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I have a list such:
List<string> list =Arrays.asList("2014-06-20 [txt1:executed]","2014-06-21 [txt2:in progressed]");
I want to extract the contents to an array:
arr[0] =2014-06-20
arr[1] =executed
arr[2] =2014-06-21
arr[3] =in progressed
You might take a look at regular expressions. They are quite powerfull to split Strings according to your wishes.
Here is an example how you can split your String.
String regex = "([0-9-]+)\\s+\\[\\w*:([\\w\\s]*)]";
List<String> list = Arrays.asList("2014-06-20 [txt1:executed]","2014-06-21 [txt2:in progressed]");
String date = list.get(0).replaceAll(regex, "$1");
String status = list.get(0).replaceAll(regex, "$2");
I hope that helps.
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I want to filter specific text from a specific array in java like
String a="code=500,code1=1000"
I want to get only 500 from index 0 by searching "code="
One approach would be to:
Split the String by "," to an array.
Now for each element of the array, do a replaceAll to remove the text before the number.
It might not be the most optimal, but this should work:
String[] split = a.split(",");
for (String s: split) {
String desiredText = s.replaceAll(".+=", "");
}
Then you could add the desiredText to a List or whatever it is you want to do with it.
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I have a string that contains String q = "What's the value of √32 and √83?";, my problem is replacing √num with sqrt(32) and sqrt(83).
That means my string should output : -
What's the value of sqrt(32) and sqrt(83)
is it possible?
Use a regex replacement on the pattern √(\d+)\b, and replace with sqrt(...):
String q = "What's the value of √32 and √83?";
String output = q.replaceAll("√(\\d+)\\b", "sqrt($1)");
System.out.println(output);
This prints:
What's the value of sqrt(32) and sqrt(83)?
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What I have:
String result = "<>hello<!><>Soumik<!><>Having a wonderful day?<!>";
What I need:
resultStrings = ["hello", "Soumik", "Having a wonderful day?"];
This regex should do the trick:
<[^>]*>([^<]+)<
Find all matches, and extract capturing group 1 from each.
Regex demo
How about that:
result = result.replace("<", "");
result = result.replace(">","";
resultStrings = result.split("!");
It's really simple.
I don't know other conditions so it may not be useful. Please add conditions so I can respond to it.
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I have a string of numbers which looks like this
["100000100685716-2","603834770-2", "604544970-3"]
can someone help me with a regular expression to match each long (first number before the "-") so i can add it to an array?
The following regex should work: (\d+)-
You do not need a regex here:
Use int pos = str.indexOf('-') to get the location of the dash
Use str.substring(0, pos) to get the initial portion of the string.
If dashes in the input strings are optional, you would need to add a check of pos to be non-negative.
(?:\"\d+)
This should do exactly what you want
String s = "[\"100000100685716-2\",\"603834770-2\", \"604544970-3\"]";
System.out.println(s.split("-")[0].substring(2));
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how to sort variables X and negated varibles X' alphabetic which are saved as string in Java?
Example: String string = "B*A'*D*H'"; result must
String sortedString="A'*B*D*H'";
are the variables always separated with * ?
In that case it'd be very simple:
String in = "B*A'*D*H'";
String[] vars = in.split("\\*");
Arrays.sort(vars);
// Java is missing a simple php-like join function ;-(
StringBuilder sorted = new StringBuilder();
for(String s: vars){
sorted.append(s);
sorted.append("*");
}
sorted.deleteCharAt(sorted.length()-1);
and you're done ;-)