a text file and return it. Im using the randTxt() to read and return a random line from the txt file.
but it only shows the same line (1st line) everytime.
public String randTxt(){
// Read in the file into a list of strings
InputStreamReader inputStream = new InputStreamReader(getResources().openRawResource(R.raw.randomstuff));
//ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
String theLine="";
int i;
try {
i = inputStream.read();
while (i != -1) {
i = inputStream.read();
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
LineNumberReader rdr = new LineNumberReader(inputStream);
int numLines = 30;
Random r = new Random();
rdr.setLineNumber(r.nextInt(numLines));
try {
theLine = rdr.readLine();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return theLine;
}
How can I fix it? and Can someone explain what's wrong in my code?

Here's the framework for doing what you need using BufferedReader. In this case, you don't need to store the values in a temp array.
InputStreamReader inputStream = new InputStreamReader
(getResources().openRawResource(R.raw.randomstuff));
BufferedReader br = new BufferedReader(inputStream);
int numLines = 30;
Random r = new Random();
int desiredLine = r.nextInt(numLines);
String theLine="";
int lineCtr = 0;
while ((theLine = br.readLine()) != null) {
if (lineCtr == desiredLine) {
break;
}
lineCtr++;
}
...
Log.d(TAG, "Magic line is: " +theLine);

You have gotten an answer of how to fix your code, but no explanation of why our original code did not work.
LineNumberReader.setLineNumber(int) does not go to the actual line, it just changes what number you call the current line.
So, say you read two lines, getLineNumber() will now return 2 (it started at 0 and increased by 1 each time a newline was encountered). if you now setLineNumber(10), getLineNumber() will return 10. Reading yet another line (your third) will cause getLineNumber() to return 11.
This is described in the Java Doc.

inputStream.read does not return a line number. it returns the byte that was read. this isn't how you would read line by line. to read line by line, you should use buffered reader's readLine method. its probably easier at that point to read it all into a local array and use that array to randomly get an entry, rather than using a line number reader.

I think Random() function returns a value between 0 and 1. hence, you may have to multiply it with 100 to get an integer value. May even consider a MOD "your upper limit" operation to guarentee that the index you finally get is between 0 and your upper limit
Use the index you calculated thus, in your setLineNumber() method.
Edit:
As john said, we can get whole number using Random() object.

public String getRandomLine(String fileLoc) throws IOException
{
BufferedReader reader = new BufferedReader(new FileReader(fileLoc));
ArrayList<String> lines = new ArrayList<String>();
String line =null;
while( (line = reader.readLine())!= null )
lines.add(line);
// Choose a random one from the list
return lines.get(new Random().nextInt(lines.size()));
}
public String getRandomLineOpt(String fileLoc)throws IOException
{
File f=new File(fileLoc);
RandomAccessFile rcf=new RandomAccessFile(f, "r");
long rand = (long)(new Random().nextDouble()*f.length());
rcf.seek(rand);
rcf.readLine();
return rcf.readLine();
}

How do I read from a File to an array

I am trying to read from a file to an array. I tried two different styles and both aren't working. Below are the two styles.
Style 1
public class FileRead {
int i;
String a[] = new String[2];
public void read() throws FileNotFoundException {
//Z means: "The end of the input but for the final terminator, if any"
a[i] = new Scanner(new File("C:\\Users\\nnanna\\Documents\\login.txt")).useDelimiter("\\n").next();
for(i=0; i<=a.length; i++){
System.out.println("" + a[i]);
}
}
public static void main(String args[]) throws FileNotFoundException{
new FileRead().read();
}
}
Style 2
public class FileReadExample {
private int j = 0;
String path = null;
public void fileRead(File file){
StringBuilder attachPhoneNumber = new StringBuilder();
try{
FileReader read = new FileReader(file);
BufferedReader bufferedReader = new BufferedReader(read);
while((path = bufferedReader.readLine()) != null){
String a[] = new String[3];
a[j] = path;
j++;
System.out.println(path);
System.out.println(a[j]);
}
bufferedReader.close();
}catch(IOException exception){
exception.printStackTrace();
}
}
I need it to read each line of string and store each line in an array. But neither works. How do I go about it?

Do yourself a favor and use a library that provides this functionality for you, e.g.
Guava:
// one String per File
String data = Files.toString(file, Charsets.UTF_8);
// or one String per Line
List<String> data = Files.readLines(file, Charsets.UTF_8);
Commons / IO:
// one String per File
String data = FileUtils.readFileToString(file, "UTF-8");
// or one String per Line
List<String> data = FileUtils.readLines(file, "UTF-8");

It's not really clear exactly what you're trying to do (partly with quite a lot of code commented out, leaving other code which won't even compile), but I'd recommend you look at using Guava:
List<String> lines = Files.readLines(file, Charsets.UTF_8);
That way you don't need to mess around with the file handling yourself at all.

Java: How to read a text file

I want to read a text file containing space separated values. Values are integers.
How can I read it and put it in an array list?
Here is an example of contents of the text file:
1 62 4 55 5 6 77
I want to have it in an arraylist as [1, 62, 4, 55, 5, 6, 77]. How can I do it in Java?

You can use Files#readAllLines() to get all lines of a text file into a List<String>.
for (String line : Files.readAllLines(Paths.get("/path/to/file.txt"))) {
// ...
}
Tutorial: Basic I/O > File I/O > Reading, Writing and Creating text files
You can use String#split() to split a String in parts based on a regular expression.
for (String part : line.split("\\s+")) {
// ...
}
Tutorial: Numbers and Strings > Strings > Manipulating Characters in a String
You can use Integer#valueOf() to convert a String into an Integer.
Integer i = Integer.valueOf(part);
Tutorial: Numbers and Strings > Strings > Converting between Numbers and Strings
You can use List#add() to add an element to a List.
numbers.add(i);
Tutorial: Interfaces > The List Interface
So, in a nutshell (assuming that the file doesn't have empty lines nor trailing/leading whitespace).
List<Integer> numbers = new ArrayList<>();
for (String line : Files.readAllLines(Paths.get("/path/to/file.txt"))) {
for (String part : line.split("\\s+")) {
Integer i = Integer.valueOf(part);
numbers.add(i);
}
}
If you happen to be at Java 8 already, then you can even use Stream API for this, starting with Files#lines().
List<Integer> numbers = Files.lines(Paths.get("/path/to/test.txt"))
.map(line -> line.split("\\s+")).flatMap(Arrays::stream)
.map(Integer::valueOf)
.collect(Collectors.toList());
Tutorial: Processing data with Java 8 streams

Java 1.5 introduced the Scanner class for handling input from file and streams.
It is used for getting integers from a file and would look something like this:
List<Integer> integers = new ArrayList<Integer>();
Scanner fileScanner = new Scanner(new File("c:\\file.txt"));
while (fileScanner.hasNextInt()){
integers.add(fileScanner.nextInt());
}
Check the API though. There are many more options for dealing with different types of input sources, differing delimiters, and differing data types.

This example code shows you how to read file in Java.
import java.io.*;
/**
* This example code shows you how to read file in Java
*
* IN MY CASE RAILWAY IS MY TEXT FILE WHICH I WANT TO DISPLAY YOU CHANGE WITH YOUR OWN
*/
public class ReadFileExample
{
public static void main(String[] args)
{
System.out.println("Reading File from Java code");
//Name of the file
String fileName="RAILWAY.txt";
try{
//Create object of FileReader
FileReader inputFile = new FileReader(fileName);
//Instantiate the BufferedReader Class
BufferedReader bufferReader = new BufferedReader(inputFile);
//Variable to hold the one line data
String line;
// Read file line by line and print on the console
while ((line = bufferReader.readLine()) != null) {
System.out.println(line);
}
//Close the buffer reader
bufferReader.close();
}catch(Exception e){
System.out.println("Error while reading file line by line:" + e.getMessage());
}
}
}

Look at this example, and try to do your own:
import java.io.*;
public class ReadFile {
public static void main(String[] args){
String string = "";
String file = "textFile.txt";
// Reading
try{
InputStream ips = new FileInputStream(file);
InputStreamReader ipsr = new InputStreamReader(ips);
BufferedReader br = new BufferedReader(ipsr);
String line;
while ((line = br.readLine()) != null){
System.out.println(line);
string += line + "\n";
}
br.close();
}
catch (Exception e){
System.out.println(e.toString());
}
// Writing
try {
FileWriter fw = new FileWriter (file);
BufferedWriter bw = new BufferedWriter (fw);
PrintWriter fileOut = new PrintWriter (bw);
fileOut.println (string+"\n test of read and write !!");
fileOut.close();
System.out.println("the file " + file + " is created!");
}
catch (Exception e){
System.out.println(e.toString());
}
}
}

Just for fun, here's what I'd probably do in a real project, where I'm already using all my favourite libraries (in this case Guava, formerly known as Google Collections).
String text = Files.toString(new File("textfile.txt"), Charsets.UTF_8);
List<Integer> list = Lists.newArrayList();
for (String s : text.split("\\s")) {
list.add(Integer.valueOf(s));
}
Benefit: Not much own code to maintain (contrast with e.g. this). Edit: Although it is worth noting that in this case tschaible's Scanner solution doesn't have any more code!
Drawback: you obviously may not want to add new library dependencies just for this. (Then again, you'd be silly not to make use of Guava in your projects. ;-)

Use Apache Commons (IO and Lang) for simple/common things like this.
Imports:
import org.apache.commons.io.FileUtils;
import org.apache.commons.lang3.ArrayUtils;
Code:
String contents = FileUtils.readFileToString(new File("path/to/your/file.txt"));
String[] array = ArrayUtils.toArray(contents.split(" "));
Done.

Using Java 7 to read files with NIO.2
Import these packages:
import java.nio.charset.Charset;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
This is the process to read a file:
Path file = Paths.get("C:\\Java\\file.txt");
if(Files.exists(file) && Files.isReadable(file)) {
try {
// File reader
BufferedReader reader = Files.newBufferedReader(file, Charset.defaultCharset());
String line;
// read each line
while((line = reader.readLine()) != null) {
System.out.println(line);
// tokenize each number
StringTokenizer tokenizer = new StringTokenizer(line, " ");
while (tokenizer.hasMoreElements()) {
// parse each integer in file
int element = Integer.parseInt(tokenizer.nextToken());
}
}
reader.close();
} catch (Exception e) {
e.printStackTrace();
}
}
To read all lines of a file at once:
Path file = Paths.get("C:\\Java\\file.txt");
List<String> lines = Files.readAllLines(file, StandardCharsets.UTF_8);

All the answers so far given involve reading the file line by line, taking the line in as a String, and then processing the String.
There is no question that this is the easiest approach to understand, and if the file is fairly short (say, tens of thousands of lines), it'll also be acceptable in terms of efficiency. But if the file is long, it's a very inefficient way to do it, for two reasons:
Every character gets processed twice, once in constructing the String, and once in processing it.
The garbage collector will not be your friend if there are lots of lines in the file. You're constructing a new String for each line, and then throwing it away when you move to the next line. The garbage collector will eventually have to dispose of all these String objects that you don't want any more. Someone's got to clean up after you.
If you care about speed, you are much better off reading a block of data and then processing it byte by byte rather than line by line. Every time you come to the end of a number, you add it to the List you're building.
It will come out something like this:
private List<Integer> readIntegers(File file) throws IOException {
List<Integer> result = new ArrayList<>();
RandomAccessFile raf = new RandomAccessFile(file, "r");
byte buf[] = new byte[16 * 1024];
final FileChannel ch = raf.getChannel();
int fileLength = (int) ch.size();
final MappedByteBuffer mb = ch.map(FileChannel.MapMode.READ_ONLY, 0,
fileLength);
int acc = 0;
while (mb.hasRemaining()) {
int len = Math.min(mb.remaining(), buf.length);
mb.get(buf, 0, len);
for (int i = 0; i < len; i++)
if ((buf[i] >= 48) && (buf[i] <= 57))
acc = acc * 10 + buf[i] - 48;
else {
result.add(acc);
acc = 0;
}
}
ch.close();
raf.close();
return result;
}
The code above assumes that this is ASCII (though it could be easily tweaked for other encodings), and that anything that isn't a digit (in particular, a space or a newline) represents a boundary between digits. It also assumes that the file ends with a non-digit (in practice, that the last line ends with a newline), though, again, it could be tweaked to deal with the case where it doesn't.
It's much, much faster than any of the String-based approaches also given as answers to this question. There is a detailed investigation of a very similar issue in this question. You'll see there that there's the possibility of improving it still further if you want to go down the multi-threaded line.

read the file and then do whatever you want
java8
Files.lines(Paths.get("c://lines.txt")).collect(Collectors.toList());