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Running a .exe file using Java
(4 answers)
Closed 9 years ago.
Actually I am working Wolfram Mathematica,we don't have any functions for running external programs, so I want to do this App using Java technology.
In my organization, C developing team, developed one Application and given to us in a .exe format.Know I want to run that .exe file from Java.
I have a .exe name as ThMapInfratab1-2.exe under C:/Users/Infratab Bangalore/Desktop/Rod's directory.
once we run the .exe file, automatically I takes .txt file as a input name as TherInput.txt from the same directory (C:/Users/Infratab Bangalore/Desktop/Rod's)
For my conformation, I run the ThMapInfratab1-2.exe file manually using command prompt in the following way.it's working great.
C:\Users\Infratab Bangalore\Desktop\Rod's>ThMapInfratab1-2.exe
Finally .exe file exports t .txt files as a output into same directory(C:/Users/Infratab Bangalore/Desktop/Rod's).
These same thing, I want to do using Java.can you explain with my directories.
For this, I wrote the following code but it's not working.
import java.io.IOException;
public class ProcessBuilderSample {
public static void main(String args[]) throws IOException {
Process process = new ProcessBuilder(
"C:\\Users\\Infratab bangalore\\Desktop\\Rod's\\ThMapInfratab1-2.exe")
.start();
}
}
If anyone knows,suggest me.
Thanks.
.
You need to execute exec() method of Runtime that returns Process instance or use ProcessBuilder class methods.
Runtime runtime = Runtime.getRuntime();
Process proc = runtime.exec("C:\\Users\\Infratab Bangalore\\Desktop\\Rod's\\ThMapInfratab1-2.exe");
You can use ProcessBuilder as
ProcessBuilder pb = new ProcessBuilder("myCommand", "myArg1", "myArg2");
Map<String, String> env = pb.environment();
env.put("VAR1", "myValue");
env.remove("OTHERVAR");
env.put("VAR2", env.get("VAR1") + "suffix");
pb.directory(new File("myDir"));
File log = new File("log");
pb.redirectErrorStream(true);
pb.redirectOutput(Redirect.appendTo(log));
Process p = pb.start();
assert pb.redirectInput() == Redirect.PIPE;
assert pb.redirectOutput().file() == log;
assert p.getInputStream().read() == -1;
You can do it like this:
Process process=Runtime.getRuntime().exec("C:\\Users\\Infratab Bangalore\\Desktop\\Rod's\\ThMapInfratab1-2.exe");
Process process=Runtime.getRuntime().exec("C:\Users\Infratab Bangalore\Desktop\Rod's>ThMapInfratab1-2.exe");
Related
I want to execute a batch file code from java button click. Also I don't want any command prompt window to be shown all from java code.
I have a code :-
C:\xyz-3.1.1\bin>dita --input=C:/Users/india/Desktop/mobile-phone/m
obilePhone.xyz --format=pdf --output=C:/Users/india/Desktop --logfile=C:/Use
rs/india/Desktop/dofhdif.txt
So I want above code to be run from batch command with C:\xyz-3.1.1\bin> as the parent directory.
Also I want to update --input file path whenever I will choose new file from JFileChooser.
I did this from the java code on button click transform:-
ProcessBuilder pb=new ProcessBuilder("dita --input=C:/Users/india/Desktop/mobile-phone/mobilePhone.xyz --format=pdf --output=C:/Users/india/Desktop --logfile=C:/Users/india/Desktop/dofhdif.txt");
pb.redirectErrorStream(true);
Process process=pb.start();
and getting IOException error.
I get stuck over here for long time , where am I going wrong.
EDIT :- error
java.io.IOException: Cannot run program "dita --input=C:/Users/india/Desktop/mobile-phone/m
obilePhone.xyz --format=pdf --output=C:/Users/india/Desktop --logfile=C:/Use
rs/india/Desktop/dofhdif.txt": CreateProcess error=2, The system cannot find the file specified
at java.lang.ProcessBuilder.start(Unknown Source)
As the Error mentioned, it cannot locate the command because the whole string will be treated as the command by ProcessBuilder.
Try to use Runtime.getRuntime().exec directly, but you have to ensure the command dita can be found.
Process process = Runtime.getRuntime().exec("C:\xyz-3.1.1\bin>dita --input=C:/Users/india/Desktop/mobile-phone/mobilePhone.xyz --format=pdf --output=C:/Users/india/Desktop --logfile=C:/Users/india/Desktop/dofhdif.txt");
process.waitFor();
int exitCode = process.exitValue();
System.out.println(IoHelper.output(process.getInputStream())); // handle the output;
Before JDK 5.0, the only way to start a process and execute it, was to use the exec() method of the java.lang.Runtime class after which ProcessBuilder can be used to help create operating system processes.
The major improvement being that, it also acts as a holder for all those attributes that influence the process. And this is how it should be used:
ProcessBuilder pb = new ProcessBuilder("myCommand", "myArg1", "myArg2");
P.S. Actually Runtime.getRuntime().exec can also be used with String... as:
Runtime.getRuntime().exec(new String[]{"curl", "-v", "--cookie", tokenString, urlString});
My personal preference:
If you have to configure the environment for the command: to control the working directory or environment variables and also you want to execute the commands several times, you'd better use it since the ProcessBuilder will hold the settings and what you need to do is just processBuilder.start() to create another process with the same settings;
If you want to execute a whole long string command as you mentioned, you'd better just use Runtime.getRuntime().exec since you can just execute it right there without any bothering of the parameter format.
Try this:
String inputFile = ...;
String outputFile = ...;
String logFile = ...;
ProcessBuilder pb = new ProcessBuilder(
"dita",
"--input=" + inputFile,
"--format=pdf",
"--output=" + outputFile,
"--logfile=" + logFile)
.directory(new File("C:\\xyz-3.1.1\\bin"))
//.inheritIO();
.redirectErrorStream(true);
Process process = pb.start();
This shows the following points:
The command is separated from the arguments
The argument values can be determined at runtime
The command's default directory (C:\xyz-3.1.1\bin) is set before starting the process
Consider using inheritIO() instead of redirectErrorStream() if you want the process's output to appear as part of your Java application's output.
I'm trying to run other java file using ProcessBuilder class.
I would like to get input of entire path of java file + file name + .java and compile it.
Example, input: C:\Windows\test.java
And then, I store input into String variable FILE_LOCATION and call processbuilder to compile input .java file.
Here is my code:
static String JAVA_FILE_LOCATION;
static String command[] = {"javac", JAVA_FILE_LOCATION};
ProcessBuilder processBuilder = new ProcessBuilder(command);
Process process = processBuilder.start();
process = new ProcessBuilder(new String[]{"java","-cp",A,B}).start();
But I don't know how to set the parameters.
process = new ProcessBuilder(new String[]{
"java","-cp",A,B}).start();
How should I set that parameter (A, B)?
To answer your exact question, let's say, for instance, your class is in package com.yourcompany.yourproduct and your class file is in /dir/to/your/classes/com/yourcompany/yourproduct/Yourclass.class.
Then A = "/dir/to/your/classes" and B = "com.yourcompany.yourproduct.Yourclass".
However, there's a few things to be aware of. Looking at your code:
static String JAVA_FILE_LOCATION;
static String command[] = {"javac", JAVA_FILE_LOCATION};
ProcessBuilder processBuilder = new ProcessBuilder(command);
No. You need to CD to the directory and then run javac. The easiest way to do that is by calling processBuilder.directory(new File("/dir/to/your/classes")). Then you need to give javac a relative path to your source file ("com/yourcompany/yourproduct/Yourclass.java").
Process process = processBuilder.start();
process = new ProcessBuilder(new String[]{"java","-cp",A,B}).start();
Wait until the first process has finished compiling before you try to run it! Between the two lines above, insert process.waitFor();. You might also want to check for any errors and only run the second process if the first has succeeded.
By the way, there's no need for all that long-hand creation of string arrays. Just use varargs: process = new ProcessBuilder("java", "-cp", A, B).start();.
I try to execute an external jar in my java application. The .jar is in my java-package ("gui").
I tried:
String filepath = this.getClass().getResource("ServerRSS.jar").getPath();
ProcessBuilder pb = new ProcessBuilder("java", filepath);
System.out.println(filepath); results in:
/C:/Users/hox/workspace/PraktikumProg/bin/gui/ServerRSS.jar
My programm doesn't start. Could the problem be the slash before the C: ?
EDIT:
The solution was:
URL filepath = this.getClass().getResource("ServerRSS.jar");
ProcessBuilder pb;
pb = new ProcessBuilder("java", "-jar", new File(filepath.toURI()).toString());
Process p = pb.start();
First get your command working ... simply on the command line.
And only then try to run it from within Java using a ProcessBuilder.
Simple answer is probably: to use -jar when invoking java.
java someJar.jar
does not work!
And yes, that slash matters big time. You simply want a fully correct file path there.
Finally: are you really sure you want to start a new JVM in order to run a main method in some class? You see, you could do that within your current JVM - without the additional performance and complexity cost of using a second JVM!
How could I run a local jar file from a java program?
The jar file is not in the class-path of the Java caller program.
I suggest you use a ProcessBuilder and start a new JVM.
Here is something to get you started:
ProcessBuilder pb = new ProcessBuilder("/path/to/java", "-jar", "your.jar");
pb.directory(new File("preferred/working/directory"));
Process p = pb.start();
Process proc = Runtime.getRuntime().exec("java -jar Validate.jar");
proc.waitFor();
// Then retreive the process output
InputStream in = proc.getInputStream();
InputStream err = proc.getErrorStream();
byte b[]=new byte[in.available()];
in.read(b,0,b.length);
System.out.println(new String(b));
byte c[]=new byte[err.available()];
err.read(c,0,c.length);
System.out.println(new String(c));
First, the description of your problem is a bit unclear. I don't understand if you want to load the classes from the jar file to use in your application or the jar contains a main file you want to run. I will assume it is the second.
If so, you have a lot of options here.
The simplest one would be the following:
String filePath; //where your jar is located.
Runtime.exec(" java -jar " + filepath);
Voila...
If you don't need to run the jar file but rather load the classes out of it, let me know.
Could something like the following be useful?
http://download.oracle.com/javase/tutorial/deployment/jar/jarclassloader.html
Another way to do on windows is:
Runtime.getRuntime().exec("cmd /c start jarFile");
this way you can set priority of your process as well (normal/low/etc)
You can run a jar file from where ever you want by using only this one line code.
Desktop.getDesktop().open(new File("D:/FormsDesktop.jar"));
where
new File("your path to jar")
Hope it helps.
Thanks.
Add jar library to your project
Import main class (see manifest in jar file)
Invoke static method main with arguments
String args[] = {"-emaple","value"};
PortMapperStarter.main(args);
To run an executable jar from inside your java application, you can copy the JarClassLoader from https://docs.oracle.com/javase/tutorial/deployment/jar/examples/JarClassLoader.java
Use it like this. In this snippet, jarUrl is the URL to download the jar from, for example file:/tmp/my-jar.jar and args is the array of strings you want to pass as command line arguments to the jar.
JarClassLoader loader = new JarClassLoader(jarUrl);
String main = loader.getMainClassName();
loader.invokeClass(main, args);
Keep in mind that you're now inserting someone else's binary into your code. If it gets stuck in an infinite loop, your Thread hangs, if it calls System.exit(), your JVM exits.
This is my appriach, which I consider is more complete:
public static Process exec(String path, String filename) throws IOException {
String javaHome = System.getProperty("java.home");
String javaBin = javaHome +
File.separator + "bin" +
File.separator + "java";
ProcessBuilder pb = new ProcessBuilder(javaBin, "-jar", path+filename);
return pb.start();
}
1) Set the class path from environment variables
2) Go to the folder where your jar file exists
3) Run the following commands through command prompt
java -jar jarfilename
I am trying to launch a .exe file through a Java program. I used the following code:
System.out.println("Opening " + path);
Process exec;
exec = Runtime.getRuntime().exec("rundll32 SHELL32.DLL,ShellExec_RunDLL " + path);//path is the path of the exe file which is passed as an argument from another java class
the output is as follows:
Opening C:\Program Files (x86)\C-Free 5\CppIDE.exe
But it is not opening.
Instead when I try
String pat="C:\\Program Files (x86)\\C-Free 5\\CppIDE.exe";
Process exec;
exec = Runtime.getRuntime().exec("rundll32 SHELL32.DLL,ShellExec_RunDLL " + pat);
the program is opened.
I don't know what the problem is.
It's very likely that the space in your path is the problem.
I suggest you pass the arguments as an array instead of passing a single string containing the whole command (alternatively you could quote the spaces correctly, but that's not quite as easy).
Either
use the String[] version of Runtime.exec() or
switch to using ProcessBuilder which has an altogether simpler and more intuitive API.
With ProcessBuilder this could look like this:
ProcessBuilder pb = new ProcessBuilder("rundll32", "SHELL32.DLL,ShellExec_RunDLL", path);
Process p = pb.start();
Also, I see no reason to invoke rundll32 at all in this scenario. This should work just as well:
ProcessBuilder pb = new ProcessBuilder(path);
Process p = pb.start();
You need to construct the path using File.separator. The path separator you are using will, in this case, will be system dependant.