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Closed 2 years ago.
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I get this error when I try to do an Onclicklistener to my customInfoWndow
The code for that is specifically this:
(GoogleMap.OnInfoWindowClickListener((new GoogleMap.OnInfoWindowClickListener))
How may I solve this error.
Thanks a lot!
You have a new keyword, so you're constructing an object. If the constructor takes no parameters, you must put empty braces anyway:
new GoogleMap.OnInfoWindowClickListener()
Related
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Closed 4 days ago.
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I have a string like "{hello}{bye}"
How can I split() the string so my output is ["{hello}, "{bye}"]
I have tried splitting with "}{" but it leaves me without the }{.
Have also tried .split("((?<=})|(?={))") but I get a "number expected" syntax error beneath the {
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Closed 6 years ago.
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System.out.println(i+"\t\t\t"+(i*i)+"\t\t\t"(i*i*i));
^
error:')'expected
You're missing a "+"
Try this :
System.out.println(i+"\t\t\t"+(i*i)+"\t\t\t"+(i*i*i));
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Closed 6 years ago.
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When using Java, what is the difference between the two following assignments:
String upperCaseDataType = "myName";
string lowerCaseDataType = "myName";
Do the 2 mean the same at compile time, just like in C#?
Thanks very much for your help.
string is not a class or type in Java
No. string s = "myName"; is not legal Java, and will not compile. Also, those are assignments (not assertions).
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Closed 8 years ago.
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If this was a string and it was parsed as a double. Would java be able to process this as the expected value or would I need to change the format of these numbers? Would I need to remove the "+" or change e to "E"?
1.3870574e+01
The string parsed to a double just fine on my system.
See Double.valueOf(String str)
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Closed 4 days ago.
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I tried to check if a property was equal to a string but I keep getting this error
Code:
if (prop.getProperty("quit").equal("true")) {
}
Error:
cannot find symbol
symbol: method equal(java.lang.String)
location: class java.lang.String
The method name is equals not equal.