Eclipse(2020 09) Java Installation issue || Windows 10 OS - java

I am new to Java programming. I have installed Java SE 11 (LTS) (JDK 11.0.8) on my OS. Note that former Java also has jre folder in it. But Java 11 onward there come only JDK folder.
So, I have set JAVA_HOME environment variable as well as, included jdk\bin in path as well.
By checking on cmd java version shows as follow:
C:\Users\user>java -version
java version "11.0.8" 2020-07-14 LTS
Java(TM) SE Runtime Environment 18.9 (build 11.0.8+10-LTS)
Java HotSpot(TM) 64-Bit Server VM 18.9 (build 11.0.8+10-LTS, mixed mode)
Then I installed eclipse 2020 09 version. But by making a simple Hello World project does not work.
And shows this error multiple times.
Description Resource Path Location TypeThe project was not built due to "Failed to init ct.sym for C:\Users\Irfan Umar\AppData\Local\Temp\eoiE758.tmp\plugins\org.eclipse.justj.openjdk.hotspot.jre.minimal.stripped.win32.x86_64_14.0.2.v20200815-0932\jre\lib\jrt-fs.jar". Fix the problem, then try refreshing this project and building it since it may be inconsistent HelloWorld Unknown Java Problem
What is the solution, I believe it is related to JRE not provided in JDK now.

Eclipse uses Java in two ways. It runs Eclipse with Java, and it allows specifying Java Runtime Environments in Preferences. I rarely see any reason to set JAVA_HOME anymore, because I specify the paths to the JDKs I want to use. I always have multiple JDKs installed.
I specify which JDK to use to run Java by setting the "-vm" path in the "eclipse.ini" file (which points to the "bin" directory).
I specify which JDK to use to compile code by adding JREs in preferences, and sometimes editing the "Execution Environments" (subsection of "Java Runtime Environments") to point to specific JREs.

Related

Installing Java OpenJDK with HomeBrew: why there are same versions of java on different locations?

Following the posts here and here, I had to have two different versions of Java/OpenJDK installed
brew install java
brew cask install java
now I have openjdk 13.0.2
openjdk 13.0.2 2020-01-14
OpenJDK Runtime Environment (build 13.0.2+8)
OpenJDK 64-Bit Server VM (build 13.0.2+8, mixed mode, sharing)
in two different locations
/usr/local/opt/openjdk/bin
/usr/local/opt/openjdk/libexec/openjdk.jdk/Contents/Home/bin/
and openjdk 14
openjdk 14 2020-03-17
OpenJDK Runtime Environment (build 14+36-1461)
OpenJDK 64-Bit Server VM (build 14+36-1461, mixed mode, sharing)
also in two different locations
/System/Library/Frameworks/JavaVM.framework/Versions/Current/Commands/
/Library/Java/JavaVirtualMachines/openjdk-14.jdk/Contents/Home/bin/
so my questions are
why there are two different locations for each installation of OpenJDK?
how to find out if there are more installations of JDK on my system? Ran sudo find / -name java which nuked my terminal (see log here).
How to know how those different versions of java are installed?
I understand that JDK is Java SDK and JRE (Java Runtime Environment) is an oracle thing which I think OpenJDK doesn't have (?) but looking at OpenJDK download page what are "JMC" and "Java SE"?!
what you are seeing is the way that a JDK works on macOS. but basically what you should know that we have two entities called JDK and JRE. JDK is a tool for java developers to compile and run their applications. JRE is a runtime for clients to run java applications. JDK is containing a JRE, so you don't need to install JRE when you have JDK.
A JDK is a folder that you can have based on your OS and copy paste it every where that you need and just add the bin folder to your PATH . so you might have lot of JDK folders but only the one that is added to your PATH is your current working JDK, and they are not working at the same time in one environment but you can have multiple Java versions on different user profiles.
what you have is one installation with its meta data and links all over the macOS.
you can have multiple JDK folders all around your hard disk but only one of them at the current time is working and that would be the one that you have in the user profile.
I don't know a way to find out how they are installed. you can query the tools like brew in your os to find out that if they installed any java or not but not from JDK itself.
JMC is java mission control which is a monitoring application for java application. JRE, as I said, is a runtime for running the applications and OpenJDK also includes a runtime in itself. JavaSE is the specification of Java for Standard edition since we have other editions too.

Eclipse (and STS) using wrong JDK to start up

I have several versions of Java on my system (OS X El Capitan, version 10.11.6). My current JAVA_HOME variable is set to a Java 8 JDK, and the bin directory is in my path:
$ java -version
java version "1.8.0_121"
Java(TM) SE Runtime Environment (build 1.8.0_121-b13)
Java HotSpot(TM) 64-Bit Server VM (build 25.121-b13, mixed mode)
Nevertheless, whenever I try to start Eclipse or STS, I get a crash, and inside the .metadata/.log file in the workspace it includes the line:
java.version=9-ea
I can edit the eclipse.ini file and add a -vm flag to get it to start with the proper JVM, but what mystifies me is where Eclipse is getting the wrong information in the first place. Isn't setting JAVA_HOME enough? Where else might it be finding Java?
I think the native launcher of Eclipse uses /usr/libexec/java_home to determine the current JVM to use and I am not aware of a way to change that command to point to a different VM as a default.

Different java versions on mac machine?

There is something going wrong with my java configuration and it is really bugging me. I am using IntelliJ IDEA and after downloading and installing java 8 I tried to configure my project to use that SDK but I could only locate version 1.6 under /Library/Java/JavaVirtualMachines/. I am new to OS X and I am really confused with the paths.
Looking on my Java control panel I can see I got installed Java 8 but after running java -version on the terminal I get 1.6.0_65.
And the which java gives back /usr/bin/java.
Please help I am completely lost
Here is an example with several Java versions installed side-by-side ...
ls /Library/Java/JavaVirtualMachines/
jdk1.7.0_25.jdk jdk1.7.0_72.jdk jdk1.8.0_05.jdk jdk1.8.0_25.jdk
User can edit ~/.profile to point explicitly at one
export JAVA_HOME=/Library/Java/JavaVirtualMachines/jdk1.7.0_72.jdk/Contents/Home
export PATH=$JAVA_HOME/bin:$PATH
And here is result ...
java -version
java version "1.7.0_72"
Java(TM) SE Runtime Environment (build 1.7.0_72-b14)
Java HotSpot(TM) 64-Bit Server VM (build 24.72-b04, mixed mode)
Well something was wrong with the installation. I completely removed the other versions (not 1.6) and reinstalled 1.8 using the default path (as there is no option to change it during installation. Now IntelliJ can see JDK 1.8
Thanks for the help anyway

What is the java.exe difference from jdk to (included) jre?

So, I had always thought there was no difference between the java.exe located in the jdk\bin and that in the jdk\jre\bin folders. Apparently, that is not the case, certainly not with java8 anyway.
I was testing the maverick ssh library and found that it would not auto-negotiate an encryption cipher from the list offered by the sshd server when using the java.exe from jdk\bin. Changing the java.exe used to that from the jre supplied with jdk (in the jdk\jre\bin folder) let the test app work fine.
So... what could possibly explain the difference - why would one java.exe work and the other not, if they are both the same?
They appear the same on the surface:
C:\Program Files\Java\jdk1.8.0_20>dir bin\java.exe
08/22/2014 03:35 PM 190,856 java.exe
C:\Program Files\Java\jdk1.8.0_20>dir jre\bin\java.exe
08/22/2014 03:35 PM 190,856 java.exe
But must be different under the hood:
C:\Program Files\Java\jdk1.8.0_20>diff bin\java.exe jre\bin\java.exe
Files bin\java.exe and jre\bin\java.exe differ
EDIT:
I did review the question which is suggested as a duplicate, however it did not address my question.
The versions of the binaries appear the same:
C:\Program Files\Java\jdk1.8.0_20>bin\java -version
java version "1.8.0_20"
Java(TM) SE Runtime Environment (build 1.8.0_20-b26)
Java HotSpot(TM) 64-Bit Server VM (build 25.20-b23, mixed mode)
C:\Program Files\Java\jdk1.8.0_20>jre\bin\java -version
java version "1.8.0_20"
Java(TM) SE Runtime Environment (build 1.8.0_20-b26)
Java HotSpot(TM) 64-Bit Server VM (build 25.20-b23, mixed mode)
I did not adjust the classpath or anything else on my commandline, other than the path to java.exe.
Compared the two using WinMerge... there are a few diffs nr the start and end (moreso) of the two files. All binary gobble-de-gook to me.
Re using that library and getting different results, that's almost certainly not anything to do with java.exe, but something to do with the classpath and jars used by the JDK install vs. the JRE install.
Re your different files, it's not just you: I dug up a Windows 8.1 machine with (an old copy of) Oracle's Java8 on it, and it's the same thing: Sizes, dates, and versions match, contents don't quite. This isn't true of my Linux box with Oracle's Java8 on it, where the jdk/bin/java and jdk/jre/bin/java files are identical (and not just symlinked). My guess is it relates to optimization defaults, but doesn't relate to your ssh library issue.

Cannot use Java 7 installation if Java 8 is installed

I normally still use Java 7 for all my coding projects (it's a company "politics" issue), but I installed Java 8 for one third-party project I am contributing to. Now, it seems I cannot have Java 8 installed in Windows 7 x64, and still use Java 7 by default:
C:\>"%JAVA_HOME%\bin\java.exe" -version
java version "1.7.0_55"
Java(TM) SE Runtime Environment (build 1.7.0_55-b13)
Java HotSpot(TM) 64-Bit Server VM (build 24.55-b03, mixed mode)
C:\>java.exe -version
java version "1.8.0_05"
Java(TM) SE Runtime Environment (build 1.8.0_05-b13)
Java HotSpot(TM) 64-Bit Server VM (build 25.5-b02, mixed mode)
As you can see, JAVA_HOME is completely ignored.
I also have Java in the path, using "%JAVA_HOME%\bin", which resolve correctly to Java 7 when I check the path in a DOS box, but it still makes no difference.
I checked in the "Java Control Panel" (not sure if this affects the default command-line Java version). Under the "Java" tab, the "View..." button, you get to see "registered" Java versions. I can add all the versions under the "User" tab, but under "System" there is only Java 8, and no way to change it.
Am I missing something, or did Oracle just make it impossible to use Java 7, unless I de-install Java 8? I don't want to have to specify the "source" and "target" everywhere, and I don't even know if it is possible for me to specify it everywhere, where Java is used.
EDIT: What I did is I de-installed all Java. Then installed the latest Java7 (both 86 and x64), and then the latest Java8 (both 86 and x64). After I did that, I noticed that the x64 JDK was gone. It seems Java8 killed it. So I re-installed the JDK 7 x64, after the JDK 8 x64. Still, JDK7 x64 did not seem to "replace" the "java.exe" which is copied into the "Windows" directory itself (I assume THAT is the problem).
When you install jdk8 it adds an entry like this
C:\ProgramData\Oracle\Java\javapath
to beginning of your PATH environment variable, removing this entry should resolve your problem.
You can select the JRE version from the command line with the -version: option.
> java -version:"1.7" MyClass
should select the 1.7 JRE if installed properly.
The list of the properly installed JRE is in the registry, see the key :
HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment (32bit)
HKEY_LOCAL_MACHINE\SOFTWARE\Wow6432Node\JavaSoft\Java Runtime Environment (64bit)
You can set the "CurrentVersion" there if you want a different default version than the latest.
See http://docs.oracle.com/javase/7/docs/technotes/tools/windows/java.html#options
Don't modify your PATH to point to a particuliar JRE, let the special java.exe in Windows/system32 do the job.
Windows and Unix both find programs using their PATH environment variable. You have an java.exe in your Windows\System32 which is appearing before your "preferred" version of Java.
Change the PATH to be the one you need, or specify the full path when you need a different version.
2 Steps
1
Change registry key **HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment\CurrentVersion** to point to 1.7
2
Copy java.exe,javaw.exe and javaws.exe from your java 1.7 version to Windows\System32 folder
(Since the corresponding files of java 1.8 are already there, you might have to overwrite with admin permissions)
3
(OOps actually not required 3rd step )
Open a new cmd window and check
java -version
Looks like you have to check where in your PATH is located your JAVA_HOME variable, the PATH is evaluated from left to right. A tip for you is to do all your Java system variables configuration at the beginning of your PATH.
PATH = %M2_HOME%\bin;%JAVA_HOME%\bin;C:\ProgramData\Oracle\Java\javapath;...
Probably that's why after doing this:
- java -version
you are getting this:
- java version "1.8.0_05"
because there are other areas in your PATH that are pointing to other java.exe, for example C:\Windows\System32 or C:\ProgramData\Oracle\Java\javapath etc.
I had to make 2 changes for it to work:
Changed the Registry key 'Software\JavaSoft\Java Runtime Environment'\CurrentVersion' to 1.7 from 1.8
The Java 8 installation adds a new entry to the PATH environment variable 'C:\ProgramData\Oracle\Java\javapath'. I removed this entry from the PATH.

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