I use Selenium 2 + Java for testing the application on IE 9.
After clicking on the link, the pop-up window is opened. I use switchTo.window method for going to pop-up window. But when I try to go back, my test is delayed on this operation and doesn't go on.
Some code:
link.click(); //Open pop-up window
Object[] windows = driverIE.getWindowHandles().toArray();
driverIE.switchTo().defaultContent();
driverIE.switchTo().window(windows[1].toString()); //Focus on pop-up window
.....
mainWindowHandle = driverIE.getWindowHandles().iterator().next(); //Handle of main window
driverIE.switchTo().window(mainWindowHandle); //Fail!
Please help me to solve the problem.
Windows handles returned by getWindowHandles() are not guaranteed to be in any order. In other words, you cannot depend on windows[1] in your code sample above to contain the window handle of the opened window. Rather, you need code that looks something like the following (NOTE: Completely untested code ahead!):
String mainHandle = driver.getWindowHandle();
// Do whatever you need to do to open a new window,
// and properly wait for the new window to appear...
Set<String> allHandles = driver.getWindowHandles();
for(String currentHandle : allHandles) {
// Note that this is cheating a bit. It will only
// work with a total of two windows. If you have
// more than two windows total, your logic here
// will have to be a little more sophisticated.
if (!currentHandle.equals(mainHandle)) {
driver.switchTo().window(currentHandle);
break;
}
}
// Work with popup window...
// Close the popup window and switch context back
// to the main window.
driver.close();
driver.switchTo().window(mainHandle);
As JimEvans stated, driver.getWindowHandles() sometimes puts windows in incorrect order, thus the for loop does not always work.
Similar to above worked for me (I only have two windows to handle):
String winHandleBefore = driver.getWindowHandle();
driver.findElement(By.cssSelector("a")).click();
Set<String> winHandle = driver.getWindowHandles();
winHandle.remove(winHandleBefore);
String winHandleNew = winHandle.toString();
String winHandleFinal = winHandleNew.replaceAll("\\[", "").replaceAll("\\]","");
driver.switchTo().window(winHandleFinal);
Related
I am writing a code using selenium.
On a particular click there are chances of coming one of two windows. and both the windows takes around 20-50 seconds of time to appear.
so i want to switch to whichever window appears.
I have no way to predict which window is going to appear
Current process - i am searching for main window for some seconds and if it is not found i am trying to search small pop up window with ok button on it. If found click on it. if not found again try to find main window it is taking time.
If i have a way to switch to latest window and by checking its title which window it is and do the appropriate action.
Edited - main window is not the original window. There are total 3 windows in picture . One og window where i have to click . now after clicking main window can appear or small popup window can apear with ok button.
You can try something like this for your problem
// Store the current window handle
String mainWin = driver.getWindowHandle();
// Perform the click operation that opens new window
//Wait till driver.getWindowHandles() returns 2 windows
// Switch to new window opened
for(String winHandle : driver.getWindowHandles()){
driver.switchTo().window(winHandle);
}
//Get current window to take decision on the next actions
String currentWin= driver.getWindowHandle();
// Perform the actions on new window
// Close the new window
driver.close();
// Switch back to original first window
driver.switchTo().window(mainWin);
To handle windows size, you can use .getWindowHandles(), and try use while loop to wait the new windows appear, then you can iteration again all current window.
int sizeBefore = driver.getWindowHandles().size();
elemnt.click();//to bring up new windows
//until current windows size>before, please keep adding timeout
while(driver.getWindowHandles().size()==sizeBefore) {
//wait in milliseconds
Thread.sleep(500);
}
//handle current size windows
ArrayList<String> hnds = new ArrayList<String> (driver.getWindowHandles());
//iteration windows
for(String hnd: hnds) {
driver.switchTo().window(hnd);
System.out.println(driver.getTitle());
}
To switch to particular windows, use:
driver.switchTo().window(hnds.get(index));
You should save the window handle for the main window before any action is done.
String mainWindow = driver.getWindowHandle();
Now click and do the following:
You can poll for 30 seconds max time with interval say 5 seconds, break the polling the moment you get more than one window handle.
Set<String> windows = driver.getWindowHandles();
let me know in which language you are working.
I can help you with the code.
Hi you can use Javascript for switching wondow: below are the code:
((JavascriptExecutor)LoginDriver).executeScript("window.open('about:blank', '-blank')");
// To switch to the new tab
ArrayList<String> tabs = new ArrayList<String>(LoginDriver.getWindowHandles());
LoginDriver.switchTo().window(tabs.get(1));
I am running below java code for switching windows and getting error message, Kindly suggest something.
Driver.findElement(By.cssSelector("body")).sendKeys(Keys.CONTROL +"t");
Set<String>set=Driver.getWindowHandles();
Iterator<String> It=set.iterator();
String PId=It.next();
String CId=It.next();
Driver.switchTo().window(CId);
Driver.get("https://www.facebook.com");/* Here again I want to come back to parent window and perform some action */
Please refer to this java documentation link for the list of available switchTo options:
https://seleniumhq.github.io/selenium/docs/api/java/org/openqa/selenium/WebDriver.TargetLocator.html
In your case, you may need to save the window handle before switching and then use it later to switch back to original window.
String originalWindow = Driver.getWindowHandle();
Driver.switchTo().window(CId);
//Operations on new window here
Driver.switchTo().window(originalWindow);
//Operations on original window here
I am working with selenium automation. I have coded to login a page and it works fine. The login passed and new child window was opened as a result and parent window was closed.
Due to that my web driver stops and result in exceptions.
Exception in thread main org.openqa.selenium.NoSuchWindowException:
No window found (WARNING: The server did not provide any stacktrace information)
Please help
Selenium keeps a list of windows (handles). The webdriver needs to point to the right handle. When a window is closed, its handle is deleted, and your driver will now point to something that doesn't exist anymore.
Likely, you have to explicitly switch window to point your driver to the right window handle. Maybe this could help:
Switch between two browser windows using selenium webdriver
Selenium python bindings: Moving between windows and frames
"new child window was opened as a result and parent window was closed"
The code below from (1) shows you how to retrieve the list of window handles, and retrieve the right handle based on its title.
private void handleMultipleWindows(String windowTitle) {
Set<String> windows = driver.getWindowHandles();
for (String window : windows) {
driver.switchTo().window(window);
if (driver.getTitle().contains(windowTitle)) {
return;
}
}
}
You can use that function (or something similar) to retrieve the new window. From the code you provided, this would give:
// Entering the credentials in the login window.
driver.findElement(By.id(txtUserId)).clear();
driver.findElement(By.id(txtUserId)).sendKeys(poovan);
driver.findElement(By.id(txtPassword)).clear();
driver.findElement(By.id(txtPassword)).sendKeys(welcome1);
driver.findElement(By.id(btnSubmit)).click();
// Here the login window gets closed, handler to that window disappears, and driver becomes stale.
// So we need update the driver to point to the new window
handleMultipleWindows("The title of my new window");
driver.findElement(By.name(bono)).sendKeys(080);
Please use below code. It will work for sure.
String parentWindow = driver.getWindowHandle();
Set<String> handles2 = driver.getWindowHandles();
for (String windowHandle : handles2) {
if (!windowHandle.equals(parentWindow)) {
driver.switchTo().window(windowHandle);
}
}
I am using Selenium to test a website. I can upload a ".txt" file and then double click on it to open,But I am not able to close the opened file using selenium!!!
I know there is a solution with robot tool by using Alt+F4 but I am not allowed to use robot, I tried the selenium code below to close the window, it does not work:
action.sendKeys(Keys.chord(Keys.ALT,Keys.F4)).build().perform();
Try this (driver is an instance of WebDriver):
String myWindow = driver.getWindowHandle();
//open file with double click
//do something ...
driver.switchTo().window(myWindow);
This stores a handle to the original window and switches back to it. The other window may be still open in background but will be closed, if you call driver.quit();
Thanks to: CODEBLACK
String parentHandle = driver.getWindowHandle(); // get the current window handle
driver.findElement(By.xpath("//*[#id='someXpath']")).click(); // click some link that opens a new window
for (String winHandle : driver.getWindowHandles()) {
driver.switchTo().window(winHandle); // switch focus of WebDriver to the next found window handle (that's your newly opened window)
}
//code to do something on new window
driver.close(); // close newly opened window when done with it
driver.switchTo().window(parentHandle); // switch back to the original window
[1]: https://stackoverflow.com/questions/19112209/how-to-handle-the-new-window-in-selenium-webdriver
After sending click with findElement, I Cant go on to the next action of handling the popup until popup closed (manually), since current window is not in control, therefore webdriver waits forever.
Im trying to do the following:
driver.findElement(By.xpath(salesforceButtons.CUSTOM_OBJECT_DELETE.getValue())).click();
Set<String> windowId = driver.getWindowHandles(); // get window id of current window
Iterator<String> itererator = windowId.iterator();
String mainWinID = itererator.next()
String newAdwinID = itererator.next();
driver.switchTo().window(newAdwinID);
But it stuck after the click.
I think you need to use the following (presuming by pop-up you mean a browser alert window):
Alert alert = driver.switchTo().alert();
alert.accept()
I may be wrong with this, and it may be that you do need to iterate through the windows, however, the code you've stated isn't doing that, it is simply changing the window focus to the one defined by the second result in the driver.getWindowHandles() set. Might I suggest the following if it's not just a simple alert:
String startWinId = driver.getWindowHandle(); // caches the current window id
driver.findElement(By.xpath(salesforceButtons.CUSTOM_OBJECT_DELETE.getValue())).click();
Set<String> windowId = driver.getWindowHandles(); // actually gets all available windows ids
Iterator<String> iterator = windowId.iterator();
// Iterates through each active window and does stuff within that window.
while (iterator.hasNext()) {
driver.switchTo().window(iterator.next());
<insert code to run against each window here>
}
// Switches back to the original window to carry on with executing tests
driver.switchTo().window(startWinId);