I have a problem with my spring boot configuration in xml I created this configuration :
<bean id="jpaVendorAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true"/>
<property name="generateDdl" value="false"/>
<property name="database" value="ORACLE"/>
</bean>
<bean id="dataSource" primary="true" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="oracle.jdbc.OracleDriver"/>
<property name="url" value="jdbc:oracle:thin:#localhost:20300:test"/>
<property name="username" value="test"/>
<property name="password" value="test"/>
</bean>
<tx:annotation-driven transaction-manager="transactionManager"/>
<bean id="entityManagerFactory" primary="true" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="jpaVendorAdapter" ref="jpaVendorAdapter"/>
<!-- spring based scanning for entity classes-->
<property name="packagesToScan" value="model.entity"/>
<property name="persistenceUnitName" value="msPersistenceUnit" />
</bean>
<tx:annotation-driven transaction-manager="transactionManager" />
<bean id="controllerService"
class="...impl.ControllerServiceImpl">
<property name="entityManager" ref="entityManagerFactory" />
<property name="dataSource" ref="dataSource"/>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" >
<constructor-arg index="0" ref="entityManagerFactory" />
</bean>
And I had the java code like this :
public void setEntityManager(final HibernateEntityManagerFactory entityManager) {
final RepositoryFactorySupport factorySupport = new JpaRepositoryFactory(entityManager.createEntityManager());
controlRepository = factorySupport.getRepository(ObjControlRepository.class);
}
when i'm using find method it's ok, but when I'm doing a save, there are not exception but the value it's not insert.
Thank your for your help.
[Edit]
To save I'm using :
/**
* The Interface ObjControlRepository.
*/
public interface ObjControlRepository extends CrudRepository<ObjControl, String> {
}
And I'm calling the method like that :
controlRepository.save(newValue);
You should try to explicitly set the hibernate.hbm2ddl.auto variable to auto. This will prevent your application to release previous data when you start your application.
You can learn more about the hibernate.hbm2ddl.auto variable here.
You should use transactions and commit the transaction in order to save an entity.
So Use #Transactionl annotation on your service layer, like this:
#Transactional
public class ControllerServiceImpl {
...
}
As ControllerServiceImpl is already declared as a bean in spring configuration file, Spring will take care about committing the transaction once you save an entity.
Related
I have an Spring MVC 3.2.8 app, and I want to run StandAlone process to generate a PDF. I want to initialize the container and manage beans from an stand-alone app.
I have this piece of code:
public class CreatePDF {
private static final Logger LOGGER = Logger.getLogger (ImportEcolabelToolboxToECAT.class);
public static void main(String[] args) {
String[] configLocations = new String[] {
"C:/Development/Workspaces/EclipseWS/devices/deviceWeb/src/main/resources/com/nicinc/dao/dataAccessContext.xml",
"C:/Development/Workspaces/EclipseWS/devices/deviceWeb/src/main/webapp/WEB-INF/dao/databaseMessageSource.xml",
"C:/Development/Workspaces/EclipseWS/devices/deviceWeb/src/main/resources/com/nicinc/services/impl/servicesContext.xml",
"C:/Development/Workspaces/EclipseWS/devices/deviceWeb/src/main/webapp/WEB-INF/applicationContext.xml",
"C:/Development/Workspaces/EclipseWS/devices/deviceWeb/src/main/resources/com/nicinc/controller/propertyeditors/propertyeditorsContext.xml"};
FileSystemXmlApplicationContext ctx =
new FileSystemXmlApplicationContext(configLocations, true);
}
}
But I have this error when running the app.
Error creating bean with name 'dataSource': Invocation of init method failed; nested exception is javax.naming.NoInitialContextException: Need to specify class name in environment or system property, or as an applet parameter, or in an application resource file: java.naming.factory.initial
and here the definition from the file dataAccessContext.xml :
<!-- The PropertyPlaceholderConfigurer replaces placeholders in Spring bean definitions with the values from the chosen properties files. -->
<!-- There is an example use in the datasource definition below. Look for the $\{jdbc.*} values. -->
<bean id="propertyConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:com/nicinc/dao/jdbc-test.properties</value>
<value>classpath:com/nicinc/dao/dbMessageSource.properties</value>
</list>
</property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
<property name="dataSource" ref="dataSource" />
</bean>
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${jdbc.driverClassName}" />
<property name="url" value="${jdbc.url}" />
<property name="username" value="${jdbc.username}" />
<property name="password" value="${jdbc.password}" />
</bean>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="persistenceXmlLocation" value="classpath*:META-INF/persistence.xml" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="databasePlatform" value="${hibernate.dialect}"/>
<property name="generateDdl" value="false"/>
<property name="showSql" value="false" />
</bean>
</property>
</bean>
<bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />
The javax.naming package comprises the JNDI Api. Since it is just an API its implementation you will have to provide. Generally the implementation is provided by App server. As per the error you are Missing the JNDI implementation.
Possible solution:
If you dont have any javaee related requirement then you should directly use DriverManagerDataSource.
You need to provide your own implementation.Below link might help.
using application data source locally.
I'm trying to create a pagination system with Spring interface PagingAndSortingRepository.
I'm following some guides on the internet, but i'm stuck at the first step.
I implemented PagingAndSortingRepository this way
public interface ArtistaRepository extends PagingAndSortingRepository<Artista,Integer> {
List<Artista> findByNome(String nome);
}
If I try to run the webapplication I get this error:
No qualifying bean of type [javax.persistence.EntityManagerFactory] is defined
I use Hibernate Session as entity manager. In all example I saw on the Internet, JPA EntityManager was used.
This is the code inside my configuration.xml file:
<bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
</bean>
<bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="packagesToScan" value="com.jeansedizioni.model"/>
</bean>
Since I'm not using JPA EntityManager, how should I edit my code?
Thank you in advance
Declaring Hibernate's Session Factory won't work. The Spring-data-jpa repositories will only work with the jpa entity manager, as fellow M. Deinum wrote.
Try this configuration:
<bean id="jpaVendorAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true"/>
<property name="generateDdl" value="false"/>
<property name="database" value="<your database - Oracle, MySQL...>"/>
</bean>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="jpaVendorAdapter" ref="jpaVendorAdapter"/>
<property name="persistenceUnitName" value="default"/>
<!-- spring based scanning for entity classes>-->
<property name="packagesToScan" value="com.jeansedizioni.model"/>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory"/>
</bean>
Try this code I hope it will be useful for you.
//Repository Code
public interface ArtistaRepository extends JpaRepository<Artista,Integer> {
Page<Artista> findByNome(String nome,Pageable page);
}
//Service code
int totalElements;
int totalPages;
int numberOfElements;
Pageable pageable = new PageRequest(page,size,Sort.Direction.DESC,"id");
Page<Artista> list=artistaRepository.findByNome(nome,pageable);
totalElements=list.getTotalElements();
numberOfElements=list.getNumberOfElements();
totalPages=list.getTotalPages();
I previously had this config for Hibernate using RESOURCE-LOCAL transaction type:
persistence.xml:
<persistence-unit name="myPU" transaction-type="JTA">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
</persistence-unit>
applicationContext (dataaccess bit):
<bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" p:entityManagerFactory-ref="entityManagerFactory"></bean>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="jpaVendorAdapter" ref="jpaAdapter" />
<property name="persistenceUnitName" value="myPU"/>
<property name="jpaProperties">
<props>
<prop key="javax.persistence.validation.mode">none</prop>
</props>
</property>
</bean>
<bean id="entityManager" class="org.springframework.orm.jpa.support.SharedEntityManagerBean">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<bean id="sessionFactory" class="org.springframework.orm.jpa.vendor.HibernateJpaSessionFactoryBean">
<property name="entityManagerFactory" ref="entityManagerFactory" />
<!-- Are there any other properties required? -->
</bean>
<bean id="jpaAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true" />
<property name="generateDdl" value="false" />
</bean>
<bean id="dataSource" class="org.springframework.jndi.JndiObjectFactoryBean">
<property name="jndiName" value="java:comp/env/jdbc/CNTXESDB" />
<property name="lookupOnStartup" value="true" />
<property name="cache" value="true" />
<property name="proxyInterface" value="javax.sql.DataSource" />
</bean>
But this kind of transaction seems not to work with Glassfish, so I had to switch to JTA transactions.
The problem is -- to get Spring to manage transaction creation (through #Transactional) I need to define a TransactionManager bean but JtaTransactionManager included in spring-tx does not accept an entityManagerFactory bean, so it does not know where the entityManager is in order to open/close/flush Hibernate session.
So how can I configure Spring with Hibernate to use JTA transactions?
EDIT:
turns out you can use RESOURCE_LOCAL transactions with Glassfish, but somehow you cannot have a persistence.xml file. I renamed this file to my_persistence.xml and configured LocalContainerEntityManagerFactoryBean like this:
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="jpaVendorAdapter" ref="jpaAdapter" />
<property name="persistenceUnitName" value="myPU"/>
<property name="persistenceXmlLocation" value="classpath:META-INF/my_persistence.xml" />
<property name="jpaProperties">
<props>
<prop key="javax.persistence.validation.mode">none</prop>
</props>
</property>
</bean>
I had a similar problem and finally I solved as you can see in this little demo:
https://github.com/miguelangelprogramacion/spring4_jpa_hibernate
With [1] as a reference, I prefer to use Spring's Transaction Support before JTA.
Also, I've used an annotation based approach.
[1] http://spring.io/blog/2011/08/15/configuring-spring-and-jta-without-full-java-ee/
I am having an issue creating xa datasources in spring 4.0.
I have setup my datasources in weblogic using an xa driver.
I then added added jndi-lookups for the data sources in spring:
<jee:jndi-lookup id="dataSourceOne" jndi-name="/jdbc/XAONE" resource-ref="true" />
<jee:jndi-lookup id="dataSourceTwo" jndi-name="/jdbc/XATWO" resource-ref="true" />
I have then created the configuration for the entity managers:
<bean id="emfone" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSourceOne" />
<property name="jpaVendorAdapter" ref="jpaVendorAdapter" />
<property name="packagesToScan" value="..." />
</bean>
<bean id="emftwo"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSourceTwo" />
<property name="jpaVendorAdapter" ref="jpaVendorAdapter" />
<property name="packagesToScan" value="..." />
</bean>
<bean id="jpaVendorAdapter"
class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="database" value="ORACLE" />
<property name="showSql" value="true" />
<property name="generateDdl" value="false" />
<property name="databasePlatform" value="org.hibernate.dialect.Oracle10gDialect" />
</bean>
After this I have my transaction manager configured:
<tx:annotation-driven />
<tx:jta-transaction-manager />
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="emfone" />
<qualifier value="tmOne"/>
</bean>
<bean id="docTransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="emftwo" />
<qualifier value="tmTwo"/>
</bean>
I have a service class method annotated with #Transactional that calls a DAO. The DAO uses both entity managers for persisting data.
When the DAO tries to persist using the emftwo a no transaction in progress error is thrown. Does anybody know where I am going wrong?
Thanks,
I have a Spring application, i want to change the data source dynamically,ie. when input a DS URL, the Spring beans and all dependency will get updated automatically.I know this is somewhat strange, but anyway i want to achieve that.
My Spring configuration as following:
<bean id="majorDataSource" class="org.postgresql.ds.PGSimpleDataSource">
<property name="serverName" value="${jdbc.serverName}" />
<property name="portNumber" value="${jdbc.portNumber}" />
<property name="user" value="${jdbc.username}" />
<property name="password" value="${jdbc.password}" />
<property name="databaseName" value="${jdbc.databaseName}" />
</bean>
<bean id="transactionManager" class="org.springframework.jdbc.datasource.DataSourceTransactionManager">
<property name="dataSource" ref="majorDataSource"/>
</bean>
<tx:annotation-driven transaction-manager="transactionManager"/>
<bean id="sqlSessionFactory" class="org.mybatis.spring.SqlSessionFactoryBean">
<property name="dataSource" ref="majorDataSource"/>
<property name="configLocation" value="classpath:sqlmap-config.xml"/>
</bean>
The questions are:
The JDBC URL is stored in properties, which could be changed runtime.
Once the URL is changed, i need to re-create the data source and maybe the dependent objects. I could not figure out how to do it elegantly in Spring?
I have known that Spring did could dynamically route data source based on one key, but the data source URL is predefined in Spring and will not change runtime. It is not my case.
You can use spring's AbstractRoutingDataSource by extending it and overriding the method determineCurrentLookupKey() that should return the key referencing the datasource's spring bean to be used.
Take a look at this blog article on spring source's blog which will show you an example of how to use that feature.
Basically to answer your questions, what you will need to do is to define the two datasources as different spring bean in your XML config. There is no need to create one dynamically, spring will load both, and use one or the other dynamically depending on your criteria in the determineCurrentLookupKey() method.
This would lead to something like:
XML config
<!-- first data source -->
<bean id="majorDataSource" class="org.postgresql.ds.PGSimpleDataSource">
<property name="serverName" value="${jdbc.major.serverName}" />
<property name="portNumber" value="${jdbc.major.portNumber}" />
<property name="user" value="${jdbc.major.username}" />
<property name="password" value="${jdbc.major.password}" />
<property name="databaseName" value="${jdbc.major.databaseName}" />
</bean>
<!-- second data source -->
<bean id="minorDataSource" class="org.postgresql.ds.PGSimpleDataSource">
<property name="serverName" value="${jdbc.minor.serverName}" />
<property name="portNumber" value="${jdbc.minor.portNumber}" />
<property name="user" value="${jdbc.minor.username}" />
<property name="password" value="${jdbc.minor.password}" />
<property name="databaseName" value="${jdbc.minor.databaseName}" />
</bean>
<!-- facade data source -->
<bean id="dataSource" class="blog.datasource.CustomerRoutingDataSource">
<property name="targetDataSources">
<map>
<entry key="MINOR" value-ref="minorDataSource"/>
<entry key="MAJOR" value-ref="majorDataSource"/>
</map>
</property>
<property name="defaultTargetDataSource" ref="majorDataSource"/>
</bean>
<!-- wiring up -->
<bean id="transactionManager" class="org.springframework.jdbc.datasource.DataSourceTransactionManager">
<property name="dataSource" ref="dataSource"/>
</bean>
<tx:annotation-driven transaction-manager="transactionManager"/>
<bean id="sqlSessionFactory" class="org.mybatis.spring.SqlSessionFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="configLocation" value="classpath:sqlmap-config.xml"/>
</bean>
Java
public class MyRoutingDataSource extends AbstractRoutingDataSource {
#Override
protected Object determineCurrentLookupKey() {
// get the current url
HttpServletRequest request = ((ServletRequestAttributes) RequestContextHolder.currentRequestAttributes()).getRequest();
if (request.getRequestURL().toString().endsWith("/minor"))
return "MINOR";
else
return "MAJOR";
}
}
I am not sure if this is the correct Way of doing this but what you can do is something like this.
<bean id="majorDataSource" class="org.postgresql.ds.PGSimpleDataSource">
<property name="serverName" value="dummydata" />
<property name="portNumber" value="dummydata" />
<property name="user" value="dummydata" />
<property name="password" value="dummydata" />
<property name="databaseName" value="dummydata" />
</bean>
<bean id="transactionManager" class="org.springframework.jdbc.datasource.DataSourceTransactionManager">
<property name="dataSource" ref="majorDataSource"/>
</bean>
<tx:annotation-driven transaction-manager="transactionManager"/>
and in Java Class
public class TestTransaction {
#Autowired
private DataSourceTransactionManager manager;
private PlatformTransactionManager transactionManager;
public testExecution(DataSource ds) {
manager.setDataSource(ds);
transactionManager = manager;
TransactionDefinition def = new DefaultTransactionDefinition();
TransactionStatus status = transactionManager.getTransaction(def);
try {
jdbcTemplate.update();
transactionManager.commit(status);
} catch (Exception ex) {
transactionManager.rollback(status);
}
}
}
Please suggest if this Approach could Work as i am Still new to Spring