I want to execute a batch file code from java button click. Also I don't want any command prompt window to be shown all from java code.
I have a code :-
C:\xyz-3.1.1\bin>dita --input=C:/Users/india/Desktop/mobile-phone/m
obilePhone.xyz --format=pdf --output=C:/Users/india/Desktop --logfile=C:/Use
rs/india/Desktop/dofhdif.txt
So I want above code to be run from batch command with C:\xyz-3.1.1\bin> as the parent directory.
Also I want to update --input file path whenever I will choose new file from JFileChooser.
I did this from the java code on button click transform:-
ProcessBuilder pb=new ProcessBuilder("dita --input=C:/Users/india/Desktop/mobile-phone/mobilePhone.xyz --format=pdf --output=C:/Users/india/Desktop --logfile=C:/Users/india/Desktop/dofhdif.txt");
pb.redirectErrorStream(true);
Process process=pb.start();
and getting IOException error.
I get stuck over here for long time , where am I going wrong.
EDIT :- error
java.io.IOException: Cannot run program "dita --input=C:/Users/india/Desktop/mobile-phone/m
obilePhone.xyz --format=pdf --output=C:/Users/india/Desktop --logfile=C:/Use
rs/india/Desktop/dofhdif.txt": CreateProcess error=2, The system cannot find the file specified
at java.lang.ProcessBuilder.start(Unknown Source)
As the Error mentioned, it cannot locate the command because the whole string will be treated as the command by ProcessBuilder.
Try to use Runtime.getRuntime().exec directly, but you have to ensure the command dita can be found.
Process process = Runtime.getRuntime().exec("C:\xyz-3.1.1\bin>dita --input=C:/Users/india/Desktop/mobile-phone/mobilePhone.xyz --format=pdf --output=C:/Users/india/Desktop --logfile=C:/Users/india/Desktop/dofhdif.txt");
process.waitFor();
int exitCode = process.exitValue();
System.out.println(IoHelper.output(process.getInputStream())); // handle the output;
Before JDK 5.0, the only way to start a process and execute it, was to use the exec() method of the java.lang.Runtime class after which ProcessBuilder can be used to help create operating system processes.
The major improvement being that, it also acts as a holder for all those attributes that influence the process. And this is how it should be used:
ProcessBuilder pb = new ProcessBuilder("myCommand", "myArg1", "myArg2");
P.S. Actually Runtime.getRuntime().exec can also be used with String... as:
Runtime.getRuntime().exec(new String[]{"curl", "-v", "--cookie", tokenString, urlString});
My personal preference:
If you have to configure the environment for the command: to control the working directory or environment variables and also you want to execute the commands several times, you'd better use it since the ProcessBuilder will hold the settings and what you need to do is just processBuilder.start() to create another process with the same settings;
If you want to execute a whole long string command as you mentioned, you'd better just use Runtime.getRuntime().exec since you can just execute it right there without any bothering of the parameter format.
Try this:
String inputFile = ...;
String outputFile = ...;
String logFile = ...;
ProcessBuilder pb = new ProcessBuilder(
"dita",
"--input=" + inputFile,
"--format=pdf",
"--output=" + outputFile,
"--logfile=" + logFile)
.directory(new File("C:\\xyz-3.1.1\\bin"))
//.inheritIO();
.redirectErrorStream(true);
Process process = pb.start();
This shows the following points:
The command is separated from the arguments
The argument values can be determined at runtime
The command's default directory (C:\xyz-3.1.1\bin) is set before starting the process
Consider using inheritIO() instead of redirectErrorStream() if you want the process's output to appear as part of your Java application's output.
Related
I try to execute an external jar in my java application. The .jar is in my java-package ("gui").
I tried:
String filepath = this.getClass().getResource("ServerRSS.jar").getPath();
ProcessBuilder pb = new ProcessBuilder("java", filepath);
System.out.println(filepath); results in:
/C:/Users/hox/workspace/PraktikumProg/bin/gui/ServerRSS.jar
My programm doesn't start. Could the problem be the slash before the C: ?
EDIT:
The solution was:
URL filepath = this.getClass().getResource("ServerRSS.jar");
ProcessBuilder pb;
pb = new ProcessBuilder("java", "-jar", new File(filepath.toURI()).toString());
Process p = pb.start();
First get your command working ... simply on the command line.
And only then try to run it from within Java using a ProcessBuilder.
Simple answer is probably: to use -jar when invoking java.
java someJar.jar
does not work!
And yes, that slash matters big time. You simply want a fully correct file path there.
Finally: are you really sure you want to start a new JVM in order to run a main method in some class? You see, you could do that within your current JVM - without the additional performance and complexity cost of using a second JVM!
I am using the below code to open the "sample.html' file.
String filename = "C:/sample.html";
String browser = "C:/Program Files (x86)/Google/Chrome/Application/chrome.exe";
Runtime rTime = Runtime.getRuntime();
Process pc = rTime.exec(browser + filename);
pc.waitFor();
However, I am getting the below error.
java.io.IOException: Cannot run program "C:/Program": CreateProcess error=2, The system cannot find the file specified
Could someone please help me figure this. Thanks in advance.
Runtime.exec(String) automatically splits the string at spaces, assuming the first token is the command name and the rest are command line parameters. Also you do not have a space between browser and file, although that is not the root cause of the problem.
It thinks you want to run "C:/Program" with two command line arguments:
"Files"
"(x86)/google/Chrome/Application/chrome.exeC:/sample.html"
Use Runtime.exec(String[]) instead, that way you have full control over what is what:
String[] command = new String[]{browser, filename};
Runtime.exec(command);
Try this.
String filename = "C:\\sample.html";
String browser = "C:\\Program Files (x86)\\Google\\Chrome\\Application\\chrome.exe";
Runtime runtime = Runtime.getRuntime();
try {
runtime.exec(new String[] {browser, filename});
} catch (IOException e) {
e.printStackTrace();
}
Stop using Runtime.exec(String) - the problem is in how it processes the single string input.
The error message indicates how/where it is failing: note that it stops after "C:/Program" (or, the first space). This indicates that exec parsed the string "incorrectly" and thus isn't even looking for the correct executable.
Cannot run program "C:/Program"
Instead, consider the use of ProcessBuilder. While the usage is still system-dependent, ProcessBuilder allows separation of the executable file-name (and need to deal with it specially) and the arguments and does it's darnedest to invoke the target correctly.
String filename = "C:\\sample.html";
String browser = "C:\\Program Files (x86)\\Google\\Chrome\\Application\\chrome.exe";
ProcessBuilder pb = new ProcessBuilder(browser, filename);
// setup other options ..
// .. and run
Process p = pb.start();
p.waitFor();
From what I can tell, in Windows, ProcessBuilder will wraps the individual components in quotes; this can create a different problem when arguments contain quotes..
Parameters must be passed separately:
Process pc = rTime.exec(new String[]{browser, filename});
Using exec() is not like using the command line - you can not use spaces to delimit the command from its parameters. Your attempt would try to execute a command whose path was the concatenation of the exec and the filename as one giant string.
I need to run executable progam (.exe) in java. This program have two different operating modes: GUI and Command line. The syntax to launch the program from the command line is as follows :
C:\Users\Ermanno\Desktop\ "programFolder"\"program.exe" /stext output.txt
in this way the program store the outoput in the file "output.txt".
I tired it:
Process p = new ProcessBuilder("C:\\Users\\Ermanno\\Desktop\\programFolder\\program.exe" ,"/stext a.txt").start();
does not create the output file.
I also tired to use a file batch that contains the command and run it to java but the result is the same.
You need to pass each argument in a single string:
... program.exe", "/stext", "a.txt")...
Also make sure that you start a background thread which reads the output of the child process. If there is a problem, then the child will print an error message to it's standard output and if you don't actively read it, then this output will be lost.
For this, loop over the streams p.getInputStream() and p.getErrorStream().
The latter is especially important since you say "I also tired to use a file batch". Java doesn't do anything different than a batch script. If you can't run the command from batch, it won't work from Java, either.
My experience was horrible with using the JDK ProcessBuilder and Runtime.getRuntime().exec. I then moved to Apache commons-exec. Here is an example:
String line = "AcroRd32.exe /p /h " + file.getAbsolutePath();
CommandLine cmdLine = CommandLine.parse(line);
DefaultExecutor executor = new DefaultExecutor();
int exitValue = executor.execute(cmdLine);
I solved using file bath. This file contains the command.
String [] _s = {"cmd.exe", "/c", "start", "file.bat"};
Process pr = Runtime.getRuntime().exec(_s);
I am trying to launch a .exe file through a Java program. I used the following code:
System.out.println("Opening " + path);
Process exec;
exec = Runtime.getRuntime().exec("rundll32 SHELL32.DLL,ShellExec_RunDLL " + path);//path is the path of the exe file which is passed as an argument from another java class
the output is as follows:
Opening C:\Program Files (x86)\C-Free 5\CppIDE.exe
But it is not opening.
Instead when I try
String pat="C:\\Program Files (x86)\\C-Free 5\\CppIDE.exe";
Process exec;
exec = Runtime.getRuntime().exec("rundll32 SHELL32.DLL,ShellExec_RunDLL " + pat);
the program is opened.
I don't know what the problem is.
It's very likely that the space in your path is the problem.
I suggest you pass the arguments as an array instead of passing a single string containing the whole command (alternatively you could quote the spaces correctly, but that's not quite as easy).
Either
use the String[] version of Runtime.exec() or
switch to using ProcessBuilder which has an altogether simpler and more intuitive API.
With ProcessBuilder this could look like this:
ProcessBuilder pb = new ProcessBuilder("rundll32", "SHELL32.DLL,ShellExec_RunDLL", path);
Process p = pb.start();
Also, I see no reason to invoke rundll32 at all in this scenario. This should work just as well:
ProcessBuilder pb = new ProcessBuilder(path);
Process p = pb.start();
You need to construct the path using File.separator. The path separator you are using will, in this case, will be system dependant.
I have an exe file which takes a file name as input.
When I execute it as a command like:
xyz.exe c:\input.txt c:\ouput.txt
It all works as expected.
But how to execute this is java?
This is the one i used and am not getting the ouput in the files:
String[] str = {"c:/input.txt","c:/output.txt"};
Process p = rt.exec("c:/xyz.exe",str);
You're using the method:
public Process exec(String command,
String[] envp)
where envp is a (quote) "array of strings, each element of which has environment variable settings in the format name=value, or null if the subprocess should inherit the environment of the current process."
Try this instead:
String[] command = {"c:/xyz.exe", "c:/input.txt", "c:/output.txt"};
Process p = Runtime.getRuntime().exec(command);
// ...
Also read this article that explains the pitfalls of Runtime.exec(...): http://www.javaworld.com/javaworld/jw-12-2000/jw-1229-traps.html
Use Runtime.exec or Processbuilder API
I believe this should answer your question http://www.daniweb.com/software-development/java/threads/133710