We Keep Coding

Can't open Tomcat startup

I can't seem to open up the Tomcat console despite having just been able to successfully do so. When I click on the "startup" Windows Batch File, the console opens then closes itself immediately afterwards. I've read that it has something to do with setting up the environment variables / paths correctly but I've looked at it and it seems fine; you can check the picture out.
NOTE: Over the course of step 6, the javac command did not work for me. To fix I added a second "C:\Program Files..jdk1.8.0_131\bin" into the Path variable (as you can see in the picture. This enabled me to use the javac command but I have no idea why it didn't detect the JAVA_HOME.
Trying to run startup via cmd console outputs the message: D:\myProject\tomcat\bin>startup
The JRE_HOME environment variable is not defined correctly
This environment variable is needed to run this program
I'm still a beginner with server management so I've been following this tutorial: https://www.ntu.edu.sg/home/ehchua/programming/howto/Tomcat_HowTo.html. I'm at the end of step 6c) where it tells me I should restart the server after compiling an servlet and creating an xml. But lo and behold, it won't open again after quitting...

You must not point JAVA_HOME to bin directory. Just point it to jdk directory, and add a %JAVA_HOME%\bin to your path variable.

My Tomcat is not running it just open and close when I click on tomcat7.exe [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about programming within the scope defined in the help center.
Closed 2 years ago.
Improve this question
I am installing Tomcat 7 in my PC it works in Eclipse but when I try to open in bin/ tomcat7.exe it just open and closes, (I am stopping the server in Eclipse). Also, in Eclipse I'am trying to open admin console like URL:(localhost:1234/admin) it shows 404 error. Can anyone who knows this problem explain a solution?

If you are using Windows, you can follow the following to run tomcat7.exe :
Open your Command prompt (cmd)
Set your JAVA_HOME or JRE_HOME. Eg. set JRE_HOME=C:\Program Files\Java\jre7
Go to the directory of your tomcat. Eg. cd C:\Program Files\apache-tomcat-7.0.35\bin
Run startup.bat file. Eg. startup.
This should start your tomcat server without using Eclipse.

First Set JAVA_HOME and CLASSPath path
For Windows Java Path Settings
Right click on Computer and open Properties.
In Windows Vista or Windows 7, go to Advanced System Settings.
Else go to next step. Go to Advanced Tab and click on Environment
Variables button.
Select CLASSPath under the list of System Variables, and press Edit and add If CLASSPath not available there click New button add
C:\Program Files\java\jre 1.x.x_xx\bin
after a semicolon.
Now click on New' button under system variables and enter
JAVA_HOME as variable name and path to jdk home directory (ex.
C:\Program Files\Java\jdk1.x.x_xx
After Completing Java Path Settings
Go to the directory of your Tomcat. Eg. cd C:\Program
Files\apache-tomcat-7.0.35\bin
Run startup.bat file

To start your application server in Windows :
Open command prompt .(Run as Administrator).
Go to the path (..\apache-tomcat-8.0.27\bin) and run startup.bat
A new command prompt opens up and should stay unclosed to tell your server is in running state.
If command prompt opens and closes automatically, then the reason can be as below.
tomcat is already in started state in Eclipse.
Check the connector port configured in server.xml file and check if that port is free in your local machine. [netstat command]
Change the connector port to some unused port, preferably in 80XX series.
Let me know if you are able to invoke localhost:(the http connector port) you have configured in server.xml through you web browser.

You don't start Tomcat by double clicking the exe, use the batch files instead.
startup.bat starts the server, shutdown.bat stops it again.
And ignore the advise to get the service installer. You don't need those unless you want the server to start on system boot and run in the background. Which you don't want unless you're going to configure a production server, which you aren't here.
The batch files are in the same directory on your computer as the exe.

you have to set JAVA_HOME and JRE_HOME in System environment.while setting the JAVA_HOME and JRE_HOME, you should assure that JRE path that you are setting is corresponding to the JDK whose path you have set in JAVA_HOME. some time what happens that there may be more than one JDK in the system so conflict occurs. better to have only one JDK and corresponding JRE.

This is probably due to a bad setup of an environment variable.
For example, if you setup incorrect JAVA_OPTS, tomcat startup will fail.
You can check your configuration by calling : catalina configtest
Here an example of the output for bad setup of JAVA_OPTS :
Error occurred during initialization of VM Could not reserve enough space for object heap
Error: Could not create the Java Virtual Machine.
Error: A fatal exception has occurred. Program will exit.

It works for me after updating the jdk path in JAVA_HOME compatible to your tomcat version in user Variables.

the JAVA_HOME and JRE_HOME environment variables set should not have semicolon or ; at the end...I was facing similar problem...removed semi-colon or ; from the end and tomcat server started from cmd screen after running startup command(of tomcat..bin folder).

I checked environment variables and compiler version everything was fine, deleting junk files from work folder worked for me.

Just download the tomcat 32-bit/64-bit Windows Service Installer (pgp, md5) as in this set up is given which will install tomcat on your PC and you can also start and stop tomcat using the tomcat service.

In my experience tomcat7 might not like it if JAVA_PATH or JDK_PATH contain bracket symbols like in "Program Files (x86)". Make sure you format path in your environmental variables correctly or move your JDK to another folder.

In my case, I had some reference to a jar file in catilana.bat, but the jar I had removed from my system. Tomcat started successfully once I removed that reference from catilana.bat

Check your JRE_HOME location in environment variables. if it didn't work then try
1). Open CMD in administration mode.
2). locate to your tomcat directory.
3). run startup.bat --->> It will show your problem.

Had the same problem with Apache Tomcat 9 version.
Solution is very simple.
Apache Tomcat 9 is supported by Java 8 and later versions. So, I had JRE_HOME with JRE7 path, I binded it to new JRE8 and everything works fine.
Different versions of Apache Tomcat are available for different versions of the Servlet and JSP specifications. The mapping between the specifications and the respective Apache Tomcat versions is:

XAMPP Tomcat/Error starting Tomcat

Can someone help me solve this:
"Tomcat Started/Stopped with errors, return code: 1 Make sure you have Java JDK or JRE installed and the required ports are free. Check the "/xampp/tomcat/logs" folder for more information."
I have installed Java JDK. Thanks

Go to https://youtu.be/JmmaeS7UZRk youtube link for better understanding:
we need to create an Environment Variable "JAVA_HOME".
and give the vale as JDK installation directory path.
Ex: "C:\Program Files\Java\jdk1.8.0_66"
we need to create an Environment Variable "JRE_HOME". and give the vale as JRE installation directory path. Ex: "C:\Program Files\Java\jre1.8.0_66"
Go to your "tomcat" installation directory and then "conf" folder. Ex: "C:\xampp\tomcat\conf".
Edit these given files with these values:
i) open server.xml file which is located inside conf folder. Go to line number "70" and change the "port" number "8080" as something else for example "9999" and save it.
ii) open context.xml file which is located inside "conf" folder and go to line number "19" and change <Context> tag as <Context reloadable="true"> and save it.
close the "XAMPP" App and restart it.
Now go to the "Config" Option inside "XAMPP" application i.e top right corner of the XAMPP app. then go to the "Service and Port Settings" then go to the "Tomcat" tab and put "9999" as the "HTTP Port" value and save it. Not restart XAMPP.
Now try to start "Tomcat" Server.
Open your browser and type localhost:9999 in the browser url and hit enter.

Run XAMPP with "Administrator Privileges" to start Tomcat.
It is as simple as that.

WINDOWS-KEY + PAUSE (shortcut to System Properties), in system properties choose
Advanced system settings --> Environment variables --> add a new System variable:
Fill in:
Variable name: JAVA_HOME
Variable value: C:\Program Files\Java\jdk1.8.0 (or whatever your location/version is)
klik ok and done(maybe you should restart tomcat after this)

Try to change your port. Maybe you have another app running in the port 8080.
If you run in the 8081 for example it will run correctly

Is your java registered in the enviorement variables.
If you open console Win+R -> CMD and write java --version (For JDK) and java -version (for JRE) do you get any output ?

windows service from batch file failed to execute

i need to execute a batch file as windows service.
For that i had created a batch file.
In this batch file i just add the below code to run a jar file.
java -jar myTest.jar
When i double click on the batch file..no problem .its working fine. It executes the jar file (a java application).
But the same batch file when i used in a windows service on a windows server, its not working.? Its just getting blinked to show the command window and gets closed. None of my code portion inside the jar file gets executed.
Another thing is i had successfully checked this from another windows server. Its working fine there.
Why this strange issue..??Can anyone help me out to solve the issue..

The service is not executed in the same environment as when you run the batch from an interactive Windows session. Make shure in the .bat file that change into the correct (working) directory, even with absolut path (cd \users\my\java\service), and maybe specify the full path to the java.exe. The other server do you mention could have a totally diferent setup of the environment, installed software, etc.
C:
cd \users\my\java\service
"\program files\java\jre\bin\java" -jar test.jar

Tomcat -- Running a web application

I'm trying to run a sample app in Tomcat. I've installed tomcat, set up the environment variable by creating a new system variable called JAVA_HOME which is set to C:\Program Files\Java\jdk1.6.0_20. And I've created a new dir for the web app in the tomcat program directory. In the cmd prompt I navigate to the tomcat program directory and type in bin/startup.sh and I get the following error: 'bin' is not recognized as an internal or external command, operable program, or batch file.
I'm using tomcat 6.0 and I'm on a windows machine. What could the problem?

On Windows you must run the startup.bat file instead of the startup.sh file (note the extension is different).
Also, enter the bin directory before executing the bat script.
cd bin
startup.bat

Your on windows try:
bin\startup.bat

If you try typing in bin\startup.bat on a Windows machine and still get the same error, there's a possibility that Windows is not seeing the batch script where it should be. As a-horse-with-no-name already said, try installing Tomcat to a location where there are no spaces in the path. In your case, anywhere other than Program Files.
EDIT: To resolve this space issue, you can do two things: 1) Install JDK/JRE to a common location without spaces (say, C:\Java) and set it to be JAVA_HOME environment variable. 2) Install Tomcat to another location (say, C:\Tomcat) and proceed from there. Since these are all in common location, I believe you can do this as a limited account user without needing admin privileges.

Try to install Tomcat (and possibly the JDK) into a directory without spaces.

The script you ran is intended for *nix systems. Try bin\startup.bat

I'm a little confused by some of the answers. First, the error you are receiving is from Windows. Nothing to do with Tomcat. The Windows OS thinks you have entered a command, and doesn't recognize it. Files with the .bat extension are always recognized by Windows as Batch file commands....... soooo..... Navigate to the bin directory, again, under your tomcat installation. Then....
Don't append the bin in front of the command. You should do a quick look to make sure that the "startup.bat" file is here (dir *.bat). Then just type "startup.bat".
Seems like I just type "catalina.bat start" (for my tomcat catalina installation)