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Split the string with hyphen symbol multiple occurrence using regex /java

Getting the string value using the below xpath
String noAndDate = driver.findElement(By.xpath("//*[#id='c38']/div/table/tbody/tr[1]/td/strong")).getText();
Output of the above string = 2928554 - 2009-09-18 (BOPI 2009-38)
my expected output
2928554
2009-09-18
i tried below split, but i'm not getting my expected output
String[] words = noAndDate.split("-");
Please advice/help me

You can instead try splitting on a regex alternation which looks for a hyphen surrounded by whitespace, or pure whitespace:
String input = "2928554 - 2009-09-18 (BOPI 2009-38)";
String[] parts = input.split("(\\s+-\\s+|\\s+)");
System.out.println(parts[0]);
System.out.println(parts[1]);
Demo

Try the below code-
String str = "2928554 - 2009-09-18 (BOPI 2009-38)";
String str1 = str.split(" - | ")[0];
String str2 = str.split(" - | ")[1];
This will return str1 as 2928554 and str2 as 2009-09-18.
Hope this will help you !

Just split with regex will do.
String given = "2928554 - 2009-09-18 (BOPI 2009-38)";
String [] splitted = given.split(" - |\\s+");
String result = splitted[0] +", "+splitted[1];
System.out.println(result);
prints
2928554, 2009-09-18

Use Regex capture groups, here you can see what you want in 2 groups:
(\d+)\s*-\s*(\d+\-\d+\-\d+)
() = group

Try this:
String[] words = noAndDate.split(" ");
then
System.out.println(words[0]);
System.out.println(words[2]);

Can we add list of strings to StringArray?

I have String , String str = "this is a very- good web-page";
On split of this , based on "-"
we get str[0],str[1],and str[2]
I want to assign each value of str[0] to a string array..
like below
String[] array = {"this", "is","a", "very"};
is this possible?
Thanks in advance..

Just split str[0] again on " "

You start with a string.
String str = "this is a very- good web-page";
You then split the string.
String[] strArray = str.split("-");
Here are the contents of strArray:
{"this is a very", " good web", "page"}
Note that, since strArray is an array of Strings, each element (i.e. strArray[0]) is a String. Now, you split strArray[0].
String[] strArray2 = strArray[0].split(" ");
Here are the contents of strArray2:
{"this", "is", "a", "very"}
This is the same as if you did the following:
String str2 = strArray[0];
String[] strArray2 = str2.split(" ");

String str = "this is a very- good web-page";
String[] arr=str.split("-");
Now arr[]={"this is a very","good web","page"};
String[] arr1=arr[0].split(" ");
Now arr1[]={"this","is","a","very"}
I hope you understand now.

Android: split a string considering 2 separating characters

I have a string containing messages. The string looks like this:
bill:hello;tom:hi;bill:how are you?;tommy:hello!; ...
I need to split the string into several srings, on the characters : and ;.
For now, I have split the string on ; and i could add the results in list elements.
List<Message> listMessages = new ArrayList<Message>();
StringTokenizer tokenizer = new StringTokenizer(messages, ";");
String result = null;
String uname = "";
String umess = "";
while (tokenizer.hasMoreTokens()) {
result = tokenizer.nextToken();
listMessages.add(new Message(result, ""));
}
I still have to do this on the : to have the two resulting strings in my list element, and I tried something like that:
List<Message> listMessages = new ArrayList<Message>();
StringTokenizer tokenizer = new StringTokenizer(messages, ";");
String result = null;
String uname = "";
String umess = "";
while (tokenizer.hasMoreTokens()) {
result = tokenizer.nextToken().split(":");
uname = result[0];
umess = result[1];
listMessages.add(new Message(result[0], result[1]));
}
But I got this error, that I don't understand?
01-23 17:12:19.168: E/AndroidRuntime(711): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.appandroid/com.example.appandroid.ListActivity}: java.lang.ArrayIndexOutOfBoundsException: length=1; index=1
Thanks in advance to look at my problem.

Instead of using StringTokenizer, you can use String.split(regex) to split based on two delimiters like below:
String test="this: bill:hello;tom:hi;bill:how are you?;tommy:hello!;";
String[] arr = test.split("[:;]");
for(String s: arr){
System.out.println(s);
}
Output:
this
bill
hello
tom
hi
bill
how are you?
tommy
hello!
EDIT:
from #njzk2 comments if you just wanna use StringTokenizer you can use one of its overloaded constructor which takes 2 args .
StringTokenizer str = new StringTokenizer(test, ":;");

Cut ':' && " " from a String with a tokenizer

right now I am a little bit confused. I want to manipulate this string with a tokenizer:
Bob:23456:12345 Carl:09876:54321
However, I use a Tokenizer, but when I try:
String signature1 = tok.nextToken(":");
tok.nextToken(" ")
I get:
12345 Carl
However I want to have the first int and the second int into a var.
Any ideas?

You have two different patterns, maybe you should handle both separated.
Fist you should split the space separated values. Only use the string split(" "). That will return a String[].
Then for each String use tokenizer.
I believe will works.
Code:
String input = "Bob:23456:12345 Carl:09876:54321";
String[] words = input.split(" ")
for (String word : words) {
String[] token = each.split(":");
String name = token[0];
int value0 = Integer.parseInt(token[1]);
int value1 = Integer.parseInt(token[2]);
}

Following code should do:
String input = "Bob:23456:12345 Carl:09876:54321";
StringTokenizer st = new StringTokenizer(input, ": ");
while(st.hasMoreTokens())
{
String name = st.nextToken();
String val1 = st.nextToken();
String val2 = st.nextToken();
}

Seeing as you have multiple patterns, you cannot handle them with only one tokenizer.
You need to first split it based on whitespace, then split based on the colon.
Something like this should help:
String[] s = "Bob:23456:12345 Carl:09876:54321".split(" ");
System.out.println(Arrays.toString(s ));
String[] so = s[0].split(":", 2);
System.out.println(Arrays.toString(so));
And you'd get this:
[Bob:23456:12345, Carl:09876:54321]
[Bob, 23456:12345]

If you must use tokeniser then I tink you need to use it twice
String str = "Bob:23456:12345 Carl:09876:54321";
StringTokenizer spaceTokenizer = new StringTokenizer(str, " ");
while (spaceTokenizer.hasMoreTokens()) {
StringTokenizer colonTokenizer = new StringTokenizer(spaceTokenizer.nextToken(), ":");
colonTokenizer.nextToken();//to igore Bob and Carl
while (colonTokenizer.hasMoreTokens()) {
System.out.println(colonTokenizer.nextToken());
}
}
outputs
23456
12345
09876
54321
Personally though I would not use tokenizer here and use Claudio's answer which splits the strings.

String between two commas Java

How can i isolate a String existed between two commas?
i.e. Angelo,Marco,Nick,Brandon,Paul
I want to retrieve the name Marco. Which is the most appropriate way? Should i use regex?If yes,can anyone explain me how?

The simplest solution is to use String.split(",")
like so:
String str = "Angelo,Marco,Nick,Brandon,Paul";
String[] myStrings = str.split(",");
String marco = myStrings[1];

Try this
String s = "Angelo,Marco,Nick,Brandon,Paul";
String array[] = s.split(",");
for (int i = 0; i < array.length; i++) {
System.out.println("element "+i+" "+array[i]);
}

You can use split e.g.
String[] names = "Angelo,Marco,Nick,Brandon,Paul".split(",");
// or
List<String> names = Arrays.asList("Angelo,Marco,Nick,Brandon,Paul".split(","));
// or
for(String name: "Angelo,Marco,Nick,Brandon,Paul".split(","))
System.out.println(name);

Well lets not make it complicated and use split() and Arrays.asList() method....
String str = "Angelo,Marco,Nick,Brandon,Paul";
String[] arr = str.split(",");
List<String> alist = new ArrayList<String>(Arrays.asList(arr);
String marco = alist.get(alist.indexOf("Marco"));
Voila..... its done... !!! Marco is with u now....

split string using comma separator.
**try it**
String str = "Angelo,Marco,Nick,Brandon,Paul";
String lines[]= str.split(",");
String name = lines[1];