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Run batch file code from java code

I want to execute a batch file code from java button click. Also I don't want any command prompt window to be shown all from java code.
I have a code :-
C:\xyz-3.1.1\bin>dita --input=C:/Users/india/Desktop/mobile-phone/m
obilePhone.xyz --format=pdf --output=C:/Users/india/Desktop --logfile=C:/Use
rs/india/Desktop/dofhdif.txt
So I want above code to be run from batch command with C:\xyz-3.1.1\bin> as the parent directory.
Also I want to update --input file path whenever I will choose new file from JFileChooser.
I did this from the java code on button click transform:-
ProcessBuilder pb=new ProcessBuilder("dita --input=C:/Users/india/Desktop/mobile-phone/mobilePhone.xyz --format=pdf --output=C:/Users/india/Desktop --logfile=C:/Users/india/Desktop/dofhdif.txt");
pb.redirectErrorStream(true);
Process process=pb.start();
and getting IOException error.
I get stuck over here for long time , where am I going wrong.
EDIT :- error
java.io.IOException: Cannot run program "dita --input=C:/Users/india/Desktop/mobile-phone/m
obilePhone.xyz --format=pdf --output=C:/Users/india/Desktop --logfile=C:/Use
rs/india/Desktop/dofhdif.txt": CreateProcess error=2, The system cannot find the file specified
at java.lang.ProcessBuilder.start(Unknown Source)

As the Error mentioned, it cannot locate the command because the whole string will be treated as the command by ProcessBuilder.
Try to use Runtime.getRuntime().exec directly, but you have to ensure the command dita can be found.
Process process = Runtime.getRuntime().exec("C:\xyz-3.1.1\bin>dita --input=C:/Users/india/Desktop/mobile-phone/mobilePhone.xyz --format=pdf --output=C:/Users/india/Desktop --logfile=C:/Users/india/Desktop/dofhdif.txt");
process.waitFor();
int exitCode = process.exitValue();
System.out.println(IoHelper.output(process.getInputStream())); // handle the output;
Before JDK 5.0, the only way to start a process and execute it, was to use the exec() method of the java.lang.Runtime class after which ProcessBuilder can be used to help create operating system processes.
The major improvement being that, it also acts as a holder for all those attributes that influence the process. And this is how it should be used:
ProcessBuilder pb = new ProcessBuilder("myCommand", "myArg1", "myArg2");
P.S. Actually Runtime.getRuntime().exec can also be used with String... as:
Runtime.getRuntime().exec(new String[]{"curl", "-v", "--cookie", tokenString, urlString});
My personal preference:
If you have to configure the environment for the command: to control the working directory or environment variables and also you want to execute the commands several times, you'd better use it since the ProcessBuilder will hold the settings and what you need to do is just processBuilder.start() to create another process with the same settings;
If you want to execute a whole long string command as you mentioned, you'd better just use Runtime.getRuntime().exec since you can just execute it right there without any bothering of the parameter format.

Try this:
String inputFile = ...;
String outputFile = ...;
String logFile = ...;
ProcessBuilder pb = new ProcessBuilder(
"dita",
"--input=" + inputFile,
"--format=pdf",
"--output=" + outputFile,
"--logfile=" + logFile)
.directory(new File("C:\\xyz-3.1.1\\bin"))
//.inheritIO();
.redirectErrorStream(true);
Process process = pb.start();
This shows the following points:
The command is separated from the arguments
The argument values can be determined at runtime
The command's default directory (C:\xyz-3.1.1\bin) is set before starting the process
Consider using inheritIO() instead of redirectErrorStream() if you want the process's output to appear as part of your Java application's output.

Is it possible to run java from Python in order to create a .png?

I currently have a working java application which from a String renders a .png file. When run from cmd it produces the image in the directory I want. However, when I've tried calling it from Python using
subprocess.call(["java", "-jar", "C:\\path\to\my\jarFile\file.jar",
inputString], shell = True)
no image is created. How can I make it create an image?
Any advice is helpful!

You could read the process output message to debug it, example code:
inputString = ''
ps = subprocess.Popen(["java", "-jar", "C:\\path\to\my\jarFile\file.jar", inputString],stdout=subprocess.PIPE,stderr=subprocess.STDOUT)
val = ps.stdout.read()
print("val: " + val)
and in my pc, it output error like this:
val: Error: Unable to access jarfile C:\path o\my\jarFileile.jar

ProcessBuilder: Start .jar in java package

I try to execute an external jar in my java application. The .jar is in my java-package ("gui").
I tried:
String filepath = this.getClass().getResource("ServerRSS.jar").getPath();
ProcessBuilder pb = new ProcessBuilder("java", filepath);
System.out.println(filepath); results in:
/C:/Users/hox/workspace/PraktikumProg/bin/gui/ServerRSS.jar
My programm doesn't start. Could the problem be the slash before the C: ?
EDIT:
The solution was:
URL filepath = this.getClass().getResource("ServerRSS.jar");
ProcessBuilder pb;
pb = new ProcessBuilder("java", "-jar", new File(filepath.toURI()).toString());
Process p = pb.start();

First get your command working ... simply on the command line.
And only then try to run it from within Java using a ProcessBuilder.
Simple answer is probably: to use -jar when invoking java.
java someJar.jar
does not work!
And yes, that slash matters big time. You simply want a fully correct file path there.
Finally: are you really sure you want to start a new JVM in order to run a main method in some class? You see, you could do that within your current JVM - without the additional performance and complexity cost of using a second JVM!

Can't launch .exe from Java

I am trying to launch a .exe file through a Java program. I used the following code:
System.out.println("Opening " + path);
Process exec;
exec = Runtime.getRuntime().exec("rundll32 SHELL32.DLL,ShellExec_RunDLL " + path);//path is the path of the exe file which is passed as an argument from another java class
the output is as follows:
Opening C:\Program Files (x86)\C-Free 5\CppIDE.exe
But it is not opening.
Instead when I try
String pat="C:\\Program Files (x86)\\C-Free 5\\CppIDE.exe";
Process exec;
exec = Runtime.getRuntime().exec("rundll32 SHELL32.DLL,ShellExec_RunDLL " + pat);
the program is opened.
I don't know what the problem is.

It's very likely that the space in your path is the problem.
I suggest you pass the arguments as an array instead of passing a single string containing the whole command (alternatively you could quote the spaces correctly, but that's not quite as easy).
Either
use the String[] version of Runtime.exec() or
switch to using ProcessBuilder which has an altogether simpler and more intuitive API.
With ProcessBuilder this could look like this:
ProcessBuilder pb = new ProcessBuilder("rundll32", "SHELL32.DLL,ShellExec_RunDLL", path);
Process p = pb.start();
Also, I see no reason to invoke rundll32 at all in this scenario. This should work just as well:
ProcessBuilder pb = new ProcessBuilder(path);
Process p = pb.start();

You need to construct the path using File.separator. The path separator you are using will, in this case, will be system dependant.

Java command Runtime.getRuntime().exec() in Mac OS

I´m using Mac OS Lion, with java version 1.6.0_26
I'm making a small app for Mac in Java with a main menu for the user, so he can choose several options.
One of them is install an app using a .pkg
Everything was working fine with these commands:
File instFolder = new File(System.getProperty("user.dir") + "/foldername/appInstaller.pkg");
String s = "open "+ instFolder.toString();
Process p = Runtime.getRuntime().exec(s);
Then I realized that there is a problem when foldername has spaces or if I copy this java file with the needed subfolders to a USB pen drive with "NO NAME" as name (or some name with spaces).
Because s will become something like:
open /Volumes/NO NAME/foldername/appInstaller.pkg
or
open /Users/user1/Desktop/folder name/appInstaller.pkg
So when you run the p process, the command will finish where the first space appears on the path
open /Volumes/NO
or
open /Users/user1/Desktop/folder
To try to fix this I changed the s definition for something like this:
String s = "open "+ "\"" + instFolder.toString() + "\"";
It stopped working fine. The strange thing is that if i copy the s value (after creating the s variable) and paste it in the terminal it works:
open "/Users/user1/Desktop/folder name/appInstaller.pkg"
but running it from Java it does't work.
Could you help me, please?
Thanks.

In order to properly escape arguments, you can use the following:
Runtime.getRuntime().exec(new String[] { "open", instFolder.toString() });
Though I would probably to use the more modern ProcessBuilder:
ProcessBuilder pb = new ProcessBuilder("open", instFolder.toString());
Process p = pb.start();
int exitCode = p.waitFor();
Though this may be worth a read depending on what you want to do with the processes output.
Note: edited to reflect question in comment

it seems your path does not have quotes when turned into the shell.
You should probably add "'" on both sides of your path, so the final shell command will look like:
open 'your path'
instead of
open your path

Here's a little trick that came out from the answers mentioned above:
ProcessBuilder pb = new ProcessBuilder(commandString.split(" "));
Say commandString = "killall Mail" then the split will separate the words making it a String[] parameter to the ProcessBuilder.