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I have a problem - is there any possibility to recognize in the text the negative number, that has a minus sign on the right?
E.g. I'm thinking about number like that: 1500.0- (instead of -1500.0).
Thank you in advance for any help.
Not only is it possible, it is actually easier to handle a trailing sign. You just convert the number as usual, continuing while you keep getting digits, then if it ends with a minus sign just negate it. Easier than having to remember a leading sign.
Despite the names of the methods provided in the JDK, this is not 'parsing', it is radix conversion.
You could use charAt or a regular Expression, and many more...
String s = "1500.00-";
if (s.charAt(s.length()-2) == '-'){
//minus on the right.
}
First move the minus (if any) from the end to the start:
num = num.replaceAll("(.*)(-)?$", "$2$1");
The good thing here is that if there's no minus sign at the end, or yjr minus us alteady at the start, nothing change it made.
Then parse it as normal, eg:
double d = Double.parseDouble(num);
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I am trying to to an equation to solve for the amount of time left on a loan based on a specific payment amount (above the normal amount).
The equation is:
nRemaining = ((-log(1-(interestRate / 12) * value2 / value3)) / (log (1+ (interestRate / 12))));
Now obviously this does not work, because I am unsure how to input logarithms.
Your code will work fine, provided a few conditions are met:
If you have to use log that way, place this statement above your class:
import static java.lang.Math.log;
Otherwise, use Math.log() everywhere else you see log.
Technically you don't have to import anything in java.lang, but this is known as a static import - something that should only be done on occasion, and allows you to write your statement a lot cleaner.
Make sure that all of your values are of type double. Otherwise, you'll get integer division, which can lead to NaN for some otherwise inexplicable reason.
Several built-in logarithm methods you might want to use: Math.log, Math.log10, Math.log1p.
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What I am looking to do is split a given string in Java using a tab delimiter. After the seventh split, I would like to keep everything after that point as an eighth split. This last split will contain tabs also, but must remain intact.
Use the split method that takes two parameters, the second being the split limit. You can pass in a limit of 8. The eighth element will contain the rest of the string after the seventh split.
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I have this code to generate a random key.
new BigInteger(130, random).toString(32);
From what I understand, the first part of the code will create a 130 bit, random, integer. Then, the .toString(int radix) method will be called on it and the number will be converted to an alpha-numeric string.
What I can't understand is which alphabet is used for the characters; in other words, which key is mapped to which character?
Note: I looked for how a Base 32 conversion can happen, but I couldn't come up with anything useful since it doesn't seem to be a unique method to do that.
The javadoc says:
" The digit-to-character mapping provided by Character.forDigit is used, and a minus sign is prepended if appropriate.".
And the latter javadoc says:
" If the digit is less than 10, then '0' + digit is returned. Otherwise, the value 'a' + digit - 10 is returned."
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I have to create a random cellnumber 07939393914 for automation testing purpose.
Last 079393(5 digits) digits should change randamly.. each time test runs..
Can any one suggest JAVA code for this ? or else Selenium Java code ?
Thanks
Is this a number or a String? I ask as it has a leading zero.
Take you initial number as 7939300000
then add to it Math.round(Math.Random()*10000)
If you want it as a String, take your string as "079393" and use Integer.toString on the result above, then concatentate them
Use RandomStringUtils class.
String randomNumbers = RandomStringUtils.randomNumeric(5);
String phNo = 079393+randomNumbers;
var num=Math.ceil(Math.Random()*100000)
for random first 5 digit numbers
and add
var your_last_5digits; //as string to your last 5 digits
cellNumber='0'+num+your_last_5digits;
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I am fairly inexperienced in Java as well as Android. I am trying to retrieve a phone number stored in one of the contacts of the android phone emulator. While I am successful to fetch it, the number has been returned in a string in a format like "(987) 654-3210".
I want to convert it to integer or long. How can I do that? If I use Integer.parseInt(String number), it returns a NumberFormatException. Failed while tried using Long.valueOf(String number) too. What should I do then? I want it like "9876543210" without any braces or hyphens.
using the long for storing number will be better
String str="(987) 654-3210";
String stt=str.replaceAll("\\D+","");
long num= Long.parseLong(stt);
System.out.println(num);
This should be simple. You could use regex in java to do this like below
phoneStr = str.replaceAll("\\D+","");
This will delete the non digits from the string and give you only numbers. Then you can use
int number = Integer.parseInt(phoneStr);