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Compare using Collections.sort

I am trying to sort a text file which is separated by tabs and trying to sort by the third field, className. I am then going to display it in a table. I wrote the following part, but it is not sorting correctly. Any ideas as to where I am going wrong?
public void sortFile(){
BufferedReader reader = null;
BufferedWriter writer = null;
//Create an ArrayList object to hold the lines of input file
ArrayList<String> lines = new ArrayList<>();
try{
//Creating BufferedReader object to read the input file
reader = new BufferedReader(new FileReader("pupilInfo.txt"));
//Reading all the lines of input file one by one and adding them into ArrayList
String currentLine = reader.readLine();
while (currentLine != null){
lines.add(currentLine);
currentLine = reader.readLine();
}
Collections.sort(lines, (String s1, String s2) -> {
s1 = lines.get(0);
s2 = lines.get(1);
String [] line1 = s1.split("\t");
String [] line2 = s2.split("\t");
String classNameLine1 = line1[2];
String classNameLine2 = line2[2];
System.out.println("classname1=" + classNameLine1);
System.out.println("classname2=" + classNameLine2);
int sComp = classNameLine1.compareTo(classNameLine2);
return sComp;
});
//Creating BufferedWriter object to write into output temp file
writer = new BufferedWriter(new FileWriter("pupilSortTemp.txt"));
//Writing sorted lines into output file
for (String line : lines){
writer.write(line);
writer.newLine();
}
}catch (IOException e){
}
finally{
//Closing the resources
try{
if (reader != null){
reader.close();
}
if(writer != null){
writer.close();
}
}catch (IOException e){
}
}
}

I'ava tried with "comparator".for simplicity my source file is as follows
pippo;pluto;paperino
casa;terra;cortile
primo;secondo;terzo
Comparator<String> comparator = new Comparator<String>() {
#Override
public int compare(String o1, String o2) {
return o1.split(";")[2].compareTo(o2.split(";")[2]);
}
};
lines.sort(comparator);
final output
[casa;terra;cortile, pippo;pluto;paperino, primo;secondo;terzo]
sorted on third field!

String cannot be converted to array

I have a program that reads in a file using a filename specified by the user.
All file contents must be read and stored in the array. I seem to have done the IO Correctly besides this error. I understand what the error is but not sure how to correct.
EDIT: The array is already defined in the file.
Zoo.java:284: error: incompatible types: String cannot be converted to
Animals
animals[ j ] = bufferedReader.readLine();
Here is my code for the readFile Submodule:
public String readFile(Animals[] animals)
{
Scanner sc = new Scanner(System.in);
String nameOfFile, stringLine;
FileInputStream fileStream = null;
BufferedReader bufferedReader;
InputStreamReader reader;
System.out.println("Please enter the filename to be read from.");
nameOfFile = sc.nextLine();
try
{
constructed = true;
fileStream = new FileInputStream(nameOfFile);
bufferedReader = new BufferedReader(new InputStreamReader(fileStream));
while((stringLine = bufferedReader.readLine()) != null)
{
for(int j = 0; j < animals.length; j++)
{
animals[j] = bufferedReader.readLine();
}
}
fileStream.close();
}
catch(IOException e)
{
if(fileStream != null)
{
try
{
fileStream.close();
}
catch(IOException ex2)
{
}
}
System.out.println("Error in file processing: " + e.getMessage();
}
}
Thanks for the help.

animals is array of Animals, but bufferedReader.readLine() reads line. You should convert it to Animal. I don't see definition of your class Animals, but, I think, there should be constructor that takes String as argument.
So, If i'm right, you should basically write:
animals[j] = new Animals(bufferedReader.readLine());

Lots of problems in your code. Starting with the method's input. Also reading from file.
public static void main(String[] args) {
// TODO code application logic here
for(String entry : readFile())
{
System.out.println(entry);
}
}
static public String[] readFile()
{
Scanner sc = new Scanner(System.in);
InputStreamReader reader;
System.out.println("Please enter the filename to be read from.");
String nameOfFile = sc.nextLine();
try(BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(new FileInputStream(nameOfFile))); )
{
//constructed = true; why?
String stringLine;
ArrayList<String> arraylist = new ArrayList();
while((stringLine = bufferedReader.readLine()) != null)
{
arraylist.add(stringLine);
}
return arraylist.toArray(new String[0]);
}
catch (FileNotFoundException ex)
{
Logger.getLogger(Filetoarray.class.getName()).log(Level.SEVERE, null, ex);
}
catch (IOException ex)
{
Logger.getLogger(Filetoarray.class.getName()).log(Level.SEVERE, null, ex);
}
return null;
}

Java read large text file with separator

I'm trying to read a large text file in the form of:
datadfqsjmqfqs+dataqfsdqjsdgjheqf+qsdfklmhvqziolkdsfnqsdfmqdsnfqsdf+qsjfqsdfmsqdjkgfqdsfqdfsqdfqdfssdqdsfqdfsqdsfqdfsqdfs+qsfddkmgqjshfdfhsqdflmlkqsdfqdqdf+
I want to read this string in the text file as one big java String. Is this possible? I know the use of the split method.
It worked to read it line by line, but what I really need is to split this long text-string at the '+' sign. Afterwards I want to store it as an array, arraylist, list,...
Can anyone help me with this? Because every information on the internet is just about reading a file line by line.
Thanks in advance!

String inpStr = "datadfqsjmqfqs+dataqfsdqjsdgjheqf+qsdfklmhvqziolkdsfnqsdfmqdsnfqsdf+qsjfqsdfmsqdjkgfqdsfqdfsqdfqdfssdqdsfqdfsqdsfqdfsqdfs+qsfddkmgqjshfdfhsqdflmlkqsdfqdqdf+";
String[] inpStrArr = inpStr.split("+");
Hope this is what you need.

You can read file using BufferedReader or any IO-classes.suppose you have that String in testing.txt file then by reading each line from file you can split it by separator (+). and iterate over array and print.
BufferedReader br = null;
try {
String sCurrentLine;
br = new BufferedReader(new FileReader("C:\\testing.txt"));//file name with path
while ((sCurrentLine = br.readLine()) != null) {
String[] strArr = sCurrentLine.split("\\+");
for(String str:strArr){
System.out.println(str);
}
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (br != null)br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}

It seems to me like your problem is that you don't want to read the file line by line. So instead, try reading it in parts (say 20 characters each time and building your string):
char[] c = new char[20]; //best to save 20 as a final static somewhere
ArrayList<String> strings = new ArrayList<String>();
StringBuilder sb = new StringBuilder();
BufferedReader br = new BufferedReader(new FileReader(filename));
while (br.read(c) == 20) {
String str = new String(c);
if (str.contains("+") {
String[] parts = str.split("\\+");
sb.append(parts[0]);
strings.add(sb.toString());
//init new StringBuilder:
sb = new StringBuilder();
sb.add(parts[1]);
} else {
sb.append(str);
}
}

You should be able to get a String of length Integer.MAX_VALUE (always 2147483647 (231 - 1) by the Java specification, the maximum size of an array, which the String class uses for internal storage) or half your maximum heap size (since each character is two bytes), whichever is smaller
How many characters can a Java String have?

Try this one:
private static void readLongString(File file){
ArrayList<String> list = new ArrayList<String>();
StringBuilder builder = new StringBuilder();
int r;
try{
InputStream in = new FileInputStream(file);
Reader reader = new InputStreamReader(in);
while ((r = reader.read()) != -1) {
if(r=='+'){
list.add(builder.toString());
builder = new StringBuilder();
}
builder.append(r);
}
}catch (IOException ex){
ex.printStackTrace();
}
for(String a: list){
System.out.println(a);
}
}

Here is one way, caveat being you can't load more than the max int size (roughly one GB)
FileReader fr=null;
try {
File f=new File("your_file_path");
fr=new FileReader(f);
char[] chars=new char[(int)f.length()];
fr.read(chars);
String s=new String(chars);
//parse your string here
} catch (Exception e) {
e.printStackTrace();
}finally {
if(fr!=null){
try {
fr.close();
} catch (IOException e) {
}
}
}

How to open a txt file and read numbers in Java

How can I open a .txt file and read numbers separated by enters or spaces into an array list?

Read file, parse each line into an integer and store into a list:
List<Integer> list = new ArrayList<Integer>();
File file = new File("file.txt");
BufferedReader reader = null;
try {
reader = new BufferedReader(new FileReader(file));
String text = null;
while ((text = reader.readLine()) != null) {
list.add(Integer.parseInt(text));
}
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (reader != null) {
reader.close();
}
} catch (IOException e) {
}
}
//print out the list
System.out.println(list);

A much shorter alternative is below:
Path filePath = Paths.get("file.txt");
Scanner scanner = new Scanner(filePath);
List<Integer> integers = new ArrayList<>();
while (scanner.hasNext()) {
if (scanner.hasNextInt()) {
integers.add(scanner.nextInt());
} else {
scanner.next();
}
}
A Scanner breaks its input into tokens using a delimiter pattern, which by default matches whitespace. Although default delimiter is whitespace, it successfully found all integers separated by new line character.

Good news in Java 8 we can do it in one line:
List<Integer> ints = Files.lines(Paths.get(fileName))
.map(Integer::parseInt)
.collect(Collectors.toList());

try{
BufferedReader br = new BufferedReader(new FileReader("textfile.txt"));
String strLine;
//Read File Line By Line
while ((strLine = br.readLine()) != null) {
// Print the content on the console
System.out.println (strLine);
}
//Close the input stream
in.close();
}catch (Exception e){//Catch exception if any
System.err.println("Error: " + e.getMessage());
}finally{
in.close();
}
This will read line by line,
If your no. are saperated by newline char. then in place of
System.out.println (strLine);
You can have
try{
int i = Integer.parseInt(strLine);
}catch(NumberFormatException npe){
//do something
}
If it is separated by spaces then
try{
String noInStringArr[] = strLine.split(" ");
//then you can parse it to Int as above
}catch(NumberFormatException npe){
//do something
}

File file = new File("file.txt");
Scanner scanner = new Scanner(file);
List<Integer> integers = new ArrayList<>();
while (scanner.hasNext()) {
if (scanner.hasNextInt()) {
integers.add(scanner.nextInt());
}
else {
scanner.next();
}
}
System.out.println(integers);

import java.io.*;
public class DataStreamExample {
public static void main(String args[]){
try{
FileWriter fin=new FileWriter("testout.txt");
BufferedWriter d = new BufferedWriter(fin);
int a[] = new int[3];
a[0]=1;
a[1]=22;
a[2]=3;
String s="";
for(int i=0;i<3;i++)
{
s=Integer.toString(a[i]);
d.write(s);
d.newLine();
}
System.out.println("Success");
d.close();
fin.close();
FileReader in=new FileReader("testout.txt");
BufferedReader br=new BufferedReader(in);
String i="";
int sum=0;
while ((i=br.readLine())!= null)
{
sum += Integer.parseInt(i);
}
System.out.println(sum);
}catch(Exception e){System.out.println(e);}
}
}
OUTPUT::
Success
26
Also, I used array to make it simple.... you can directly take integer input and convert it into string and send it to file.
input-convert-Write-Process... its that simple.

Read data from a text file using Java

I need to read a text file line by line using Java. I use available() method of FileInputStream to check and loop over the file. But while reading, the loop terminates after the line before the last one. i.e., if the file has 10 lines, the loop reads only the first 9 lines.
Snippet used :
while(fis.available() > 0)
{
char c = (char)fis.read();
.....
.....
}

You should not use available(). It gives no guarantees what so ever. From the API docs of available():
Returns an estimate of the number of bytes that can be read (or skipped over) from this input stream without blocking by the next invocation of a method for this input stream.
You would probably want to use something like
try {
BufferedReader in = new BufferedReader(new FileReader("infilename"));
String str;
while ((str = in.readLine()) != null)
process(str);
in.close();
} catch (IOException e) {
}
(taken from http://www.exampledepot.com/egs/java.io/ReadLinesFromFile.html)

How about using Scanner? I think using Scanner is easier
private static void readFile(String fileName) {
try {
File file = new File(fileName);
Scanner scanner = new Scanner(file);
while (scanner.hasNextLine()) {
System.out.println(scanner.nextLine());
}
scanner.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
}
}
Read more about Java IO here

If you want to read line-by-line, use a BufferedReader. It has a readLine() method which returns the line as a String, or null if the end of the file has been reached. So you can do something like:
BufferedReader reader = new BufferedReader(new InputStreamReader(fis));
String line;
while ((line = reader.readLine()) != null) {
// Do something with line
}
(Note that this code doesn't handle exceptions or close the stream, etc)

String file = "/path/to/your/file.txt";
try {
BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream(file)));
String line;
// Uncomment the line below if you want to skip the fist line (e.g if headers)
// line = br.readLine();
while ((line = br.readLine()) != null) {
// do something with line
}
br.close();
} catch (IOException e) {
System.out.println("ERROR: unable to read file " + file);
e.printStackTrace();
}

You can try FileUtils from org.apache.commons.io.FileUtils, try downloading jar from here
and you can use the following method:
FileUtils.readFileToString("yourFileName");
Hope it helps you..

The reason your code skipped the last line was because you put fis.available() > 0 instead of fis.available() >= 0

In Java 8 you could easily turn your text file into a List of Strings with streams by using Files.lines and collect:
private List<String> loadFile() {
URI uri = null;
try {
uri = ClassLoader.getSystemResource("example.txt").toURI();
} catch (URISyntaxException e) {
LOGGER.error("Failed to load file.", e);
}
List<String> list = null;
try (Stream<String> lines = Files.lines(Paths.get(uri))) {
list = lines.collect(Collectors.toList());
} catch (IOException e) {
LOGGER.error("Failed to load file.", e);
}
return list;
}

//The way that I read integer numbers from a file is...
import java.util.*;
import java.io.*;
public class Practice
{
public static void main(String [] args) throws IOException
{
Scanner input = new Scanner(new File("cards.txt"));
int times = input.nextInt();
for(int i = 0; i < times; i++)
{
int numbersFromFile = input.nextInt();
System.out.println(numbersFromFile);
}
}
}

Try this just a little search in Google
import java.io.*;
class FileRead
{
public static void main(String args[])
{
try{
// Open the file that is the first
// command line parameter
FileInputStream fstream = new FileInputStream("textfile.txt");
// Get the object of DataInputStream
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
String strLine;
//Read File Line By Line
while ((strLine = br.readLine()) != null) {
// Print the content on the console
System.out.println (strLine);
}
//Close the input stream
in.close();
}catch (Exception e){//Catch exception if any
System.err.println("Error: " + e.getMessage());
}
}
}

Try using java.io.BufferedReader like this.
java.io.BufferedReader br = new java.io.BufferedReader(new java.io.InputStreamReader(new java.io.FileInputStream(fileName)));
String line = null;
while ((line = br.readLine()) != null){
//Process the line
}
br.close();

Yes, buffering should be used for better performance.
Use BufferedReader OR byte[] to store your temp data.
thanks.

user scanner it should work
Scanner scanner = new Scanner(file);
while (scanner.hasNextLine()) {
System.out.println(scanner.nextLine());
}
scanner.close();

public class ReadFileUsingFileInputStream {
/**
* #param args
*/
static int ch;
public static void main(String[] args) {
File file = new File("C://text.txt");
StringBuffer stringBuffer = new StringBuffer("");
try {
FileInputStream fileInputStream = new FileInputStream(file);
try {
while((ch = fileInputStream.read())!= -1){
stringBuffer.append((char)ch);
}
}
catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("File contents :");
System.out.println(stringBuffer);
}
}

public class FilesStrings {
public static void main(String[] args) throws FileNotFoundException, IOException {
FileInputStream fis = new FileInputStream("input.txt");
InputStreamReader input = new InputStreamReader(fis);
BufferedReader br = new BufferedReader(input);
String data;
String result = new String();
while ((data = br.readLine()) != null) {
result = result.concat(data + " ");
}
System.out.println(result);

File file = new File("Path");
FileReader reader = new FileReader(file);
while((ch=reader.read())!=-1)
{
System.out.print((char)ch);
}
This worked for me

Simple code for reading file in JAVA:
import java.io.*;
class ReadData
{
public static void main(String args[])
{
FileReader fr = new FileReader(new File("<put your file path here>"));
while(true)
{
int n=fr.read();
if(n>-1)
{
char ch=(char)fr.read();
System.out.print(ch);
}
}
}
}