I'm not very familiar with Hibernate, but I need to set the random seed on a PostgreSQL database using Hibernate.
This is what I'm trying to run:
String seedSql = "select setseed(0.123)";
Query seedQuery = entityManager.createQuery(seedSql);
seedQuery.getSingleResult();
However, this query does not return any entity mapped by Hibernate, thus I'm receiving the following error:
org.hibernate.QueryException: No data type for node: org.hibernate.hql.internal.ast.tree.MethodNode (...)
Any suggestions?
According to the docs, createQuery() takes a JPQL string, and apparently doesn't know what to do with your Postgres function call.
To run an SQL query, use createNativeQuery() instead.
After some trial and error I noticed that I had to use .createNativeQuery() since setseed() is a function from PostgreSQL:
String seedsql = "select cast(setseed(0.123) as text)";
Query seedQuery = DatabaseInterface.getEm().createNativeQuery(seedsql);
seedQuery.setMaxResults(1).getSingleResult();
I used cast(setseed(0.123) as text) to avoid another error:
org.hibernate.MappingException: No Dialect mapping for JDBC type: 1111
Related
I want to make dynamic query in which if particular parameter is sent, the Native query should filter the result based on it. In case it's null, it should not reflect the result.
I am using Spring Data JPA with Native query mechanism + Oracle DB
For String parameters this approach works fine
:email is null or s.email = :email
but for Integer parameters when they have value, the Query works but if the parameter is null the query fails with the error
Caused by: java.sql.SQLSyntaxErrorException: ORA-00932: inconsistent datatypes: expected NUMBER got BINARY
I am using the exactly the same approach for for Integer instead of String
I am wondering whether the problem is on my side or it's some kind of bug?
In Oracle DB it's not worked this way. A workaround is using JPQL like
SELECT s FROM Entity s WHERE :id is null OR s.id = COALESCE(:id, -1)
Or for native query use TO_NUMBER function of oracle
SELECT s FROM Entity s WHERE :id is null OR s.id = TO_NUMBER(:id)
I'm using Spring Data JPA + QueryDSL. I create my dynamic queries like this:
JPAQuery<Foo> query = jpaQueryFactory.select(...);
I have found this old article that shows how to retrieve programatically the native sql string: https://antoniogoncalves.org/2012/05/24/how-to-get-the-jpqlsql-string-from-a-criteriaquery-in-jpa/ but it doesn't work for me.
I have tried this:
String queryString1 = query.createQuery().unwrap(org.hibernate.query.Query.class).getQueryString();
String queryString2 = query.createQuery().unwrap(org.eclipse.persistence.jpa.JpaQuery.class).getDatabaseQuery().getSQLString();
The first doesn't returns me the the native sql but the JPQL string and the second fails to unrwap org.hibernate.query.internal.QueryImpl to org.eclipse.persistence.jpa.JpaQuery.
PS: I've tested before and after fetching the query.
If you need native SQL query generated by Querydsl, then you need to use SQLQueryFactory instead JPAQueryFactory. Your JPQL query returned by JPAQueryFactory is transformed to SQL by JPA not by Querydsl.
When I try to call a stored procedure from Java - Hibernate. I got the below error.
org.hibernate.QueryException: Not all named parameters have been set:
and my Code
Query query = session.createSQLQuery("select commsrules.evalcommsrules(?::text,?::commsrules.t_commstype)");
query.setString(0, in_query);
query.setString(1, "TRIG");
result = query.list();
and I got the below exception
org.hibernate.QueryException: Not all named parameters have been set: [:text, :commsrules.t_commstype] [select commsrules.evalcommsrules(?::text,?::commsrules.t_commstype)]
at org.hibernate.internal.AbstractQueryImpl.verifyParameters(AbstractQueryImpl.java:390)
at org.hibernate.internal.SQLQueryImpl.verifyParameters(SQLQueryImpl.java:179)
at org.hibernate.internal.SQLQueryImpl.list(SQLQueryImpl.java:118)
please help me to resolve this issue
Looks like it's parsing :text and the other as a named parameter, even though you're trying to use positional parameters.
You could modify the query to use CAST instead of the :: shorthand.
I have an Oracle table that has a CLOB in it. Inside this CLOB can be a SQL statement. This can be changed at any time.
I am currently trying to dynamically run these SQL statements and return the column names and data back. This is to be used to dynamically create a table on the web page.
Using Hibernate, I create the query and get the data like so:
List<Object[]> queryResults = null;
SQLQuery q = session.createSQLQuery(sqlText);
queryResults = q.list();
This gets the data I need, but not the column names. I have tried using the getReturnAliases() method, but it throws an error that the "java.lang.UnsupportedOperationException: SQL queries do not currently support returning aliases"
So my question is: Is there a way through Hibernate to get these values dynamically?
You can use :
q.setResultTransformer(AliasToEntityMapResultTransformer.INSTANCE);
List<Map<String,Object>> aliasToValueMapList=query.list();
to get column names in createSQLQuery.
For more details please refer to this question.
You can use the addScalar method to define the columns.
Look at 16.1.1
https://docs.jboss.org/hibernate/orm/3.3/reference/en-US/html/querysql.html
You could implement a ResultTransformer ( http://docs.jboss.org/hibernate/orm/4.3/javadocs/org/hibernate/transform/ResultTransformer.html ) and set it on the native query. I think with a native SQL query you get the aliases as specified in the SQL as alias parameter in the callback method.
In 2018 I would suggest using NativeQueryTupleTransformer with native queries.
query.setResultTransformer(new NativeQueryTupleTransformer());
The result format is List<Tuple>. This format is very convenient to work with native SQL queries.
I got very typical issue. My dynamically generated query like this...
UPDATE Templates t SET t.TEMPLATE_DATA = replace(t.TEMPLATE_DATA, 'Test\'s Test', 'Kent"s Test'), t.TEMPLATE_DATA = replace(t.TEMPLATE_DATA, 'Test"s Test', 'Kent"s Test'), UPDATE_DATE = NOW() where PRACTICE_ID = 1 AND CATEGORY_ID IN (1)
This works perfect when I explictily fire this query in db. but by using hibernate's session.createQuery(-- my query --) if thwows an error QueryTranslatorException.
Database : Mysql 5.3
Have any one faced this issue?
Thanks in advance.
Try to run this in Hibernate as native SQL query:
session.createSQLQuery(-- query text --);
Because if you use
session.createQuery(-- query text --);
Hibernate will try to execute it as HQL query which differs from usual SQL query.
HQL is object oriented query language. It operates in terms of objects rather then in terms of tables. Here posted a brief description of difference between SQL and HQL. But if you have time better to read appropriate sections of hibernate's documentation about HQL and Native SQL usage.
If you want to execute SQL Query in hibernate, Use : session.createSQLQuery(String query);