I have a string like this 210115 I want to represent it as 21:01:15 any ideas?.
I tried using Gregorian calendar but it adds date to it which I don't want
SimpleDateFormat sdf = new SimpleDateFormat("HHmmss");
Date date = new Date();
try{
date = sdf.parse("210115");
}
catch(Exception e){
}
Calendar calendar = GregorianCalendar.getInstance();
calendar.setTime(date);
System.out.print(calendar.getTime());
Output is Thu Jan 01 21:01:15 UTC 1970 but what I want is just 21:01:15
Thanks.
To output a formatted date, you use another SimpleDateFormat object with a pattern with the format you want.
In this case, it sounds like you might want to use something like
SimpleDateFormat outputFormat = new SimpleDateFormat("HH:mm:ss");
System.out.println( outputFormat.format(date) );
So what you want is just a time, without time zone. I would recommend using the LocalTime class, which is exactly that, instead of the Date class.
LocalTime time = LocalTime.parse("210115", DateTimeFormatter.ofPattern("HHmmss"));
If u r getting the date string in "210115" this format and you want it in "21:01:15" format then why are you using date format.
Simply do string operation as:
String time="210115";
String newtime=time.substring(0,2)+":"+time.substring(2,4)+":"+time.substring(4,6);
System.out.println(newtime);
you will get the required format.21:01:15
Related
How can i get data in format "YYYY-MM-DD 00:00:00.0" using class Date (it's extremly important to use exactly this class)?
I tried to do everything i can think of:
SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd");
df.format(date)
and
String pattern = "yyyy-MM-dd HH:mm:ss.S";
SimpleDateFormat format = new SimpleDateFormat(pattern);
try {
Date date = format.parse("2011-01-18 00:00:00.0");
} catch (ParseException e) {
e.printStackTrace();
}
byt when i print date using logger i get this format "Tue Sep 30 00:00:00 MSK 1913".
Try this
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.S");
Date date = format.parse("2011-01-18 00:00:00.0");
System.out.println(format.format(date));
Are you sure you want the hours, minutes, secs to be zeroes?
Or do you mean the pattern yyyy-MM-dd HH:mm:ss ?
The date class is always independent of the formatting. It only needs to be translated when you print it, like this:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String out = df.format(date)
System.out.println(out);
Or do you want to strip the time out of the date object? or something.
You are confused by Date.toString() and SimpleDateFormat.format()
An object of Date (java.util.Date) has no format information. If you call date.toString(), (which is called by your logger), you got default representation of this object, you have seen what it is.
However, SimpleDateFormat.format() will give you a string as return value, this value will format the Date object with a pattern defined by SimpleDateFormat.
In your code, you first parsed the string, with certain pattern, to get the date object. If it was successful, you got the Date object, here, for this date object, you don't have any format information, even if you have defined a pattern to parse the input string. If you want to print/output (to string again) the date object, you have to use the SimpleDateFormat.format() method.
I hope the below one will solve your problem when you need to do for dynamic dates.
Date today = new Date();
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd 00:00:00");
String formattedDate = sdf.format(today);
System.out.println(formattedDate);
//Above line output (formatted String object) is 2017-12-29 00:00:00
System.out.println(format.format(formattedDate));
//Above line output(parsed Date object) is Fri Dec 29 00:00:00 IST 2017
For Date object you can't get the output as yyyy-MM-dd 00:00:00, but you will get this format in String object type.
I want to store today's date in the format yyyy-mm-dd. before storing I have took today's date,formatted it and again parse the formatted string to date. It gives the output date in a different format other than what I want. How can i get the date, format it in 'yyyy-mm-dd'
and again convert it into date and want the output in the format 'yyyy-mm-dd'.Please find the below code and tell me where I am wrong
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd");
java.util.Date date = new java.util.Date();
java.util.Date date1;
String datestring=dateFormat.format(date);
try {
date1=dateFormat.parse(datestring);
System.out.print(date1);
} catch (ParseException ex) {
Logger.getLogger(accordcclass.class.getName()).log(Level.SEVERE, null, ex);
}
The output for the above code I get is
Thu Mar 07 00:00:00 GMT 2013. But I want the output as 2013-01-07
I had the same problem, this is what I did:
DateFormat inputDateFormat = new SimpleDateFormat("dd-MMM-yyyy HH:mm");
DateFormat outputDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm");
System.out.println(outputDateFormat.format(inputDateFormat.parse("09-SEP-2013 10:00")));
That way I can parse the date in the original format and output it in the database compatible format.
There is the posibility of using PreparedStatement as someone mentiones before but I don't want to.
Don't use a Date object to print, use directly your datestring variable. Using a Date will call toString which will be formatted using the Locale.
Edit : Adding that if you want to store your Date variable with a format, it doesn't work that way. A Date doesn't hold a format, it just represents the time. How you show it in a GUI, console or anywhere else is where you need to specify a format if you want it to differ from the current Locale format.
You're using the DateFormat to format and reparse.
You don't need to re-parse. Simply use the DateFormat only to format.
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd");
java.util.Date date = new java.util.Date();
String datestring=dateFormat.format(date);
System.out.println( datestring );
I have a DateTime object DT which stores current time. When I print DT, I want it to only print the time part, ie HH-MM-SS (H = hours, M = minutes, S = seconds) and ignore the date part.
How can I do this ? For that matter, is it even possible to create a date time object which will only contain HH-MM-SS and nothing related to date ? If that is true, then I can simply print it instead of extracting the HH-MM-SS part.
Thanks.
If you only want the time, you should use a LocalTime instead of a DateTime. You can use DateTime.toLocalTime() to get the time part of an existing DateTime.
If you actually want to keep the DateTime but only reveal the time part when formatting, you can create a DateTimeFormatter with a pattern which only includes the time parts, but I'd usually consider this a design smell.
You can use Java date formatter which is in java.util.Date package.
Like :
Date todaysDate = new java.util.Date();
1. // Formatting date into yyyy-MM-dd HH:mm:ss e.g 2008-10-10 11:21:10
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String formattedDate = formatter.format(todaysDate);
2. // Formatting date into yyyy-MM-dd e.g 2008-10-10
formatter = new SimpleDateFormat("yyyy-MM-dd");
formattedDate = formatter.format(todaysDate);
3. // Formatting date into MM/dd/yyyy e.g 10/10/2008
formatter = new SimpleDateFormat("MM/dd/yyyy");
formattedDate = formatter.format(todaysDate);
With Java you can do it like this
Date obj = new Date() ;
System.out.println(new SimpleDateFormat("hh:mm:ss").format(obj)) ;
but it could be an expensive call.
But jodatime gives LocalTime which you can try out.
I have a date that I get from a server formatted in EST like this
05/07/2012 16:55:55 goes month/day/year then time
if the phone is not in EST how can I convert it to the timezone the phone is in?
it would be not problem if I got the time in milliseconds but I dont
EDIT:
ok now the time is not correct when formatting
String sTOC = oNewSTMsg.getAttribute("TOC").toString();
String timezoneID = TimeZone.getDefault().getID();
DateFormat format = new SimpleDateFormat("MM/dd/yy HH:mm:ss");
format.setTimeZone(TimeZone.getTimeZone("EST"));
String newtimezoneID = TimeZone.getDefault().getID();
Date timestamp = null;
try{
timestamp = format.parse(sTOC);
format.setTimeZone(TimeZone.getDefault());
timezoneID = format.format(timestamp);
}catch(ParseException e){
}
I convert it to "EST" then format that time to the default TimeZone but the time is always off by an hour, not sure why?
Use the following code to get a UNIX timestamp:
String serverResp = "05/07/2012 16:55:55";
DateFormat format = new SimpleDateFormat("MM/dd/yy HH:mm:ss");
Date date = format.parse(serverResp);
Now you have the timestamp, which you know how to use.
Here's another question which covers conversion, in case you are curious: Android Convert Central Time to Local Time
Use the DateFormat class to parse the String into a Date. See the introduction to the API document here... http://docs.oracle.com/javase/1.5.0/docs/api/java/text/DateFormat.html
You can then create a Calendar for the Date...
Calendar cal = Calendar.getInstance().setTime(date);
And then you can change the timezone on the Calendar to a different timezone using setTimezone(). Or just get the time in milliseconds, using getTimeInMillis()
Using the Calendar, Date, and DateFormat classes should put you in the right direction.
See the Calendar documentation here... http://docs.oracle.com/javase/1.5.0/docs/api/java/util/Calendar.html
I have My Database data in this format
18-NOV-10
I have to pass the same format into java.util.Date like this
Date date = new java.util.Date(dateformater);
so that the result of java.util.Date is like this 18-NOV-10
Is this possible ??
I tried this way
String strDate = "12-NOV-07";
SimpleDateFormat sdfSource = new SimpleDateFormat("dd-MMM-yy");
Date date = sdfSource.parse(strDate);
System.out.println(date);
But i am getting the result as "Mon Nov 12 00:00:00 IST 2007 " which i want it only
12-NOV-07"
You can use java.text.DateFormat (actually SimpleDateFormat) to get you where you want to go, but maybe you shouldn't be storing the dates as strings in your database. It will do output and parsing.
SimpleDateFormat sdf =
new SimpleDateFormat("DD-MMM-YY");
Date parsed = sdf.parse(dateString);
See http://javatechniques.com/blog/dateformat-and-simpledateformat-examples/
Once you get the Date, you can turn it into the format you want but it will be held in memory as a Date object. You can get it in the form you want using
String dateString = sdf.format(parsed);
As others have pointed out, you should probably store your dates as dates, not strings; nevertheless...
If you want to turn a Date back into a string in that format you can use the following:
DateFormat formatter = new SimpleDateFormat("dd-MMM-yy");
Date date = new Date();
String dateStr = formatter.format(date); // Gives "22-May-11"
If you need MAY instead of May, just use toUpperCase() on the resultant string.
DateFormat sdf = new SimpleDateFormat("dd-MMM-yy");
Date d = sdf.parse("18-NOV-10");
Try System.out.println(sdfSource.format(date).toUpperCase()); instead. The Date object will always have a time component to it; there is no way to "disable" that feature. What you can do instead is to ignore it in your calculations and display. If all Date objects you use are set to the same time of the day, then you can safely ignore the effect of the time component in your comparisons. If you look carefully, the time component of your Date object is set to midnight.