java -version
java version "1.6.0_26"
Java(TM) SE Runtime Environment (build 1.6.0_26-b03)
Java HotSpot(TM) Server VM (build 20.1-b02, mixed mode)
Now I have a Java application which says
A different version of Java Runtime Environment (JRE) is required to use this application.
and it is 1.6.0_17...
What to do?
It's really strange that the software you are trying to run requires a very specific update release (such as Oracle Java 6 update 17). Update releases are compatible and there should not be a need to require a very specific release.
On this page you can download earlier versions of Oracle's Java implementation, including Java 6 update 17.
if you really want to have different version of the application running, then the keyword java needs to be fully provided with a path.
one good way is to export the java_home before you run the application and have the application always read the java home when starting the server.
export JAVA_HOME = c:\jdk7
JAVA_HOME/bin/java -server ...
export JAVA_HOME = c:\jdk6
You have to uninstall your current version of java and install the desired version.
You can found all previous version of java on this (Java Older versions) location.
If you are using windows you can directly uninstall and install the older version.
Note: we can use multiple versions in a system by changing the system or user environment variable to use some version as my current java version make or put the path as followed it should be pasted first in path
C:\Program Files\Java\jdk1.7.0_12\bin;.;
[;.;] this will indicate as current working directory and this version will only take as default version while installing java dependent sofware installations ex:netbeans,tomcat etc
Related
I am new to Java programming. I have installed Java SE 11 (LTS) (JDK 11.0.8) on my OS. Note that former Java also has jre folder in it. But Java 11 onward there come only JDK folder.
So, I have set JAVA_HOME environment variable as well as, included jdk\bin in path as well.
By checking on cmd java version shows as follow:
C:\Users\user>java -version
java version "11.0.8" 2020-07-14 LTS
Java(TM) SE Runtime Environment 18.9 (build 11.0.8+10-LTS)
Java HotSpot(TM) 64-Bit Server VM 18.9 (build 11.0.8+10-LTS, mixed mode)
Then I installed eclipse 2020 09 version. But by making a simple Hello World project does not work.
And shows this error multiple times.
Description Resource Path Location TypeThe project was not built due to "Failed to init ct.sym for C:\Users\Irfan Umar\AppData\Local\Temp\eoiE758.tmp\plugins\org.eclipse.justj.openjdk.hotspot.jre.minimal.stripped.win32.x86_64_14.0.2.v20200815-0932\jre\lib\jrt-fs.jar". Fix the problem, then try refreshing this project and building it since it may be inconsistent HelloWorld Unknown Java Problem
What is the solution, I believe it is related to JRE not provided in JDK now.
Eclipse uses Java in two ways. It runs Eclipse with Java, and it allows specifying Java Runtime Environments in Preferences. I rarely see any reason to set JAVA_HOME anymore, because I specify the paths to the JDKs I want to use. I always have multiple JDKs installed.
I specify which JDK to use to run Java by setting the "-vm" path in the "eclipse.ini" file (which points to the "bin" directory).
I specify which JDK to use to compile code by adding JREs in preferences, and sometimes editing the "Execution Environments" (subsection of "Java Runtime Environments") to point to specific JREs.
I need to install open JDK in my Windows 64-bit os. I have used ORACLE open JDK and downloaded from the below link: https://jdk.java.net/8/
While downloading I have selected Accept License Agreement and installed.
But, after the installation when I tried checking the version using command java -version it's showing like regular JDK.
Can anyone help me to get where I went wrong? Or is there any better vendor to install open JDK in windows. Thanks.
Amazon offers an open jdk for Windows (and other OS), but just for Java 8, 11 and 16.
You can download it from here: https://aws.amazon.com/es/corretto/
After installing it and running the java -version command, you will see something like this:
>java -version
openjdk version "1.8.0_242"
OpenJDK Runtime Environment Corretto-8.242.08.1 (build 1.8.0_242-b08)
OpenJDK 64-Bit Server VM Corretto-8.242.08.1 (build 25.242-b08, mixed mode)
You need to set your java version in environment of you machine and target your JDK8 bin folder, or any JDK that you want to have at your disposal when you run java -version.
The best way to do this is to use the builds from adoptopenjdk. They're very high quality and come in multiple variants for Windows ranging from zip files to MSI installers. Dead simple to install JDK 8, 11 or 15.
But, after the installation when I tried checking the version using command java -version it's showing like regular JDK.
This is because JAVA_HOME is pointing to your old JDK. You need to go to Control Panel and change the Environment Variables. Just do a search on Windows 10 for "Environment Variables" to easily find that configuration panel.
Azul Systems provides builds of OpenJDK and relative installers, for all OSes and JDK versions.
It also provides builds of the JDK with OpenJFX included.
The installers bind JAR files to be executed by Java on Windows.
Download from azul.com website
I know this is old but should anyone run across this in search of OpenJDK 8 go here
https://developers.redhat.com/products/openjdk/download
I am getting below result, Does it mean I am having JDK 1.7.0_45 and JRE is 1.42 ? Please advise.
$ javac -version
Eclipse Java Compiler v_677_R32x, 3.2.1 release, Copyright IBM Corp 2000, 2006. All rights reserved.
$ java -version
java version "1.7.0_45"
Java(TM) SE Runtime Environment (build 1.7.0_45-b18)
Java HotSpot(TM) 64-Bit Server VM (build 24.45-b08, mixed mode)
$ alternatives --config java
There is 1 program that provides 'java'.
Selection Command
-----------------------------------------------
*+ 1 **/usr/lib/jvm/jre-1.4.2-gcj/bin/java**
Enter to keep the current selection[+], or type selection number:
It would appear that you have two versions of Java installed:
The Java on your PATH is Java 1.7.0. I think it is an Oracle build rather than a build from your Linux system's package repository.
The Java configured using alternatives looks like a GCJ Java that is compatible with Java 1.4.2. It was probably installed from your package repository. IMO, it is inadvisable to use this from a technical standpoint. In fact, I would recommend uninstalling it.
Actually I am getting "Unsupported major.minor version 51.0" error after uploading a external jar file to Informatica powercenter Java transformation.
That implies that Informatica is using the Java 1.4.2 installation.
Now, the version of Java that an application uses will depend on what version of Java the application's launcher / launch script is using. That could depend on a number of things:
If the launcher uses an absolute path for the java command, then that is what will use.
If the launcher uses a simple name (e.g. java) then the version used will depend on the launcher's $PATH. This is probably what is happening ... and the $PATH used is different from your shell's $PATH.
So what is the solution?
You could add the Oracle Java install to the alternatives system. See man alternatives or Google for instructions using "java oracle alternatives install"
You could tweak the $PATH used by the application's launcher.
Depending on your Linux distro, you could install an OpenJDK 1.7.0 JDK or JRE from the package repos. That will (should) add the new installed Java to the alternatives database, so that you can select it instead of the old GCJ 1.4.2 installation.
I normally still use Java 7 for all my coding projects (it's a company "politics" issue), but I installed Java 8 for one third-party project I am contributing to. Now, it seems I cannot have Java 8 installed in Windows 7 x64, and still use Java 7 by default:
C:\>"%JAVA_HOME%\bin\java.exe" -version
java version "1.7.0_55"
Java(TM) SE Runtime Environment (build 1.7.0_55-b13)
Java HotSpot(TM) 64-Bit Server VM (build 24.55-b03, mixed mode)
C:\>java.exe -version
java version "1.8.0_05"
Java(TM) SE Runtime Environment (build 1.8.0_05-b13)
Java HotSpot(TM) 64-Bit Server VM (build 25.5-b02, mixed mode)
As you can see, JAVA_HOME is completely ignored.
I also have Java in the path, using "%JAVA_HOME%\bin", which resolve correctly to Java 7 when I check the path in a DOS box, but it still makes no difference.
I checked in the "Java Control Panel" (not sure if this affects the default command-line Java version). Under the "Java" tab, the "View..." button, you get to see "registered" Java versions. I can add all the versions under the "User" tab, but under "System" there is only Java 8, and no way to change it.
Am I missing something, or did Oracle just make it impossible to use Java 7, unless I de-install Java 8? I don't want to have to specify the "source" and "target" everywhere, and I don't even know if it is possible for me to specify it everywhere, where Java is used.
EDIT: What I did is I de-installed all Java. Then installed the latest Java7 (both 86 and x64), and then the latest Java8 (both 86 and x64). After I did that, I noticed that the x64 JDK was gone. It seems Java8 killed it. So I re-installed the JDK 7 x64, after the JDK 8 x64. Still, JDK7 x64 did not seem to "replace" the "java.exe" which is copied into the "Windows" directory itself (I assume THAT is the problem).
When you install jdk8 it adds an entry like this
C:\ProgramData\Oracle\Java\javapath
to beginning of your PATH environment variable, removing this entry should resolve your problem.
You can select the JRE version from the command line with the -version: option.
> java -version:"1.7" MyClass
should select the 1.7 JRE if installed properly.
The list of the properly installed JRE is in the registry, see the key :
HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment (32bit)
HKEY_LOCAL_MACHINE\SOFTWARE\Wow6432Node\JavaSoft\Java Runtime Environment (64bit)
You can set the "CurrentVersion" there if you want a different default version than the latest.
See http://docs.oracle.com/javase/7/docs/technotes/tools/windows/java.html#options
Don't modify your PATH to point to a particuliar JRE, let the special java.exe in Windows/system32 do the job.
Windows and Unix both find programs using their PATH environment variable. You have an java.exe in your Windows\System32 which is appearing before your "preferred" version of Java.
Change the PATH to be the one you need, or specify the full path when you need a different version.
2 Steps
1
Change registry key **HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment\CurrentVersion** to point to 1.7
2
Copy java.exe,javaw.exe and javaws.exe from your java 1.7 version to Windows\System32 folder
(Since the corresponding files of java 1.8 are already there, you might have to overwrite with admin permissions)
3
(OOps actually not required 3rd step )
Open a new cmd window and check
java -version
Looks like you have to check where in your PATH is located your JAVA_HOME variable, the PATH is evaluated from left to right. A tip for you is to do all your Java system variables configuration at the beginning of your PATH.
PATH = %M2_HOME%\bin;%JAVA_HOME%\bin;C:\ProgramData\Oracle\Java\javapath;...
Probably that's why after doing this:
- java -version
you are getting this:
- java version "1.8.0_05"
because there are other areas in your PATH that are pointing to other java.exe, for example C:\Windows\System32 or C:\ProgramData\Oracle\Java\javapath etc.
I had to make 2 changes for it to work:
Changed the Registry key 'Software\JavaSoft\Java Runtime Environment'\CurrentVersion' to 1.7 from 1.8
The Java 8 installation adds a new entry to the PATH environment variable 'C:\ProgramData\Oracle\Java\javapath'. I removed this entry from the PATH.
So I'm trying to get the latest version of Java. When I run:
java -version
I get:
java version "1.6.0_65"
Java(TM) SE Runtime Environment (build 1.6.0_65-b14-462-11M4609)
Java HotSpot(TM) 64-Bit Server VM (build 20.65-b04-462, mixed mode)
When I run:
javac -version
I get:
javac 1.6.0_65
Now I've just downloaded and installed JDK 8. When I go into System Preferences --> Java --> Update, I see:
Your system has the recommended vesion of Java.
Java 8 Update 05.
I guess I have a few questions:
1) Don't I want the JDK and my version of Java to match up?
2) Why does my Java Control Panel claim I have Java 8, but my work in the terminal (when checking my Java version) says otherwise?
Thanks for the help,
Mariogs
The probably "simple" answer is you have two versions of java installed. On the command line you currently use 1.6. Thus the old one is active. In system preferences you see the version of java 8.
Windows:
You can change the version of the command line to java 8. Set PATH environment variable and JAVA_HOME or via windows preferences. I recommend the first one.
Mac: /usr/libexec/java_home is the starting point for switching java versions on the command line. Check out this post to understand how to handle different java versions on the Mac. IMHO this answer is a good solution.
The Java Platform offers both the JRE and the JDK in order for users to run Java programs. The JRE stands for the Java Runtime Environment, and the JDK stands for the Java Development Kit.
The JDK is meant for Java developers - that is, those who build applications/write programs in Java. It contains tools that are needed for Java coding, including -javac to compile programs.
The JRE is meant for regular users - those who only need to run Java programs on their computer and are not interested in development.
The reason for the discrepancy in your case is because you're looking at the JRE and JDK and trying to compare the two. The current JDK that you have is Java 8, whereas the current JRE that you have is 1.6.0_65. It is problematic that your JRE version does not match your JDK version, but without your PATH variable or other information about your install, we can't help you fix your installation.
1) Yes, if you use the JDK at all, you want the JRE (runtime environment) to come from the JDK (development environment) (a JDK necessarily includes a JRE).
2) Likely your path variable is set so that you invoke Java from your Java 6 installation; you need to find the equivalent for your Java 8 installation and set the path for that. Without information about your operating system, we can't help you do that.
We should know the reason for this
Our OS comes with a predefined (built-in)set of tools and utilities. When we try to execute the command e.g. cls in the Windows command line then it is already present in system path variable and os will refer the corresponding binary of cls to execute the command.
However, when we install any third party tool/software then path variable is not updated accordingly.
When we install different versions of java on your system then installations go to different directories. E.g. JDK installation directory for Windows will be
C:\Program Files\Java\jdk1.8.0_161
Similarly, JRE installation directory for Windows will be JDK installation directory for Windows will be
C:\Program Files\Java\jre1.8.0_161
We need to update the path variable of OS to point to the appropriate directory. If we set the path of JDK then it will execute a binary from JDK bin directory.
Solution
we need to update JDK or JRE version specific directory location into PATH Environment variable.
Let me see if I can clear it up for you.
1)Yes, arguably you nearly want this to be true.
2)It could be few things, but most likely that a previous instillation was not properly removed. So one gets called instead of the other.