I'm using the following configuration for my db integration test:
#RunWith(SpringJUnit4ClassRunner.class)
#ContextConfiguration(locations = { "classpath:spring/spring-master.xml"})
#TransactionConfiguration(transactionManager = "transactionManager", defaultRollback = false)
#Transactional()
public class EmployeeAccessPropertyTest {
spring-master.xml loads spring config files in the following order:
<import resource="classpath:spring/db/dev-datasource-config.xml"/>
<import resource="classpath:spring/db/jpa-config.xml"/>
<import resource="classpath:spring/db/transaction-config.xml"/>
<import resource="classpath:spring/db/component-config.xml"/>
dev-datasource-config.xml defines dataSource and initializes db scheme via liquibase:
<context:property-placeholder location="classpath:db/config/dev-data-access.properties"/>
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
<property name="driverClassName" value="${jdbc.driver}"/>
<property name="url" value="${jdbc.url}"/>
<property name="username" value="${jdbc.username}"/>
<property name="password" value="${jdbc.password}"/>
</bean>
<bean id="liquibase" class="liquibase.integration.spring.SpringLiquibase">
<property name="dataSource" ref="dataSource" />
<property name="changeLog" value="classpath:db/changelog/db.changelog-master.xml" />
<property name="dropFirst" value="true" />
</bean>
Now, when I run test, I'm getting the following error:
javax.persistence.PersistenceException: [PersistenceUnit: studentPersistenceUnit] Unable to build EntityManagerFactory
...
Caused by: org.hibernate.HibernateException: Missing table: employees
It seems, table is not created when entityManagerFactory is initialized (in the jpa-config.xml file). Ok, I generate scheme via liquibase maven plugin first:
mvn initialize liquibase:update
Comment the following db scheme generation via Spring context:
<!--<bean id="liquibase" class="liquibase.integration.spring.SpringLiquibase">-->
<!--<property name="dataSource" ref="dataSource" />-->
<!--<property name="changeLog" value="classpath:db/changelog/db.changelog-master.xml" />-->
<!--<property name="dropFirst" value="true" />-->
<!--</bean>-->
And the problem is gone. What can I do to make sure that Spring first loads dev-datasource-config.xml, initializes the liquibase bean and only then loads jpa-config.xml where which looks like:
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
p:dataSource-ref="dataSource"/>
Use the 'depends-on' attribute, as described in spring manual:
http://static.springsource.org/spring/docs/3.2.x/spring-framework-reference/html/beans.html#beans-factory-dependson
E.g.
<bean id="beanOne" class="ExampleBean" depends-on="manager"/>
<bean id="manager" class="ManagerBean" />
Related
I am trying external configuration with properties file. dataSource bean is defined in security-context-xml file and hibernate.cfg.xml use them for database informations and sessionFactory.
I want externally dataSource configuration with encrypted password.
Used code following:
<context:property-placeholder
location="classpath:sample.properties" ignore-unresolvable="true" />
<bean id="dataSource"
class="org.apache.commons.dbcp2.BasicDataSource"
destroy-method="close">
<property name="driverClassName"
value="oracle.jdbc.OracleDriver" />
<property name="url" value="${jdbc.url}" />
<property name="username" value="${jdbc.username}" />
<property name="password" value="${jdbc.password}" />
</bean>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="configLocation"
value="classpath:hibernate.cfg.xml" />
</bean>
And sample.properties file is:
jdbc.url="*****"
jdbc.username="****"
jdbc.password="****"
This didn't work and throws exception:
Caused by: java.sql.SQLException: Cannot create JDBC driver of class 'oracle.jdbc.OracleDriver' for connect URL '${jdbc.url}'
at org.apache.commons.dbcp2.BasicDataSource.createConnectionFactory(BasicDataSource.java:2023)
at org.apache.commons.dbcp2.BasicDataSource.createDataSource(BasicDataSource.java:1897)
at org.apache.commons.dbcp2.BasicDataSource.getConnection(BasicDataSource.java:1413)
at org.hibernate.engine.jdbc.connections.internal.DatasourceConnectionProviderImpl.getConnection(DatasourceConnectionProviderImpl.java:139)
at org.hibernate.internal.AbstractSessionImpl$NonContextualJdbcConnectionAccess.obtainConnection(AbstractSessionImpl.java:380)
at org.hibernate.engine.jdbc.internal.LogicalConnectionImpl.obtainConnection(LogicalConnectionImpl.java:228)
... 56 more
I have an Spring MVC 3.2.8 app, and I want to run StandAlone process to generate a PDF. I want to initialize the container and manage beans from an stand-alone app.
I have this piece of code:
public class CreatePDF {
private static final Logger LOGGER = Logger.getLogger (ImportEcolabelToolboxToECAT.class);
public static void main(String[] args) {
String[] configLocations = new String[] {
"C:/Development/Workspaces/EclipseWS/devices/deviceWeb/src/main/resources/com/nicinc/dao/dataAccessContext.xml",
"C:/Development/Workspaces/EclipseWS/devices/deviceWeb/src/main/webapp/WEB-INF/dao/databaseMessageSource.xml",
"C:/Development/Workspaces/EclipseWS/devices/deviceWeb/src/main/resources/com/nicinc/services/impl/servicesContext.xml",
"C:/Development/Workspaces/EclipseWS/devices/deviceWeb/src/main/webapp/WEB-INF/applicationContext.xml",
"C:/Development/Workspaces/EclipseWS/devices/deviceWeb/src/main/resources/com/nicinc/controller/propertyeditors/propertyeditorsContext.xml"};
FileSystemXmlApplicationContext ctx =
new FileSystemXmlApplicationContext(configLocations, true);
}
}
But I have this error when running the app.
Error creating bean with name 'dataSource': Invocation of init method failed; nested exception is javax.naming.NoInitialContextException: Need to specify class name in environment or system property, or as an applet parameter, or in an application resource file: java.naming.factory.initial
and here the definition from the file dataAccessContext.xml :
<!-- The PropertyPlaceholderConfigurer replaces placeholders in Spring bean definitions with the values from the chosen properties files. -->
<!-- There is an example use in the datasource definition below. Look for the $\{jdbc.*} values. -->
<bean id="propertyConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:com/nicinc/dao/jdbc-test.properties</value>
<value>classpath:com/nicinc/dao/dbMessageSource.properties</value>
</list>
</property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
<property name="dataSource" ref="dataSource" />
</bean>
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${jdbc.driverClassName}" />
<property name="url" value="${jdbc.url}" />
<property name="username" value="${jdbc.username}" />
<property name="password" value="${jdbc.password}" />
</bean>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="persistenceXmlLocation" value="classpath*:META-INF/persistence.xml" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="databasePlatform" value="${hibernate.dialect}"/>
<property name="generateDdl" value="false"/>
<property name="showSql" value="false" />
</bean>
</property>
</bean>
<bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />
The javax.naming package comprises the JNDI Api. Since it is just an API its implementation you will have to provide. Generally the implementation is provided by App server. As per the error you are Missing the JNDI implementation.
Possible solution:
If you dont have any javaee related requirement then you should directly use DriverManagerDataSource.
You need to provide your own implementation.Below link might help.
using application data source locally.
I have a problem with my spring boot configuration in xml I created this configuration :
<bean id="jpaVendorAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true"/>
<property name="generateDdl" value="false"/>
<property name="database" value="ORACLE"/>
</bean>
<bean id="dataSource" primary="true" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="oracle.jdbc.OracleDriver"/>
<property name="url" value="jdbc:oracle:thin:#localhost:20300:test"/>
<property name="username" value="test"/>
<property name="password" value="test"/>
</bean>
<tx:annotation-driven transaction-manager="transactionManager"/>
<bean id="entityManagerFactory" primary="true" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="jpaVendorAdapter" ref="jpaVendorAdapter"/>
<!-- spring based scanning for entity classes-->
<property name="packagesToScan" value="model.entity"/>
<property name="persistenceUnitName" value="msPersistenceUnit" />
</bean>
<tx:annotation-driven transaction-manager="transactionManager" />
<bean id="controllerService"
class="...impl.ControllerServiceImpl">
<property name="entityManager" ref="entityManagerFactory" />
<property name="dataSource" ref="dataSource"/>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" >
<constructor-arg index="0" ref="entityManagerFactory" />
</bean>
And I had the java code like this :
public void setEntityManager(final HibernateEntityManagerFactory entityManager) {
final RepositoryFactorySupport factorySupport = new JpaRepositoryFactory(entityManager.createEntityManager());
controlRepository = factorySupport.getRepository(ObjControlRepository.class);
}
when i'm using find method it's ok, but when I'm doing a save, there are not exception but the value it's not insert.
Thank your for your help.
[Edit]
To save I'm using :
/**
* The Interface ObjControlRepository.
*/
public interface ObjControlRepository extends CrudRepository<ObjControl, String> {
}
And I'm calling the method like that :
controlRepository.save(newValue);
You should try to explicitly set the hibernate.hbm2ddl.auto variable to auto. This will prevent your application to release previous data when you start your application.
You can learn more about the hibernate.hbm2ddl.auto variable here.
You should use transactions and commit the transaction in order to save an entity.
So Use #Transactionl annotation on your service layer, like this:
#Transactional
public class ControllerServiceImpl {
...
}
As ControllerServiceImpl is already declared as a bean in spring configuration file, Spring will take care about committing the transaction once you save an entity.
I have configured Hibernate(5.2.6) via spring(4.3.5) But when I run my Junit(4.12) tests it gives out an error saying that it could not locate hibernate.cfg.xml file. Can anyone help me out?
After I run the Junit test, tables are created in database but data is not added, I can see the sql queries being run as I have enables show_sql
did you specify hibernate configured xml file name in web.xml.?
if not specify name of xml file in web.xml
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:hibernateContext.xml</param-value>
</context-param>
How is applicationContext is configured for spring and hibernate integration?
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location">
<value>classpath:properties/jdbc.properties</value>
</property>
</bean>
<bean id="dataSource" class="org.apache.commons.dbcp2.BasicDataSource"
destroy-method="close">
<property name="driverClassName" value="${jdbc.driverClassName}" />
<property name="url" value="${jdbc.url}" />
<property name="username" value="${jdbc.username}" />
<property name="password" value="${jdbc.password}" />
</bean>
<!-- Hibernate session factory -->
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource">
<ref bean="dataSource" />
</property>
<property name="configLocation">
<value>classpath:hibernate/hibernate.cfg.xml</value>
</property>
</bean>
I am using Hibernate 4, Spring 3, JSF 2.0 and Weblogic 10.3.6 as server.
I have created datasource on Weblogic server and in applicationContext.xml I have defined datasource as
<!-- Data Source Declaration -->
<bean id="DataSource" class="org.springframework.jndi.JndiObjectFactoryBean">
<property name="jndiName" value="jdbc/myDS"/>
</bean>
If I would want to use the P6Spy for logging SQL parameters, how can and where I should add the following in applicationcontext.xml?
<property name="hibernate.connection.driver_class">com.p6spy.engine.spy.
P6SpyDriver</property>
Any help is highly appreciable.
Thanks
The easiest way to integrate p6spy using spring is to use the P6DataSource class. The P6DataSource class is just a proxy for the real data source. This lets you obtain the real data source using any of the spring data source factory implementations.
<bean id="dataSource" class="com.p6spy.engine.spy.P6DataSource">
<constructor-arg>
<bean id="DataSource" class="org.springframework.jndi.JndiObjectFactoryBean">
<property name="jndiName" value="jdbc/myDS"/>
</bean>
</constructor-arg>
</bean>
If you are using an XADatasource, just change the classname to P6ConnectionPoolDataSource as shown below. Note: P6ConnectionPoolDataSource implements the ConnectionPoolDataSource and XADataSource interfaces.
<bean id="dataSource" class="com.p6spy.engine.spy.P6ConnectionPoolDataSource">
<constructor-arg>
<bean id="DataSource" class="org.springframework.jndi.JndiObjectFactoryBean">
<property name="jndiName" value="jdbc/myDS"/>
</bean>
</constructor-arg>
</bean>
You need to create bean of session factory in applicationContext.xml file as follows:
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
<property name="dataSource">
<ref bean="dataSource" />
</property>
</bean>
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.p6spy.engine.spy.
P6SpyDriver" />
<property name="url" value="jdbc\:mysql\://localhost\:3306/testdb" />
<property name="username" value="my_username" />
<property name="password" value="my_password" />
</bean>
Please refer to: http://www.mkyong.com/hibernate/how-to-display-hibernate-sql-parameter-values-solution/ for more about P6Spy library.
We can omit "dataSource" bean and directly write properties. Ref: how to configure hibernate config file for sql server