I have a DateTime object DT which stores current time. When I print DT, I want it to only print the time part, ie HH-MM-SS (H = hours, M = minutes, S = seconds) and ignore the date part.
How can I do this ? For that matter, is it even possible to create a date time object which will only contain HH-MM-SS and nothing related to date ? If that is true, then I can simply print it instead of extracting the HH-MM-SS part.
Thanks.
If you only want the time, you should use a LocalTime instead of a DateTime. You can use DateTime.toLocalTime() to get the time part of an existing DateTime.
If you actually want to keep the DateTime but only reveal the time part when formatting, you can create a DateTimeFormatter with a pattern which only includes the time parts, but I'd usually consider this a design smell.
You can use Java date formatter which is in java.util.Date package.
Like :
Date todaysDate = new java.util.Date();
1. // Formatting date into yyyy-MM-dd HH:mm:ss e.g 2008-10-10 11:21:10
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String formattedDate = formatter.format(todaysDate);
2. // Formatting date into yyyy-MM-dd e.g 2008-10-10
formatter = new SimpleDateFormat("yyyy-MM-dd");
formattedDate = formatter.format(todaysDate);
3. // Formatting date into MM/dd/yyyy e.g 10/10/2008
formatter = new SimpleDateFormat("MM/dd/yyyy");
formattedDate = formatter.format(todaysDate);
With Java you can do it like this
Date obj = new Date() ;
System.out.println(new SimpleDateFormat("hh:mm:ss").format(obj)) ;
but it could be an expensive call.
But jodatime gives LocalTime which you can try out.
Related
I am creating a DSL with ANTLR 4, and I wonder if it is possible to convert several date format (string) to date with the same function without passing the format for example if my DSL is like that
date1 = "2020-05-08"
date2 = "2020/05/08"
date3 = "20200508"
...
and in my java code I convert the string directly to date without knowing the format for example
Date date1 = convertToDate(date1);
Date date2 = convertToDate(date2);
Date date1 = convertToDate(date3);
instead of writing
Date date1 = convertToDate(date1,"yyyy-mm-dd");
Date date2 = convertToDate(date2,"yyyy/mm/dd");
Date date1 = convertToDate(date3,"yyyymmdd");
Since Java 8, which introduced the new Date and Time API, you are no longer advised to use Date, Calendar, SimpleDateFormat and so on. Those are now legacy types.
Also, if you intend to parse the month, you are supposed to use MM instead of mm (which indicates minutes).
With the new Date and Time API, you could use DateTimeFormatter with optional patterns using [ and ]. Then you can parse the string dates to LocalDate instances, as shown below:
DateTimeFormatter dateFormatter = new DateTimeFormatterBuilder()
.appendPattern("[yyyy-MM-dd]")
.appendPattern("[yyyy/MM/dd]")
.appendPattern("[yyyyMMdd]")
.toFormatter();
LocalDate date1 = LocalDate.parse("2020-05-08", dateFormatter);
LocalDate date2 = LocalDate.parse("2020/05/08", dateFormatter);
LocalDate date3 = LocalDate.parse("20200508", dateFormatter);
System.out.println(date1);
System.out.println(date2);
System.out.println(date3);
In the example you've passed you can remove all non digit symbols to use only one convert function. Ex:
date1 = "2020-05-08"
date2 = "2020/05/08"
date3 = "20200508"
...
dateN = removeSymbols(dateN);
Date date = convertToDate(dateN,"yyyymmdd");
To remove the non digit you can use this function:
dateN = dateN.replaceAll("\\D", "");
You should be able to accomplish this with a simple regex.
Pattern datePattern = Pattern.compile("^(?<Year>\\d{4})[/-]?(?<Month>\\d{2})[/-]?(?<Day>\\d{2})$")
Then build the date with the match groups.
I need to format a String that looks like this:
"2018-07-20 18:53:46.598000 +02:00:00"
into a DateTime object like this:
20/07/2018 (HH with Timezone applied):53:46
My approach has been:
String dateTimePattern = "dd/MM/yyyy HH:mm:ss";
SimpleDateFormat dateTimeFormat = new SimpleDateFormat(dateTimePattern);
Date feUltModDateTime = dateTimeFormat.parse(feUltMod);
feUltMod = feUltModDateTime.toString();
But I'm getting a parse error:
java.text.ParseException: Unparseable date: "2018-07-20 18:53:46.598000 +02:00:00"
java.time
DateTimeFormatter origFormatter
= DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss.SSSSSS XXXXX");
DateTimeFormatter desiredFormatter = DateTimeFormatter.ofPattern("dd/MM/uuuu HH:mm:ss");
ZoneId desiredZone = ZoneId.of("America/Fort_Nelson");
String feUltMod = "2018-07-20 18:53:46.598000 +02:00:00";
OffsetDateTime dateTime = OffsetDateTime.parse(feUltMod, origFormatter);
ZonedDateTime dateTimeWithTimeZoneApplied = dateTime.atZoneSameInstant(desiredZone);
feUltMod = dateTimeWithTimeZoneApplied.format(desiredFormatter);
System.out.println(feUltMod);
Output from this snippet is:
20/07/2018 09:53:46
Generally you need two formatters for converting a date or date-time from one format to another: one that specifies the format to convert from and one that specifies the format to convert to.
into a DateTime object like this
A date-time object doesn’t have a format, so in that respect cannot be “like this”. dateTimeWithTimeZoneApplied in the above snippet is in the specified time zone, so has the hours adjusted. After converting to this time zone I have formatted into a string in the format you mentioned, in case you wanted this (I didn’t find it clear).
I am using and recommending java.time, the modern Java date and time API. The date and time classes you were using, Date and SimpleDateFormat, are long outdated and poorly designed, it’s not worth struggling with them. Also SimpleDateFormat supports only milliseconds so can only work correctly with exactly 3 decimals on the seconds, not with the 6 decimals you have got.
Link: Oracle tutorial: Date Time explaining how to use java.time.
final SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm");
Date df = new Date();
String yourString = sdf.format(df);
Date parsedDate = sdf.parse(yourString);
Timestamp sqlDate = new java.sql.Timestamp(parsedDate.getTime());
The above code will give you current Timestamp.Timestamp will provide better feasibilty
I have a string like this 210115 I want to represent it as 21:01:15 any ideas?.
I tried using Gregorian calendar but it adds date to it which I don't want
SimpleDateFormat sdf = new SimpleDateFormat("HHmmss");
Date date = new Date();
try{
date = sdf.parse("210115");
}
catch(Exception e){
}
Calendar calendar = GregorianCalendar.getInstance();
calendar.setTime(date);
System.out.print(calendar.getTime());
Output is Thu Jan 01 21:01:15 UTC 1970 but what I want is just 21:01:15
Thanks.
To output a formatted date, you use another SimpleDateFormat object with a pattern with the format you want.
In this case, it sounds like you might want to use something like
SimpleDateFormat outputFormat = new SimpleDateFormat("HH:mm:ss");
System.out.println( outputFormat.format(date) );
So what you want is just a time, without time zone. I would recommend using the LocalTime class, which is exactly that, instead of the Date class.
LocalTime time = LocalTime.parse("210115", DateTimeFormatter.ofPattern("HHmmss"));
If u r getting the date string in "210115" this format and you want it in "21:01:15" format then why are you using date format.
Simply do string operation as:
String time="210115";
String newtime=time.substring(0,2)+":"+time.substring(2,4)+":"+time.substring(4,6);
System.out.println(newtime);
you will get the required format.21:01:15
My first attempt was:
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z");
Date date = formatter.parse(string);
It throws ParseException, so I found this hack:
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z");
TimeZone timeZone = TimeZone.getTimeZone("Etc/GMT");
formatter.setTimeZone(timeZone);
Date date = formatter.parse(string);
It did not work either, and now I'm stuck. It parses without problems if I just change the timezone to "GMT".
edit: An example string to parse would be "2011-11-29 10:40:24 Etc/GMT"
edit2: I would prefer not to remove timezone information completely. I am coding a server that receives the date from an external user, so perhaps other dates will have other timezones.
To be more precise: This specific date I receive is from the receipt from the apple server after making an in app purchase on an iphone app, but I could also receive dates from other sources.
Don't know if this question is still relevant to you, but if you use Joda time, this'll work:
DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss ZZZ").parseDateTime(s)
Without Joda time the following will work (bit more work though):
String s = "2011-11-29 10:40:24 Etc/GMT";
// split the input in a date and a timezone part
int lastSpaceIndex = s.lastIndexOf(' ');
String dateString = s.substring(0, lastSpaceIndex);
String timeZoneString = s.substring(lastSpaceIndex + 1);
// convert the timezone to an actual TimeZone object
// and feed that to the formatter
TimeZone zone = TimeZone.getTimeZone(timeZoneString);
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
formatter.setTimeZone(zone);
// parse the timezoneless part
Date date = formatter.parse(dateString);
It didn't work for me either the thing is I tried setting TimeZone of SimpleDateFormatter to "Etc/GMT" and then formatted a new date here is the output:
2011-11-30 10:46:32 GMT+00:00
So Etc/GMT is being translated as GMT+00:00
If you really want to stick to parse "2011-09-02 10:26:35 Etc/GMT" then following will help too without even considering explicit Timezone change:
java.text.SimpleDateFormat isoFormat = new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss 'Etc/GMT'");
isoFormat.parse("2010-05-23 09:01:02 Etc/GMT");
Works fine.
Following code is working for me
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
sdf.setTimeZone(TimeZone.getTimeZone("Etc/GMT"));
try { System.out.println( sdf.parse("2011-09-02 10:26:35 Etc/GMT") );
} catch (ParseException e){
e.printStackTrace();
}
I have My Database data in this format
18-NOV-10
I have to pass the same format into java.util.Date like this
Date date = new java.util.Date(dateformater);
so that the result of java.util.Date is like this 18-NOV-10
Is this possible ??
I tried this way
String strDate = "12-NOV-07";
SimpleDateFormat sdfSource = new SimpleDateFormat("dd-MMM-yy");
Date date = sdfSource.parse(strDate);
System.out.println(date);
But i am getting the result as "Mon Nov 12 00:00:00 IST 2007 " which i want it only
12-NOV-07"
You can use java.text.DateFormat (actually SimpleDateFormat) to get you where you want to go, but maybe you shouldn't be storing the dates as strings in your database. It will do output and parsing.
SimpleDateFormat sdf =
new SimpleDateFormat("DD-MMM-YY");
Date parsed = sdf.parse(dateString);
See http://javatechniques.com/blog/dateformat-and-simpledateformat-examples/
Once you get the Date, you can turn it into the format you want but it will be held in memory as a Date object. You can get it in the form you want using
String dateString = sdf.format(parsed);
As others have pointed out, you should probably store your dates as dates, not strings; nevertheless...
If you want to turn a Date back into a string in that format you can use the following:
DateFormat formatter = new SimpleDateFormat("dd-MMM-yy");
Date date = new Date();
String dateStr = formatter.format(date); // Gives "22-May-11"
If you need MAY instead of May, just use toUpperCase() on the resultant string.
DateFormat sdf = new SimpleDateFormat("dd-MMM-yy");
Date d = sdf.parse("18-NOV-10");
Try System.out.println(sdfSource.format(date).toUpperCase()); instead. The Date object will always have a time component to it; there is no way to "disable" that feature. What you can do instead is to ignore it in your calculations and display. If all Date objects you use are set to the same time of the day, then you can safely ignore the effect of the time component in your comparisons. If you look carefully, the time component of your Date object is set to midnight.