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Split the string with hyphen symbol multiple occurrence using regex /java

Getting the string value using the below xpath
String noAndDate = driver.findElement(By.xpath("//*[#id='c38']/div/table/tbody/tr[1]/td/strong")).getText();
Output of the above string = 2928554 - 2009-09-18 (BOPI 2009-38)
my expected output
2928554
2009-09-18
i tried below split, but i'm not getting my expected output
String[] words = noAndDate.split("-");
Please advice/help me

You can instead try splitting on a regex alternation which looks for a hyphen surrounded by whitespace, or pure whitespace:
String input = "2928554 - 2009-09-18 (BOPI 2009-38)";
String[] parts = input.split("(\\s+-\\s+|\\s+)");
System.out.println(parts[0]);
System.out.println(parts[1]);
Demo

Try the below code-
String str = "2928554 - 2009-09-18 (BOPI 2009-38)";
String str1 = str.split(" - | ")[0];
String str2 = str.split(" - | ")[1];
This will return str1 as 2928554 and str2 as 2009-09-18.
Hope this will help you !

Just split with regex will do.
String given = "2928554 - 2009-09-18 (BOPI 2009-38)";
String [] splitted = given.split(" - |\\s+");
String result = splitted[0] +", "+splitted[1];
System.out.println(result);
prints
2928554, 2009-09-18

Use Regex capture groups, here you can see what you want in 2 groups:
(\d+)\s*-\s*(\d+\-\d+\-\d+)
() = group

Try this:
String[] words = noAndDate.split(" ");
then
System.out.println(words[0]);
System.out.println(words[2]);

How to append to beginning of java string using replace with regex?

How can I use java string replaceAll or replaceFirst to append to beginning?
String joe = "Joe";
String helloJoe = joe.replaceAll("\\^", "Hello");
Desired Output: "Hello Joe"

You don't need to escape ^ because ^ is a special meta character in regex which matches the start of a line.
String helloJoe = whatever.replaceFirst("^", "Hello ");

You could perform a simple String append with +, or String.format(String, Object...) like
String whatever = "Joe";
String helloJoe = String.format("Hello %s", whatever);
// String helloJoe = "Hello " + whatever;
System.out.println(helloJoe);
Output is (as requested)
Hello Joe

regex to match and replace two characters between string

I have a string String a = "(3e4+2e2)sin(30)"; and i want to show it as a = "(3e4+2e2)*sin(30)";
I am not able to write a regular expression for this.

Try this replaceAll:
a = a.replaceAll("\) *(\\w+)", ")*$1");

You can go with this
String func = "sin";// or any function you want like cos.
String a = "(3e4+2e2)sin(30)";
a = a.replaceAll("[)]" + func, ")*siz");
System.out.println(a);

this should work
a = a.replaceAll("\\)(\\s)*([^*+/-])", ") * $2");

String input = "(3e4+2e2)sin(30)".replaceAll("(\\(.+?\\))(.+)", "$1*$2"); //(3e4+2e2)*sin(30)

Assuming the characters within the first parenthesis will always be in similar pattern, you can split this string into two at the position where you would like to insert the character and then form the final string by appending the first half of the string, new character and second half of the string.
string a = "(3e4+2e2)sin(30)";
string[] splitArray1 = Regex.Split(a, #"^\(\w+[+]\w+\)");
string[] splitArray2 = Regex.Split(a, #"\w+\([0-9]+\)$");
string updatedInput = splitArray2[0] + "*" + splitArray1[1];
Console.WriteLine("Input = {0} Output = {1}", a, updatedInput);

I did not try but the following should work
String a = "(3e4+2e2)sin(30)";
a = a.replaceAll("[)](\\w+)", ")*$1");
System.out.println(a);

Making a song name out of a URL

I have a URL and I want it to look like this:
Action Manatee - Action
http://xxxxxx.com/songs2/Music%20Promotion/Stream/Action%20Manatee%20-%20Action.mp3
What is the syntax for trimming up to where it after this "Stream/" and make spaces where the %20 is. I also want to trim the .mp3

Hmm, for that particular example, I would split the string according to the '/' character then trim the text that follows the final '.' character. Finally, do a replace of "%20" into " ". That should leave you with the string you want
Tested
String initial = "http://xxxxxx.com/songs2/Music%20Promotion/Stream/Action%20Manatee%20-%20Action.mp3";
String[] split = initial.split("/");
String output = split[split.length-1];
int length = output.lastIndexOf('.');
output = output.substring(0, length);
output = output.replace("%20", " ");

String urlParts[] = URL.split("\/");
String urlLast = urlParts[length-1];
String nameDotMp = urlLast.replaceAll("%20");
String name = nameDotMp.substring(0,nameDotMp.length-5);

You could use the split() and replace() methods to accomplish this, here are two ways:
Split your string apart by using the forward slashes:
string yourUrl = [URL Listed];
//Breaks your URL into sections on slashes
string[] sections = yourUrl.split("\/");
//Grabs the last section after the slashes, and replaces the %20 with spaces
string newString = sections[sectiongs.length-1].replace("%20"," ");
Split your string at the Stream/ section: (Only use this if you can guarantee it will be in that form)
string yourUrl = [URL Listed];
//This will get everything after Stream (your song name)
string newString = yourUrl.split("Stream\/")[1];
//Replaces your %20s with spaces
newString = newString.replace("%20"," ");

URL songURL = new URL("yourpath/filename");
String filename = songURL.getFile();

removing space before new line in java

i have a space before a new line in a string and cant remove it (in java).
I have tried the following but nothing works:
strToFix = strToFix.trim();
strToFix = strToFix.replace(" \n", "");
strToFix = strToFix.replaceAll("\\s\\n", "");

myString.replaceAll("[ \t]+(\r\n?|\n)", "$1");
replaceAll takes a regular expression as an argument. The [ \t] matches one or more spaces or tabs. The (\r\n?|\n) matches a newline and puts the result in $1.

try this:
strToFix = strToFix.replaceAll(" \\n", "\n");
'\' is a special character in regex, you need to escape it use '\'.

I believe with this one you should try this instead:
strToFix = strToFix.replace(" \\n", "\n");
Edit:
I forgot the escape in my original answer. James.Xu in his answer reminded me.

Are you sure?
String s1 = "hi ";
System.out.println("|" + s1.trim() + "|");
String s2 = "hi \n";
System.out.println("|" + s2.trim() + "|");
prints
|hi|
|hi|

are you sure it is a space what you're trying to remove? You should print string bytes and see if the first byte's value is actually a 32 (decimal) or 20 (hexadecimal).

trim() seems to do what your asking on my system. Here's the code I used, maybe you want to try it on your system:
public class so5488527 {
public static void main(String [] args)
{
String testString1 = "abc \n";
String testString2 = "def \n";
String testString3 = "ghi \n";
String testString4 = "jkl \n";
testString3 = testString3.trim();
System.out.println(testString1);
System.out.println(testString2.trim());
System.out.println(testString3);
System.out.println(testString4.trim());
}
}