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how to sort variables X and negated varibles X' alphabetic which are saved as string in Java?
Example: String string = "B*A'*D*H'"; result must
String sortedString="A'*B*D*H'";
are the variables always separated with * ?
In that case it'd be very simple:
String in = "B*A'*D*H'";
String[] vars = in.split("\\*");
Arrays.sort(vars);
// Java is missing a simple php-like join function ;-(
StringBuilder sorted = new StringBuilder();
for(String s: vars){
sorted.append(s);
sorted.append("*");
}
sorted.deleteCharAt(sorted.length()-1);
and you're done ;-)
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I want to filter specific text from a specific array in java like
String a="code=500,code1=1000"
I want to get only 500 from index 0 by searching "code="
One approach would be to:
Split the String by "," to an array.
Now for each element of the array, do a replaceAll to remove the text before the number.
It might not be the most optimal, but this should work:
String[] split = a.split(",");
for (String s: split) {
String desiredText = s.replaceAll(".+=", "");
}
Then you could add the desiredText to a List or whatever it is you want to do with it.
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I have a String value "\u0004"
I need to convert it to character '\u0004'
I need to store this character back to the string.
How can this be done?
Maybe this is answer you want
// string value that has "\" in front
String s = "\\u0004";
// substring to leave "\u" out
char c = (char)Integer.parseInt(s.substring(2));
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I have a string that contains String q = "What's the value of √32 and √83?";, my problem is replacing √num with sqrt(32) and sqrt(83).
That means my string should output : -
What's the value of sqrt(32) and sqrt(83)
is it possible?
Use a regex replacement on the pattern √(\d+)\b, and replace with sqrt(...):
String q = "What's the value of √32 and √83?";
String output = q.replaceAll("√(\\d+)\\b", "sqrt($1)");
System.out.println(output);
This prints:
What's the value of sqrt(32) and sqrt(83)?
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Sorry for the basic question but I have a Java String that I need to return as part of a method as a Set<String>
I cannot find a reference on how to do this. Any clues?
The usual way to do this, with a normal set:
String s = "hello";
Set<String> set = new HashSet<>();
set.add(s)
return set;
Or if you prefer an immutable set with just a single element:
String s = "hello";
return Collections.singleton(s);
If you are using Java 9 or newer, use Set.of():
return Set.of("foo");
Collections.singleton("yourString")
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I have a list such:
List<string> list =Arrays.asList("2014-06-20 [txt1:executed]","2014-06-21 [txt2:in progressed]");
I want to extract the contents to an array:
arr[0] =2014-06-20
arr[1] =executed
arr[2] =2014-06-21
arr[3] =in progressed
You might take a look at regular expressions. They are quite powerfull to split Strings according to your wishes.
Here is an example how you can split your String.
String regex = "([0-9-]+)\\s+\\[\\w*:([\\w\\s]*)]";
List<String> list = Arrays.asList("2014-06-20 [txt1:executed]","2014-06-21 [txt2:in progressed]");
String date = list.get(0).replaceAll(regex, "$1");
String status = list.get(0).replaceAll(regex, "$2");
I hope that helps.