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Defining two different Threads in java

Im new to Threads and I was wondering how could I define what two or more different Threads do in a Java program. Do i define them all in the same public void run method? If so, how do I do it? I would like the Threat t1 to invoke the increment method, t2 to invoke the decrement method and both of them to call the value method
Here's the code example:
package interference;
/**
*
* #author rodrigopeniche
*/
public class Interference implements Runnable{
/**
* #param args the command line arguments
*
*/
Counter counter1= new Counter();
class Counter{
private int c= 0;
public void increment()
{
c++;
}
public void decrement()
{
c--;
}
public int value()
{
return c;
}
}
public static void main(String[] args) {
// TODO code application logic here
Thread t1= new Thread(new Interference());
Thread t2= new Thread(new Interference());
t1.start();
t2.start();
}
#Override
public void run() {
counter1.increment();
counter1.decrement();
counter1.value();
}
}

You can set names to threads like thread1, thread2. After that, in the run method, check the name of the thread currently running and do the necessary action.
You have to add a while loop inside the run method if you need to run it longer.
public static void main(String[] args) {
Interference interference = new Interference();//create a new Interference object
Thread t1 = new Thread(interference, "thread1");//pass the runnable interference object and set the thread name
Thread t2 = new Thread(interference, "thread2");//pass the runnable interference object and set the thread name
t1.start();
t2.start();
}
#Override
public void run() {
while (true) {//to run it forever to make the difference more visual
String threadName = Thread.currentThread().getName();//get the current thread's name
if (threadName.equals("thread1")) {//if current thread is thread1, increment
counter1.increment();
} else if (threadName.equals("thread2")) {//if current thread is thread2, decrement
counter1.decrement();
}
System.out.println(counter1.value());//print the value
}
}
When you run the code, you can see count is going up and down in a random manner.

In your current code, counter1 is an instance variable of class Interference. You create 2 instances of Interference and then use them to create two Thread objects. When the threads start to run, each Thread is actually working on it's own copy of counter1. I think that may not be what you expect.
package interference;
public class Interference {
static class Counter {
private int c = 0;
public void increment() {
c++;
}
public void decrement() {
c--;
}
public int value() {
return c;
}
}
public static void main(String[] args) {
Counter counter = new Counter();
Thread t1 = new Thread(new Runnable() {
public void run() {
counter.increment();
System.out.println(counter.value());
}
});
Thread t2 = new Thread(new Runnable() {
public void run() {
counter.decrement();
System.out.println(counter.value());
}
});
t1.start();
t2.start();
}
}

Why doesn't run method call?

I've write the following example:
public class MyThread extends Thread{
MyThread(Runnable r){
super(r);
}
public void run(){
System.out.println("run");
}
}
public static void main(String[] args)
{
Thread t = new MyThread(new Runnable() {
#Override
public void run() {
System.out.println("rrrrrrrrrruuuuuuuuuuuun");
}
});
t.start(); //run
}
Why does run methdo defined in MyThread was called instead?

Because the default behavior of a thread constructed with a Runnable is to delegate to the runnable passed as argument to the constructor. But you overrode run() in the thread itself, so instead of delegating to the runnable, it executes the code inside the overridden run() method.
For the record, here's the default implementation of Thread.run(), that you overrode:
private Runnable target;
public void run() {
if (target != null) {
target.run();
}
}

Because you the MyThread.run is not override, but the Runnable.run is. Now if you look at your implementation of MyThread.run, the stored Runnable plays no part in it. In other words, it doesn't matter what kind of runnable you give with the constructor. You should use:
public static void main(String[] args)
{
Thread t = new MyThread() {
#Override
public void run() {
System.out.println("rrrrrrrrrruuuuuuuuuuuun");
}
});
t.start(); //run
}
As #BorisTheSpider notes, overriding a Thread is in general not good practice: a Thread has the responsibility to start a Thread and give control to a runnable. A better implementation would be:
public static void main(String[] args)
{
Thread t = new Thread(new MyThread() {
#Override
public void run() {
System.out.println("rrrrrrrrrruuuuuuuuuuuun");
}
}));
t.start(); //run
}

How to run a class' method using thread

If I do the following, I will be able to create an object as a thread and run it.
class ThreadTest
{
public static voic main(String[] args)
{
HelloThread hello = new HelloThread();
Thread t = new Thread(hello);
t.start();
}
}
class HelloThread extends Thread
{
public void run()
{
System.out.println(" Hello ");
}
}
Now, if my HelloThread class has a another method call runThisPlease(), how are we supposed to run it with a thread?
Example:
class HelloThread extends Thread
{
public void run()
{
System.out.println(" Hello ");
}
public void runThisPlease(String input)
{
System.out.println (" Using thread on another class method: " + input );
}
}
Que: When I try Thread t = new Thread(hello.runThisPlease());, it doesn't work. So how can we call the method runThisPlease() using a thread?
Edit: Argument needed in method for runThisPlease();

In java 8 you can use
Thread t = new Thread(hello::runThisPlease);
hello::runThisPlease will be converted to a Runnable with a run method that calls hello.runThisPlease();.
If your want to call a method, that needs parameters, e.g. System.out.println, you can of course use a normal lambda expression too:
final String parameter = "hello world";
Thread t = new Thread(() -> System.out.println(parameter));
If you use a java version < 8, you can of course replace the method reference / lambda expression with anonymus inner classes that extend Runnable (which is what a java8 compiler does, AFAIK), see other answers.
However you can also use a anonymus inner class that extends Thread:
final HelloThread hello = //...
Thread t = new Thread() {
#Override
public void run() {
hello.runThisPlease();
}
};

Simply calling the runThisPlease() from within the run() method will make it part of a new thread.
Try this:
class HelloThread extends Thread
{
public void run()
{
System.out.println(" Hello .. Invoking runThisPlease()");
runThisPlease();
}
public void runThisPlease()
{
System.out.println (" Using thread on another class method ");
}
}

Things are maybe more clear if you use the Runnable interface:
public class HelloThread implements Runnable
{
#Override
public void run() {
// executed when the thread is started
runThisPlease();
}
public void runThisPlease() {...}
}
To launch this call:
Thread t=new Thread(new HelloThread());
t.start();
The Thread class can not see your extra method because it is not part of the Runnable interface.
As a convenience Thread implements Runnable but I don't think it helps in clarity :(

You have to only call this method inside run() method.
public void run(){
System.out.println(" Hello ");
runThisPlease();
}
If you want to pass some argument then you can use below code
String str = "Welcome";
Thread t = new Thread(new Runnable() {
public void run() {
System.out.println(str);
}});

Creating thread to print out message

Not sure sure if I am doing this right. I need to make a new thread to write out message certain number of times. I think this works so far but not sure if its the best way of doing it. Then i need to display another message after thread has finished running. How do I do that ? Using isAlive() ? How do i implement that ?
public class MyThread extends Thread {
public void run() {
int i = 0;
while (i < 10) {
System.out.println("hi");
i++;
}
}
public static void main(String[] args) {
String n = Thread.currentThread().getName();
System.out.println(n);
Thread t = new MyThread();
t.start();
}
}

Till now you are on track. Now, to display another message, when this thread has finished, you can invoke Thread#join on this thread from your main thread. You would also need to handle InterruptedException, when you use t.join method.
Then your main thread will continue, when your thread t has finished. So, continue your main thread like this: -
t.start();
try {
t.join();
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("Your Message");
When your call t.join in a particular thread (here, main thread), then that thread will continue its further execution, only when the thread t has completed its execution.

Extending the Thread class itself is generally not a good practice.
You should create an implementation of the Runnable interface as follows:
public class MyRunnable implements Runnable {
public void run() {
//your code here
}
}
And pass an intance of it to the thread as follows:
MyRunnable r = new MyRunnable();
Thread t = new Thread(r);
t.start();
Please check this answer here on SO: Implementing Runnable vs. extending Thread

This is how you can do that.........
class A implements Runnable
{
public void run()
{
for(int i=1;i<=10;i++)
System.out.println(Thread.currentThread().getName()+"\t"+i+" hi");
}
}
class join1
{
public static void main(String args[])throws Exception
{
A a=new A();
Thread t1=new Thread(a,"abhi");
t1.start();
t1.join();
System.out.println("hello this is me");//the message u want to display
}
}
see join() details on
join

Java and 2 threads

I am trying to learn Java's threads in order to do an assignment, but I do not understand how I can make each thread to do its own code. I also get an error:
Program.java:1: error: Program is not abstract and does not override abstract me
thod run() in Runnable
public class Program implements Runnable {
^
1 error
Because it is required by the assignment, I have to do everything within the same file, so I tried the code below:
public class Program implements Runnable {
Thread thread1 = new Thread () {
public void run () {
System.out.println("test1");
}
};
Thread thread2 = new Thread () {
public void run () {
System.out.println("test2");
}
};
public void main (String[] args) {
thread1.start();
thread2.start();
}
}
Could you please fix it for me and show how to have 2 threads which do different tasks from each other? I have already seen examples that print threads' names, but I did not find them helpful.
Thank you.

Your Program class is defined as implementing the Runnable interface. It therefore must override and implement the run() method:
public void run () {
}
Since your two Thread objects are using anonymous inner Runnable classes, you do not need and your should remove the implements Runnable from your Program class definition.
public class Program {
...

try this:
class Program {
public static void main(String[] args) {
Thread thread1 = new Thread() {
#Override
public void run() {
System.out.println("test1");
}
};
Thread thread2 = new Thread() {
#Override
public void run() {
System.out.println("test2");
}
};
thread1.start();
thread2.start();
}
Or you can create a separate class implementing Runnable and ovverriding method run().
Then in main method create an instance of Thread with you class object as argument :
class SomeClass implements Runnable {
#Override
run(){
...
}
}
and in main:
Thread thread = new Thread(new SomeClass());

When you implement an interface (such as Runnable) you must implement its methods, in this case run.
Otherwise for your app to compile and run just erase the implements Runnable from your class declaration:
public class Program {
public void main (String[] args) {
Thread thread1 = new Thread () {
public void run () {
System.out.println("test1");
}
};
Thread thread2 = new Thread () {
public void run () {
System.out.println("test2");
}
};
thread1.start();
thread2.start();
}
}