I'm currently using Eclipselink, but I know now days most JPA implementations have been pretty standardized. Is there a native way to map a JPA entity to a view? I am not looking to insert/update, but the question is really how to handle the #Id annotation. Every entity in the JPA world must have an ID field, but many of the views I have created do not conform to this. Is there native support for this in the JPA or do I need to use hacks to get it to work? I've searched a lot and found very little information about doing this.
While using the #Id annotation with fields of directly supported types is not the only way to specify an entity's identity (see #IdClass with multiple #Id annotations or #EmbeddedId with #Embedded), the JPA specification requires a primary key for each entity.
That said, you don't need entities to use JPA with database views. As mapping to a view is no different from mapping to a table from an SQL perspective, you could still use native queries (createNativeQuery on EntityManager) to retrieve scalar values instead.
I've been looking into this myself, and I've found a hack that I'm not 100% certain works but that looks promising.
In my case, I have a FK column in the view that can effectively function as a PK -- any given instance of that foreign object can only occur once in the view. I defined two objects off of that one field: one is designated the ID and represents the raw value of the field, and the other is designated read-only and represents the object being referred to.
#Id
#Column(name = "foreignid", unique = true, nullable = false)
public Long getForeignId() {
...
#OneToOne
#JoinColumn(name = "foreignid", insertable=false, updatable=false)
public ForeignObject getForeignObject() {
...
Like I said, I'm not 100% sure on this one (and I'll just delete this answer if it turns out not to work), but it got my code past a particular crash point.
Dunno if it applies to your specific situation, though. And there's an excellent chance that after 11 months, you no longer care. :-) What the hell, that "Necromancer" badge doesn't just earn itself....
In my view I have a "unique" id, so I mapped it as the Entity id.
It works very well:
#Entity
#Table(name="table")
#NamedQuery(name="Table.findAll", query="SELECT n FROM Table n")
public class Table implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#Column(name="column_a")
private int columnA;
JPA - 2.5.4
CREATE MATERIALIZED VIEW IF NOT EXISTS needed_article as select product_id, count(product_id) as count from product_article group by product_id;
CREATE MATERIALIZED VIEW IF NOT EXISTS available_article as select product_id, count(product_id) as count from article a inner join product_article p
on a.id = p.article_id and a.stock >= p.amount_of group by product_id;
CREATE UNIQUE INDEX productId_available_article ON available_article (product_Id);
CREATE UNIQUE INDEX productId_needed_article ON needed_article (product_Id);
Entity.java
#Entity
#Immutable // hibernate import
#Getter
#Setter
public class NeededArticle {
#Id
Integer productId;
Integer count;
}
Repository.java
#Repository
public interface AvailableProductRepository extends CrudRepository<AvailableArticle, Integer> {
#Query("select available.productId from AvailableArticle available, NeededArticle needed where available.productId = needed.productId and available.count = needed.count")
List<Integer> availableProduct();
Related
consider an entity with just an id and text field:
#lombok.Data
class Entity {
#javax.persistence.Id
UUID id;
String name;
}
consider that the table definition is as follows:
create table entity (
id uniqueidentifier not null primary key default newid(),
name varchar(max)
);
I am then curious why this doesn't work and how i could make it work:
UUID savedId = entityRepository.save(new Entity().setName("entity name")).getId();
In JPA, entity IDs can be either assigned by the application code, or generated (by the JPA provider, such as Hibernate, or by the database). In many situations, it's desirable to have the entity IDs be generated instead of applicaiton-assigned; it seems like that's what you are expecting.
If so, you need to annotate the id field with #GeneratedValue. For example:
class Entity {
#Id
#GeneratedValue
UUID id;
String name;
}
Note that there are considerations to be made regarding the generation strategy, so you'll want to educate yourself about them and make the right choice based on your situation. This is a good page that discusses the options. This SO Answer also is worth reading (the author is a well-known expert on JPA and Hibernate).
I have an #Entity A that references another entity B using OneToOne relation ship. I fetch entity A using spring data JpaRepository
A a = aRepository.findById(1);
int b_id = a.getB().getId();
As you can see I need to query ID of the B table, however in order to do that, I need to call getter of the B table, which will cause lazy-loading the B table itself. I do not want to do that because the only thing I need is the get ID, nothing else, and that ID is present in the first A table.
Is there any trick that will help me to get ID of the dependent table without triggering new query?
UPDATE
#Entity
class A {
#Id
private Long id;
#OneToOne
private B b;
}
#Entity
class {
#Id
private Long id;
}
Without looking at the entity mapping, I suspect, your entity classes might be using hibernate annotations on the field. With this if you call even the getId() method as in a.getB().getId() on the entity it will result in initializing the proxy (i.e., B object) and hits the database to fetch it.
So if the intent is only to get the id of the entity you can place the hibernate annotations on the getter methods instead. This doesn't result initializing the proxy (B object) to return the id. Although accessing any property other than id will result in hitting the database.
Have a look at related bug at HHH-3718
So, try using property/getter AccessType instead of field access. As an example instead of placing the annotations on field
#Id
#GeneratedValue(...)
private long id;
place them on the getters
#Id
#GeneratedValue(...)
public long getId() { ... }
Make sure you make similar changes to all the fields of B entity. Although you can explore #Access(AccessType.PROPERTY/FIELD) later.
There is already a related bug HHH-3718 regarding this behavior.
And a related topic on hibernate forum regarding field vs property access type that might be of interest for you Field Vs Property access
Posting your entities classes would help, if this doesn't resolve the issue.
I'm using Spring 3.2 with Roo 1.2.3 to build a database-backed Java application via Hibernate. I have several bidirectional OneToMany/ManyToOne relationships among the tables in my database. When I set up the ManyToOne side of the relationship using #JoinColumn (via "field reference" in Roo), a new field whose type is the related entity (the "one" in ManyToOne) is created. However, once this is done, there seems to be no way to access the underlying column value on which the ManyToOne relationship is based. This is a problem when the underlying join column contains data needed by the application (i.e. when the join column contains product stock numbers).
Is there any way to set up my entity class so that the column on which its ManyToOne relationship is based remains accessible without traversing the new join property? How can I define an accessor method for the value of this column?
I've been looking online for an answer to this question for several days, but to no avail. Thanks in advance for your help.
just map the column a second time with insertable=false and updateable=false
To make it more concrete. It's possible to do a HQL-SELCT and restrict a ManyToOne relationship, without any join in the resulting SQL:
Instead of using a join in
session.createQuery("FROM Person person WHERE person.adress.id = 42")
we use can use the adress_idcolumn
session.createQuery("FROM Person person WHERE person.adressId = 42")
This works, if you specify an additional adressId field, which is only used as mapping info for Hibernate:
#Entity
#Access(AccessType.FIELD)
public class Person{
#Id
String id;
#JoinColumn(name = "adress_id")
#ManyToOne(fetch = FetchType.LAZY)
#Nullable
public Adress adress;
#Column(name = "adress_id", insertable = false, updatable = false)
private String adressId;
}
#Entity
#Access(FIELD)
public class Adress{
#Id
String id;
}
The AccessType.FIELD is not needed (But we can leave getters/setters in example). The FetchType.LAZY and #Nullable are also optional, but make it clear when it makes sense to use it. We are able to load Person entities which have a specific Address (we know the address id). But we don't need a join because it's not needed for the WHERE-clause and not for the initial fetch (the address can be fetched lazy).
I wanted to know if there is a way to get in a One2Many relationship a field of the One side that is an aggregate of the Many side.
Let's take the following example:
#Entity
public class A {
#Id
private Long id;
#OneToMany (mappedBy="parentA")
private Collection<B> allBs;
// Here I don't know how to Map the latest B by date
private B latestB;
// Acceptable would be to have : private Date latestBDate;
}
#Entity
public class B {
#Id
private Long id;
private Date date;
#ManyToOne (targetEntity=A.class)
private A parentA;
}
My question is how can I make the mapping of the field latestB in the A entity object without doing any de-normalization (not keeping in sync the field with triggers/listeners)?
Perhaps this question gives some answers, but really I don't understand how it can work since I still want to be able to fetch all childs objects.
Thanks for reading/helping.
PS: I use hibernate as ORM/JPA provider, so an Hibernate solution can be provided if no JPA solution exists.
PS2: Or just tell me that I should not do this (with arguments of course) ;-)
I use hibernate as ORM/JPA provider, so an Hibernate solution can be provided if no JPA solution exists.
Implementing the acceptable solution (i.e. fetching a Date for the latest B) would be possible using a #Formula.
#Entity
public class A {
#Id
private Long id;
#OneToMany (mappedBy="parentA")
private Collection<B> allBs;
#Formula("(select max(b.some_date) from B b where b.a_id = id)")
private Date latestBDate;
}
References
Hibernate Annotations Reference Guide
2.4.3.1. Formula
Resources
Hibernate Derived Properties - Performance and Portability
See,
http://en.wikibooks.org/wiki/Java_Persistence/Relationships#Filtering.2C_Complex_Joins
Basically JPA does not support this, but some JPA providers do.
You could also,
- Make the variable transient and lazy initialize it from the OneToMany, or just provide a get method that searches the OneToMany.
- Define another foreign key to the latest.
- Remove the relationship and just query for the latest.
I am trying to establish a relationship between 2 entities which would be zero-to-one. That is, the Parent can be saved without the associated Child entity and also along with the assoicated Child.
Following are the 2 Entity classes...
Employee (Parent)
public class Employee {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#Column(name="EMP_NAME")
private String name;
#PrimaryKeyJoinColumn
#OneToOne(cascade = {CascadeType.ALL})
private EmployeeInfo info;
#Column(name="EMP_ENUM")
private Integer enumId;
EmployeeInfo (Child)
public class EmployeeInfo {
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
private Long id;
#Column(name="EMPLOYEE_EMAIL")
private String email;
With such kind of a relation and id column of the only Parent (Employee) table set to AUTO INCREMENT in MySql DB, the problem is that while saving a Parent->Child object graph, I get the following exception
org.springframework.orm.hibernate3.HibernateJdbcException: JDBC exception on Hibernate data access: SQLException for SQL [insert into EMP_INFO
Caused by: java.sql.SQLException: Field 'id' doesn't have a default value
I tried setting the Child Table's Id property to AUTO INCREMENT in the DB , and the persistence of such a Parent->Child object graph is successful.
However, the problem described here surfaces, because I have a scenario in which I would like to save the parent (Employee) object without the associated EmpInfo object, and hence do NOT want to have AUTO INCREMENT on the Child's id column.
One solution could be not use the PrimaryKeyJoinColumn, but use a particular JoinColumn, but that adds an unnecessary column to my existing Table.
Has anyone come across such a problem? If yes, any pointers would be much helpful.
Finally, I got it working thanks to Pascal and some googling from my side. Apparently, I cannot use the Native key generator for such relationships where the parent can exist without the child (optional = true).
The thing that worked finally was the following, leaving me the downside of having to deal with Hibernate specific annotation (#GenericGenerator) and also having to make-do with bi-directional relationships instead of the unidirectional that I wanted.
Employee (Parent) class remains unchanged as above. It has AUTO INCREMENT on the Id column.
As for the child class (EmployeeInfo) it changed to the following, and again WITHOUT having the AUTO INCREMENT set on the Id column.
#Table(name="EMP_INFO")
#Entity
public class EmployeeInfo {
#Id
#GeneratedValue(generator="foreign")
#GenericGenerator(name="foreign", strategy = "foreign", parameters={
#Parameter(name="property", value="verifInfo")})
private Long id;
#OneToOne(optional=false)
#JoinColumn (name="id")
private Employee emp;
#Column(name="EMPLOYEE_EMAIL")
private String email;
This helped me achieve what I wanted but on the downside, GenericGenerator is not a JPA annotation, it is a hibernate annotation, and sadly I have to make do with that as of now because JPA does not currently support this(or any similar) annotation.
Anyway, it helps to get through such cases :-)
I have a scenario in which I would like to save the parent (Employee) object without the associated EmpInfo object.
The optional attribute of a OneToOne is true by default, which is what you want.
However, you are somehow misusing the #PrimaryKeyJoinColumn here (well, it actually depends on what you really want to achieve but your current combination of annotations is not correct).
IF you want to map a OneToOne with a shared primary-key, use the #PrimaryKeyJoinColumn. But in that case, don't use a GeneratedValue on EmployeeInfo and set the id manually or, if you don't want to set it manually, use the Hibernate specific foreign generator that I already mentioned in your previous question. Check also the related question mentioned below.
And IF you do not want to use a shared primary key (like in your current code since you're trying to get the id generated by the database), then do not use the PrimaryKeyJoinColumn.
You have to make a choice.
References
JPA 1.0 specification:
9.1.32 PrimaryKeyJoinColumn Annotation
Related question
JPA Hibernate One-to-One relationship.