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Set random seed on Postgres using hibernate

I'm not very familiar with Hibernate, but I need to set the random seed on a PostgreSQL database using Hibernate.
This is what I'm trying to run:
String seedSql = "select setseed(0.123)";
Query seedQuery = entityManager.createQuery(seedSql);
seedQuery.getSingleResult();
However, this query does not return any entity mapped by Hibernate, thus I'm receiving the following error:
org.hibernate.QueryException: No data type for node: org.hibernate.hql.internal.ast.tree.MethodNode (...)
Any suggestions?

According to the docs, createQuery() takes a JPQL string, and apparently doesn't know what to do with your Postgres function call.
To run an SQL query, use createNativeQuery() instead.

After some trial and error I noticed that I had to use .createNativeQuery() since setseed() is a function from PostgreSQL:
String seedsql = "select cast(setseed(0.123) as text)";
Query seedQuery = DatabaseInterface.getEm().createNativeQuery(seedsql);
seedQuery.setMaxResults(1).getSingleResult();
I used cast(setseed(0.123) as text) to avoid another error:
org.hibernate.MappingException: No Dialect mapping for JDBC type: 1111

jOOQ - error with alias and quotes

I have this query:
Field<String> yearMonth = DSL.field("FORMATDATETIME({0}, 'yyyy-MM')",
String.class, LICENZE.CREATION_DATE).as("anno_mese");
List<Record3<Integer, String, String>> records =
create.select(DSL.count().as("num_licenze"), LICENZE.EDIZIONE, yearMonth).
from(LICENZE).
groupBy(LICENZE.EDIZIONE, yearMonth).
orderBy(yearMonth).
fetch();
this query generates:
select
count(*) "num_licenze",
"PUBLIC"."LICENZE"."EDIZIONE",
FORMATDATETIME("PUBLIC"."LICENZE"."CREATION_DATE", 'yyyy-MM') "anno_mese"
from "PUBLIC"."LICENZE"
group by
"PUBLIC"."LICENZE"."EDIZIONE",
"anno_mese"
order by "anno_mese" asc
executing it i get: Column "anno_mese" not found; SQL statement
Testing the generated query and removing the quotes from anno_mese in every parts of the query make the query works instead.
Is my query wrong or am I using jooq in the wrong way?
The alias in this query is not so important, I can run the query without using it too but just to understand how it works.
I am using h2 as database.
Thanks for the help

I suspect this is a bug in H2, which I've reported here, because the query looks fine to me. Here are some workarounds that you can do from the jOOQ side:
Don't reference the "anno_mese" column by name
While SQL is a bit repetitive otherwise, you won't notice the difference with jOOQ. I simply moved the as("anno_mese") method call into the SELECT clause. You don't really need it in the GROUP BY and ORDER BY clauses.
Field<String> yearMonth = DSL.field("FORMATDATETIME({0}, 'yyyy-MM')",
String.class, LICENZE.CREATION_DATE);
List<Record3<Integer, String, String>> records =
create.select(DSL.count().as("num_licenze"),
LICENZE.EDIZIONE,
yearMonth.as("anno_mese")).
from(LICENZE).
groupBy(LICENZE.EDIZIONE, yearMonth).
orderBy(yearMonth).
fetch();
Disable quoting in jOOQ generated queries
You can use jOOQ's Settings to prevent schema / table / column names from being quoted. Example:
DSLContext create = DSL.using(connection, SQLDialect.H2,
new Settings().withRenderNameStyle(RenderNameStyle.AS_IS);
Use upper case column names
This will probably work: DSL.field(...).as("ANNO_MESE")

Get dynamic SQL column names from Hibernate

I have an Oracle table that has a CLOB in it. Inside this CLOB can be a SQL statement. This can be changed at any time.
I am currently trying to dynamically run these SQL statements and return the column names and data back. This is to be used to dynamically create a table on the web page.
Using Hibernate, I create the query and get the data like so:
List<Object[]> queryResults = null;
SQLQuery q = session.createSQLQuery(sqlText);
queryResults = q.list();
This gets the data I need, but not the column names. I have tried using the getReturnAliases() method, but it throws an error that the "java.lang.UnsupportedOperationException: SQL queries do not currently support returning aliases"
So my question is: Is there a way through Hibernate to get these values dynamically?

You can use :
q.setResultTransformer(AliasToEntityMapResultTransformer.INSTANCE);
List<Map<String,Object>> aliasToValueMapList=query.list();
to get column names in createSQLQuery.
For more details please refer to this question.

You can use the addScalar method to define the columns.
Look at 16.1.1
https://docs.jboss.org/hibernate/orm/3.3/reference/en-US/html/querysql.html

You could implement a ResultTransformer ( http://docs.jboss.org/hibernate/orm/4.3/javadocs/org/hibernate/transform/ResultTransformer.html ) and set it on the native query. I think with a native SQL query you get the aliases as specified in the SQL as alias parameter in the callback method.

In 2018 I would suggest using NativeQueryTupleTransformer with native queries.
query.setResultTransformer(new NativeQueryTupleTransformer());
The result format is List<Tuple>. This format is very convenient to work with native SQL queries.

How to use CONCAT_WS() in Hibernate HQL

To combine multiple columns as one,
I found one answer
SELECT id,CONCAT_WS(',', field_1, field_2, field_3, field_4) list
FROM `table`;
This query working fine in SQL but it gives me error in HQL:
Error is .
(java.lang.IllegalStateException: No data type for node: org.hibernate.hql.internal.ast.tree.MethodNode )
please help me to find out what wrong i did, help me to know how to use CONCAT_WS() IN HQL
below how i written my HQL query
SELECT C1._URI,C1.HEALTH_FACILITY,C1.DISTRICT,CONCAT_WS(',', C1.BLOCKS_OF_BHUBRI, C1.BLOCKS_OF_GOLAGHAT, C1.BLOCKS_OF_HAILAKANDI) as Block_name
FROM GapAnalysisWashInHealthFacilitiesCore C1
any help will appreciate

CONCAT_WS is a function specific to mySql. HQL is a generic language and not aware of native SQL functions and syntax. If you really need the function, then you should use Hibernate's API for native SQL.
Session session = ...;
Query query = session.createSQLQuery("
SELECT id,CONCAT_WS(',', field_1, field_2, field_3, field_4) Block_name FROM `table`");
List result = query.list();
Then you may like to have a look at Result Transformers to get result as list of GapAnalysisWashInHealthFacilitiesCore objects.

Hibernate session.createQuery error while replace method with single quote

I got very typical issue. My dynamically generated query like this...
UPDATE Templates t SET t.TEMPLATE_DATA = replace(t.TEMPLATE_DATA, 'Test\'s Test', 'Kent"s Test'), t.TEMPLATE_DATA = replace(t.TEMPLATE_DATA, 'Test"s Test', 'Kent"s Test'), UPDATE_DATE = NOW() where PRACTICE_ID = 1 AND CATEGORY_ID IN (1)
This works perfect when I explictily fire this query in db. but by using hibernate's session.createQuery(-- my query --) if thwows an error QueryTranslatorException.
Database : Mysql 5.3
Have any one faced this issue?
Thanks in advance.

Try to run this in Hibernate as native SQL query:
session.createSQLQuery(-- query text --);
Because if you use
session.createQuery(-- query text --);
Hibernate will try to execute it as HQL query which differs from usual SQL query.
HQL is object oriented query language. It operates in terms of objects rather then in terms of tables. Here posted a brief description of difference between SQL and HQL. But if you have time better to read appropriate sections of hibernate's documentation about HQL and Native SQL usage.

If you want to execute SQL Query in hibernate, Use : session.createSQLQuery(String query);