right now I am a little bit confused. I want to manipulate this string with a tokenizer:
Bob:23456:12345 Carl:09876:54321
However, I use a Tokenizer, but when I try:
String signature1 = tok.nextToken(":");
tok.nextToken(" ")
I get:
12345 Carl
However I want to have the first int and the second int into a var.
Any ideas?
You have two different patterns, maybe you should handle both separated.
Fist you should split the space separated values. Only use the string split(" "). That will return a String[].
Then for each String use tokenizer.
I believe will works.
Code:
String input = "Bob:23456:12345 Carl:09876:54321";
String[] words = input.split(" ")
for (String word : words) {
String[] token = each.split(":");
String name = token[0];
int value0 = Integer.parseInt(token[1]);
int value1 = Integer.parseInt(token[2]);
}
Following code should do:
String input = "Bob:23456:12345 Carl:09876:54321";
StringTokenizer st = new StringTokenizer(input, ": ");
while(st.hasMoreTokens())
{
String name = st.nextToken();
String val1 = st.nextToken();
String val2 = st.nextToken();
}
Seeing as you have multiple patterns, you cannot handle them with only one tokenizer.
You need to first split it based on whitespace, then split based on the colon.
Something like this should help:
String[] s = "Bob:23456:12345 Carl:09876:54321".split(" ");
System.out.println(Arrays.toString(s ));
String[] so = s[0].split(":", 2);
System.out.println(Arrays.toString(so));
And you'd get this:
[Bob:23456:12345, Carl:09876:54321]
[Bob, 23456:12345]
If you must use tokeniser then I tink you need to use it twice
String str = "Bob:23456:12345 Carl:09876:54321";
StringTokenizer spaceTokenizer = new StringTokenizer(str, " ");
while (spaceTokenizer.hasMoreTokens()) {
StringTokenizer colonTokenizer = new StringTokenizer(spaceTokenizer.nextToken(), ":");
colonTokenizer.nextToken();//to igore Bob and Carl
while (colonTokenizer.hasMoreTokens()) {
System.out.println(colonTokenizer.nextToken());
}
}
outputs
23456
12345
09876
54321
Personally though I would not use tokenizer here and use Claudio's answer which splits the strings.
Related
I have an application that suppose to read data from the text file with student details (student.txt), such that I have a studentNo, StudentName, Marks etc. . .
Here is a sample of the data that's in the textfile :
20405587 "ZULU,B M" 65 67
20407388 "JUGGERNATH,N" 66 63
20408427 "KHATHI,P X" 60 60
20409821 "SINGH,T" 62 59
20410422 "NKOMO,N N" 58 60
I'm using a scanner to read from the file, here is my code so far. . .it gives me an error
try
{
BufferedReader br = new BufferedReader(new FileReader("student.txt"));
String line = br.readLine();
while (line!=null)
{
Scanner scan = new Scanner(line);
scan.useDelimiter(" ");
String dummystudent=scan.next();
int studentNo= Integer.parseInt(dummystudent);
String dummyname1 = scan.next();
String dummyname2 = scan.next();
String studentName = dummyname1+dummyname2;
String dummytest1 = scan.next();
int test1= Integer.parseInt(dummytest1);
String dummytest2 = scan.next();
int test2= Integer.parseInt(dummytest2);
tad1.setText(tad1.getText()+"Student Number: " + studentNo + '\n' + "Student Name :" + studentName );
line = br.readLine();
}
br.close();
}
catch(Exception b)
{
JOptionPane.showMessageDialog(null,b.getMessage());
}
You set the delimiter to a single space. This is the problem. next will return an empty string a few times because those lines of yours has more than one consecutive spaces.
Instead you want to say one or more spaces:
sc.useDelimiter(" +");
It's still not 100% since "ZULU,B M" has a space in the middle and "JUGGERNATH,N" doesn't, but I'll leave that to you to figure out. Maybe:
sc.useDelimiter("\"");
somewhere in the middle there.
The + has to do with regular expressions, see this for more in general and this for more Java-specific.
Your parsing seems to be overkill.
Consider using Scanner to read the line and use StringUtils.split() to parse the line.
Here is some code:
public static void main(String[] args)
{
int index = 1; // Just for printing.
for (String current : input)
{
String[] split1; // result: number, name, numbers
String[] split2;
String studentName1;
String studentName2;
String studentNumber;
String testScore1;
String testScore2;
split1 = StringUtils.split(current, '"');
studentNumber = StringUtils.trim(split1[0]);
split2 = StringUtils.split(split1[1], ',');
studentName1 = StringUtils.trim(split2[0]);
studentName2 = StringUtils.trim(split2[1]);
split2 = StringUtils.split(split1[2]); // default seperator is whitespace.
testScore1 = StringUtils.trim(split2[0]);
testScore2 = StringUtils.trim(split2[1]);
System.out.println(
index + ":" +
" Number: " + ">" + studentNumber + "" + studentName1 + "" + studentName2 + "" + testScore1 + "" + testScore2 + "
Note: StringUtils is from Apache Commons Lang
Easiest way to end would to be go line by line.
Pattern filePatten = Pattern.compile("\\s*(\\d+)\\s+(\"[^\"]+\")\\s+(\\d+)\\s+(\\d+)\\s*");
while (scanner.hasNextLine()) {
String line = scanner.nextLine();
Matcher matcher = filePattern.matcher(line);
if (matcher.matches()) {
String id = matcher.group(1);
String name = matcher.group(2);
//etc
} else {
//Warn : Fragile Regex
}
}
Each group in the regex captures a part of the line. The second group captures the name with quotes. You might want to remove it.
You should be using the delimiter "? +"?, the delimiter is a regex, and your string has multiple spaces to separate fields, you also need to take into account quotes around string fields. I'm yet to workout how to solve string fields with spaces.
http://docs.oracle.com/javase/1.5.0/docs/api/java/util/Scanner.html#useDelimiter(java.lang.String)
Using Regex you should be able to do it using the below regex string, and select the subgroups 1-4, through a Matcher
([0-9]{8}) +"([A-Z, ]+)" +([0-9]{2}) +([0-9]{2})
I have a string containing messages. The string looks like this:
bill:hello;tom:hi;bill:how are you?;tommy:hello!; ...
I need to split the string into several srings, on the characters : and ;.
For now, I have split the string on ; and i could add the results in list elements.
List<Message> listMessages = new ArrayList<Message>();
StringTokenizer tokenizer = new StringTokenizer(messages, ";");
String result = null;
String uname = "";
String umess = "";
while (tokenizer.hasMoreTokens()) {
result = tokenizer.nextToken();
listMessages.add(new Message(result, ""));
}
I still have to do this on the : to have the two resulting strings in my list element, and I tried something like that:
List<Message> listMessages = new ArrayList<Message>();
StringTokenizer tokenizer = new StringTokenizer(messages, ";");
String result = null;
String uname = "";
String umess = "";
while (tokenizer.hasMoreTokens()) {
result = tokenizer.nextToken().split(":");
uname = result[0];
umess = result[1];
listMessages.add(new Message(result[0], result[1]));
}
But I got this error, that I don't understand?
01-23 17:12:19.168: E/AndroidRuntime(711): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.appandroid/com.example.appandroid.ListActivity}: java.lang.ArrayIndexOutOfBoundsException: length=1; index=1
Thanks in advance to look at my problem.
Instead of using StringTokenizer, you can use String.split(regex) to split based on two delimiters like below:
String test="this: bill:hello;tom:hi;bill:how are you?;tommy:hello!;";
String[] arr = test.split("[:;]");
for(String s: arr){
System.out.println(s);
}
Output:
this
bill
hello
tom
hi
bill
how are you?
tommy
hello!
EDIT:
from #njzk2 comments if you just wanna use StringTokenizer you can use one of its overloaded constructor which takes 2 args .
StringTokenizer str = new StringTokenizer(test, ":;");
I have a txt file formatted like:
Name 'Paul' 9-years old
How can I get from a "readline":
String the_name="Paul"
and
int the_age=9
in Java, discarding all the rest?
I have:
...
BufferedReader bufferedReader = new BufferedReader(fileReader);
StringBuffer stringBuffer = new StringBuffer();
String line;
while ((line = bufferedReader.readLine()) != null) {
//put the name value in the_name
//put age value in the_age
}
...
Please suggest, thanks.
As you're using BufferedReader and everything is on the one line, you would have to split it to extract the data. Some additional formatting is then required to remove the quotes & extract the year part of age. No need for any fancy regex:
String[] strings = line.split(" ");
if (strings.length >= 3) {
String the_name= strings[1].replace("'", "");
String the_age = strings[2].substring(0, strings[2].indexOf("-"));
}
I notice you have this functionality in a while loop. For this to work, make sure that every line keeps the format:
text 'Name' digit-any other text
^^ ^^ ^
Important chars are
Spaces: min of 3 tokens needed for split array
Single quotes
- Hyphen character
use java.util.regex.Pattern:
Pattern pattern = Pattern.compile("Name '(.*)' (\d*)-years old");
for (String line : lines) {
Matcher matcher = pattern.matcher(line);
if (matcher.matches()) {
String theName = matcher.group(1);
int theAge = Integer.parseInt(matcher.group(2));
}
}
You can use the String.substring, String.indexOf, String.lastIndexOf, and Integer.parseInt methods as follows:
String line = "Name 'Paul' 9-years old";
String theName = line.substring(line.indexOf("'") + 1, line.lastIndexOf("'"));
String ageStr = line.substring(line.lastIndexOf("' ") + 2, line.indexOf("-years"));
int theAge = Integer.parseInt(ageStr);
System.out.println(theName + " " + theAge);
Output:
Paul 9
I have a String
String testString = "IN NEWYORK AND (OUT FLORIDA)" ;
I want to split out this string in array Like :
String testArray[] = testString.split("\\s()");
I would like the result to be:
testArray[0] = "IN";
testArray[1] = "NEWYORK";
testArray[2] = "AND";
testArray[3] = "(";
testArray[4] = "OUT";
testArray[5] = "FLORIDA";
testArray[6] = ")";
However, the output I get is:
testArray[0] = "IN";
testArray[1] = "NEWYORK";
testArray[2] = "AND";
testArray[3] = "(OUT";
testArray[4] = "FLORIDA)";
It is splitting on white spaces but not on "(" and ")" , I want "(" and ")" to be as seperate strings .
Try the below:
String testArray[] = testString.split("\\s|(?<=\\()|(?=\\))");
split() requires a deleimeter to remove. Use StringTokenizer and instruct it to keep the delimiters.
StringTokenizer st = new StringTokenizer("IN NEWYORK AND (OUT FLORIDA)", " ()", true);
while (st.hasMoreTokens()) {
String t = st.nextToken();
if (!t.trim().equals("")) {
System.out.println(t);
}
}
If you want to do it with string split, then monstrous regexes like \s+|((?<=\()|(?=\())|((?<=\))|(?=\))) are pretty much inevitable. This regex is based on this question, btw, and it almost works.
Easiest way is to either surround parentheses with spaces as suggested by #acerisara or use StringTokenizer as suggested by #user1030723
String test = "IN NEWYORK AND (OUT FLORIDA)";
// this can for sure be done better, hope you get the idea
String a = test.replaceAll("(", "( ");
String b = a.replaceAll(")", " )";
String array[] = b.split("\\s");
I was wondering if someone could provide me some code or point me towards a tutrial which explain how I can convert my string so that each word begins with a capital.
I would also like to convert a different string in italics.
Basically, what my app is doing is getting data from several EditText boxes and then on a button click is being pushed onto the next page via intent and being concatenated into 1 paragraph. Therefore, I assume I need to edit my string on the intial page and make sure it is passed through in the same format.
Thanks in advance
You can use Apache StringUtils. The capitalize method will do the work.
For eg:
WordUtils.capitalize("i am FINE") = "I Am FINE"
or
WordUtils.capitalizeFully("i am FINE") = "I Am Fine"
Here is a simple function
public static String capEachWord(String source){
String result = "";
String[] splitString = source.split(" ");
for(String target : splitString){
result
+= Character.toUpperCase(target.charAt(0))
+ target.substring(1) + " ";
}
return result.trim();
}
The easiest way to do this is using simple Java built-in functions.
Try something like the following (method names may not be exactly right, doing it off the top of my head):
String label = Capitalize("this is my test string");
public String Capitalize(String testString)
{
String[] brokenString = testString.split(" ");
String newString = "";
for(String s : brokenString)
{
s.charAt(0) = s.charAt(0).toUpper();
newString += s + " ";
}
return newString;
}
Give this a try, let me know if it works for you.
Just add android:inputType="textCapWords" to your EditText in layout xml. This wll make all the words start with the Caps letter.
Strings are immutable in Java, and String.charAt returns a value, not a reference that you can set (like in C++). Pheonixblade9's will not compile. This does what Pheonixblade9 suggests, except it compiles.
public String capitalize(String testString) {
String[] brokenString = testString.split(" ");
String newString = "";
for (String s : brokenString) {
char[] chars = s.toCharArray();
chars[0] = Character.toUpperCase(chars[0]);
newString = newString + new String(chars) + " ";
}
//the trim removes trailing whitespace
return newString.trim();
}
String source = "hello good old world";
StringBuilder res = new StringBuilder();
String[] strArr = source.split(" ");
for (String str : strArr) {
char[] stringArray = str.trim().toCharArray();
stringArray[0] = Character.toUpperCase(stringArray[0]);
str = new String(stringArray);
res.append(str).append(" ");
}
System.out.print("Result: " + res.toString().trim());