I have a timestamp as ms and format this with a SimpleDateFormater like this:
SimpleDateFormat sdfDate = new SimpleDateFormat("MM/d/yyyy h:mm a");
return sdfDate.format(new Date(timeStamp));
Now I'd like to change this to use the new Java 8 abilities. Seems like I really can't find a way to get this working with the new Java 8 Classes. Anyone got a hint?
If all you have is a millisecond value (assuming from the Unix Epoch) you can get an LocalDateTime using something like:
LocalDateTime ldt = LocalDateTime.ofInstant(Instant.ofEpochMilli(timeInMillis), ZoneId.systemDefault());
System.out.println(ldt);
Which can print something like:
2015-09-29T16:57:40.077
You can then format it using something like this:
System.out.println(ldt.format(DateTimeFormatter.ofPattern("MM/dd/yyyy h:mm a")));
Which can print something like (based on the original time from the previous example):
09/29/2015 4:57 PM
I hope you can try this in Java 8 to get Date from timestamp:
timeStamp.toLocalDateTime().toLocalDate();
For formatting you can use LocalDateTime as:
String str = "1997-03-18 11:30";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm");
LocalDateTime dateTime = LocalDateTime.parse(str, formatter);
Related
I'm trying to parse a date with the format "" to Date.
DateFormat sdf = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss");
Date date = sdf.parse(dateStr);
String = sdf.format(date);
An example of the dateStr is "2020-04-14 16:34:40.0117372".
I get an error when trying to parse the string, but I don't know why.
The error I'm getting is the following:
java.text.ParseException: Unparseable date: "2020-04-14 16:34:40.0117372"
Why can't I parse this date? How can I do it?
You are using "dd/MM/yyyy" for date format, but you should be using "yyyy-MM-dd" (inverse order, and dashes instead of slashes)
Also I suggest you use modern java.time packages and do something like this:
String str = "2020-04-14 16:34:40.0117372";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSSSSSS");
LocalDateTime dateTime = LocalDateTime.parse(str, formatter);
Edit: Having 7 digits for milliseconds is correct, first digits for milliseconds and the rest for nanoseconds. strange. Usually you want 3 digits because 1000 milliseconds is a second. You likely have nanoseconds, which should be dealt with by this method.
Hi I have a problem with joda time. I'm trying to get the 'Z' value at the end of datetime but couldn't :
I have tried with below syntax but no luck, not sure exactly
LocalDateTime currentDateTime = LocalDateTime.now(DateTimeZone.forID("GMT"));
Output: 2019-06-11T21:29:42.474
LocalDateTime currentDateTime = LocalDateTime.now(DateTimeZone.forID("GMT"));
DateTimeFormatter fmt = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
DateTime parsedDateTimeUsingFormatter
= DateTime.parse(currentDateTime.toString(), fmt);
System.out.println(parsedDateTimeUsingFormatter);
Output: 2019-06-11T21:29:42.474-04:00
But I need like the below in GMT format:
Expected output: 2019-06-11T21:29:42.474Z
It sounds like you just need to create a DateTime in UTC:
DateTime utcNow = DateTime.now(DateTimeZone.UTC);
System.out.println(utcNow);
It's not a matter of "just putting a Z at the end" - you need to make sure you're actually obtaining a UTC timestamp to start with.
You can try this:
LocalDateTime localNow = LocalDateTime.now(TimeZone.getTimeZone("GMT").toZoneId());
Now That we have it set to GMT, we can proceed with;
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
String formatDateTime = localNow.format(formatter);
Answer will be in this format
2019-06-11T22:28:20.062Z
I need to format a String that looks like this:
"2018-07-20 18:53:46.598000 +02:00:00"
into a DateTime object like this:
20/07/2018 (HH with Timezone applied):53:46
My approach has been:
String dateTimePattern = "dd/MM/yyyy HH:mm:ss";
SimpleDateFormat dateTimeFormat = new SimpleDateFormat(dateTimePattern);
Date feUltModDateTime = dateTimeFormat.parse(feUltMod);
feUltMod = feUltModDateTime.toString();
But I'm getting a parse error:
java.text.ParseException: Unparseable date: "2018-07-20 18:53:46.598000 +02:00:00"
java.time
DateTimeFormatter origFormatter
= DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss.SSSSSS XXXXX");
DateTimeFormatter desiredFormatter = DateTimeFormatter.ofPattern("dd/MM/uuuu HH:mm:ss");
ZoneId desiredZone = ZoneId.of("America/Fort_Nelson");
String feUltMod = "2018-07-20 18:53:46.598000 +02:00:00";
OffsetDateTime dateTime = OffsetDateTime.parse(feUltMod, origFormatter);
ZonedDateTime dateTimeWithTimeZoneApplied = dateTime.atZoneSameInstant(desiredZone);
feUltMod = dateTimeWithTimeZoneApplied.format(desiredFormatter);
System.out.println(feUltMod);
Output from this snippet is:
20/07/2018 09:53:46
Generally you need two formatters for converting a date or date-time from one format to another: one that specifies the format to convert from and one that specifies the format to convert to.
into a DateTime object like this
A date-time object doesn’t have a format, so in that respect cannot be “like this”. dateTimeWithTimeZoneApplied in the above snippet is in the specified time zone, so has the hours adjusted. After converting to this time zone I have formatted into a string in the format you mentioned, in case you wanted this (I didn’t find it clear).
I am using and recommending java.time, the modern Java date and time API. The date and time classes you were using, Date and SimpleDateFormat, are long outdated and poorly designed, it’s not worth struggling with them. Also SimpleDateFormat supports only milliseconds so can only work correctly with exactly 3 decimals on the seconds, not with the 6 decimals you have got.
Link: Oracle tutorial: Date Time explaining how to use java.time.
final SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm");
Date df = new Date();
String yourString = sdf.format(df);
Date parsedDate = sdf.parse(yourString);
Timestamp sqlDate = new java.sql.Timestamp(parsedDate.getTime());
The above code will give you current Timestamp.Timestamp will provide better feasibilty
I have the following string "2015-04-02 11:52:00+02" and I need to parse it in Java to a Timestamp.
I tried all sorts of formats including
SimpleDateFormat mdyFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss+Z");
but nothing seems to work - I keep getting a ParseException
Can anyone help?
I need something like:
SimpleDateFormat mdyFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss+Z");
Timestamp t = new Timestamp(mdyFormat.parse("2015-04-02 11:52:00+02").getTime());
Try This
String str="2009-12-31 23:59:59 +0100";
/\
||
Provide Space while providing timeZone
SimpleDateFormat mdyFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss Z");
System.out.println(mdyFormat.parse(str));
Output
Fri Jan 01 04:29:59 IST 2010
java.sql.Timestamp objects don't have time zones - they are instants in time, like java.util.Date
So try this:
SimpleDateFormat mdyFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Timestamp t = new Timestamp(mdyFormat.parse("2015-04-02 11:52:00").getTime());
try "yyyy-MM-dd HH:mm:ssX"
Z stand for timezone in the following format: +0800
X stand for timezone in the following format: +08
Examples here
ISO 8601
Replace that SPACE in the middle with a T and you have a valid standard (ISO 8601) string format that can be parsed directly by either the Joda-Time library or the new java.time package built into Java 8 (inspired by Joda-Time). Search StackOverflow for hundreds of examples.
If using java.time, read my comment on Question about a bug when parsing hours-only offset value.
Example in Joda-Time 2.7.
String inputRaw = "2015-04-02 11:52:00+02";
String input = inputRaw.replace( " ", "T" );
DateTimeZone zone = DateTimeZone.forID( "America/Montreal" ); // Specify desired time zone adjustment.
DateTime dateTime = new DateTime( input, zone );
I want to parse the following string in Java and convert it to a date:
DTSTART;TZID=America/Los_Angeles:20140423T120000
I tried this:
SimpleDateFormat sdf = new SimpleDateFormat("'DTSTART;TZID='Z':'yyyyMMdd'T'hhmmss");
Date start = sdf.parse("DTSTART;TZID=America/Los_Angeles:20140423T120000");
And this:
SimpleDateFormat sdf = new SimpleDateFormat("'DTSTART;TZID='z':'yyyyMMdd'T'hhmmss");
Date start = sdf.parse("DTSTART;TZID=America/Los_Angeles:20140423T120000");
But it still doesn't work. I think the problem is in America/Los_Angeles.
Can you help me please?
Thank you
Try this one using TimeZone.
Note: You have to split your date string before doing this operation.
SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd'T'hhmmss");
TimeZone tz = TimeZone.getTimeZone("America/Los_Angeles");
sdf.setTimeZone(tz);
Date start = sdf.parse("20140423T120000");
In SimpleDateFormat pattern Z represent RFC 822 4-digit time zone
For more info have a look at SimpleDateFormat#timezone.
If you look for a solution how to parse the whole given string in one and only one step then Java 8 offers this option (the pattern symbol V is not supported in SimpleDateFormat):
// V = timezone-id, HH instead of hh for 24-hour-clock, u for proleptic ISO-year
DateTimeFormatter dtf =
DateTimeFormatter.ofPattern("'DTSTART;TZID='VV:uuuuMMdd'T'HHmmss");
ZonedDateTime zdt =
ZonedDateTime.parse("DTSTART;TZID=America/Los_Angeles:20140423T120000", dtf);
Instant instant = zdt.toInstant();
// if you really need the old class java.util.Date
Date jdkDate = Date.from(instant);