I've installed BIRT Web-Viewer on my server and am able to build the report with this URL:
http://hostname:port/birt/run?__report=test.rptdesign
Now I need to programmatically call this URL from my Java Code and retrieve the result as stream or file.
Is there any API for the Web-Viewer?
If not, could I just call the URL like this and extract the PDF?:
HttpClient httpClient = HttpClients.createDefault();
HttpGet postRequest = new HttpPost("http://hostname:port/birt/run");
List<NameValuePair> formData = new ArrayList<>();
formData.add(new BasicNameValuePair("__report", "test.rptdesign"));
HttpEntity entity = new UrlEncodedFormEntity(formData);
HttpResponse response = httpClient.execute(postRequest);
I found out, if I use the __format parameter with the value pdf, the response to the request is the PDF content, which is exactly what I wanted.
The standard response is a HTML, which will be returned with a second request. I'm pretty sure that response has to be retrieved with sessions.
Edit:
As requested I will post my request code. I modified it a bit, because I used some custom classes to hold configuration and the report.
public InputStream getReport() throws Exception {
StringBuilder urlBuilder = new StringBuilder()
.append("http://example.com:9080/contextRoot/run")
.append("?__report=ReportDesign.rptdesign&__format=pdf");
if (reportParameters != null) {
for (Map.Entry<String, String> parameter : reportParameters.entrySet()) {
String key = StringEscapeUtils.escapeHtml(parameter.getKey());
String value = StringEscapeUtils.escapeHtml(parameter.getValue());
urlBuilder.append('&')
.append(key);
.append('=');
.append(value);
}
}
URL requestUrl = new URL(burlBuilder.toString());
HttpURLConnection connection = (HttpURLConnection) requestUrl.openConnection();
connection.setRequestMethod("GET");
connection.setDoInput(true);
connection.connect();
return connection.getInputStream();
}
I also had another method write the used data as XML to the file system before I called requestUrl.openConnection(), but I think this is only necessary if you use very dynamic data like I did.
Related
I'm new to android development and I'm working on an app that is supposed to send a local image file to a web service and get the response back.
I was able to send a URL of an image from general online sources through my code, and it worked.
But the requirement is to pass an image from the gallery via the API.
The Code I have set up is giving me an invalid URL error when I get the information for the image selected as below. How do I get around this to pass the image from the gallery?
The API allows for multipart/form-data too. I'm not sure how to extract the image data for it using the gallery data.
I have commented the line of code in the JSON object accumulate which does not work.
'''
//setting uploaded image to view
Uri selectedImage = data.getData();
//get url
String URILOCATION = selectedImage.getPath();
imageView.setImageURI(data.getData());
HttpClient httpclient = HttpClients.createDefault();
try
{
URIBuilder builder = new URIBuilder("https://eastus.api.cognitive.microsoft.com/customvision/v3.0/Prediction/aaead50a-95cd-403c-a3c2-9b774399e43b/classify/iterations/Iteration6/url");
URI uri = builder.build();
HttpPost request = new HttpPost(uri);
request.setHeader("Content-Type", "application/json");
request.setHeader("Prediction-key", predictionApiKey);
String json = "";
// 3. build jsonObject
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("url","https://i.ibb.co/XCnhQ2m/IMG20210503153531.jpg");
//jsonObject.accumulate("url",URILOCATION);
// 4. convert JSONObject to JSON to String
json = jsonObject.toString();
// Request body
StringEntity reqEntity = new StringEntity(json);
request.setEntity(reqEntity);
HttpResponse response = httpclient.execute(request);
HttpEntity entity = response.getEntity();
if (entity != null)
{
System.out.println(EntityUtils.toString(entity));
}
'''
I need to send a GET request with a json body in java/spring boot. I'm aware of the advice against it, however I have to do it this was for a couple of reasons:
1. The 3rd party API I'm using only allows GET requests, so POST is not an option.
2. I need to pass an extremely large parameter in the body (a comma separated list of about 8-10k characters) so tacking query params onto the url is not an option either.
I've tried a few different things:
apache HttpClient from here: Send content body with HTTP GET Request in Java. This gave some error straight from the API itself about a bad key.
URIComponentsBuilder from here: Spring RestTemplate GET with parameters. This just tacked the params onto the url, which as I explained before is not an option.
restTemplate.exchange. This seemed the most straightforward, but the object wouldn't pass: https://docs.spring.io/spring/docs/current/javadoc-api/org/springframework/web/client/RestTemplate.html#exchange-java.lang.String-org.springframework.http.HttpMethod-org.springframework.http.HttpEntity-java.lang.Class-java.util.Map-
as well as probably another thing or two that I've forgotten about.
Here is what I'm talking about in Postman. I need to be able to pass both of the parameters given here. It works fine if run through Postman, but I can't figure it out in Java/Spring Boot.
Here is a code snippet from the restTemplate.exchange attempt:
public String makeMMSICall(String uri, List<String> MMSIBatchList, HashMap<String, String> headersList) {
ResponseEntity<String> result = null;
try {
RestTemplate restTemplate = new RestTemplate();
HttpHeaders headers = new HttpHeaders();
for (String key : headersList.keySet()) {
headers.add(key, headersList.get(key));
}
Map<String, String> params = new HashMap<String, String>();
params.put("mmsi", String.join(",", MMSIBatchList));
params.put("limit", mmsiBatchSize);
HttpEntity<?> entity = new HttpEntity<>(headers);
result = restTemplate.exchange(uri, HttpMethod.GET, entity, String.class, params);
System.out.println(result.getBody());
} catch (RestClientException e) {
LOGGER.error("Exception in makeGetHTTPCall :" + e.getMessage());
throw e;
} catch (Exception e) {
LOGGER.error("Exception in makeGetHTTPCall :" + e.getMessage());
throw e;
}
return result.getBody();
}
Thanks for helping!
You can try java.net.HttpUrlConnection, it works for me but indeed I normally use a POST
HttpURLConnection connection = null;
BufferedReader reader = null;
String payload = "body";
try {
URL url = new URL("url endpoint");
if (url.getProtocol().equalsIgnoreCase("https")) {
connection = (HttpsURLConnection) url.openConnection();
} else {
connection = (HttpURLConnection) url.openConnection();
}
// Set connection properties
connection.setRequestMethod(method); // get or post
connection.setReadTimeout(3 * 1000);
connection.setDoOutput(true);
connection.setUseCaches(false);
if (payload != null) {
OutputStream os = connection.getOutputStream();
os.write(payload.getBytes(StandardCharsets.UTF_8));
os.flush();
os.close();
}
int responseCode = connection.getResponseCode();
}
There's no way of implementing it via RestTemplate, even with .exchange method. It'll simply not send the request body for GET calls even if we pass the entity within the function parameters.(Tested via interceptor logs)
You can use the Apache client to solve this issue/request (whatever you'd like to call it). The code you need is something along following lines.
private static class HttpGetWithBody extends HttpEntityEnclosingRequestBase {
JSONObject requestBody;
public HttpGetWithBody(URI uri, JSONObject requestBody) throws UnsupportedEncodingException {
this.setURI(uri);
StringEntity stringEntity = new StringEntity(requestBody.toString());
super.setEntity(stringEntity);
this.requestBody = requestBody;
}
#Override
public String getMethod() {
return "GET";
}
}
private JSONObject executeGetRequestWithBody(String host, Object entity) throws ClientProtocolException, IOException {
CloseableHttpClient httpClient = HttpClients.createDefault();
try{
JSONObject requestBody = new JSONObject(entity);
URL url = new URL(host);
HttpRequest request = new HttpGetWithBody(url.toURI(), requestBody);
request.addHeader(HttpHeaders.CONTENT_TYPE, MediaType.APPLICATION_JSON_VALUE);
request.addHeader(HttpHeaders.ACCEPT, MediaType.APPLICATION_JSON_VALUE);
HttpResponse response;
if(url.getPort() != 0) response = httpClient.execute(new HttpHost(url.getHost(), url.getPort()), request);
else response = httpClient.execute(new HttpHost(url.getHost()), request);
if(response.getStatusLine().getStatusCode() == HttpStatus.SC_OK){
JSONObject res = new JSONObject(EntityUtils.toString(response.getEntity(), StandardCharsets.UTF_8));
httpClient.close();
return res;
}
}catch (Exception e){
log.error("Error occurred in executeGetRequestWithBody. Error: ", e.getStackTrace());
}
httpClient.close();
return null;
}
If you inspect even Apache client library doesn't support passing the body natively(checked via code implementation of HttpGet method), since contextually request body for a GET request is not a good and obvious practice.
Try creating a new custom RequestFactory.
Similar to
get request with body
I try to create a group of devices in Firebase Cloud Messaging and I got an ioexception "https://android.googleapis.com/gcm/googlenotification".
I have several questions about it:
What I need to put in fields: senderId, registrationId, idToken?
How I change this part of code to create a group and not add to group?
Where I need to put "authorization", "key=AIzaS..."?
Code:
public String addNotificationKey(
String senderId, String userEmail, String registrationId, String idToken)
throws IOException, JSONException {
URL url = new URL("https://android.googleapis.com/gcm/googlenotification");
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setDoOutput(true);
// HTTP request header
con.setRequestProperty("project_id", senderId);
con.setRequestProperty("Content-Type", "application/json");
con.setRequestProperty("Accept", "application/json");
con.setRequestMethod("POST");
con.connect();
// HTTP request
JSONObject data = new JSONObject();
data.put("operation", "add");
data.put("notification_key_name", userEmail);
data.put("registration_ids", new JSONArray(Arrays.asList(registrationId)));
data.put("id_token", idToken);
OutputStream os = con.getOutputStream();
os.write(data.toString().getBytes("UTF-8"));
os.close();
// Read the response into a string
InputStream is = con.getInputStream();
String responseString = new Scanner(is, "UTF-8").useDelimiter("\\A").next();
is.close();
// Parse the JSON string and return the notification key
JSONObject response = new JSONObject(responseString);
return response.getString("notification_key");
}
For #3:
con.setRequestProperty("Authorization", "key=AIzaS...");
What I need to put in fields: senderId, registrationId, idToken?
See their definitions in Credentials.
Sender ID can be found in your Firebase Console. Go to Project Settings, then Cloud Messaging tab.
Registration token is generated on your client app side. See the corresponding setup documentation depending on the client app type here.
idToken is (AFAIK) only used on the client app side. See the (Android) documentation here.
How I change this part of code to create a group and not add to group?
Change
data.put("operation", "add");
to
data.put("operation", "create");
Where I need to put "authorization", "key=AIzaS..."?
See Puf's answer.
I wanted to send XML file as attachment over URL from Java class
Code with which i am trying is as below
File request_XML_file = new File("src/request.xml");
URL url = new URL("https://************?p_xml_file="+request_XML_file);
conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setRequestProperty("enctype","multipart/form-data");
But value passed for p_xml_file is src/request.xml
You can also consider the new features of Java 7
Path path = Paths.get("/tmp/foo/bar.txt"); Files.createDirectories(path.getParent()); try { Files.createFile(path); } catch (FileAlreadyExistsException e) { System.err.println("already exists: " + e.getMessage()); } } }
Kindly use this link
http://svn.apache.org/viewvc/httpcomponents/oac.hc3x/trunk/src/examples/PostXML.java?view=markup
DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost postRequest = new HttpPost("http://localhost:8080/TESTINGrestful/rest/polls/comment"); StringEntity input = new StringEntity("<Comment>...</Comment>"); input.setContentType("text/xml"); postRequest.setEntity(input); HttpResponse response = httpClient.execute(postRequest);
After 2 days search got some use full stuff and its worked for me.. No need to import any additional Jar file..
If we wanted to send an file as attachment over RESTFul Web service URL MultipartUtility is correct why to do it..
Here we go..!! A ready made code --> http://www.codejava.net/java-se/networking/upload-files-by-sending-multipart-request-programmatically
Is it possible to embed a file attachment in a JSON Object. I have a HTML Form, which has several text field inputs and a file attachment. I want to send a JSON Object wrapping all these form data (including the file attachment) to the server.
Are there any particular libraries in Java available to do that? Can you give possible solution for this.
Thanks
If you want to send the actual data of the file, you'd probably want to encode it as a base64 string and send that in your JSON - see fiddle for example of encoding it in javascript:
http://jsfiddle.net/eliseosoto/JHQnk/
Then you could do the opposite on your server-side using whatever language and/or libraries are appropriate.
Use MultipartEntity, someone else posted a similar question: How to send file in JSON on android?
You could also consider saving the files on the server and sending a path/url to the file location where the other server can access them.
public String SendToServer(String aUrl,File Filename)
{
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(filename);
try
{
MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
entity.addPart("file", new FileBody(Filename));
entity.addPart("video-title", new StringBody("Video"));
entity.addPart("video-type", new StringBody("1"));
httpPost.setEntity(entity);
HttpContext context = new BasicHttpContext();
// Bind custom cookie store to the local context
context.setAttribute(ClientContext.COOKIE_STORE, Globals.sessionCookie);
HttpResponse response = httpClient.execute(httpPost, context);
HttpEntity resEntity = response.getEntity();
String Response = "";
if (response != null)
{
Response = EntityUtils.toString(resEntity);
}
return Response;
}
catch (IOException e)
{
e.printStackTrace();
}
return "Exception";
}