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i am using util.Scanner to read input from the user. I don't understand how to read a long datatype value.
Scanner scr=new Scanner(System.in);
long l=scr.nextInt();
I am unable to read 64-bit data using the above code — it just gives me an input mismatch exception.
use the nextLong method :
long l=scr.nextLong();
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I have a string like "{hello}{bye}"
How can I split() the string so my output is ["{hello}, "{bye}"]
I have tried splitting with "}{" but it leaves me without the }{.
Have also tried .split("((?<=})|(?={))") but I get a "number expected" syntax error beneath the {
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Closed 2 years ago.
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I get this error when I try to do an Onclicklistener to my customInfoWndow
The code for that is specifically this:
(GoogleMap.OnInfoWindowClickListener((new GoogleMap.OnInfoWindowClickListener))
How may I solve this error.
Thanks a lot!
You have a new keyword, so you're constructing an object. If the constructor takes no parameters, you must put empty braces anyway:
new GoogleMap.OnInfoWindowClickListener()
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Closed 6 years ago.
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When using Java, what is the difference between the two following assignments:
String upperCaseDataType = "myName";
string lowerCaseDataType = "myName";
Do the 2 mean the same at compile time, just like in C#?
Thanks very much for your help.
string is not a class or type in Java
No. string s = "myName"; is not legal Java, and will not compile. Also, those are assignments (not assertions).
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If this was a string and it was parsed as a double. Would java be able to process this as the expected value or would I need to change the format of these numbers? Would I need to remove the "+" or change e to "E"?
1.3870574e+01
The string parsed to a double just fine on my system.
See Double.valueOf(String str)
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I guess its a rather simple question but i just cant find my mistake.
int[] myIntArray = new int[20];
myIntArray[5] = 5;
int a = myIntArray[5];
TextIO.putf("arr[i]: d%",a );
The error I get is Illegal format string in TextIO.putf() method.
So I assume the value at the index 5 is not an int?
The error message says exactly what the problem is: your format string is wrong. You probably meant %d (or better yet, %d%n to add a newline).
The format string elements are in the form
%[modifiers]type
not
something%
Change d% to %d.