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I have to create a random cellnumber 07939393914 for automation testing purpose.
Last 079393(5 digits) digits should change randamly.. each time test runs..
Can any one suggest JAVA code for this ? or else Selenium Java code ?
Thanks
Is this a number or a String? I ask as it has a leading zero.
Take you initial number as 7939300000
then add to it Math.round(Math.Random()*10000)
If you want it as a String, take your string as "079393" and use Integer.toString on the result above, then concatentate them
Use RandomStringUtils class.
String randomNumbers = RandomStringUtils.randomNumeric(5);
String phNo = 079393+randomNumbers;
var num=Math.ceil(Math.Random()*100000)
for random first 5 digit numbers
and add
var your_last_5digits; //as string to your last 5 digits
cellNumber='0'+num+your_last_5digits;
Related
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I am fairly inexperienced in Java as well as Android. I am trying to retrieve a phone number stored in one of the contacts of the android phone emulator. While I am successful to fetch it, the number has been returned in a string in a format like "(987) 654-3210".
I want to convert it to integer or long. How can I do that? If I use Integer.parseInt(String number), it returns a NumberFormatException. Failed while tried using Long.valueOf(String number) too. What should I do then? I want it like "9876543210" without any braces or hyphens.
using the long for storing number will be better
String str="(987) 654-3210";
String stt=str.replaceAll("\\D+","");
long num= Long.parseLong(stt);
System.out.println(num);
This should be simple. You could use regex in java to do this like below
phoneStr = str.replaceAll("\\D+","");
This will delete the non digits from the string and give you only numbers. Then you can use
int number = Integer.parseInt(phoneStr);
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I have a Vast list of Strings in an ArrayList. I need to compare my input string with the entire list and return the Exact Match or the approximate match. How can I achieve this in Java ?
Compute the hamming edit distance between your search string and each string in your list. Pick the string or strings with the lowest edit distance. If you have to support strings that might need to add or remove characters to match the search string, use the Levenshtein distance..
try=
ArrayList.contains("StringToBeChecked");
If the String is present in the ArrayList, this function will return true, else will return false.
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I have a string array
String[] albumnames;
now how to take a string from particular index position with limited number of charachters.
For example,
if, albumnames[position] have value "abcdefghijk"
then i want to take the first 5 characters only.
That is "abcde".
The substring method of String can be used to achieve this. Try
String s = albumnames[position].substring(0,5);
See substring docs
albumnames[position].substring(0,5);
you can see the methods in String class, like substring, indexof
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multiply any 2 numbers. The numbers can be extremely large (i.e. run into hundreds of digits) and are provided as strings.
The expected output is a string which represents the product of the two numbers.
example-
multiply("268435456","524288")="140737488355328"
multiply("12321412423524534534543","0")="0"
Use BigDecimal, which has a multiply method and a constructor which takes a String. It also contains corresponding toString() and toPlainString() methods to get your result as a string.
(If the numbers are always whole numbers, then use BigInteger instead.)
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I am fairly inexperienced in Java as well as Android. I am trying to retrieve a phone number stored in one of the contacts of the android phone emulator. While I am successful to fetch it, the number has been returned in a string in a format like "(987) 654-3210".
I want to convert it to integer or long. How can I do that? If I use Integer.parseInt(String number), it returns a NumberFormatException. Failed while tried using Long.valueOf(String number) too. What should I do then? I want it like "9876543210" without any braces or hyphens.
using the long for storing number will be better
String str="(987) 654-3210";
String stt=str.replaceAll("\\D+","");
long num= Long.parseLong(stt);
System.out.println(num);
This should be simple. You could use regex in java to do this like below
phoneStr = str.replaceAll("\\D+","");
This will delete the non digits from the string and give you only numbers. Then you can use
int number = Integer.parseInt(phoneStr);