Hibernate ManyToOne with #Formula - java

I have two database tables and would like to set up a many to one relationship between the two using Hibernate.
I did not construct these two tables, but were already made when I started on the project. I am new to Hibernate and would like to make a ManyToOne relationship between the two tables.
This normally would be strait forward, but the link between the two tables, "Praxiscode" is not the primary key, and I would like to do something like
#ManyToOne(targetEntity = PraxisIITest.class)
#Fetch(FetchMode.JOIN)
#NotFound(action = NotFoundAction.IGNORE)
#Formula(value = "(SELECT praxis.ID FROM lstPraxis praxis where praxis.Praxiscode=Praxiscode and Testdate BETWEEN praxis.BeginDate AND praxis.EndDate)")
private PraxisIITest praxisIITest;
but when specifying the #Formula described above it throws an exception complaining that a column is not in 'field list'
org.hibernate.exception.SQLGrammarException: Unknown column 'praxisiite1_.praxisIITest_ID' in 'field list'
org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:82)
Here is where ID is specified in PraxisIITest ->
#Entity
#Table(name="lstPraxis")
#Cache(region="edu.uky.cepis.cache.praxisIItest", usage=CacheConcurrencyStrategy.READ_WRITE)
public class PraxisIITest implements java.util.Comparator<PraxisIITest>, Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
#Column(name="ID")
private long id;
Am I going about this all wrong? or am I missing something very basic, My understanding is this should work...
Any thoughts or advice is greatly appreciated! Thanks again in advance!

I think the problem is that you aren't using a valid SQL fragment; it assumes that Hibernate will do some aliasing:
(SELECT praxis.ID FROM lstPraxis praxis where praxis.Praxiscode=Praxiscode and Testdate BETWEEN praxis.BeginDate AND praxis.EndDate)
Testdate doesn't exist in lstPraxis table (according to your images), it is in the tbl20Praxis table. Even if that table is what the PraxisIITest entity is mapped to, I think you need to explicitly do the table join in your #Formula fragment.
I didn't think that Hibernate did any processing of the formula, treating it as native SQL instead. But that makes the error you're seeing all the more confusing...

Related

Hibernate: ManyToOne Relation, Load Many relation Only Once

Using Hibernate 5.2 and Java 8
I have a table named PatientMetaData which has the followng fields (in the DB table itself, hmo is an integer):
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int uid;
private String name;
#ManyToOne
#JoinColumn(name="hmo")
private Hmo hmo;
The Hmo table contains a uid and a name:
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int uid;
private String name;
and is related to the patients table through the uid in hmo table and hmo in patients table.
When loading all the patients, I see that for each patient, there is a query for its HMO.
However there 10K patients and only 7 HMOs, so it seems redundant to load the HMO for each patient.
I there a way to avoid all these queries?
One option is to define the PatientMetadata entity class to have the hmo as an integer so I will only load the patients, then load all the HMOs into a Java map, and finally I will grammatically attach an HMO from the map to each patient.
This looks a little cumbersome.
Is there a better way of doing so directly with Hibernate?
Hibernate has curious behavior when using lazy fetch on a #ManyToOne, so this will probably not work.
I recommend using #BatchSize (2 possible positions, on Hmo class or on the relation in the patient).
Depending on how you retrieve your patients, you can also fetch Hmos via root.fetch() in JPA criteria queries, so that HMos get loaded with a left join.
The workaround is really a hack imo and should be avoided.

#GeneratedValue polymorphic abstract superclass over MySQL

In a Spring MVC application using Hibernate and MySQL, I have an abstract superclass BaseEntity that manages the values of the IDs for all the other entities in the model. The id field uses #GeneratedValue. I am encountering a problem whenever my code tries to save any of the subclasses that extend BaseEntity. The problem comes with the choice of GenerationType for the #GeneratedValue.
At every place in my code where a subclass of BaseEntity tries to save to the underlying MySQL database, I get the following error:
ERROR SqlExceptionHelper - Table 'docbd.hibernate_sequences' doesn't exist
I have read many postings about this on SO and on google, but they either deal with other databases (not MySQL) or they do not deal with abstract superclasses. I cannot solve the problem by using GenerationType.IDENTITY because I am using an abstract superclass to manage id fields for all entities in the model. Similarly, I cannot use GenerationType.SEQUENCE because MySQL does not support sequences.
So how do I solve this problem?
Here is the code for BaseEntity.java:
#Entity
#Inheritance(strategy = InheritanceType.TABLE_PER_CLASS)
public abstract class BaseEntity {
#Id
#GeneratedValue(strategy = GenerationType.TABLE)
protected Integer id;
public void setId(Integer id) {this.id = id;}
public Integer getId() {return id;}
public boolean isNew() {return (this.id == null);}
}
Here is an example of the code for one of the entities that extends BaseEntity:
#Entity
#Table(name = "ccd")
public class CCD extends BaseEntity{
//other stuff
}
Here is the DDL:
CREATE TABLE IF NOT EXISTS ccd(
id int(11) UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
#other stuff
)engine=InnoDB;SHOW WARNINGS;
Here is the JPQL code in the DAO:
#Override
#Transactional
public void saveCCD(CCD ccd) {
if (ccd.getId() == null) {
System.out.println("[[[[[[[[[[[[ about to persist CCD ]]]]]]]]]]]]]]]]]]]]");
this.em.persist(ccd);
this.em.flush();
}
else {
System.out.println("]]]]]]]]]]]]]]]]]] about to merge CCD [[[[[[[[[[[[[[[[[[[[[");
this.em.merge(ccd);
this.em.flush();
}
}
EDIT:
The reason I cannot use #MappedSuperClass in this situation is that I need to have ManyToOne relationships that allow for multiple subtypes to be used interchangeably. Look at the AccessLog class below as an example. It has an actor_entity and a target_entity. There can be many types of actor entities and many types of target entities, but they all inherit from BaseEntity. This inheritance enables the underlying accesslogs data table in MySQL to just have one actor_entity_id field and just one target_entity_id field instead of having to have several fields for each. When I change #Entity above BaseEntity to #MappedSuperClass, a different error gets thrown indicating that AccessLog cannot find BaseEntity. BaseEntity needs #Entity annotation in order for AccessLog to have polymorphic properties.
#Entity
#Table(name = "accesslogs")
public class AccessLog extends BaseEntity{
#ManyToOne
#JoinColumn(name = "actorentity_id")
private BaseEntity actor_entity;
#ManyToOne
#JoinColumn(name = "targetentity_id")
private BaseEntity target_entity;
#Column(name="action_code")
private String action;
//getters, setters, & other stuff
}
SECOND EDIT:
As per JBNizet's suggestion, I created a hibernate_sequences table as follows:
CREATE TABLE IF NOT EXISTS hibernate_sequences(
sequence_next_hi_value int(11) UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY
)engine=InnoDB;SHOW WARNINGS;
But now I am getting the following error:
Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'sequence_name' in 'where clause'
Here is the hibernate sql causing the error, followed by the next 2 lines of the stack trace:
Hibernate: select sequence_next_hi_value from hibernate_sequences where sequence_name = 'BaseEntity' for update
ERROR MultipleHiLoPerTableGenerator - HHH000351: Could not read or init a hi value
com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'sequence_name' in 'where clause'
How do I resolve this?
What a mess... AUTO_INCREMENT is MySQL's hidden sequence. The radical problem is that MySQL can not insert and return the PK at the same time, but Hibernate need this while INSERTing a new Entity.
The Problems you run into:
If Hibernate save a new Entity, he try to immerdentelly set the id to the new EntityBean. Therefore hibernate must read what ID will the Database use before hibernate save the new Tuple to the Table.
If you have multiple Servers who access the database, you shall let hibernate's session-factory decide to use the built-in sequence(AUTO-INCREMENT) or let hibernate decide (GenerationType.AUTO/GenerationType.IDENTITY) how large the open range of reserved PK's is (Job of a DB-Architect). (We have about 20 servers to one Database, so on a good-used table we use a PK-distance of +100). If only one server have access to the database GenerationType.TABLE shall be correct.
Hibernate must calculate the next id by yourself using max(*)+1 but:
What if two requests ask for max(*)+1 at the same time/with the same result? Right: The last try to insert will fail.
So you need to have a Table LAST_IDS in the database who stores the last Table-PK's. If you like to add one, you must do this steps:
Start read-optimistic transaction.
SELECT MAX(address_id) FROM LAST_IDS
store the maximum in a java-variable i.e.: $OldID.
$NewID = $OldID + 1. (+100 in pessimistic-lock)
UPDATE LAST_IDS SET address_id= $newID WHERE address_id= $oldID?
commit the read-optimistic transaction.
if commit was successfull, store $newID to setID() in the HibernateBean you like to save.
Finally let Hibernate call the insert.
This is the only way i know.
BTW: Hibernate-Entitys shall only use inheritance if the Database support inheritance between tables like PostgreSQL or Oracle.
Because you use the TABLE identifier generator you need to have that table created. If you are not using the enhanced identifier generators, chances are you are going to use the MultipleHiLoPerTableGenerator.
The MultipleHiLoPerTableGenerator can use one table for all table identifier generators.
My suggestion is to grab the table ddl from your integration tests, in case you use hbmddl to build the test schema. If you use flyway or liquibase for testing, you can add a maven plugin to generate the ddl schema.
Once you have the schema, you need to take the exact create table command and make add it to your MySQL database.

Hibernate mapping a specific field to be loaded by a table join

Is there a way I can map a field in an hibernate object to be loaded with a table query?
As an example lets say Table_Message has fields id(int),message_key(varchar),message_content(Clob),language(varchar). This table will hold messages in different languages(locale).
And another table thats mapped to an entity using hibernate. Comments with fields id(int),comment_message_id(varchar),created_date(datetime). comment_message_id refers to Table_Message's message_key column.
EDIT: Table_Message is NOT a mapped Entity in hibernate
Assuming my comment class is
public class Comment
{
int id;
String message;
Date createdDate;
}
Is there a way to tell hibernate to load message by joining Comment table and Table_Message table by message_key with a default locale (for example 'en').
Basically is there a way to tell hibernate to load a field by running a specific query? And if so what is that way?
I know about writing a Custom SQL query for loading the entity. But since I'm using XDoclet there doesn't seem to be a way to do that. Also it will be very convenient if there's a way to do that for a single field.
I guess ResultTransformer may help you in this. Please check
http://docs.jboss.org/hibernate/orm/3.3/api/org/hibernate/transform/ResultTransformer.html
http://stackoverflow.com/questions/6423948/resulttransformer-in-hibernate-return-null
You must join the tables by comment_message_id with message_key and further filter the result by language. I assume the message_key is unique.
As a side notice: you should use integer keys to have better performance.
You can try to write a database view in SQL and create an entity to opaque the view:
CREATE VIEW Comment_Table_Message AS
SELECT c.id, c.comment_message_id, c.created_date, m.id AS mid,
m.message_content, m.language
FROM Comment c, Table_Message m
WHERE c.comment_message_id = t.message_key;
Now you can create an entity CommentTableMessage and use JPQL to filter results by language:
SELECT x FROM CommentTableMessage x WHERE x.language=?1
If Table_Message was a Hibernate entity you would write (in JPA terms):
#Entity
public class Comment
{
int id;
#ManyToOne()
#JoinColumn(name="comment_message_id")
TableMessage tableMessage;
String message;
Date createdDate;
}
#Entity
public class TableMessage {
int id;
#Id
String messageKey;
bytes[] messageContent; //I don't know how you want to deal with Blobs?
String language;
}
Having that you can write a simple JPA Query: (Can you use JPA ? - next assumption)
SELECT c FROM Comment c WHERE c.tableMessage.language=?1

Hibernate zeroToOne

I am trying to establish a relationship between 2 entities which would be zero-to-one. That is, the Parent can be saved without the associated Child entity and also along with the assoicated Child.
Following are the 2 Entity classes...
Employee (Parent)
public class Employee {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#Column(name="EMP_NAME")
private String name;
#PrimaryKeyJoinColumn
#OneToOne(cascade = {CascadeType.ALL})
private EmployeeInfo info;
#Column(name="EMP_ENUM")
private Integer enumId;
EmployeeInfo (Child)
public class EmployeeInfo {
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
private Long id;
#Column(name="EMPLOYEE_EMAIL")
private String email;
With such kind of a relation and id column of the only Parent (Employee) table set to AUTO INCREMENT in MySql DB, the problem is that while saving a Parent->Child object graph, I get the following exception
org.springframework.orm.hibernate3.HibernateJdbcException: JDBC exception on Hibernate data access: SQLException for SQL [insert into EMP_INFO
Caused by: java.sql.SQLException: Field 'id' doesn't have a default value
I tried setting the Child Table's Id property to AUTO INCREMENT in the DB , and the persistence of such a Parent->Child object graph is successful.
However, the problem described here surfaces, because I have a scenario in which I would like to save the parent (Employee) object without the associated EmpInfo object, and hence do NOT want to have AUTO INCREMENT on the Child's id column.
One solution could be not use the PrimaryKeyJoinColumn, but use a particular JoinColumn, but that adds an unnecessary column to my existing Table.
Has anyone come across such a problem? If yes, any pointers would be much helpful.
Finally, I got it working thanks to Pascal and some googling from my side. Apparently, I cannot use the Native key generator for such relationships where the parent can exist without the child (optional = true).
The thing that worked finally was the following, leaving me the downside of having to deal with Hibernate specific annotation (#GenericGenerator) and also having to make-do with bi-directional relationships instead of the unidirectional that I wanted.
Employee (Parent) class remains unchanged as above. It has AUTO INCREMENT on the Id column.
As for the child class (EmployeeInfo) it changed to the following, and again WITHOUT having the AUTO INCREMENT set on the Id column.
#Table(name="EMP_INFO")
#Entity
public class EmployeeInfo {
#Id
#GeneratedValue(generator="foreign")
#GenericGenerator(name="foreign", strategy = "foreign", parameters={
#Parameter(name="property", value="verifInfo")})
private Long id;
#OneToOne(optional=false)
#JoinColumn (name="id")
private Employee emp;
#Column(name="EMPLOYEE_EMAIL")
private String email;
This helped me achieve what I wanted but on the downside, GenericGenerator is not a JPA annotation, it is a hibernate annotation, and sadly I have to make do with that as of now because JPA does not currently support this(or any similar) annotation.
Anyway, it helps to get through such cases :-)
I have a scenario in which I would like to save the parent (Employee) object without the associated EmpInfo object.
The optional attribute of a OneToOne is true by default, which is what you want.
However, you are somehow misusing the #PrimaryKeyJoinColumn here (well, it actually depends on what you really want to achieve but your current combination of annotations is not correct).
IF you want to map a OneToOne with a shared primary-key, use the #PrimaryKeyJoinColumn. But in that case, don't use a GeneratedValue on EmployeeInfo and set the id manually or, if you don't want to set it manually, use the Hibernate specific foreign generator that I already mentioned in your previous question. Check also the related question mentioned below.
And IF you do not want to use a shared primary key (like in your current code since you're trying to get the id generated by the database), then do not use the PrimaryKeyJoinColumn.
You have to make a choice.
References
JPA 1.0 specification:
9.1.32 PrimaryKeyJoinColumn Annotation
Related question
JPA Hibernate One-to-One relationship.

Does JPA support mapping to sql views?

I'm currently using Eclipselink, but I know now days most JPA implementations have been pretty standardized. Is there a native way to map a JPA entity to a view? I am not looking to insert/update, but the question is really how to handle the #Id annotation. Every entity in the JPA world must have an ID field, but many of the views I have created do not conform to this. Is there native support for this in the JPA or do I need to use hacks to get it to work? I've searched a lot and found very little information about doing this.
While using the #Id annotation with fields of directly supported types is not the only way to specify an entity's identity (see #IdClass with multiple #Id annotations or #EmbeddedId with #Embedded), the JPA specification requires a primary key for each entity.
That said, you don't need entities to use JPA with database views. As mapping to a view is no different from mapping to a table from an SQL perspective, you could still use native queries (createNativeQuery on EntityManager) to retrieve scalar values instead.
I've been looking into this myself, and I've found a hack that I'm not 100% certain works but that looks promising.
In my case, I have a FK column in the view that can effectively function as a PK -- any given instance of that foreign object can only occur once in the view. I defined two objects off of that one field: one is designated the ID and represents the raw value of the field, and the other is designated read-only and represents the object being referred to.
#Id
#Column(name = "foreignid", unique = true, nullable = false)
public Long getForeignId() {
...
#OneToOne
#JoinColumn(name = "foreignid", insertable=false, updatable=false)
public ForeignObject getForeignObject() {
...
Like I said, I'm not 100% sure on this one (and I'll just delete this answer if it turns out not to work), but it got my code past a particular crash point.
Dunno if it applies to your specific situation, though. And there's an excellent chance that after 11 months, you no longer care. :-) What the hell, that "Necromancer" badge doesn't just earn itself....
In my view I have a "unique" id, so I mapped it as the Entity id.
It works very well:
#Entity
#Table(name="table")
#NamedQuery(name="Table.findAll", query="SELECT n FROM Table n")
public class Table implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#Column(name="column_a")
private int columnA;
JPA - 2.5.4
CREATE MATERIALIZED VIEW IF NOT EXISTS needed_article as select product_id, count(product_id) as count from product_article group by product_id;
CREATE MATERIALIZED VIEW IF NOT EXISTS available_article as select product_id, count(product_id) as count from article a inner join product_article p
on a.id = p.article_id and a.stock >= p.amount_of group by product_id;
CREATE UNIQUE INDEX productId_available_article ON available_article (product_Id);
CREATE UNIQUE INDEX productId_needed_article ON needed_article (product_Id);
Entity.java
#Entity
#Immutable // hibernate import
#Getter
#Setter
public class NeededArticle {
#Id
Integer productId;
Integer count;
}
Repository.java
#Repository
public interface AvailableProductRepository extends CrudRepository<AvailableArticle, Integer> {
#Query("select available.productId from AvailableArticle available, NeededArticle needed where available.productId = needed.productId and available.count = needed.count")
List<Integer> availableProduct();

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