I'm new to android development and I'm working on an app that is supposed to send a local image file to a web service and get the response back.
I was able to send a URL of an image from general online sources through my code, and it worked.
But the requirement is to pass an image from the gallery via the API.
The Code I have set up is giving me an invalid URL error when I get the information for the image selected as below. How do I get around this to pass the image from the gallery?
The API allows for multipart/form-data too. I'm not sure how to extract the image data for it using the gallery data.
I have commented the line of code in the JSON object accumulate which does not work.
'''
//setting uploaded image to view
Uri selectedImage = data.getData();
//get url
String URILOCATION = selectedImage.getPath();
imageView.setImageURI(data.getData());
HttpClient httpclient = HttpClients.createDefault();
try
{
URIBuilder builder = new URIBuilder("https://eastus.api.cognitive.microsoft.com/customvision/v3.0/Prediction/aaead50a-95cd-403c-a3c2-9b774399e43b/classify/iterations/Iteration6/url");
URI uri = builder.build();
HttpPost request = new HttpPost(uri);
request.setHeader("Content-Type", "application/json");
request.setHeader("Prediction-key", predictionApiKey);
String json = "";
// 3. build jsonObject
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("url","https://i.ibb.co/XCnhQ2m/IMG20210503153531.jpg");
//jsonObject.accumulate("url",URILOCATION);
// 4. convert JSONObject to JSON to String
json = jsonObject.toString();
// Request body
StringEntity reqEntity = new StringEntity(json);
request.setEntity(reqEntity);
HttpResponse response = httpclient.execute(request);
HttpEntity entity = response.getEntity();
if (entity != null)
{
System.out.println(EntityUtils.toString(entity));
}
'''
Related
I'm trying to publish image from my automation suite to slack channel.
URL to hit: https://slack.com/api/files.upload
Body is form-data type and it has,
file - image file upload
initial_comment - some string
channels - the slack channel to be published.
i tried using MultipartEntity class inside HttpPost
MultipartEntity multiPartEntity = new MultipartEntity();
FileBody fileBody = new FileBody(file);
//Prepare payload
multiPartEntity.addPart("file", fileBody);
multiPartEntity.addPart("file_type", new StringBody("JPG"));
multiPartEntity.addPart("initial_comment", new StringBody("cat shakes"));
multiPartEntity.addPart("channels", new StringBody("bot-e2e-report"));
//Set to request body
postRequest.setEntity(multiPartEntity);
Im getting the success response from http post. but the image is not posted in slack channel.any help!
The problem was with header. Actually, this slack api gives 200 response even for the wrong header. Working code:
CloseableHttpClient httpclient = HttpClients.createDefault();
try {
//Set various attributes
MultipartEntityBuilder entitybuilder = MultipartEntityBuilder.create();
entitybuilder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);
entitybuilder.addBinaryBody("file", file);
entitybuilder.addTextBody("initial_comment", "cat");
entitybuilder.addTextBody("channels","bot-e2e-report");
HttpEntity mutiPartHttpEntity = entitybuilder.build();
RequestBuilder reqbuilder = RequestBuilder.post("https://slack.com/api/files.upload");
reqbuilder.setEntity(mutiPartHttpEntity);
//set Header
reqbuilder.addHeader("Authorization", "Bearer xoxb-16316687382-1220823299362-fdkBklPrY7rc72bQk3WSOSjD");
HttpUriRequest multipartRequest = reqbuilder.build();
// call post
HttpResponse response = httpclient.execute(multipartRequest);
// Parse the response
HttpEntity entity = response.getEntity();
String json = EntityUtils.toString(entity, StandardCharsets.UTF_8);
System.out.println(json);
I've installed BIRT Web-Viewer on my server and am able to build the report with this URL:
http://hostname:port/birt/run?__report=test.rptdesign
Now I need to programmatically call this URL from my Java Code and retrieve the result as stream or file.
Is there any API for the Web-Viewer?
If not, could I just call the URL like this and extract the PDF?:
HttpClient httpClient = HttpClients.createDefault();
HttpGet postRequest = new HttpPost("http://hostname:port/birt/run");
List<NameValuePair> formData = new ArrayList<>();
formData.add(new BasicNameValuePair("__report", "test.rptdesign"));
HttpEntity entity = new UrlEncodedFormEntity(formData);
HttpResponse response = httpClient.execute(postRequest);
I found out, if I use the __format parameter with the value pdf, the response to the request is the PDF content, which is exactly what I wanted.
The standard response is a HTML, which will be returned with a second request. I'm pretty sure that response has to be retrieved with sessions.
Edit:
As requested I will post my request code. I modified it a bit, because I used some custom classes to hold configuration and the report.
public InputStream getReport() throws Exception {
StringBuilder urlBuilder = new StringBuilder()
.append("http://example.com:9080/contextRoot/run")
.append("?__report=ReportDesign.rptdesign&__format=pdf");
if (reportParameters != null) {
for (Map.Entry<String, String> parameter : reportParameters.entrySet()) {
String key = StringEscapeUtils.escapeHtml(parameter.getKey());
String value = StringEscapeUtils.escapeHtml(parameter.getValue());
urlBuilder.append('&')
.append(key);
.append('=');
.append(value);
}
}
URL requestUrl = new URL(burlBuilder.toString());
HttpURLConnection connection = (HttpURLConnection) requestUrl.openConnection();
connection.setRequestMethod("GET");
connection.setDoInput(true);
connection.connect();
return connection.getInputStream();
}
I also had another method write the used data as XML to the file system before I called requestUrl.openConnection(), but I think this is only necessary if you use very dynamic data like I did.
I am developing an android app which uses a login api, which will allow its web users to login with their same credentials on the android device.....
the url for the api is
https://api.ecoachsolutions.com/main.php?ecoachsignin=1&server=remote&user=ecoachguest&pass=ecoachguest
which retuns a response in json
JSON object: {
status: <success or error>,
msg: <response message>,
profile: <user profile object>
}
I tried this code which I found searching on the internet but it isn't working,
private void doLogin(View view) {
//ALERT MESSAGE
_spinner.setVisibility(View.VISIBLE);
Toast.makeText(mContext, "connecting to server.... ",
Toast.LENGTH_SHORT).show();
// URLEncode user defined data
String usernameValue = username.getText().toString();
String passValue = password.getText().toString();
// Create http cliient object to send request to server
HttpClient Client = new DefaultHttpClient();
// Create URL string
String URL = "https://api.ecoachsolutions.com/main.php?ecoachsignin=1&server=remote&user="+usernameValue+"&pass="+passValue;
Log.i("httpget", URL);
try
{
String SetServerString ;
// Create Request to server and get response
HttpGet httpget = new HttpGet(URL);
ResponseHandler<String> responseHandler = new BasicResponseHandler();
SetServerString = Client.execute(httpget, responseHandler);
System.out.println(usernameValue);
System.out.println(passValue);
// Show response on activity
Toast.makeText(getBaseContext(),SetServerString,Toast.LENGTH_LONG).show();
}
catch(Exception ex)
{
Toast.makeText(getBaseContext(),"Fail",Toast.LENGTH_LONG).show();
_spinner.setVisibility(View.INVISIBLE);
}
}
will appreciate the help or the positive direction thanks :)
Change your code to get the HttpResponse like below,
String responseBody = "";
HttpResponse response = client.execute(post);
int responseCode = response.getStatusLine().getStatusCode();
Log.i("GET Response Code ",responseCode + "");
switch(responseCode) {
// Means server is responding
case 200:
HttpEntity entity = response.getEntity();
if(entity != null) {
responseBody = EntityUtils.toString(entity);
// Now you can try printing your returned string here, before you go for JSON parsing
}
break;
// Add more case statements to handle other scenarios
}
The code is simple, but if still unable to understand, don't hesitate to ask.
Hi iam creating an android application. In my application i have some form fields like edittext and radio buttons i am creating a JSONObject by retrieving text from all the form fields. JsonObject is created successfully. Now i want to pass this object to my PHP page where i have written code for getting this details and storing it in database. My problem is i am not understanding how to send this JSON object through httpPost or httpGet method. Only way i know is send parameters through List<NameValuePair> so i'm trying to convert JSONObject to List<NameValuePair>. Can anybody provide a method which can directly convert my JSONObject to List<NameValuePair>. Is there any predefined method for doing this. Or can any one provide solution where i can directly send by JSONObject to PHP and retrieve there.
Pass your JSONObject as a string to the String Entity constructor and then pass it to setEntity()
Sample:
HttpPost request = new HttpPost("//website");
StringEntity params =new StringEntity("passmyjson=" + yourJSONOBject.toString());
request.addHeader("content-type", "//header");
request.setEntity(params);
HttpResponse response = httpClient.execute(request);
in php File to check that it works;
<?php
print_r($_POST);
$json_string = $_POST['passmyjson'];
$json = json_decode($json_string);
print_r($json);
?>
You can do that with Apache HttpClient. I assume you have already a PHP handler that handles this request. Simply,
Create your JSONObject
Put your desired values
Send that json to php handler
You need to send request as application/x-www-form-urlencoded
Let's call url : http://your_php_service.com/handleJson;
HttpClient httpClient = new DefaultHttpClient();
JSONObject json = new JSONObject();
json.put("key", "val");
try {
HttpPost request = new HttpPost("http://your_php_service.com/handleJson");
StringEntity params = new StringEntity("json=" + json.toString());
request.addHeader("content-type", "application/x-www-form-urlencoded");
request.setEntity(params);
HttpResponse response = httpClient.execute(request);
} catch (Exception ex) {
} finally {
httpClient.getConnectionManager().shutdown();
}
The format of request param will be ;
json={"key": "val"}
And you can handle this on php side like;
<?php
.....
$json = $_POST["json"]; // This will be json string
.....
Thank you all i got it
I added the following lines to my android Activity class
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpResponse httpResponse;
HttpPost httppost = new HttpPost(link); //-->link is the php page url
httppost.setEntity(new StringEntity(obj.toString())); //-->obj is JSONObject
httpResponse = httpClient.execute(httppost);
HttpEntity httpEntity = httpResponse.getEntity();
and in my php file i have added the following code
$msg=json_decode(file_get_contents('php://input'), true);
To get particular value from recieved Json string i added this $data = $msg['name'] ;
It is working
Is it possible to embed a file attachment in a JSON Object. I have a HTML Form, which has several text field inputs and a file attachment. I want to send a JSON Object wrapping all these form data (including the file attachment) to the server.
Are there any particular libraries in Java available to do that? Can you give possible solution for this.
Thanks
If you want to send the actual data of the file, you'd probably want to encode it as a base64 string and send that in your JSON - see fiddle for example of encoding it in javascript:
http://jsfiddle.net/eliseosoto/JHQnk/
Then you could do the opposite on your server-side using whatever language and/or libraries are appropriate.
Use MultipartEntity, someone else posted a similar question: How to send file in JSON on android?
You could also consider saving the files on the server and sending a path/url to the file location where the other server can access them.
public String SendToServer(String aUrl,File Filename)
{
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(filename);
try
{
MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
entity.addPart("file", new FileBody(Filename));
entity.addPart("video-title", new StringBody("Video"));
entity.addPart("video-type", new StringBody("1"));
httpPost.setEntity(entity);
HttpContext context = new BasicHttpContext();
// Bind custom cookie store to the local context
context.setAttribute(ClientContext.COOKIE_STORE, Globals.sessionCookie);
HttpResponse response = httpClient.execute(httpPost, context);
HttpEntity resEntity = response.getEntity();
String Response = "";
if (response != null)
{
Response = EntityUtils.toString(resEntity);
}
return Response;
}
catch (IOException e)
{
e.printStackTrace();
}
return "Exception";
}