Caution while extending a class which is Serializable - java

I have a class A implementing Serializable and another class B extends A, but I want to use class B for XML binding, not for serialization.
Is there anything I should worry about?

Assuming you've implemented all of the Serializable methods in A, nope. You won't need to worry about implementing them, since that's already done. If there are any naming conflicts between XML binding and serialization, you can define the method in B and your XML binding library will call the methods for B, not those of A (i.e. polymorphism).
The only potential worry is a method that takes an argument of type Serializable -- if B, for whatever reason, shouldn't be (de)serialized, this is a problem. I doubt that this is a problem for you, if only because there are so few cases when it would apply.

Related

Adding properties to abstract class which are already extending from that abstract class

I have an abstract class A. There are at least 10 other concrete classes that are extending from Abstract class A. Class C is one of those concrete classes. I have a requirement to add a property of type C to all those classes. The best way would have been to add that to class A so as to avoid code duplication. However since C is also extending from A, this would not be possible.
Is there any way to achieve the above?
Maybe consider using an Interface. Though java does not support multiple class inheritance, it does allow for multiple implementations of an interface. This way, you would be able to have the methods you need in C, can be stored in an interface, that way other classes that need that method, can inherit them from the interface, and also use the abstract class at the same time.

Serialization with default methods in interface (BWC)

I have an interface A, and implementation of this interface AImpl
Interface has 1 method which is implemented in AImpl.
Implementation AImpl has few members and no serialVersionUID.
Question what will happen If new default method will be added to interface A, without overriding it in AImpl ? Have I did break here? Will I have same result of serialization/deserialization ?
Not only are methods not serialized, but interfaces are not serialized either.
The purpose of serialization is to write the data associated with an object, not it's behaviour (unless this is explicitly encoded as data as well, e.g. GregorianCalendar's TimeZone)
There is no way to see in a serialized object what interfaces or methods the class has so changing them has no effect.
(You might infer about the methods used for serialization only)
Java serialization does encode the super-class hierarchy of a class so you can't change that easily.
However, most serialization libraries don't do this and you can't see this information nor does it matter if you change them. The downside is that many serialization libraries don't support having the same field name multiple times in your class hierarchy but Java serialization does.

Java : If A extends B and B extends Object, is that multiple inheritance

I just had an interview, and I was asked a question.
Interviewer - Does Java support multiple inheritance?
Me - No
Interviewer - Each class in Java extends class Object (except class Object) and if we externally extend one class like
Class A extends B{
// some code here
}
then you can say that class A extend class B and class Object, which means it is multiple inheritance. So how can you say Java does not support multiple inheritance?
Me - Actually class B extends class Object, so when you extend class B in class A then class A extends class Object indirectly. This is multi-level inheritance, not multiple inheritance.
But my answer did not satisfy him.
Is my answer correct? Or where am I wrong?
What actually happens internally?
My answer is correct?
Yes, mostly, and certainly in the context you describe. This is not multiple inheritance:
It's what you said it is, single inheritance with multiple levels.
This is multiple inheritance: Inheriting from two or more bases that don't have any "is a" relationship with each other; that would be inheriting from unrelated lines, or from lines that had previously diverged (in Java, since Object is always a base, it would be the latter):
(Image credits: http://yuml.me in "scruffy" mode)
Internally What happens actually?
Just what you said: There are multiple levels. When the compiler is resolving a member on an instance:
obj.member
...it looks to see if the type of obj (which in this case is a class, say ClassB) has member, either because it provides it directly or it has it through inheritance. At runtime, the JVM uses the member the object actually has.
The reason I said "mostly" above is that Java has interfaces, and as of Java 8 it has "default methods" on interfaces. This complicates things a bit, but your answer about levels is correct in the context of what you described the interviewer saying about Object, ClassA, and ClassB.
Interfaces have always made it possible, in Java, for something to have an "is a" relationship with two different types: A class type it inherits from, and any of several interface types it implements. Interfaces without default methods aren't multiple inheritance in a practical way (the class has to provide the implementation), but they did make it possible for a class to have multiple "is a" relationships from unrelated type trees. (I'm not an academic, it's possible an academic would argue that they provide multiple inheritance in an academic way.)
With Java 8, interfaces can provide default implementations of the methods they define, which really blurs the lines even at the practical level. Let's look at that a bit more deeply:
Say we have ClassA:
class ClassA {
void doSomething() {
// Code here
}
}
and Interface1:
interface Interface1 {
default void doSomethingElse() { // Requires Java 8
// Code here
}
}
and finally ClassB:
class ClassB extends ClassA implements Interface1 {
}
ClassB inherits the implementation of doSomething from ClassA. But it also gets the "default" version of doSomethingElse from Interface1. We didn't implement it in ClassB, but ClassB isn't abstract: It really has doSomethingElse. It gets it from the interface. I used the word "gets" rather than "inherits" there, but this looks a lot like inheriting the default method.
This is basically multiple-inheritance "light" (as in "light beer"). It does an end-run around the thornier problems with true multiple inheritance, like:
What should the type of super be? (Java 8's answer: ClassA)
What order do you run constructors in? (Java 8's answer: Single-lineage constructor chaining, interfaces don't have constructors.)
Do you run constructors that you inherit more than once, more than once? (Java 8's answer: You can't inherit constructors more than once, interfaces don't have them.)
What happens if you inherit multiple methods with the same signature? (Java 8's answer: If one of them is from the base class, that's the one that's used; a base class's implementation can override the default method of multiple interfaces. If you have multiple default methods with the same signature from different interfaces at compile-time, it's a compile-time error. If an interface has been changed without the class being recompiled and the situation arises at runtime, it's a runtime IncompatibleClassChangeError exception listing the conflicting default methods.)
you are correct
First of all, Object class is the super/base/parent class of every class including user-defined classes.
So even if we don't mention it explicitly, the user-defined classes extends Object class by default.
its like
class A
class B extends A
but compiler read it as
class A extends Object
class B extends A
proved
for more detail check this java documentation for inheritance
My answer is correct?
You are absolutely correct in saying that it is multi-level inheritance and not multiple inheritance.
Only the root of the hierarchy is Object, all classes don't individually extend Object.
A counter to the interviewer:
If all classes extend Object, then how many times constructor of Object will be called on A a = new A();
The answer is only once, and that will be for the root of the hierarchy.
Multiple inheritance and class Object
Yes, you are correct... as many others have pointed out. I just wanted to say that interviews are not only about technical knowledge, it is also about sticking to your guns. Some interviewers will question your answer, not because they want to know if you are sure of your convictions but also to test how well you can teach others and how well you handle an authoritative figure.
For the first point, if you can't teach others then you can't be a mentor. Nowadays it is crucial to hire someone who can coach junior developers.... because it makes sense economically.
For the second point, because they don't want you changing technical aspects just because your boss asked you to. If your boss asks you to remove all indexes from the database because they take up too much space, would you do it? Would you try to convince your boss otherwise? How?
Does java support multiple inheritance?
Yes for interfaces but not for classes.
The class and interface can implements many interfaces but extends only one class
Your answer is correct !
class Object //for illustration purpose
{
}
class B
{
}
class A extends B
{
}
When you create an object of class A, constructor chaining happens.
i.e. the constructor of class A calls super() implicitly and hence the constructor of class B is invoked, which then calls its super class implicitly which is the Object class.
In java, a class extends only a single class because the constructor of that class only call one super class constructor. This is not true in case of Interfaces since they do not have constructors.
Also when an object of class A is created, and assume that you have defined the constructors of both classes A and B, then constructor of class B is executed first and then the constructor of class A.
Your answer is perfectly alright. You can explain interms of multilevel inheritance support from Object class in java
Your answer is right, because java doesn't support multiple inheritance from classes. Java supports multiple inheritance from interfaces, and there is no any other inheritance. But you can use composition of classes, but that's another story.
What a dumb question.
Of course Java doesn't support multiple inheritance, and interfaces are not inherited.
Inheritance only happens via "extends", not via "implements". When you define a class implements several interfaces you are not saying it will be an extension of those interfaces, but it will have the same behavior, and behavior (at least in Java), doesn't define inheritance.
For Java to support multiple inheritance, it would need to support something like
public class MI extends Object, MyOtherClass
Which Java can't.
Well, maybe I wouldn't get the job for calling the interviewer's question dumb :)
Your answer is absolutely correct.
These types of questions asked just to check whether a candidate is conceptually strong or not.
Well the simplest and precise answer to this question is here:
"Classes can be derived from classes that are derived from classes that are derived from classes, and so on, and ultimately derived from the topmost class, Object. Such a class is said to be descended from all the classes in the inheritance chain stretching back to Object."
Please refer this link
https://docs.oracle.com/javase/tutorial/java/IandI/subclasses.html
The answer you gave is correct. The interviewer was wrong:
Internal process
if suppose Class A Doesn't extends any other class
then ---> Class B extends java.lang.Object
then ---> Class A extends B
then class A also inherited the property of java 'Object' class...
so,Java doesn't support multiple inheritance.
If you want to verify this process just generate 'javadoc' for your class A and verify the results.

(Java) Creating methods for new object created via reflection?

I have abstract methods in a class that need to be implemented by a foreign class in a SEPARATE project that uses my project.
-- All classes instanceof A are initially generated using reflection --
So anyway, say Class A is abstract, and Class B (non-abstract) extends A
B has all the unimplemented methods in Class A because B is in my workspace so I know to add those methods.
C also extends A, but C only has a subset of the abstract methods in A. C, however, is not in my workspace.
Therefore, for each abstract method in C NOT in A, I need to find some way to add the method for A like so:
(For each method)
public <corresponding return type> <missingMethodName>() { return null; }
Is this possible?
P.S. Please assume that I either have to completely rewrite my code to be in sync with the objects I have no control over, or implement a solution like the one I am alluding to above.
No, unless I'm reading you incorrectly, what you're asking for doesn't really make much sense.
If you wanted to inject a method
public <corresponding return type> <missingMethodName>() { super.<missingMethodName>(); }
into C, which extends A, which doesn't implement that method, what would it exactly do?
If you want to provide a default implementation in A, that's fine, and it won't affect C. If you add abstract methods into A, C must implement them, mark itself as abstract, or it won't compile (or throw serialization, or some weird error) if you run with a C compiled with an older A.
You should never need to do this as any instance method which has a super implementation can be called on a sub-class instance.
You can add these methods using byte code, but the only difference they would make is to change the list of getDefinedMethods(). However it wouldn't change the behaviour of the objects of the class.
its quiet difficult but you can do it with Javassist
Javassist (Java programming assistant) is a Java library providing a means to manipulate the Java bytecode of an application.1 In this sense Javassist provides the support for structural reflection, i.e. the ability to change the implementation of a class at run time.
Bytecode manipulation is performed at load-time through a provided class loader.
http://en.wikipedia.org/wiki/Javassist

Does removing an interface break code calling methods on the object?

I need to do some refactoring in Java, and I need to maintain some degree of binary compatibility. In this case I want to remove some legacy interfaces, that are not used anywhere anymore and which require a rather big (and also deprecated) external dependency.
I have class C that implements interface I, and I have code that calls a method (declared in the interface) on an instance of C. The calling code knows that it is using C, not just the interface.
class C implements I {
void theMethod(){} ; // is declared in the interface I
}
C object;
object.theMethod();
When I remove the interface from the class definition (but keep all the methods), will the calling code (which does not refer to the interface at all) still work (without a recompile)?
Yes, it will work - as long as it doesn't explicitly refer to interface I anywhere.
From JLS: Resolution of Symbolic References:
The binary representation of a class
or interface references other classes
and interfaces and their fields,
methods, and constructors
symbolically, using the binary names
(ยง13.1) of the other classes and
interfaces
Class ClientClass referring to field / method of class C contains no implicit references to interface I that class may implement.
It works as long as an object of class C is never referred to as I.
You can also refer to Evolving Java-based APIs part 2.
You might have a problem with the calling Code if it imports the Interface anywhere. If there is no import of the interface in any of the calling code, you can be reasonably confident that your refactoring will work as planned.

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