I have to execute a java code using batch script where java code has to take a variable value generated from the .bat file and execute java code and then return the another variable value back to .bat .
In say, exec.bat file i l get a value "456" .this "456" has to be sent to java file and there after execution we get another value "789" .And I want this "789" to be return back to exe.bat .
Please let me know the code and syntax to be written in both java and batch file.
Thanks in Advance
Here is one way to do it:
In Java code :
At the end of the program put this line
System.exit(789);
Here 789 is the value you would return to your batch file.
In the batch file:
#echo off
java Test %1
set exitcode=%ERRORLEVEL%
echo %exitcode%
Here
java Test %1 is the usual java execution with argument passed from batch file where %1 will map to the first parameter passed to the batch file from command prompt (like wise you could have %2 etc ... Check this article ).
ERRORLEVEL is the standard batch variable use to store the value returned from java
Assuming that your batch file name is Test.bat, you run this from command prompt batch as
Test 456
EDIT:Example for adding two numbers
Example.java
public class Example extends TestBase<String>
{
public static void main(String[] arg){
int result = Integer.parseInt(arg[0].trim()) ;+Integer.parseInt(arg[1].trim())
System.exit(result);
}
}
Compile this file and generate a class file Example.class
Batch file :
Example.bat
#echo off
java Example %1 %2
set exitcode=%ERRORLEVEL%
echo %exitcode%
Put this batch file and Example.class in a folder. Open command prompt from that folder and run as follows
Example 111 222
This will print the addition of these two numbers
Related
I have a java class, which has 3 methods and each method returns a String. I exported the .jar file out of that Java project. When I run the jar file from git bast using the command ./script1.sh, I get the output in the command window. My question is, how can I assign those values to the three variable that are in the script1.sh file. If I type echo ${"Source_branch"}, i should get output as "XXX_Source_Branch".
Here is my Java code :
package com.main;
public class Engine {
public static void main(String[] args) {
try {
getSourceBranch();
getDestinationBranch();
getDestEnv();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public static String getSourceBranch() {
return "XXX_Source_Branch";
}
public static String getDestinationBranch() {
return "XXX_Dest_Branch";
}
public static String getDestEnv() {
return "XXX_Dest_Env";
}
}
The name of the jar file is Engine.jar.
And my script file is
runjar.sh
java -jar Engine.jar
Source_branch
Destination_brnach
Destination_env
pass data from java to bash
If you want to save data from java to the overlaying String, you will need to print that to System.out and read them from the shell.
Java code:
System.out.println("your source branch")
System.out.println("your destination branch")
Shell code
out="$(java -jar Engine.jar)"
sBranch="$(echo "$out"|sed -n '1p' /dev/stdin)"
destBranch="$(echo "$out"|sed -n '2p' /dev/stdin)"
pass data from bash to java
If you hard-code the Strings, java will just use the Strings. If you want to change that, you will need to modify your java code.
option 1 - arguments
If you want to pass the strings in the script using java -jar Engine.jar Source_branch Destination_brnach Destination_env, you can use them in your main method with the args parameter.
For example, you can print the first String in your main method using
System.out.println(args[0]);
If you do that, please test if args.length is greater than the highest argument you are accessing.
option 2 - System properties
If you want to get parameters without accessing args(independent of your main method), you will need to use System properties.
At first, change the script to be like that:
java -jar -DSource_branch=yourSourceBranch -DDestination_branch=yourDestinationBranch -DDestination_env=yourDestinationEnv
Engine.jar
Note that -D. That indicates that you are passing System properties. The syntax for this is -D<key>=<value> and it should be located between java and -jar.
Also, you will need to use System.getProperty() to access it from anywhere in your code.
For example:
public static String getSourceBranch() {
return System.getProperty("Source_Branch");
}
Create a .sh file with any file editor, like-
$> vi runJar.sh
Then, paste the below script ,
#!/bin/sh
java -jar Engine.jar
After saving the file, give execution permission -
$> chmod +x runJar.sh
Then run using
$> ./runJar.sh
Make sure the jar file and shell script file are in the same directory.
I had batch script which executes TestRun class by taking jvm arguments as shown below
java -cp "./lib/*;./statoil.jar" -DURI=localhost:8080 -DOWUser=abc -DOWPassword=abc123 -DpipelineName=EDMStatOil -Ddatabase=edm -DproviderName=141Provider -DdestinationName=110EDM -DproviderWellName=Serno Grad com.statoil.rts.test.TestRun
But while running batch script getting error:
Error: Could not find or load main class Grad
I know it is treating Grad as class file. But how we can avoid this error while passing jvm argument with space?
Java doesn't care if there is a space in the JVM argument's value, but the terminal will split -DproviderWellName=Serno Grad into two command line arguments and pass those to the java executable.
You have to put quotes around the whole argument:
java "-DproviderWellName=Serno Grad"
In you batch file try setting the variable first and then pass that parameter to the actual command like these.
set WellName="Serno Grad"
java -cp "./lib/*;./statoil.jar" -DURI=localhost:8080 -DOWUser=abc -DOWPassword=abc123 -DpipelineName=EDMStatOil -Ddatabase=edm -DproviderName=141Provider -DdestinationName=110EDM -DproviderWellName=%WellName% com.statoil.rts.test.TestRun
OR
set WellName="Serno Grad"
java -cp "./lib/*;./statoil.jar" -DURI=localhost:8080 -DOWUser=abc -DOWPassword=abc123 -DpipelineName=EDMStatOil -Ddatabase=edm -DproviderName=141Provider -DdestinationName=110EDM -DproviderWellName="%WellName%" com.statoil.rts.test.TestRun
On my system either of them works fine.
try with escape characters -DproviderWellName="\"Serno Grad\""
I'm new with Perl and I'm trying to do something and can't find the answer.
I created a Java project that contains a main class that gets several input parameters.
I want to wrap my Java with Perl: I want to create a Perl script that gets the input parameters, and then passes them to the Java program, and runs it.
For example:
If my main is called mymain, and I call it like this: mymain 3 4 hi (3, 4 and hi are the input parameters), I want to create a Perl program called myperl which when it is invoked as myperl 3 4 hi will pass the arguments to the Java program and run it.
How can I do that?
Running a Java program is just like running any other external program.
Your question has two parts :
How do I get the arguments from Perl to the Java program?
How do I run the program in Perl?
For (1) you can do something like
my $javaArgs = " -cp /path/to/classpath -Xmx256";
my $className = myJavaMainClass;
my $javaCmd = "java ". $javaArgs ." " . $className . " " . join(' ', #ARGV);
Notice the join() function - it will put all your arguments to the Perl program and separate them with space.
For (2) you can follow #AurA 's answer.
Using the system() function
my $ret = system("$javaCmd");
This will not capture (i.e. put in the variable $ret) the output of your command, just the return code, like 0 for success.
Using backticks
my $out = `$javaCmd`;
This will populate $out with the whole output of the Java program ( you may not want this ).
Using pipes
open(FILE, "-|", "$javaCmd");
my #out = <FILE>
This is more complicated but allows more operations on the output.
For more information on this see perldoc -f open.
$javaoutput = `java javaprogram`;
or
system "java javaprogram";
For a jar file
$javaoutput = `java -jar filename.jar`;
or
system "java -jar filename.jar";
I need to run an .sh file and get its output. I need to see the setup of the file as well.
The .sh file simply runs a java app through terminal.
Any ideas? I'm truly stuck on this.....
Elijah
The server.sh file:
echo Starting Jarvis Program D.
ALICE_HOME=.
SERVLET_LIB=lib/servlet.jar
ALICE_LIB=lib/aliceserver.jar
JS_LIB=lib/js.jar
# Set SQL_LIB to the location of your database driver.
SQL_LIB=lib/mysql_comp.jar
# These are for Jetty; you will want to change these if you are using a different http server.
HTTP_SERVER_LIBS=lib/org.mortbay.jetty.jar
PROGRAMD_CLASSPATH=$SERVLET_LIB:$ALICE_LIB:$JS_LIB:$SQL_LIB:$HTTP_SERVER_LIBS
java -classpath $PROGRAMD_CLASSPATH -Xms64m -Xmx128m org.alicebot.server.net.AliceServer $1
My current code:
NSTask *server = [NSTask new];
[server setLaunchPath:#"/bin/sh"];
[server setArguments:[NSArray arrayWithObject:#"/applications/jarvis/brain/server.sh"]];
NSPipe *outputPipe = [NSPipe pipe];
[server setStandardInput:[NSPipe pipe]];
[server setStandardOutput:outputPipe];
[server launch];
NSMutableString *outputString = [NSMutableString string];
while ([outputString rangeOfString:#"Jarvis>"].location == NSNotFound) {
[outputString appendString:[[[NSString alloc] initWithData:[[outputPipe fileHandleForReading] readDataToEndOfFile] encoding:NSUTF8StringEncoding] autorelease]];
NSRunAlertPanel(#"", outputString, #"", #"", #"");
}
The NSRunAlertPanel is just for checking the output. Now my code is freezing and not even getting to the alertpanel.
See answer to this question.
There are a couple of things that should be fixed in your script:
The script should begin with a
shebang. Also make sure that the
script has its executable bit set.
Because the environment variables are set up relative to the shell script directory, you need to make sure that the script directory is the current directory.
You need to export the environment variables that should be visible to the Java process.
In the last line you can use exec to replace the shell process with the Java executable that runs Jetty.
Here is a revised version of your script:
#!/bin/sh
echo Starting Jarvis Program D.
cd "`dirname \"$0\"`"
export ALICE_HOME=.
export SERVLET_LIB=lib/servlet.jar
export ALICE_LIB=lib/aliceserver.jar
export JS_LIB=lib/js.jar
# Set SQL_LIB to the location of your database driver.
export SQL_LIB=lib/mysql_comp.jar
# These are for Jetty; you will want to change these if you are using a different http server.
export HTTP_SERVER_LIBS=lib/org.mortbay.jetty.jar
export PROGRAMD_CLASSPATH=$SERVLET_LIB:$ALICE_LIB:$JS_LIB:$SQL_LIB:$HTTP_SERVER_LIBS
exec java -classpath $PROGRAMD_CLASSPATH -Xms64m -Xmx128m org.alicebot.server.net.AliceServer $1
Invoking the shell script in Objective-C with multiple arguments:
NSTask *server = [NSTask new];
[server setLaunchPath:#"/bin/sh"];
[server setArguments:[NSArray arrayWithObjects:#"/applications/jarvis/brain/server.sh", #"argument", nil]];
...
Using AMShellWrapperTest.app you can filter (save, ...) the stdout stream of server.sh by modifying "- (void)appendOutput:(NSString *)output" in BannerController.m. (... but maybe there is a better way to do this ...)
/*
// output from stdout
- modified AMShellWrapper/AMShellWrapperTest/BannerController.m (http://www.harmless.de/cocoa-code.php)
to print server.sh setup information to "Error Messages:" text output field (or Console.app as an
alternative) and the Q & A dialog to the "Output:" text field
- use of default charliebot, http://sourceforge.net/projects/charliebot/, modified only to run server.sh
with complete path (here: ~/Desktop/charliebot/server.sh) in AMShellWrapperTest.app
*/
- (void)appendOutput:(NSString *)output
{
NSMutableString *outputString = [NSMutableString string];
if (
([output rangeOfString:#"Charlie>"].location != NSNotFound ) || \
([output rangeOfString:#"[Charlie] user>"].location != NSNotFound )
) {
[self write: output];
[self write: #"\n"];
} else {
[outputString appendString: output];
//[outputString writeToFile:#"/dev/console" atomically: NO]; // alternative
[errorOutlet setString:[[errorOutlet string] stringByAppendingString: outputString]];
}
}
yes, but why isn't my code (posted above) not working?
I guess your "Jarvis>" line is the first line of the server.sh ouput stream that expects some user input, which means that this line is incomplete without a terminating newline character "\n". If server.sh had been run in Terminal.app, the user would have to press the return key to let the dialog continue. The conditional code of the while loop (NSNotFound) cannot finish its job on this incomplete line (which would be to abort the while loop) and gets stuck.
You have to drop the while loop and use the 'readInBackgroundAndNotify' mode on NSFileHandle to get non-blocking I/O stdout stream behaviour!
See: NSTask/NSPipe STDIN hangs on large data, sometimes...
So, if you like, just transform the source code of AMShellWrapperTest.app into a pure command-line tool by removing the GUI code.
I have a bat file with the following contents:
set logfile= D:\log.txt
java com.stuff.MyClass %1 %2 %3 >> %logfile%
when I run the bat file though, I get the following:
C:\>set logfile= D:\log.txt
C:\>java com.stuff.MyClass <val of %1> <val of %2> <val of %3> 1>>D:\log.txt
The parameter is incorrect.
I'm almost positive the "The parameter is incorrect." is due to the extraneous 1 in there. I also think this might have something with the encoding of the .bat file, but I can't quite figure out what is causing it. Anyone ever run into this before or know what might be causing it and how to fix it?
Edit
And the lesson, as always, is check if its plugged in first before you go asking for help. The bat file, in version control, uses D:\log.txt because it is intended to be run from the server which contains a D drive. When testing my changes and running locally, on my computer which doesn't have a D drive, I failed to make the change to use C:\log.txt which is what caused the error. Sorry for wasting you time, thanks for the help, try to resist the urge to downvote me too much.
I doubt that that's the problem - I expect the command processor to deal with that part for you.
Here's evidence of it working for me:
Test.java:
public class Test
{
public static void main(String args[]) throws Exception
{
System.out.println(args.length);
for (String arg : args)
{
System.out.println(arg);
}
}
}
test.bat:
set logfile= c:\users\jon\test\test.log
java Test %1 %2 %3 >> %logfile%
On the command line:
c:\Users\Jon\Test> [User input] test.bat first second third
c:\Users\Jon\Test>set logfile= c:\users\jon\test\test.log
c:\Users\Jon\Test>java Test first second third 1>>c:\users\jon\test\test.log
c:\Users\Jon\Test> [User input] type test.log
3
first
second
third
the 1 is not extraneous: it is inserted by cmd.exe meaning stdout (instead of ">>", you can also write "1>>". contrast this to redirecting stderr: "2>>"). so the problem must be with your parameters.
This may seem like a stupid question, but is there an existing D: drive in the context that the bat file runs in?
Once I had a case where a bat file was used as the command line of a task within the Task Manager, but the Run As user was set to a local user on the box, giving no access to network drives.
Interpolated for your case, if the D: drive were a network drive, running the bat file as, say, the local administrator account on that machine instead of a domain user account would likely fail to have access to D:.